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   <channel>
      <title>Exploring Lines and Graphs by Mr. Sladkey</title>
      <link>https://padlet.com/dsladkey2/exploringlinesandgraphing</link>
      <description>https://tinyurl.com/exploringlinesandgraphs
Pick 2 problems and post your solution and HOW you did them.  Give your Desmos link as a check for each question. </description>
      <language>en-us</language>
      <pubDate>2015-08-23 19:32:39 UTC</pubDate>
      <lastBuildDate>2025-10-11 13:12:26 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
      <image>
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      <item>
         <title>Braeden Boor</title>
         <author>baboor</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286244947</link>
         <description><![CDATA[<div>Soultion= y=3(x+2)<br><br>How I got this: <br>How I got this was that I graphed the points (-2,3), then saw that my slope was 3 so I went up 3 and sideways one so the fraction of that is 3/1 which is the rise over run but still the slope that was given to me. How I got my equation was that I knew that the slope was 3 so that´s to the left of my parenthesis and the x and x value (2) is in the parenthesis, and to the left of the parenthesis is the y value that we are adding (also 3)</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/haivnxpcbi" />
         <pubDate>2018-09-26 20:00:36 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286244947</guid>
      </item>
      <item>
         <title>Alyssa Radman</title>
         <author></author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286290699</link>
         <description><![CDATA[<div>Equation: y=3x+9<br>Explanation: First I plotted my point (-2,3) on my graph. After I plotted my point, I saw my slope was 3 so I used my slope to keep adding points like (-3,0) (-1,6) and (0,9). My y intercept was 9 so I could create my equation y =3x+9 because the y intercept is 9 and the slope was 3. </div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/coyfhr06pr" />
         <pubDate>2018-09-26 23:21:34 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286290699</guid>
      </item>
      <item>
         <title>Alyssa Radman</title>
         <author></author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286291289</link>
         <description><![CDATA[<div>Equation: y = -3x +3<br>Explanation: First I plotted my point and I knew that the y intercept was 3 so the point would have to be (0,3). The slope was -3 so i kept moving down the graph and adding points like (1,0), (2,-3) and (7,-1). My y intercept was 3 and my slope was -3 so the equation would be y=-3x +3.</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/28y5srfgtq" />
         <pubDate>2018-09-26 23:26:13 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286291289</guid>
      </item>
      <item>
         <title>Braeden Boor</title>
         <author>baboor</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286304821</link>
         <description><![CDATA[<div>Solution: y=-⅔(x+4) +5<br>How I got this: <br>How I got this was that I graphed the points (-4,5), then saw that my slope was -2/3 so I went down -2 and sideways 3 so the fraction of that is -2/3 which is the rise over run but still the slope that was given to me. How I got my equation was that I knew that the slope was -2/3 so that´s to the left of my parenthesis and the x and x value (-4) is in the parenthesis, and to the left of the parenthesis is the y value that we are adding (also 5)<br><br></div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/38ibqxrznc" />
         <pubDate>2018-09-27 00:53:32 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286304821</guid>
      </item>
      <item>
         <title>Anna Vukovich </title>
         <author>acvukovich</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286467302</link>
         <description><![CDATA[<div>Solution: Y= 1/2 x+2.5<br>Problem: Graph and create an equation for the line that points (1,3) and (-1,2) make <br>Explanation: by subtracting 2 from 3 (which is 1) and putting it over <br>1-(-1) you get a slope of 1/2 and when graphed you see the y-intercept of 2.5. <br>Graph: </div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/ou8fmlnmuu" />
         <pubDate>2018-09-27 12:39:44 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286467302</guid>
      </item>
      <item>
         <title>Brynn Wozniak</title>
         <author>bewozniak</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286470192</link>
         <description><![CDATA[<div>Solution: y-3=3(x+2)<br>Explanation: I first graphed the point (-2, 3) and then I added the slope and that was 3 so I went up 3 and over 1. My next point on the graph was (-1, 6). So that's how I got my solution which is                      y-3=3(x+2).<br><br></div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/s7pbcwf9a2" />
         <pubDate>2018-09-27 12:45:14 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286470192</guid>
