<?xml version="1.0"?>
<rss version="2.0">
   <channel>
      <title>Kesetimbangan Kimia by DWI HARI SUGIARTO</title>
      <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6</link>
      <description>Posting respons Anda ke topik diskusi dengan mengklik tombol plus di bawah ini.</description>
      <language>en-us</language>
      <pubDate>2024-10-23 06:37:35 UTC</pubDate>
      <lastBuildDate>2024-10-30 07:38:57 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
      <image>
         <url>https://padlet.net/icons/png/1f4ac.png</url>
      </image>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183169540</link>
         <description><![CDATA[<p>Revan Ringgo Ramadhan</p><p><br/></p><p>Ketika beban yg lebih berat posisi jungkat jungkit ke bawah, maka juga sebaliknya harus beban lebih ringan posisi jungkat jungkit diatas.</p><p><br/></p><ol><li><p>Agcl(s) = Ag ( Aq ) + Cl ( Aq ) = heterogen</p><p>alasan : karena campuran heterogen merupakan campuran yang komposisinya tidak seragam di seluruh campuran.</p></li><li><p>PCL2 (g) = PCL (g) + CL2 (g) = homogen</p><p>alasan : karena campuran homogen merupakan campuran zat yg penyusunannya lebih sempurna.</p></li><li><p>Fe2O3 (s) + 3CO (g) = 2Fe(s) + 3CO2 (g) = heterogen</p><p>alasan : karena campuran heterogen merupakan campuran dgn komposisi tidak merata karena terbentuk dari 2 fase.</p></li><li><p>2N2O5(g) = 4NO2(g) + O2(g) = homogen</p><p>alasan : karena bahan terlarut dgn jumlah yg sama di seluruh larutan.</p></li></ol><p><br/></p><p>soal nomor 1</p><ol><li><p>Sb2S3(s) + 3H2 (g) = 2sb(s) + 3H2(g)</p><p>Kh = (H3)2 / (H)3</p></li></ol>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/2931726282/7f0244aee8bce1f6f01a2880147c7d71/photo.jpeg" />
         <pubDate>2024-10-23 06:49:14 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183169540</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183169881</link>
         <description><![CDATA[<p>Muhammad Arkazora Agdrihan</p><p><br/></p><ol><li><p>jungkat-jungkit adalah balok yang dipasang pada tuas. Keseimbangan jungkat-jungkit dapat terjadi ketika anak-anak dengan berat yang sama diposisikan pada jarak yang sama dari pusat jungkat-jungkit. Oleh karena itu, Jungkat-jungkit dapat menggambarkan reaksi kesetimbangan kimia karena keduanya membutuhkan keseimbangan</p></li><li><p>a.<strong> AgCl(s) --&gt; &lt;-- Ag+(aq) + Cl-(aq) = Heterogen</strong></p><p>Alasannya: Karena zat penyusunnya tidak tercampur sempurna. </p><p>b. <strong>PCl5(g)--&gt;&lt;-- PCl3(g) + Cl2(g) = Homogen</strong></p><p>Alasannya: Karena zat penyusunnya tercampur sempurna</p><p>c. <strong>Fe2O3(s) +3CO(g)--&gt;&lt;--2Fe(s) + 3CO2(g) = Heterogen</strong></p><p>Alasannya: Karena zat penyusunnya tidak tercampur sempurna</p><p>d. <strong>2N2O5(g)--&gt;&lt;--4NO2(g) + O2(g) = Homogen</strong></p><p>Alasannya: Karena zat penyusunnya tercampur sempurna</p></li></ol>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/2931726834/735dc6586f49738e096a2f5eed5695e7/photo.jpeg" />
         <pubDate>2024-10-23 06:49:25 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183169881</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183170338</link>
         <description><![CDATA[<p>Caca</p>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/2931722806/976eb001fb990603e9f4882e2a2cb401/17296660950121493274314992179742.jpg" />
         <pubDate>2024-10-23 06:49:41 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183170338</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183171289</link>
         <description><![CDATA[<p>Yumna</p>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/2931736691/ab3ad1b321f0175051bd2ad34f5614d4/d6f6d108c5f02e23c66008e5a2797f97.jpg" />
         <pubDate>2024-10-23 06:50:08 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183171289</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183172426</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/2931732541/a3629e2499c5c294a8550647daaedddd/photo.jpeg" />
