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      <title>我大樂透的 Padlet by 20522邱品翔</title>
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      <pubDate>2023-03-30 01:36:30 UTC</pubDate>
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         <title>抽籤取亂數</title>
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         <pubDate>2023-03-30 01:48:20 UTC</pubDate>
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         <title>排序亂數</title>
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         <pubDate>2023-03-30 01:50:40 UTC</pubDate>
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         <title>抽籤號碼不重複</title>
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         <pubDate>2023-03-30 01:52:04 UTC</pubDate>
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         <title>產生 [N期] 的中獎號碼</title>
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         <title>運行理念</title>
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         <description><![CDATA[<div>藉由<strong><mark>random.randint(a,b)</mark></strong>從範圍a~b中取出數字，接著由下方<strong><mark>if條件句</mark></strong>判斷取出數字是否符合條件，一切符合則將數字放入陣列中。</div>]]></description>
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         <title>運行理念</title>
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         <link>https://padlet.com/s11030048/utrl7byeopyid4e6/wish/2540996483</link>
         <description><![CDATA[<div>在隨機取多個數字後使用<strong><mark>bubble sort氣泡排序法</mark></strong>，將陣列中的數字依序進行比大小，如果前面一個數字比後一個數字大就互相交換位置，最後就能產出由小排到大的數列。</div>]]></description>
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         <pubDate>2023-04-02 08:23:34 UTC</pubDate>
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         <title>運行理念</title>
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         <description><![CDATA[<div>在取完亂數後為了不讓重複的數字進入陣列，使用了<strong><mark>if number not in result:</mark></strong>來確認陣列中是否已經有相同數字在內，確定沒有後再將數字匯入陣列中。<br><br></div>]]></description>
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         <pubDate>2023-04-02 08:39:23 UTC</pubDate>
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         <title>運行理念</title>
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         <link>https://padlet.com/s11030048/utrl7byeopyid4e6/wish/2541002930</link>
         <description><![CDATA[<div>我使用抽出N期號碼的方式是先<strong><mark>int</mark></strong>選出要抽出的期數，接著用<strong><mark>for迴圈</mark></strong>重複執行N次抽籤和排序</div>]]></description>
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         <pubDate>2023-04-02 08:39:41 UTC</pubDate>
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         <title> 加上特別號 / 查詢期別</title>
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         <pubDate>2023-04-27 01:18:07 UTC</pubDate>
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         <title>選擇+條件判斷</title>
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         <pubDate>2023-04-27 01:22:19 UTC</pubDate>
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