      </item>
      <item>
         <title>Jack Jasica</title>
         <author>jejasica1</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286470234</link>
         <description><![CDATA[<div>Solution: y-3=3(x+2)<br>Explanation:<br>First I plotted the point (-2,3) and used the slope, 3, to rise three and run 1, getting me to my next point, (-1,6). Then I used my point and my slope and put it into point slope form, giving me y-3=3(x+2)</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/hpokcmyfm2" />
         <pubDate>2018-09-27 12:45:19 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286470234</guid>
      </item>
      <item>
         <title>Anna Vukovich </title>
         <author>acvukovich</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286472704</link>
         <description><![CDATA[<div>Solution: y=2x <br>Problem: create a parallel line to <br>2x-y=-2 that passes through the point (0,0) <br>Explanation: by adding the opposite and subtracting 2x from both sides and dividing everything by -1 you get the equation y=-2x+2. since the line has to be parallel to that, I take the slope and use the y intercept 0. <br>Graph: <br><br></div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/tihdgj8gwr" />
         <pubDate>2018-09-27 12:49:32 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286472704</guid>
      </item>
      <item>
         <title>Jack Jasica</title>
         <author>jejasica1</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286475683</link>
         <description><![CDATA[<div>Solution: y-5=-2/3(x+2)<br>Explanation:<br>First I graphed the point, (-4,5) and used the slope, -2/3 to rise 2 and run 3, getting me to my next point, (-1,3). I then used point slope form, getting me y-5=-2/3(x+4)</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/od0otsm9gh" />
         <pubDate>2018-09-27 12:54:53 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286475683</guid>
      </item>
      <item>
         <title>Maddie Weber</title>
         <author>mmweber</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286475947</link>
         <description><![CDATA[<div>Equation : y=1/2 + -1<br>Explantation: The problem gave you the x-intercept and the y-intercept. So to start I plotted those points (0,-1) and (2,0) then I counted the slope between those two points. Which is up 1 over 2 or positive 1/2. Now that we have both the slope (1/2) and the y-intercept ((0,-1))  them fill them in to y=mx+b or slope intercept form. Another way you could have done this was to use m=\frac{y_2-y_1}{x_2-x_1}<br>and fill in the x-intercept (2,0) and the y-intercept (0,-1)</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/kfbarmyuhb" />
         <pubDate>2018-09-27 12:55:28 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286475947</guid>
      </item>
      <item>
         <title>Matelaine Kingsbury</title>
         <author>mnkingsbury</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286476382</link>
         <description><![CDATA[<div>Solution: Y=3x+9
Explanation:
First I plotted the coordinates (-2,3), then I did the slope of 3 from that point up 3 over 1 and then estimated the Y intercept to be 9
<br></div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/embjds8dmf" />
         <pubDate>2018-09-27 12:56:22 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286476382</guid>
      </item>
      <item>
         <title>Maddie Weber</title>
         <author>mmweber</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286476552</link>
         <description><![CDATA[<div>Equation: y=-3x+3<br>Explanation: This problem already has everything you need for slope incerpt form so just do that form of slope equation. <br>first take y=mx+b and take the slope of -3 and the y-intercept of 3, since m= the slope, and b=y-intercept. I just filled it in. so y=-3x+3<br>To graph this, I set my point at the y-intercept (0,3) , then go down 3 and right 1 becuase it is a negative slope.</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/nrz5g5ovkl" />
         <pubDate>2018-09-27 12:56:45 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286476552</guid>
      </item>
      <item>
         <title>Brynn Wozniak</title>
         <author>bewozniak</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286478573</link>
         <description><![CDATA[<div>Solution: y=-3x+3<br>Explanation: So what you needed to do for this problem was to create slope equation. I used the form y=mx+b so what I did was take the slope of -3 and the y intercept of 3 so the m is slope and so it would be y=-3x+b and then plugged in the b which is y intercept and so it would be y=-3x+3.</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/dfxx0aqnup" />
         <pubDate>2018-09-27 13:00:37 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286478573</guid>
      </item>
      <item>
         <title>Matelaine Kingsbury</title>
         <author>mnkingsbury</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286478636</link>