         <pubDate>2024-10-23 06:50:40 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183172426</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183173864</link>
         <description><![CDATA[<p>tasya</p><p><br></p>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/2931733955/b7cffb0cc43c2f8a0319da0470191824/image.jpg" />
         <pubDate>2024-10-23 06:51:34 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183173864</guid>
      </item>
      <item>
         <title></title>
         <author>dwi924_</author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183202944</link>
         <description><![CDATA[<p>Soal Nomor 2</p><p><br/></p><p><br/></p>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/2221276877/e9c07e70e4db803f5bb90df2fd692cbb/image.png" />
         <pubDate>2024-10-23 07:10:18 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183202944</guid>
      </item>
      <item>
         <title></title>
         <author>dwi924_</author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183248805</link>
         <description><![CDATA[<p>Soal nomor 3</p><p><br/></p>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/2221276877/57639fdd7eccb7f90f1e79761109ef4a/image.png" />
         <pubDate>2024-10-23 07:42:12 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3183248805</guid>
      </item>
      <item>
         <title></title>
         <author>dwi924_</author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193961049</link>
         <description><![CDATA[<p>Soal Nomor 4</p><p><br/></p><p><br/></p>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/2221276877/e4d03cd08e403f2086cf35f292175e82/image.png" />
         <pubDate>2024-10-30 06:53:04 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193961049</guid>
      </item>
      <item>
         <title></title>
         <author>dwi924_</author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193963457</link>
         <description><![CDATA[<p>Sumber Buku</p>]]></description>
         <enclosure url="https://static.buku.kemdikbud.go.id/content/pdf/bukuteks/kurikulum21/Kimia-BS-KLS-XI.pdf" />
         <pubDate>2024-10-30 06:54:31 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193963457</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193965245</link>
         <description><![CDATA[<p>1. NOCl₂(g) K PNO Pd, PNOCI NO(g) + Cl2(g)</p><p>2. 2NO(g) + O2(g) 2NO2(g) (PNO)2 Kp = (PNO) PO</p>]]></description>
         <enclosure url="" />
         <pubDate>2024-10-30 06:56:05 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193965245</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193968077</link>
         <description><![CDATA[<p>Soal No. 1 dan 2</p><ol><li><p>NOCL2(g) = NO(g) + CL2 ( g )</p><p>Kp =  (PnO)  x (Pcl2) / (Pnocl2)</p></li><li><p>2NO(g) + O2 ( g ) = 2NO2(g)</p><p>Kp = ( Pno2)2 / ( Pno )2 x ( Po2 )</p><p><br></p></li></ol>]]></description>
         <enclosure url="" />
         <pubDate>2024-10-30 06:58:44 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193968077</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193972860</link>
         <description><![CDATA[<p>Muhammad Arkazora Agdrihan</p><p>Soal Nomor 3</p><ol><li><p>Sb2S2(s) + 3H2(g) --&gt;&lt;-- 2Sb(s) +3H2(g)</p><p>Kc = [H2]3</p><p>        _______</p><p>         [H2]3</p></li><li><p>CaCO2(s)--&gt;&lt;-- CaO(s) + CO2(g)</p><p>Kc = [CO2}</p></li><li><p>C6H12O6(s) + 6O2(g)--&gt;&lt;-- 6CO2(g) + 6H2O(g)</p><p>Kc=  [CO2]6+[H2O]6</p><p>         _________________</p><p>                [O2]6</p></li><li><p>CO2(g) + C(s)--&gt;&lt;--CO(g)</p><p>Kc=  [CO]</p><p>       _______</p><p>        [CO2]</p></li></ol>]]></description>
         <enclosure url="" />
