https://padlet.com/drew_polly/z2gigstewj1j Made with a wish on a star en-us 2017-11-03 08:25:26 UTC 2026-02-27 16:44:38 UTC hello@padlet.com kmcdan12 https://padlet.com/drew_polly/z2gigstewj1j/wish/203554578 On page one, I chose AB+B0=75, this one was pretty simple because I started in the ones place and figured out what plus 0 would give me 5 and then in the tens place that would leave 5 to replace the B leaving me to figure out A and 2+5=7 which means that 2=A. I also chose 129+BBB=240 and used a similar thought process. On page 2, I chose TXW+TXW=864, this one seemed like a pretty obvious one to choose because all I had to do was take the total number and divide it by two since the two numbers were the same. I also chose ABA+ABC=691, this one was a little more difficult but not by much, I had to think about how 2 of the same number could give me an odd number (9) and then realized that A+C would have to equal something that would allow me to carry the one over. The last page was significantly more challenging but I chose HHH+THT=1271 and I had to think again about how numbers would carry over, then last I chose 699+BBB =9BA and this one was trial and error and I tried 1 first then went to 2. ]]> 2017-11-04 17:23:16 UTC https://padlet.com/drew_polly/z2gigstewj1j/wish/203554578 sclemon5 https://padlet.com/drew_polly/z2gigstewj1j/wish/203571211
My strategies to solve the problems were to think about what I needed to add first. For example, when I add a multi-digit numbers with a multi-digit number, I know I need to start in the ones place and move to the left to higher place values until I have completed the addition process. As I started this process, starting in the ones place proved to be successful since there wasn’t any regrouping necessary to solve the problems. However, once I got to the third page and started solving those problems, I noticed my strategy of starting in the ones place wasn’t as effective or helpful. For example, with the problem of TYX + YYT = 9XY, I tried to fill in T and Y from the hundreds column with numbers that totaled 9 and then fill in the gaps from there. After a few attempts, I realized that I would need to regroup my ones to make another 10 in the tens place, so I added that extra ten and that helped me solve the problem more efficiently. I used that same strategy for the second problem on page 3 and that helped solve the problem more quickly as well.

]]> 2017-11-04 21:01:35 UTC https://padlet.com/drew_polly/z2gigstewj1j/wish/203571211 https://padlet.com/drew_polly/z2gigstewj1j/wish/203647173 Heather Curtis-Sowell
In order to begin these problems, I looked at each place to see if any grouping was needed to arrive at the answers. I started with those places first and worked backwards to find the other values. I also thought about the Sudoku puzzles I have played around with in the past when trying to figure out how the numbers would work together. In order to make letters work in different place values, I also thought about doubles and fact families that would work for the given solutions. ]]> 2017-11-05 16:34:58 UTC https://padlet.com/drew_polly/z2gigstewj1j/wish/203647173 scaligan https://padlet.com/drew_polly/z2gigstewj1j/wish/205115654 Sheri Caligan
With each puzzle I asked myself, "What do I know? and :What patterns do I see?"  For example, if I saw two of the same letters, I knew I needed to have the same number in each of those spots.  This was fairly easy on the first two pages where they was little regrouping.  I used my knowledge of partners, or two numbers that can make up another number when added together, to mentally figure out which number would fit in the puzzle.  After selecting a number for a variable, I then had to see if it "worked"  On the last page where there were only variables in the addends, this was a bit more difficult.  For example, for the problem BBBB+CBB=DE298 I first tried placing 4 in all of the places with a B.  When I moved to the tens place I realized this would not work and that I would have to use when added in the ones place would result in regrouping.]]> 2017-11-09 02:20:08 UTC https://padlet.com/drew_polly/z2gigstewj1j/wish/205115654 ecurry4 https://padlet.com/drew_polly/z2gigstewj1j/wish/205886833 Elizabeth Curry
Before solving each puzzle, I looked at the final sum that was provided. Most of the puzzles I selected had a least one numerical digit in the sum, so after looking at that I worked backwards to determine what number combinations could be used to equal the digit provided in the sum. I would do somewhat of a process of elimination especially if one of the letters was repeated within the equation. I relied pretty heavily on my knowledge of number combinations that can equal a certain number. If students were to solve these tasks and didn't know all possible number combinations then it would be next to impossible for them to solve.]]> 2017-11-11 14:03:17 UTC https://padlet.com/drew_polly/z2gigstewj1j/wish/205886833 BreanaB https://padlet.com/drew_polly/z2gigstewj1j/wish/207047935 Breana Barrett
 To begin I think it important to see what the sum is and work backwards. By understanding that a part joined with another part makes a whole when adding and then you can use the invers operation to subtract and find the missing number. For example with the problem AB + B0 I know that the B in the ones place has to be 5. The answer for that place value is five and the missing number is 0 joined with another number which also shows that 5-0 is 5 (the missing value). Then when it comes to solving in the tens place, when two numbers are joined with each other they make 7. As long as both of the addends yield an answer of 7, the missing values will be correct. Therefore A is 4 and B is 3 because 4+3 is 7.

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