<?xml version="1.0"?>
<rss version="2.0">
   <channel>
      <title>Chemistry 1.3 by Taylor keates</title>
      <link>https://padlet.com/taylorkeates/y4l6wtuaxd4</link>
      <description>Made with charm</description>
      <language>en-us</language>
      <pubDate>2019-01-30 12:12:38 UTC</pubDate>
      <lastBuildDate>2023-04-09 03:08:31 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
      <image>
         <url>https://padlet-assets.s3.amazonaws.com/icons/Soccerball.png</url>
      </image>
      <item>
         <title>Percentage yield</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795544</link>
         <description><![CDATA[<div><mark>percentage yield = <br>actual product ÷ predicted product x 100<br></mark>Usually has numbers in the question.<br><br><strong>Ethanoic acid &amp; ethanol have a </strong><strong><mark>1:1 ratio</mark></strong><strong>. If </strong><strong><mark>32.1g of acid </mark></strong><strong>are produced from the oxidation of </strong><strong><mark>27.6g of ethanol</mark></strong><strong>, what is the % yield?<br></strong>obtained÷actual x100<br>Mr ethnoic acid - 60.04<br>Mr ethanol - 46.06<br><strong>moles=mass÷Mr<br></strong>27.6÷46.06= 0.6<br>1:1    0.6:0.6<br>mass = moles x Mr<br>0.6 x 60.04 = 36.024<br>32.1÷36.024 x 100 = <mark>89%<br></mark><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795544</guid>
      </item>
      <item>
         <title>Titration calculations</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795547</link>
         <description><![CDATA[<div>Finding out the number of moles that will react together. Indicators are used to determine the end point in acid-based titrations. A burette measures a precise volume of liquid.<br><br>Eg. You have <mark>50cm</mark><mark><sup>3 </sup></mark><mark>of NaOH</mark>(base) solution. Using methyl orange indicator you titrate the base against a <mark>0.10moldm</mark><mark><sup>-3</sup></mark><mark> solution of H</mark><mark><sub>2</sub></mark><mark>SO</mark><mark><sub>4</sub></mark>. It takes <mark>22.3cm</mark><mark><sup>3</sup></mark><mark> of 0.10moldm</mark><mark><sup>-3</sup></mark><mark> H</mark><mark><sub>2</sub></mark><mark>SO</mark><mark><sub>4</sub></mark><mark> to neutralise 50.0cm</mark><mark><sup>3</sup></mark><mark> of NaOH.</mark><br><strong><mark>What is the conc. of NaOH solution?<br></mark></strong><mark>Step 1: </mark>BALANCE EQUATION<br>2NaOH + H<sub>2</sub>SO<sub>4</sub> --&gt; Na<sub>2</sub>SO<sub>4</sub> + 2H<sub>2</sub>O<br><mark>Step 2</mark>: CONC. &amp; VOL.<br>conc. acid - 0.10dm<sup>-3</sup><br>vol. acid - 22.3cm<sup>3</sup><br>conc. base - ?<br>vol. base - 50.0cm<sup>3<br></sup><mark>Step 3</mark>: RATIO<br>n=cv÷1000<br>0.10 x 22.3 ÷ 1000 = 2.23x10<sup>-3</sup><br>2:1 NaOH:H<sub>2</sub>SO<sub>4</sub> <br>NaOH - 4.46x10<sup>-3</sup><br><mark>Step 4:</mark> CONCENTRATION<br>c=n x 1000 ÷ v<br>1000 x (4.46 x10<sup>-3</sup>) ÷ 50 =0.0892 moldm<sup>-3</sup></div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795547</guid>
      </item>
      <item>
         <title>Kelvin</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795550</link>
         <description><![CDATA[<div>To change celcius to kelvin..... add 273 to degree celcius</div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795550</guid>
      </item>
      <item>
         <title>Ideal gas law</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795552</link>
         <description><![CDATA[<div>              <mark>pV = nRT</mark><br>p = pressure --&gt; Pa or Nm<sup>-2</sup><br>V = volume --&gt; m<sup>3</sup><br>n = moles <br>R = gas constant <br>T = temperature --&gt; K</div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795552</guid>
      </item>
      <item>
         <title>Concentration</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795554</link>
         <description><![CDATA[<div>The concentration measures how much of a substance is dissolved(<strong>solute</strong>) per unit volume of a solution(<strong>solvent</strong>).<br>Can be called molarity.<br><strong><mark>Measured in 2 ways: </mark></strong><br>molar conc. - moldm<sup>-3</sup> or mass conc. - gdm<sup>-3<br><br></sup><mark>moles = concentration(moldm</mark><mark><sup>-3</sup></mark><mark>) x volume(cm</mark><mark><sup>3</sup></mark><mark>) ÷ 1000<br>n = cV÷1000</mark></div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795554</guid>
      </item>
      <item>
         <title>Stoichiometry</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795556</link>
