Javac is the executable for compiling java applications.   When compiling a java program from command line, this is the most common issue people face.  Let’s see how we can fix this issue.

Please note that having JRE is not enough to develop java applications. JRE only helps to run already built applications, we need JDK to compile Java code. 

If java is installed, then you need to check if PATH environment variable points to the java executables directory.

 c:\>set path
Path=C:\Program Files (x86)\Windows Resource Kits\Tools\;C:\WINDOWS\system32;C:\WINDOWS;C:\WINDOWS\System32\Wbem;C:\WINDOWS\System32\WindowsPowerShell\v1.0\;C:\Program Files (x86)\Quarantine\;C:\Program Files\Perforce;C:\Program Files\Microsoft Network Monitor 3\;c:\Program Files\Java\jdk1.7.0_17\bin 

 How to set JDK path 
1.Open System properties 
2.Go to Advanced tab
3.Click ‘Environment variables’ 
4. Under ‘System Variables’ scroll down to find PATH. Edit the entry and add JDK path.
5.Click OK and close the windows. 

Now open new command prompt and run ‘set path’, you can see that JDK path is added.  Note that if you run the command from a window which was opened before you modified the PATH variable, it would not print updated path. Even for compiling java programs, you need to open a new command window after setting PATH. 
 

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2.Chang Khoon Lim  55643 
3.Tang Jie Jie            58097
4.Koh Zhe Wei            56321  
5.Kang Zhi Zheng      56268 

What is wrong with the following program? Provide a recommendation program to fix the error. 

Queston:
 public class GotError{ 
 public static void main(String[] args){
for ( int i=0; i<10; i++);
system.out.println(i+4);
}
}

Answer:

public class GotError{ 
 public static void main(String[] args){
for ( int i=0; i<10; i++)
{
System.out.println (i+4);
}
} 
}

Output:
4
5
6
7
8
9
10
11
12
13

explanation:
FOR statement no need ";"
Save file must same name with class

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1.NURDIAH BASIHOL 57410
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3. ZAHIDA BINTI AHMAD ZAWAWI 58369
4. NOR RAS AMIERZA BINTI MARZUKI 57046

1.  Fatin Hanani Binti Kamaluddin (58602) 

2. Elizabeth anak Ubam (58571) 

3. Alya Syazana Binti Yumat (58439) 

4. Nor Hazirah Binti Mohd. Tamin (58901) 

5. Nurqamarina Binti Ramlan (59053) 

Explain the following code with its definition and syntax.

public class MyFirstJava{

public static void main(String[] args)}

System.out.println("Hello World");

}

}

Explaination:

Line 1= public class MyFirstJava{

class is an application/program and every class begins with the word public and class followed by the class name (MyFirstJava)

Line 2= public static void main(String[] args)}

Is the first line of the class's main method. A method is a name section of a class that perform a task.

Line 3= System.out.println("Hello World");

This line instruct the computer to print "Hello World" on the screen.

("Hello World") is called a string.

All statements are terminated with a semicolon (;)

- Curly braces {......} on line 1 and 5 mark the beginning and the end of the MyFirstJava class. 

- Curly braces on line 2 and 4 mark the beginning and the end of the main method. 

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public class pp {

     public static void main(String[] args) {
     
     int ans;
 System.out.println("Group 14\n Demonstrate with code example the differences between continue and break");
 System.out.println("The number presented will be: 0,1,2,3,4");
 
 br();
 System.out.println("\n\n");
 con();
 
 System.out.println("1. Alex Fong 51130\n2.Arif 54426\n3.Wee Kai Zhi 58280\n4.Chia Yit Hoong 55679\n");
     }

     public static void br(){
     System.out.println("This is break");
         for(int i = 0; i <5; i++){
         if(i != 3){
         System.out.println(i);
         }
         else{
         break;
         }
         }
     }

     public static void con(){
     System.out.println("This is continue");
     for(int i = 0; i<5;i++){
     if(i != 3){
     System.out.println(i);
     }
     else{
     continue;
     }

     }
     }
     

 }

public class GotErrors{
          public static void main(String[] args){
           int i=0;
           int j=5;

           if(j>3)
           system.out.println(i+4);
           }
} 

The error occurs when the integer i is not initialised with value

Lim Hui Sin 56436
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Tan Pooi Yan 58078

Question :  write a program that receive a stringand a number from the user. The program then displays a concatenation of a string and a number . 

Answer 
import java.util.Scanner;
 
class GetInputFromUser
{
   public static void main(String args[])
   {
      int a;
      float b;
      String s;
 
      Scanner in = new Scanner(System.in);
 
      System.out.println("Enter a string");
      s = in.nextLine();
      System.out.println("You entered string "+s);
 
      System.out.println("Enter an integer");
      a = in.nextInt();
      System.out.println("You entered integer "+a);
 
      System.out.println("Enter a float");
      b = in.nextFloat();
      System.out.println("You entered float "+b);   
   }
}
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