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      <title>Tricky Maths ! by </title>
      <link>https://padlet.com/ipthi_saif/uoc7jv0v49</link>
      <description>Try Guessin&#39; and Solvin&#39;. . . . .        Until u succeed :D
A number with an interesting property:

When I divide it by 2, the remainder is 1.
When I divide it by 3, the remainder is 2.
When I divide it by 4, the remainder is 3.
When I divide it by 5, the remainder is 4.
When I divide it by 6, the remainder is 5.
When I divide it by 7, the remainder is 6.
When I divide it by 8, the remainder is 7.
When I divide it by 9, the remainder is 8.
When I divide it by 10, the remainder is 9.

It&#39;s not a small number, but it&#39;s not really big, either.
When I looked for a smaller number with this property I couldn&#39;t find one.

Can you find it?</description>
      <language>en-us</language>
      <pubDate>2013-02-05 10:44:48 UTC</pubDate>
      <lastBuildDate>2025-11-14 20:20:56 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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      <item>
         <title>Anusree</title>
         <author>anusreegovind</author>
         <link>https://padlet.com/ipthi_saif/uoc7jv0v49/wish/6912066</link>
         <description><![CDATA[<p>Is it 2519?</p>]]></description>
         <enclosure url="" />
         <pubDate>2013-02-05 13:31:43 UTC</pubDate>
         <guid>https://padlet.com/ipthi_saif/uoc7jv0v49/wish/6912066</guid>
      </item>
      <item>
         <title>Heba Sharif</title>
         <author></author>
         <link>https://padlet.com/ipthi_saif/uoc7jv0v49/wish/6962118</link>
         <description><![CDATA[<p>the number is 2519.</p>]]></description>
         <enclosure url="" />
         <pubDate>2013-02-06 14:26:32 UTC</pubDate>
         <guid>https://padlet.com/ipthi_saif/uoc7jv0v49/wish/6962118</guid>
      </item>
      <item>
         <title>SREETHI SREENU</title>
         <author>sreenudivakaran</author>
         <link>https://padlet.com/ipthi_saif/uoc7jv0v49/wish/7010570</link>
         <description><![CDATA[<p>LCM OF THE NUMBERS FROM 2-10 = 2520</p><p>x+1 = 2520</p><p>x= 2520-1 = 2519 </p><p>THEREFORE THE NUMBER IS 2519.</p>]]></description>
         <enclosure url="" />
         <pubDate>2013-02-07 13:30:47 UTC</pubDate>
         <guid>https://padlet.com/ipthi_saif/uoc7jv0v49/wish/7010570</guid>
      </item>
      <item>
         <title>Shreya Prabhakumar Nair</title>
         <author></author>
         <link>https://padlet.com/ipthi_saif/uoc7jv0v49/wish/7030052</link>
         <description><![CDATA[LCM of 2,3,4,5,6,7,8,9,10 = <br> 2 = 2<br> 3 = 3<br> 4 = 2^2<br> 5 = 5<br> 6 = 2 x 3<br> 7 = 7<br> 8 = 2^3<br> 9 = 3^2<br> 10 = 2 x5<br><br> LCM = 2^3 x 3^2 x 5 x 7 <br> LCM = 8 x 6 x 5 x 7 = 2520.<br><br> The answer you want is<br> 2520 - 1 = 2519.<br>]]></description>
         <enclosure url="" />
         <pubDate>2013-02-07 19:17:53 UTC</pubDate>
         <guid>https://padlet.com/ipthi_saif/uoc7jv0v49/wish/7030052</guid>
      </item>
      <item>
         <title>Anupama</title>
         <author>anupamaramadas</author>
         <link>https://padlet.com/ipthi_saif/uoc7jv0v49/wish/7111038</link>
         <description><![CDATA[<p>The answer is 2519</p><p>2519/2 remainder        =1</p><p>2519/3 "                         "=2</p><p>2519/4"                          "=3</p><p>2519/5                             =4</p><p>2519/6                             =5</p><p>2519/7                             =6</p><p>2519/8                             =7</p><p>2519/9                             =8</p><p>2519/19                           =9</p>]]></description>
         <enclosure url="" />
         <pubDate>2013-02-11 17:52:19 UTC</pubDate>
         <guid>https://padlet.com/ipthi_saif/uoc7jv0v49/wish/7111038</guid>
      </item>
      <item>
         <title>Shreya Prabhakumar Nair</title>
         <author>thundilkumar</author>
         <link>https://padlet.com/ipthi_saif/uoc7jv0v49/wish/7112462</link>
         <description><![CDATA[Let N be your number. Notice that if you add 1 to your number<br> then the result, N + 1 , is divisible by 2 through 9 since the<br> remainders all become zero.&nbsp; The smallest such number<br> divisible by 2 through 9 is the least common multiple of<br> 2 through 9 which is 2520 = N + 1. Then, N = 2519.]]></description>
         <enclosure url="" />
         <pubDate>2013-02-11 18:25:38 UTC</pubDate>
         <guid>https://padlet.com/ipthi_saif/uoc7jv0v49/wish/7112462</guid>
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