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      <title>HỌC TOÁN CÙNG 4A5 by Loan Duong</title>
      <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4</link>
      <description>Được tạo ra bằng tiếng cười</description>
      <language>en-us</language>
      <pubDate>2021-10-06 00:05:36 UTC</pubDate>
      <lastBuildDate>2022-03-03 09:49:41 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
      <image>
         <url>https://padlet.net/icons/png/1f970.png</url>
      </image>
      <item>
         <title>Dương Đức khánh</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075405700</link>
         <description><![CDATA[<div>bài 2:<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; tổng cả hai loại bi là&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 3/8 + 1/6 =13/24 ( tổng cả hai&nbsp; loại bi)<br>&nbsp; &nbsp; &nbsp; số bi trắng bằng số phần tổng số bi là:<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;24/24-13/24=11/24(phần)<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Đáp số : 11/24 phần<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 08:57:42 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075405700</guid>
      </item>
      <item>
         <title>Phạm Bảo Ngân</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075408529</link>
         <description><![CDATA[<div>Tổng số bi xanh và bi đỏ có số phần tổng số bi là :<br>3/8 + 1/6 = 13/24 (ổng số bi)<br>Có số bi trắng là :<br>24/24 - 13/24 = 11/24 (tổng số bi)<br>Đáp số : 11/24 tổng số bi</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 08:59:52 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075408529</guid>
      </item>
      <item>
         <title>Vũ Thành Đạt</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075412198</link>
         <description><![CDATA[<div>Tổng số bi đỏ và bi xanh là:<br>3/8+1/6=13/24(tổng số bi)<br>Số bi trắng của Nam là:<br>24/24-13/24=11/24(tổng số bi)<br>Đáp số:11/24 tổng số bi</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:02:41 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075412198</guid>
      </item>
      <item>
         <title>Lê Nhật Khanh</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075414615</link>
         <description><![CDATA[<div>bài 2</div><div>Tổng số bi đỏ và bi xanh là:<br>3/8+1/6=13/24(tổng số bi)<br>Số bi trắng của Nam là:<br>24/24-13/24=11/24(tổng số bi)<br>Đáp số:11/24 tổng số bi</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:04:35 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075414615</guid>
      </item>
      <item>
         <title>Khánh Hà </title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075415243</link>
         <description><![CDATA[<div>tổng cả hai loại bi màu xanh và đỏ là :<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;3/8+1/6=13/24 (tổng cả hai loại bi)<br>có số viên bi trắng là :<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 24/24-13/24=11/24(phần)<br>                           Đáp số : 11/24 phần</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:05:06 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075415243</guid>
      </item>
      <item>
         <title>Nguyễn Quỳnh Anh </title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075415844</link>
         <description><![CDATA[<div>Bài giải&nbsp;<br>Bi đọc và bi xanh có phần tổng số bi là:<br>3/8+1/6=13/24(tổng số bi)<br>Số bi trắng của Nam bằng số phần tổng số bi là :<br>24/24-13/24=11/24(tổng số bi)<br>Đáp số : 11/24 tổng số bi<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:05:34 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075415844</guid>
      </item>
      <item>
         <title>Phạm Kiên Cường</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075417325</link>
         <description><![CDATA[<div>Tổng hai loại bi xanh và đỏ là<br>3/8+1/6=13/24( Tổng số bi )<br>Số bi trắng bằng số phần là&nbsp;<br>24/24- 13/24=11/24( tổng số bi)<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Đáp số 11/24 số bi trắng&nbsp;<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:06:49 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075417325</guid>