         <description><![CDATA[<div>The mass of reactants and a balanced chemical equation means we can find the mass of the products.<br><strong>Question. Fe</strong><strong><sub>2</sub></strong><strong>O</strong><strong><sub>3 </sub></strong><strong>is heated with carbon in a blast furnace. Fe</strong><strong><sub>2</sub></strong><strong>O</strong><strong><sub>3</sub></strong><strong> reduced to Fe &amp; CO is produced. I receive an order of </strong><strong><mark>50kg of Fe</mark></strong><strong>.</strong><strong><mark><br>How much Fe</mark></strong><strong><mark><sub>2</sub></mark></strong><strong><mark>O</mark></strong><strong><mark><sub>3</sub></mark></strong><strong><mark> do I need?<br></mark></strong><mark>Step 1: BALANCED EQ.<br></mark>Fe<sub>2</sub>O<sub>3</sub> + <del>3C</del> --&gt; 2Fe + <del>3CO<br></del><mark>Step 2: RATIO<br></mark>Fe<sub>2</sub>O<sub>3</sub>:Fe      1:2<br><mark>Step 3: MASS --&gt; MOLES<br></mark>Fe Ar= 55.8 <strong>moles=mass÷Ar</strong><br>kg--&gt;g 50000g<br>50000÷55.8= <strong>896mol Fe<br></strong>Fe<sub>2</sub>O<sub>3</sub> = 896÷2= <strong>448mol<br></strong><mark>Step 4: MOLES--&gt;MASS</mark><br>mass=moles x Mr<br>448 x 159.6 = 71.5kg<br><strong>Fe</strong><strong><sub>2</sub></strong><strong>O</strong><strong><sub>3</sub></strong><strong>=159.6</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795556</guid>
      </item>
      <item>
         <title>Gas volumes</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795558</link>
         <description><![CDATA[<div>We use the volume of mass per mole, molar volume(Vm) E.g at <mark>0°C</mark> &amp; <mark>atmospheric pressure(STP)</mark> we can say that <mark>Vm=22.4dm</mark><mark><sup>3</sup></mark><mark> </mark>for any gas. This changes with temperature &amp; pressure changes.<br><strong><mark>Volume of gas = moles x molar volume<br>V = M x Vm</mark></strong><mark><br>Eg. 10g Zinc, reaction at STP, calculate hydrogen volume.<br></mark>Zn + 2HCl --&gt; H<sub>2</sub> + ZnCl<sub>2</sub><br>Zn:H<sub>2</sub> = 1:1 ratio<br>V = M x 22.4         N=M÷Ar<br>N = 10÷65.4 = 0.153mol<br>V = 0.153 x 22.4 = <mark>3.43dm</mark><mark><sup>3</sup></mark><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795558</guid>
      </item>
      <item>
         <title>Empirical &amp; molecular formulae</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795562</link>
         <description><![CDATA[<div><mark>moles = mass ÷ Ar/Mr</mark><br>The <strong>empirical formula</strong> is the simplest ratio.<mark><br></mark><strong><mark>Question. Find the empirical formula for the compound made of 75% C &amp; 25% H.</mark></strong><mark><br></mark>moles= 75÷12= 6.25<br>moles= 25÷1.01= 24.7524<br>6.25<mark>÷6.25</mark>=1 24.7524<mark>÷6.25</mark>=4 *divide by smallest number*<br>                    1:4 compound - CH<sub>4<br></sub><strong><mark>Question. 87.5% nitrogen &amp; 12.5% hydrogen.<br></mark></strong>87.4÷14= 6.25     12.5÷1.01=12.4<br>6.25÷6.25=1        12.4÷6.25=1.98<br>                     1:2 NH<sub>2</sub><br><strong> </strong><strong><mark>The Mr is 32.04.<br></mark></strong>Mr of NH2 = 16.02 <br>NH<sub>2</sub> ---&gt;(x2) N<sub>2</sub>H<sub>4</sub></div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795562</guid>
      </item>
      <item>
         <title>Mass spectra of Cl</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795564</link>
         <description><![CDATA[<div>Made up of 2 isotopes - <sup>35</sup>Cl &amp; <sup>37</sup>Cl. The Chlorine35 isotope is three times more likely than the Chlorine37 isotope. </div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795564</guid>
      </item>
      <item>
         <title>Calculating relative atomic mass</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795566</link>
         <description><![CDATA[<div>*Assume 100 atoms*<br>QUESTION EXAMPLE:<br>A mass spectrum of a hydrogen sample showed it to contagion<sup> 1</sup>H 99.20% and <sup>2</sup>H 0.8000%. <br>Calculate the Ar of Hydrogen to 4sf.</div><div><mark>(99.2 x 1) + (0.8000 x 2)<br></mark>                   <mark> ÷</mark><br>                <mark>100</mark>          <mark> = 1.008</mark></div><div><br></div>]]></description>
         <enclosure url="https://padletuploads.blob.core.windows.net/prod/251754296/61d134c104922be0beab54f3c59befac/zygGJGL.png" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795566</guid>
      </item>
      <item>
         <title>Mass spectrometer </title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795569</link>