         <description><![CDATA[<div>Solution: Y=1/2x+2.5
Explanation:
First, I plotted the coordinates (1,3) and (-1,2). Nest, I found the slope of the two points to be 1/2 and after drawing the line the Y intercept was 2.5.</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/vzw3uhwpws" />
         <pubDate>2018-09-27 13:00:45 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286478636</guid>
      </item>
      <item>
         <title>Judd Chamberlain</title>
         <author>jcchamberlain</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286491486</link>
         <description><![CDATA[<div>Equation:    x=2<br>Explanation: you are given the point (2,4) and the information that the slope is undefined so all you need to do is plot any point on the x intercept of 2 and it will be an undefined slope.<br><br></div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/wgc22wb4vc" />
         <pubDate>2018-09-27 13:20:24 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286491486</guid>
      </item>
      <item>
         <title>Judd Chamberlain</title>
         <author>jcchamberlain</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286494432</link>
         <description><![CDATA[<div>Equation:   y-2=0(x-3)<br>Explanation: you are provided with the slope of 0 and contains the point (-3,2) giving that the slope is zero means that any point with the y being 2 would work in this problem</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/oq9qq0zp5x" />
         <pubDate>2018-09-27 13:24:08 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286494432</guid>
      </item>
      <item>
         <title>Bella Schilaci</title>
         <author>iaschilaci</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286497754</link>
         <description><![CDATA[<div>Equation~ 2x-1&nbsp;<br>Explanation~the x intercept is 2 and the y intercept is -1 so  you would go up by 2 and over 1 to the right.</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/6zen4ww6kn" />
         <pubDate>2018-09-27 13:28:22 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286497754</guid>
      </item>
      <item>
         <title>Evan King</title>
         <author>ewking</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286498846</link>
         <description><![CDATA[<div>y=3x+9<br>first I plotted the first point of (-2,3) then plotted the slope of 3 which later made a y-intercept of 9.</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/zasmvnlp28" />
         <pubDate>2018-09-27 13:29:58 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286498846</guid>
      </item>
      <item>
         <title>Evan King</title>
         <author>ewking</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286540749</link>
         <description><![CDATA[<div>y=1/2x - 1<br>First I plotted the x intercept of 2 and y intercept of -1 then when counting for slope I got 1 up and 2 to the right which comes to a slope of 1/2.</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/t2yxouhl5b" />
         <pubDate>2018-09-27 14:28:55 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286540749</guid>
      </item>
      <item>
         <title>Ella Tucker</title>
         <author></author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286641231</link>
         <description><![CDATA[<div>Solution: y=1x+2 <br>Explanation: I first graphed the line that is given. I then plotted my points and tried to figure out how I could make them parallel to each other. I figured out that it is an undefined slope. I then used that and figured out that my point has to be used by the x intercept instead of the y intercept.   </div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/9xbi4dkvth" />
         <pubDate>2018-09-27 17:03:22 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286641231</guid>
      </item>
      <item>
         <title>Ella Tucker</title>
         <author></author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286648371</link>
         <description><![CDATA[<div>Solution: y=-3x+3 <br>Explanation: I started by graphing the y intercept and then putting in the slope. Once I got enough points I figured out my answer or y=-3x+3</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/i6xpdh2t0b" />
         <pubDate>2018-09-27 17:15:52 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286648371</guid>
      </item>
      <item>
         <title>Alexandra Yesutis</title>
         <author>anyesutis2</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286751139</link>
         <description><![CDATA[<div>Answer:  y=-3x+3<br>Explanation:  I put the numbers in slope-intercept form.  I graphed the y intercept  at (0,3).   I used the equation of the line to solve for y when x=1.  This gave me another data point of (1,0) to graph.   </div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/aub0em7aww" />
         <pubDate>2018-09-27 21:17:50 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286751139</guid>
      </item>
      <item>
         <title>Alexandra Yesutis</title>
