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      <title> E214-2D-W24P L12 Pre-Lesson Activity by Lim Siew Hoon</title>
      <link>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk</link>
      <description>Made with panache</description>
      <language>en-us</language>
      <pubDate>2020-08-10 02:30:26 UTC</pubDate>
      <lastBuildDate>2020-08-11 05:14:17 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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         <title>Instructions</title>
         <author>lim_siew_hoon7</author>
         <link>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk/wish/673785967</link>
         <description><![CDATA[<div>Once you are done typing your answer, type '<strong>Done</strong>' after the answer.</div>]]></description>
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         <pubDate>2020-08-10 02:30:26 UTC</pubDate>
         <guid>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk/wish/673785967</guid>
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         <title>Team 5</title>
         <author>lim_siew_hoon7</author>
         <link>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk/wish/673785968</link>
         <description><![CDATA[<div>a) chi-sqaure test statistic (jw)<br>goodness of fit test!!!!!!<br><br>b) H0: The population follows the hypothesized distribution<br>H1: the population does not follow the hypothesized distribution (Ee Lin)<br><br>c) Degree of Freedom = Number of Category - 1 <br>= 3 -1 <br>= 2 (Zhe Ming)<br><br>d) Expected Frequency:<br>     Less than 18 = 0.2*500 = 100<br>     Age 18-40 = 0.3*500 = 150<br>     Above 40 = 0.5*500 = 250<br>     (Peerawat)<br>    <br><br>e) Expected Frequency for age less than 18: 500 * 20% = 100 <br>    Expected Frequency for age between 18 - 40: 500 * 30% = 150<br>   Expected Frequency for age above 40:<br>     500 * 0.50 = 250 <br>Test Statistic: (124 - 100)^2/100 + (263 - 150)^2/150 + (113-250)^2/250 <br>= 5.76 + 85.12666667 + 75.076<br>= 165.9626667<br>= 165.96267 (5 D.P.) (Zhe Ming)<br><br> <br><br></div>]]></description>
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         <pubDate>2020-08-10 02:30:26 UTC</pubDate>
         <guid>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk/wish/673785968</guid>
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         <title>Team 4</title>
         <author>lim_siew_hoon7</author>
         <link>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk/wish/673785969</link>
         <description><![CDATA[<div>a) Chi-sqaure goodness of fit (Cheh Wei)<br><br>b) Null hypothesis: The population distribution of ages follows the distribution of ages in the last 10 years. (Cheh Wei)<br><br>c)Degree of freedom=3-1<br>                                     =2(Pauline)<br><br>d) Test statistics = (124-100)^2/100 + (263-150)^2/150 + (113-250)^2/250 (Cheh Wei)<br><br>e)500x0.2=100<br>500x0.3=150<br>500x0.5=250(xx)<br><br></div>]]></description>
         <pubDate>2020-08-10 02:30:26 UTC</pubDate>
         <guid>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk/wish/673785969</guid>
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      <item>
         <title>Team 3</title>
         <author>lim_siew_hoon7</author>
         <link>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk/wish/673785970</link>
         <description><![CDATA[<div>a) Chi-square goodness of fit test (Fiona)<br><br>b) h0: the population follows the hypothesized distribution (Darryl) <br>h1: the population distribution does not follow the hypothesized distribution (Darryl) <br><br><br>c) df = 3 -1 =2 (Baron)<br><br>d) expected frequencies for less than 18: 0.20*500 = 100<br>for 18 - 40: 0.30*500 = 150<br>for above 40: 0.50*500 = 250 <br>(Fiona)<br>e) (124-100)^2/100 + (263-150)^2/150 + (113-250)^2/250 = 165.96 (Baron)<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2020-08-10 02:30:26 UTC</pubDate>
         <guid>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk/wish/673785970</guid>
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      <item>
         <title>Team 2</title>
         <author>lim_siew_hoon7</author>
         <link>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk/wish/673785971</link>
         <description><![CDATA[<div>a) Chi-Square Goodness-of-Fit test(Natasha)<br><br>b)H0: The population distribution of ages follows the distribution of ages in the last 10 years<br>H1: The population distribution of ages does not follows the distribution of ages in the last 10 years(Natasha)<br><br>c) degrees of freedom = 3-1 = 2 (ZiHao)<br><br>d) Expected frequency: <br>124+263+113=500<br>0.2*500 = 100<br>0.3*500 = 150<br>0.5*500 = 250<br><br><br>e) test stat = ((124-100)^2)/100 + ((263-150)^2)/150 + ((113-250)^2)/250 = 165.9627 (Wee hrng)<br><br></div>]]></description>
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         <pubDate>2020-08-10 02:30:26 UTC</pubDate>
         <guid>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk/wish/673785971</guid>
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      <item>
         <title>Team 1</title>
         <author>lim_siew_hoon7</author>
         <link>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk/wish/673785972</link>
         <description><![CDATA[<div>a) Chi - Square Goodness-of-fit Test (Mirza)<br><br>Chi-Square Goodness of Fit test (Jane)<br><br>b)Ho: The population distribution of ages  follows the hypothesized distribution<br>H1: The population distribution of ages   does not follow the hypothesized distribution (Bryan)<br><br>c) degrees of freedom = 3 -1 = 2 (Ekka)<br><br>d) Expected frequency:<br>Less than 18 = 0.2 * 500 = 100 (Mirza)<br>18-40 = 0.3 * 500 = 150<br>&gt; 40 = 0.5 * 500 = 250<br><br>e)<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2020-08-10 02:30:26 UTC</pubDate>
         <guid>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk/wish/673785972</guid>
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      <item>
         <title></title>
         <author>19028119</author>
         <link>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk/wish/675086510</link>
         <description><![CDATA[<div>5<br>a) chi-square goodness of fit test</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-08-11 01:39:59 UTC</pubDate>
         <guid>https://padlet.com/lim_siew_hoon7/wbce0ls5af18ktgk/wish/675086510</guid>
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