         <pubDate>2024-10-30 07:03:07 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193972860</guid>
      </item>
      <item>
         <title></title>
         <author>shakilaghitasantoso09</author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193974771</link>
         <description><![CDATA[<p>No4</p>]]></description>
         <enclosure url="" />
         <pubDate>2024-10-30 07:04:39 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193974771</guid>
      </item>
      <item>
         <title></title>
         <author>hafiizh</author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193975009</link>
         <description><![CDATA[<p>4</p>]]></description>
         <enclosure url="" />
         <pubDate>2024-10-30 07:04:49 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193975009</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193976943</link>
         <description><![CDATA[<p>Muhammad Arkazora Agdrihan</p><p>Soal No 4</p><p><br/></p><ol><li><p>NOCl2(g)--&gt;&lt;--NO(g) + Cl2(g)</p><p>Kp = (PnO x (Pcl2) / PNOCl2)</p></li><li><p>2NO(g + O2 (g) = 2NO2(g)</p><p>Kp= (PNO2 2/ (PNO)2 x (PO2)</p></li></ol>]]></description>
         <enclosure url="" />
         <pubDate>2024-10-30 07:06:26 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193976943</guid>
      </item>
      <item>
         <title></title>
         <author>naayumnaaw</author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193979870</link>
         <description><![CDATA[<p>No. 4 </p>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/2964479026/fd79696a2507349d2fa134cd0b3828ec/17302720786561220529283027016084.jpg" />
         <pubDate>2024-10-30 07:08:19 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193979870</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193980290</link>
         <description><![CDATA[<p>Soal no. 3, 4</p><p>3. C6H12O6 (s) + 6O2 (g) =  6CO2 (g) + 6H2O(g)</p><p>Kc = (Co2)6 x (H2O)6 / (C6H12O6) x (O2)6</p><p>= (H2O)6 / (O2)6</p><ol start="4"><li><p>CO2 (g) + C(s) = CO(g)</p><p>Kc = (CO)/ (CO2) x (C)</p><p>= (CO)/ (CO2)</p></li></ol>]]></description>
         <enclosure url="" />
         <pubDate>2024-10-30 07:08:32 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3193980290</guid>
      </item>
      <item>
         <title></title>
         <author>dwi924_</author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3194010991</link>
         <description><![CDATA[<p>Soal Nomor 5</p><p><br/></p>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/2221276877/85262928fdf7952a03d4b6b447d58322/image.png" />
         <pubDate>2024-10-30 07:28:38 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3194010991</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3194022556</link>
         <description><![CDATA[<ol><li><p>2NO2(g) = 2NO(g) + O2(g)</p><p>Kc = (NO2) / (O2)</p><p>MNO2 = 5 mol / 1 Liter = 5 molar</p><p>MO2 = 2 mol / 1 Liter = 2 molar</p></li></ol><p>= ( 5 mol )3 / ( 2 mol )3 = ( 125 ) / ( 8 ) = 15.625 molar</p>]]></description>
         <enclosure url="https://padlet.com/dwi924_/kesetimbangan-kimia-zpsdkctba4ok0wu6/wish/wKmOZ5edyeRnZzMA" />
         <pubDate>2024-10-30 07:35:59 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3194022556</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3194023163</link>
         <description><![CDATA[<ol><li><p>2NO2(g)--&gt;&lt;--2NO(g)+O2(g)</p><p>Kc= [NO]2+[O2]</p><p>       _____________</p><p>           [NO2]2</p><p>MNO2 = 5 mol gas/1 liter = 5 molar</p><p>MO2 = 2 mol /1 liter = 2 molar</p><p>= (5 mol )3 / (2 mol)3 = (125)/(8) = 15.625 molar</p></li></ol>]]></description>
         <enclosure url="https://padlet.com/dwi924_/kesetimbangan-kimia-zpsdkctba4ok0wu6/wish/wKmOZ5edyeRnZzMA" />
         <pubDate>2024-10-30 07:36:22 UTC</pubDate>
         <guid>https://padlet.com/dwi924_/zpsdkctba4ok0wu6/wish/3194023163</guid>
      </item>
   </channel>
</rss>