         <description><![CDATA[<div>It is used to find....</div><ul><li>the mass of different isotopes of an element</li><li>relative abundance of each isotope of an element </li></ul><div><strong><em>Ionisation<br></em></strong>Vapour passes into the ionisation chamber. The particle sample is bombarded with a stream of electron &amp; some collisions knock one(sometimes more) electrons to make positive ions.<br><strong><em>Acceleration</em></strong><br>an electric field accelerates the positive ions to a high speed.<br><strong><em>Deflection</em></strong><br>Different ions are deflected by a magnetic field by different amounts. Depends on....mass(lighter ions deflected more), charge on the ion(2+ are deflected more). These factors are combined into the mass/charge ratio<br><strong><em>Detection</em></strong><br>Beams of ions are detected electronically. Only ions with the right mass/charge ratio make it to the detector(other ions collide with the wall &amp; pick up electrons becoming neutralised). These get removed by a vacuum pump. The signal often correct ions is amplified &amp; recorded. <br><br>Ions need a free run through the machine without hitting air molecules, so a vacuum is needed.</div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795569</guid>
      </item>
      <item>
         <title>Percentage error </title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795571</link>
         <description><![CDATA[<div><strong>Burette</strong> - 0.1cm3</div><div><strong>0.2</strong><strong><em>°</em></strong><strong> thermometer </strong>- 0.2<em>°<br></em><strong>3-place scale</strong> - 0.001g/1mg<br><mark>%error = error ÷ quantity measured x 100 <br></mark>quantity measured....titre(burette), Difference in temp(thermometer), mass(balance)</div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795571</guid>
      </item>
      <item>
         <title>Avogadro constant</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795573</link>
         <description><![CDATA[<div>6.02 x 10<sup>23</sup> mol<sup>-1</sup></div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795573</guid>
      </item>
      <item>
         <title>Molar mass</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795575</link>
         <description><![CDATA[<div>amount in moles(n) = mass(m) ÷ molar mass(M)<br><br><strong><mark>E.g What is the amount of sodium present in 0.23g of sodium?<br></mark></strong><mark>Ar=23.0 <br>23.0 ÷ 23.0gmol</mark><mark><sup>-1</sup></mark><mark> = 0.01mol</mark></div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:40 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795575</guid>
      </item>
      <item>
         <title>Atom economy</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795578</link>
         <description><![CDATA[<div><mark>atom economy =<br>required product ÷ mass of  reactants x 100<br></mark>Usually has a chemical equation in the question. <br><br><strong><mark>Calculate atom economy for making iron.<br></mark></strong><mark>Fe</mark><mark><sub>2</sub></mark><mark>O</mark><mark><sub>3</sub></mark><mark> </mark>+<mark> 3CO</mark> --&gt;<mark> 2Fe</mark> + 3CO<sub>2</sub><strong><sub><br></sub></strong>required÷total x 100<br>111.6 ÷ 243.6 x 100 = 45.8%</div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:40 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795578</guid>
      </item>
      <item>
         <title>Solubility</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795579</link>
         <description><![CDATA[<ul><li>Solute - what you're dissolving</li><li>Solvent - liquid</li><li>Solution- product</li></ul><div>Often measure in g per 100g - g/100g<br>The density of water is 1gcm<sup>-3<br><br></sup><strong>Eg. </strong><strong><mark>Potassium nitrate</mark></strong><strong> has a solubility of </strong><strong><mark>31.6g/100g water. </mark></strong><strong>Convert this to </strong><strong><mark>moldm</mark></strong><strong><mark><sup>-3</sup></mark></strong><strong><mark><br></mark></strong>Mr KNO<sup>3 </sup>- 101.1 <br>moles = mass ÷ mr<br>31.6 ÷ 101.1 = 0.313<br>0.313 x 10 = 3.13 moldm<sup>-3</sup><strong><br></strong><sup><br></sup><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:40 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795579</guid>
      </item>
      <item>
         <title>Gas constant</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795580</link>
         <description><![CDATA[<div>R = 8.31Jk<sup>-1</sup>mol<sup>-1</sup></div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:40 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795580</guid>
      </item>
      <item>
         <title>Mass Spectrometer</title>
         <author>taylorkeates</author>
         <link>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795581</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padletuploads.blob.core.windows.net/prod/251754296/fd5f2e1f91b5a8ca8c9a7705f4b4a903/igMpB.png" />
         <pubDate>2019-01-30 12:12:40 UTC</pubDate>
         <guid>https://padlet.com/taylorkeates/y4l6wtuaxd4/wish/325795581</guid>
      </item>
   </channel>
</rss>
