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      <title>Activity Hints by Mr. Stubbs</title>
      <link>https://padlet.com/collinstubbs/ActivityHints</link>
      <description></description>
      <language>en-us</language>
      <pubDate>2015-11-20 15:15:42 UTC</pubDate>
      <lastBuildDate>2017-05-17 08:09:13 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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         <title>20 Bananas Hint</title>
         <author>collinstubbs</author>
         <link>https://padlet.com/collinstubbs/ActivityHints/wish/82691544</link>
         <description><![CDATA[<p>- If I add 5 to my counter everytime I press a button and I can't go over 20, then my counter has to accept button presses for all numbers until 16
	- Reason: 
		- 16+5 = 21 &lt;- this is greater than 20!
		- one could say that (<b>**MAJOR HINT ALERT**</b>)</p><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p> if (counter &lt; 16 )</p><p>{&nbsp;</p></blockquote></blockquote><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>counter = counter + 5;</p></blockquote></blockquote></blockquote><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>} </p></blockquote></blockquote>]]></description>
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         <pubDate>2015-11-20 15:35:07 UTC</pubDate>
         <guid>https://padlet.com/collinstubbs/ActivityHints/wish/82691544</guid>
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         <title>Loops Hint</title>
         <author>collinstubbs</author>
         <link>https://padlet.com/collinstubbs/ActivityHints/wish/82691966</link>
         <description><![CDATA[<blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>- i++ means the exact same thing as i = i+1</p><p>- if you want to go up by 8 you would write i = i+8</p><p>- ex/</p></blockquote><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>for( int i = 1000 ; i &gt;=0  ; i = i - 100 )</p></blockquote><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>{</p></blockquote></blockquote><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>System.out.println(i);</p><p>//this will make i go down by 100 each time</p></blockquote></blockquote></blockquote><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>}</p></blockquote></blockquote>]]></description>
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         <pubDate>2015-11-20 15:36:17 UTC</pubDate>
         <guid>https://padlet.com/collinstubbs/ActivityHints/wish/82691966</guid>
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         <title>Error Checking Hints</title>
         <author>collinstubbs</author>
         <link>https://padlet.com/collinstubbs/ActivityHints/wish/82706394</link>
         <description><![CDATA[<p>- if you already know that the textfield is empty (txtInput.getText().isEmpty()) then why would we check for an "@" symbol?
		- remember "nesting" if statements</p>]]></description>
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         <pubDate>2015-11-20 16:13:39 UTC</pubDate>
         <guid>https://padlet.com/collinstubbs/ActivityHints/wish/82706394</guid>
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         <title>Random Numbers Hint</title>
         <author>collinstubbs</author>
         <link>https://padlet.com/collinstubbs/ActivityHints/wish/82708202</link>
         <description><![CDATA[<p>- you could use our formula to get a random number between 1 and 4</p><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><pre>int random = (int) ((max - min + 1)*Math.random() + min);</pre></blockquote><p>- make if statements that correspond to the number generated (if random == 2)</p>]]></description>
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         <pubDate>2015-11-20 16:18:35 UTC</pubDate>
         <guid>https://padlet.com/collinstubbs/ActivityHints/wish/82708202</guid>
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