      </item>
      <item>
         <title>Phương Linh</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075417330</link>
         <description><![CDATA[<div>Bài 2 :                                                                                         Nam có tất cả số bi xanh và bi dỏ là :                  3/8 + 1/6 = 13/24 ( tổng số bi )                             Số bi trắng bằng tổng số bi là :                           24/24 - 13/24 = 11/24 ( tổng số bi )                            Đáp số : 11/24 tổng số bi</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:06:50 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075417330</guid>
      </item>
      <item>
         <title>Quách Gia Lộc</title>
         <author>qvanphuc</author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075418112</link>
         <description><![CDATA[<div>Bài 2:<br>Bài giải<br>Tổng số bi đỏ và bi xanh là:<br>3/8+1/6=13/24(tổng số bi)<br>Số bi trắng của Nam là:<br>24/24-13/24=11/24(tổng số bi)<br>Đáp số:11/24 tổng số bi</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:07:26 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075418112</guid>
      </item>
      <item>
         <title>Phạm trung hải</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075418371</link>
         <description><![CDATA[<div>Bài 2:<br>Bài giải<br>Tổng số bi xanh và bi đỏ có số bi là<br>3/8×1/6=3/48(viên bi)<br>Số bi trắng có sô bi là:<br>3/48÷3=1/48<br>Đáp số:1/48 viên bi<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:07:33 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075418371</guid>
      </item>
      <item>
         <title>Mai Hải Yến</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075421140</link>
         <description><![CDATA[<div>Số bi xanh và số bi đỏ có số phần tổng số bi là:<br>&nbsp; &nbsp;3&nbsp; &nbsp; &nbsp; &nbsp; 1&nbsp; &nbsp; &nbsp; &nbsp;13<br>&nbsp; ---&nbsp; + --- = ---&nbsp; { tổng số bi }<br>&nbsp; &nbsp;8&nbsp; &nbsp; &nbsp; &nbsp; 6&nbsp; &nbsp; &nbsp; &nbsp;24<br>Số bi trắng của Nam bằng số phần tổng số bi là:<br>&nbsp; 24&nbsp; &nbsp; &nbsp;13&nbsp; &nbsp; &nbsp;11<br>&nbsp; --- - --- = --- { tổng số bi }<br>&nbsp; 24&nbsp; &nbsp; &nbsp;24&nbsp; &nbsp; 24<br>&nbsp; &nbsp; &nbsp; Đáp số: 11<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; --- tổng số bi<br>                     24</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:09:18 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075421140</guid>
      </item>
      <item>
         <title>Hiểu Minh</title>
         <author>nguyenhieulam2009</author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075427065</link>
         <description><![CDATA[<div>bài 2:<br>Tổng cả hai loại bi là:&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;<br>3/8 + 1/6 =13/24 (tổng cả hai&nbsp; loại bi)<br>Số bi trắng bằng số phần tổng số bi là:<br>24/24-13/24=11/24(phần)<br>Đáp số:11/24phần</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:13:47 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075427065</guid>
      </item>
      <item>
         <title>Vũ Trúc Quỳnh Anh</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075427302</link>
         <description><![CDATA[<div>bài 2<br>                          bài giải<br>Tổng số bi đỏ và bi xanh là:<br>       3/8+1/6=13/24(tổng số bi)<br>Số bi trắng của Nam bằng số phần tổng số bi là :<br>        24/24-13/24=11/24(tổng số bi)<br>         Đáp số : 11/24 tổng số bi<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:13:59 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075427302</guid>
      </item>
      <item>
         <title>Phạm Bảo Ngân</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075437361</link>
         <description><![CDATA[<div>a)3/5 + 2/9 = 27/45 + 10/45 =37/45<br>b)4 - 5/7 =4/1-5/7 = 28/7 - 5/7 =23/7<br>c)4/5 x 10/4 = 4 x 10/5 x 4 =40/20 =2/1<br>d)5/6 : 10/4 =5/6 x 4/10 =20/60 = 20 : 20 / 60 :20 =1/3<br>e)7/8 - 1/4 x 2/10 = 7/8 - 2/40 = 35/40 - 2/40 =33/40<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:21:39 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075437361</guid>