         <author>anyesutis2</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286751960</link>
         <description><![CDATA[<div>Solution:  X=4<br>Explanation:  It tells us the line is parallel to X=5.  This means it has to have the same slope.  It also has to pass thru the point of (4,-2).  The only way it can pass thru (4,-2) and have the same slope is to be a vertical line where x=4.</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/nrowyvjhax" />
         <pubDate>2018-09-27 21:21:59 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286751960</guid>
      </item>
      <item>
         <title>Stevie Sellers</title>
         <author>TTVStreamerBTW</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286765683</link>
         <description><![CDATA[<var>Solution: y=\frac{1}{2}x+2.5</var><div>Explanation: First I set my Y intercept to 2.5. I then set my slope to 1/2. This means that it would go down 1, and left 2 and up one, and right 2. Because of this it was able to intercept both points.</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/rslobijk81" />
         <pubDate>2018-09-27 22:52:21 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286765683</guid>
      </item>
      <item>
         <title>Abbey Bergquist</title>
         <author>aabergquist</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286766303</link>
         <description><![CDATA[<div>Solution: y=3x + 9<br>Explanation: First I plotted the point (-2, 3) and I knew that the slope was 3 (or 3 over 1) so the rise was 3 and the run was 1. So from (-2,3) I went up 3 on the y axis and to the right on the x axis by one.</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/gpdba0mo5s" />
         <pubDate>2018-09-27 22:56:13 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286766303</guid>
      </item>
      <item>
         <title>Abbey Bergquist</title>
         <author>aabergquist</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286766907</link>
         <description><![CDATA[<div>Solution: y=-4x+ 6<br>Explanation: First I plotted the points it had given me (1, 3) (-1, 2), then to find the slope of the line I counted the rise and the run between the two points and it came out to be -4, and I knew that if I kept going with this that the y-intercept would be 6.</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/b9bwrp3jfq" />
         <pubDate>2018-09-27 22:59:03 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286766907</guid>
      </item>
      <item>
         <title>Stevie Sellers</title>
         <author>TTVStreamerBTW</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286767477</link>
         <description><![CDATA[<div>Solution: x=2<br>&nbsp;Explanation: I was giving the point (2,4) and it has to be an undefined slope. Since there is no y coordinate and only x, and y coordinate point meets it. this works because it goes straight up ( undefined) because any y coordinate works the 4 does work.<br><br></div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/stf0h2op6j" />
         <pubDate>2018-09-27 23:03:04 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286767477</guid>
      </item>
      <item>
         <title>Bella Schilaci</title>
         <author>iaschilaci</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286795796</link>
         <description><![CDATA[<div>equation~ y=3x&nbsp;<br>Explanation~ the point (-2,3) yo would plot that on the graph and go up 3 over 1 because the slope is 3 </div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/yfwvxypjxc" />
         <pubDate>2018-09-28 02:31:37 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286795796</guid>
      </item>
      <item>
         <title>Paige Kolbe</title>
         <author></author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286925969</link>
         <description><![CDATA[<div>Equation: y=2x+4<br>Explination: The problem already gives you the y-intercept and the point (-1,2). First you graph (-1,2) then go up two and over one. </div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/p3uejysrfd" />
         <pubDate>2018-09-28 13:02:26 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/286925969</guid>
      </item>
      <item>
         <title>Reagan Black</title>
         <author>rcblack</author>
         <link>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/287366647</link>
         <description><![CDATA[<div>Solution: y = -1/2x - 1<br>Explanation: The problem itself provides you with the y-intercept and the x-intercept. First I started with plotting the y and x-intercepts and from there I figured out a "rule" or the slope. Since the y-intercept is -1 and the x-intercept is 2, the only way to get these two numbers is to go up by 1 and over 2.</div>]]></description>
         <enclosure url="https://www.desmos.com/calculator/ixyokjgotu" />
         <pubDate>2018-09-30 18:55:07 UTC</pubDate>
         <guid>https://padlet.com/dsladkey2/exploringlinesandgraphing/wish/287366647</guid>
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