--> Find the total nuclear binding energy and divide by (A) total neutrons + protons. Represents the binding energy between each proton and neutron.

=1 x 10⁶

eV --> J

= 1 x ( 1.6 x 10^-19 )

Higher wavelength 1/∝ ejection rate

The formula for calculating the de Broglie wavelength (λ) is λ = h/p, where h is Planck's constant and p is the particle's momentum.

and this emits a positron and neutrino

so density (p)

p ∝ 1/R³ ∝1/A

M∝A

When electricity flows through the coils, it goes in loops creating a magnetic field. When a magnetic field is created and is in an A.C circuit, the direction changes creating an electric field. This electric field will charge the induction coil in the phone, converting the energy into electricity.

What chatGPT said:

An induction coil in a wireless phone charger is a coil of wire that generates a changing magnetic field when alternating current (AC) flows through it. This alternating magnetic field induces an electric current in the receiving coil inside the phone, wirelessly transferring energy and converting it into electricity to charge the battery.

E_{k rotational} = 1/2 IW²

U - initial angular velocity

V - angular velocity

A - angular acceleration

T - Time

Symbols on data booklet, like the kinematics formulas.

Power can be found in electricity, kinematics, ect. For example in electricity, Work done = force X distance costheta. If we differenciate this we can find power (f is a constant). So this will become Fsintheta V. Example question --> below

Examples:

Time

Voltage

Examples:

Current

Displacement

How to solve:

• Induced current opposes the change in flux.

• Magnetic field direction goes into the page

• Increasing → induced field out of page

• Decreasing → induced field into page

Anwser: C

Magnetic field is only in a small region, not whole circuit

Solving notes

Only wire segment in changing field gets induced emf (IMPORTANT REMEMBER)

Anwser: B

When solving remember:

Falling magnet → changing magnetic flux → induced current creates opposing force to reach equilibrium

Equal and opposite force on loop

Anwser: B

Remember Newton’s 3rd law

force on magnet = opposite force on loop.

Apply left-hand rule so the force moves the rod to the right

Explain how is this possible.

Hint: 1. What stays constant during refraction and what changes?

2. Think about topic E1 atomic physics and the cause of colour.

Ohms law: current through a conductor is directly proportional to the voltage across it and emf is equal to IR.

When solving for r, since this is a series circuit we just add the resistance to get the total resistance in the circuit. the total resistance will be the resistor + the internal resistor meaning R + r and know we reaggange to find r. With this we get 0.56 ohms

This formula is used because U' is the velocity of the same body in the original frame of reference. let U is speed of x and V = speed of Y. Direction also matters. So the anwser is 0.81c which is option C

Anwser: B

Resistance = R

Current = I

Firstly use emf formula e=IR since r is negligible. Since this is a series just add resistance so it = 40. so 12=40I, find I than sub into the formula V=IR, than solve for V which will be 7.5V.

Anwser: D

emf= energy transfered / charge

For this question 26:

The answer is B. The distractor option is D because its saying that the emf of the batter is the energy transfered in the batter minus the resistor /Q. This distracts you as you think that by doing this you will find the emf for the battery only. However the energy transfer in the resistor does not affect the battery. So the answer is B

• Isochoric (isovolumetric): Volume is constant, so no work is done W=0.

• Isobaric: Pressure is constant, volume changes, so work is done P=0.

• Isothermal: Temperature is constant, so internal energy does not change U=0.

• Adiabatic: No heat transfer Q=0.

We can use the formula Q=U+W and the goal is to not let the equation = 0, hence the only option that does not affect this is option B.

• A neutron inside a nucleus decays into a proton

• This process emits an electron and an electron antineutrino

• At the quark level, a down quark (d) changes into an up quark (u) by emitting a boson

• The boson then decays into an electron and an electron antineutrino

Sooooo

• The initial quark should be a down quark

• The final quark should be an up quark

• The emitted boson should be W-

• The boson decays into an electron and an electron antineutrino

So the answer is D

but the issue i need help with is determining if this collision is inelastic. I don't understand what factors contribute to a collisions inelasticity.

I think I might be mixing up the x axis but, how do I find the half life in this graph. I thought it would be 7 days but the answer says otherwise. (It does not give a worked solution =0 )