https://padlet.com/toh_xiao_qi/uyfdpao4z3me Made with an open mind en-us 2017-02-21 03:39:39 UTC 2023-05-14 18:01:07 UTC hello@padlet.com https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054638 Yes, it will remain unchanged as both the shape have the same right angle and lengths remain unchanged. Hence, the formula will still work on it. as long as the circumference of the semi-circle is the same as the length of the square.]]> 2017-02-21 03:46:46 UTC https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054638 https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054701 (a) Yes, the relationship remains unchanged. Although the squares were changed to semi-circles,the triangle remained right-angled, so the Pythagoras' theorem still applies.
(b) it doesn't matter if the squares were changed to semi-circles, the triangle still has a right angle and a hypotenuse and the Pythagoras' theorem still implies.(a² + b² = c²)]]> 2017-02-21 03:47:31 UTC https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054701 https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054778 Yes the relationship will remain the same.
 Since the only thing that changed is the formula for the area of the sides, only the length changed, the relationship will still remain the same. And it will always be a right-angled triangle.
pie(r)^ only the changes


]]> 2017-02-21 03:48:23 UTC https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054778 https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054823 Yes, the relationship will remain unchanged
-because they all have a constant variable of pie, thus it does not affect the answer.
-Although the formula to find the semi-circle is different from the square, the formula used is still constant among the three lines.

eg. 
Line AB=3cm 
Area of semicirlcle= 1/2 x pie x 1.5 x1.5 =1.125
Line CA= 4cm
Area of semi-circle=1/2 x 2 x2 x pie
= 2
Line BC= 5cm
Area of semi-circle=1/2 x 2.5 x 2.5 x pie
=3.125

1.125+2=3.125 

]]> 2017-02-21 03:48:57 UTC https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054823 Lollichan https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054848 (a) As long as the diameters of each semi-circle form a right -angled triangle, the square of hypotenuse is equal to the sum of the square of the remaining sides.

(b)  The length of the sides of the right-angled triangle remains the same although the squares are replaced with semi-circles.

e.g: ]]> 2017-02-21 03:49:13 UTC https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054848 https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054853 yes .  The relationship will still remain the same
a) the area of a and b still equal to area of c as the triangle is still right angled.

]]> 2017-02-21 03:49:17 UTC https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054853 https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054889 The relationship remains unchanged . The triangle is still a right angled triangle. The bottom of a semi-circle and the length of a square are straight lines.

]]> 2017-02-21 03:49:29 UTC https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054889 stella_ho1111 https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054900 Yes. The relationship will remain unchanged.
Reasons being:
a) There will always be a right-angled triangle and the formula is still applicable to it.
b)

]]> 2017-02-21 03:49:37 UTC https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054900 toh_xiao_qi https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054997 2017-02-21 03:50:45 UTC https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155054997 https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155055132 yes the relationship will remain unchanged as a right angled triangle, the Pythagoras' Theorem, c^2 = b^2 + a^2


]]> 2017-02-21 03:52:27 UTC https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155055132 jyjy https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155055141 as long as there is a right angle; the relationship remains the same]]> 2017-02-21 03:52:32 UTC https://padlet.com/toh_xiao_qi/uyfdpao4z3me/wish/155055141