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      <title>Soy un experto  4 - 4A by </title>
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      <description>Sube tu solución a este mural.</description>
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      <pubDate>2020-07-17 14:22:27 UTC</pubDate>
      <lastBuildDate>2024-12-10 02:42:38 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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         <title></title>
         <author>rosaguerra1</author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/656925612</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-07-17 14:24:56 UTC</pubDate>
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         <title>Valeria</title>
         <author>Valeria241010</author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657031558</link>
         <description><![CDATA[<div>1 1/10 x 2 = 2 2/20<br>La masa de un recipiente lleno es de 2 enteros 2/20 kg.</div>]]></description>
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         <pubDate>2020-07-17 17:00:44 UTC</pubDate>
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         <title>Flavia</title>
         <author>75648974</author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657032313</link>
         <description><![CDATA[<div>La masa de un recipiente vacío es 3/10 kg.<br>Cuando el recipiente contiene agua hasta la mitad, la ma es 1 1/10 kg. ¿Cuál es la masa del recipiente cuando esta lleno de agua? <br>1 1/10 = 11/10 x 2 = 22/20<br>22 entre 20 = 2 2/20<br>Rpta: Hay 2 2/20 de agua en un recipiente lleno.</div>]]></description>
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         <pubDate>2020-07-17 17:01:58 UTC</pubDate>
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         <title>Alejandro</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657032762</link>
         <description><![CDATA[<div>La masa es 3/ 10 kg.</div>]]></description>
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         <pubDate>2020-07-17 17:02:52 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657032762</guid>
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         <title>Dara</title>
         <author>62608946</author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657056422</link>
         <description><![CDATA[<div>La masa del recipiente es de 2 Kg. Porque lleno seria 2 1/10, lo cual haciendo en fracciones sería 20/10, lo cual da 2. Así que lleno seria 2 kg.</div>]]></description>
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         <pubDate>2020-07-17 17:40:54 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657056422</guid>
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         <title>Juan</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657057936</link>
         <description><![CDATA[<div>La mita de 1 1/10 = 11/10 .<br>Lleno es  = 11/10 mas 8/10 es = 19/10=1 9/10</div>]]></description>
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         <pubDate>2020-07-17 17:42:51 UTC</pubDate>
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      <item>
         <title>RAFAEL</title>
         <author>76113455</author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657069067</link>
         <description><![CDATA[<div>La masa es 3/ 10 kg.</div>]]></description>
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         <pubDate>2020-07-17 18:01:24 UTC</pubDate>
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         <title></title>
         <author>76113455</author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657069124</link>
         <description><![CDATA[La masa es 3/ 10 kg.]]></description>
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         <pubDate>2020-07-17 18:01:31 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657069124</guid>
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         <title>Victor</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657104772</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-07-17 19:05:16 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657104772</guid>
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         <title>Mariana</title>
         <author>74332349</author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657119450</link>
         <description><![CDATA[<div>Para saber la masa del recipiente lleno necesito saber la masa del agua x2    me da la masa solo del agua del recipiente lleno  pero falta que le agregemos la masa del recipiente vacio y eso seria la mas que es : 1 entero y 9/10<br><br></div>]]></description>
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         <pubDate>2020-07-17 19:29:39 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657119450</guid>
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      <item>
         <title>Daira Chavez Gamboa</title>
         <author>74523578</author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657174302</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-07-17 21:34:52 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657174302</guid>
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      <item>
         <title>Daira Paola Castillo Castro </title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657206801</link>
         <description><![CDATA[<div>La masa del recipiente cuando esta lleno de agua es de 17/10.</div>]]></description>
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         <pubDate>2020-07-17 23:00:55 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657206801</guid>
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         <title>Leonardo</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657219725</link>
         <description><![CDATA[<div> Mita 1  1/10 = 11/10  <br>Lleno = 11/10¡+8/10 =19/10 es = 1 9/10 </div>]]></description>
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         <pubDate>2020-07-17 23:38:15 UTC</pubDate>
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         <title>Rodrigo Sanchez</title>
         <author>62499758</author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657272027</link>
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         <pubDate>2020-07-18 02:18:09 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657272027</guid>
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         <title>Ángel</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657280063</link>
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         <pubDate>2020-07-18 02:44:47 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657280063</guid>
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      <item>
         <title>Alessandra</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/yua6mssemip3wqad/wish/657627222</link>
         <description><![CDATA[<div>La masa del recipiente cuando está llen de agua es 19/10 </div>]]></description>
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         <pubDate>2020-07-19 03:42:41 UTC</pubDate>
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