      </item>
      <item>
         <title>DƯƠNG ĐỨC KHÁNH</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075444330</link>
         <description><![CDATA[<div>BÀI 3&nbsp;<br>A,3/5 + 2/9=27/45+10/45=37/45<br>B,4-5/7=28/7-5/7=23/7<br>C,4/5 X 10/4=40/20=40:20/20:20=2/1<br>D,5/6 : 10/4=5/6 X 4/10 =20/60 =20:20/60:20=1/3<br>E,7/8 - 1/4 X 2/10=7/8-2/40=33/40</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:26:29 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075444330</guid>
      </item>
      <item>
         <title>Lê Nhật khanh khánh</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075446337</link>
         <description><![CDATA[<div><br>bài3<br>a)3/5 + 2/9 = 27/45 + 10/45 =37/45<br>b)4 - 5/7 =4/1-5/7 = 28/7 - 5/7 =23/7<br>c)4/5 x 10/4 = 4 x 10/5 x 4 =40/20 =2/1<br>d)7/8 -1/4 x 2/10 =7/8 - 2/40 = 35/40 - 2/40=33/40<br><br><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:27:50 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075446337</guid>
      </item>
      <item>
         <title>Phạm Kiên Cường</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075451211</link>
         <description><![CDATA[<div>a) 3/5+2/9=27/45+10/45=37/45</div><div>b) 4-5/7=28/7-5/7=23/7<br>c) 4/5 x 10/4=40/20=40:20/20:20=2/1<br>d) 5/6 : 10/4=5/6 x 4/10 =20/60 =20:20/60:20=1/3<br>e) 7/8 - 1/4 x 2/10=7/8-2/40=33/40</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:31:24 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075451211</guid>
      </item>
      <item>
         <title>Vũ Thành Đạt</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075454415</link>
         <description><![CDATA[<div>a,3/5+2/9=27/45+10/45=37/45<br>b,4-5/7=28/7-5/7=23/7<br>c,4/5x10/4=4x10/5x4=10/5=2/1=2<br>d,5/6:10/4=5/6x4/10=20/60=1/3<br>e,7/8-1/4x2/10=7/8-2/40=35/40-2/40=33/40</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:33:47 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075454415</guid>
      </item>
      <item>
         <title>Nguyễn Quỳnh Anh </title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075456363</link>
         <description><![CDATA[<div>A)3/5+2/9=27/45+10/45=37/45<br>B)4-5/7=28/7-5/7=23/7<br>C)4/5x10/4=4x10/5x4=40/20=40:2/20:2=20/10=20:5/10:5=4/2=4:2/2:2=2/1=2<br>D)5/6:10/4=5/6x4/10=20/60=20:2/60:2=10/30=10:5/30:5=2/6=2:2/6:2=1/3<br>E)7/8-1/4x2/10=7/8-2/40=35/40-2/40=33/40</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:35:10 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075456363</guid>
      </item>
      <item>
         <title>Khánh Hà</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075457248</link>
         <description><![CDATA[<div>a.3/5+2/9=27/45+10/45=37/45<br>b.4-5/7=4/1-5/7=28/7-5/7=23/7<br>c.4/5:10/4=40/20=40:20/20:20=2/1<br>d.5/6:10/4=5/6x4/10=20/60=20:20/60:20=1/3<br>e.7/8-1/4x2/10=7/8-2/40=33/40</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:35:48 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075457248</guid>
      </item>
      <item>
         <title>Hiểu Minh</title>
         <author>nguyenhieulam2009</author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075462310</link>
         <description><![CDATA[<div>Bài 3:<br>a)3/5+2/9=27/45+10/45=37/45<br>b)4-5/7=28/7-5/7=23/7<br>c)4/5x10/4=40/20=40:20/20:20=2/1<br>d)5/6:10/4=5/6x4/10=20/60 =20:20/60:20=1/3<br>e)7/8-1/4x2/10=7/8-2/40=33/40</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:39:35 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075462310</guid>
      </item>
      <item>
         <title>Quách Gia Lộc</title>
         <author>qvanphuc</author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075465777</link>
         <description><![CDATA[<div>Bài 3:<br>A)3/5+2/9=27/45+10/45=37/45<br>B)4-5/7=28/7-5/7=23/7<br>C)4/5x10/4=4x10/5x4=40/20=40:2/20:2=20/10=20:5/10:5=4/2=4:2/2:2=2/1=2<br>D)5/6:10/4=5/6x4/10=20/60=20:2/60:2=10/30=10:5/30:5=2/6=2:2/6:2=1/3<br>E)7/8-1/4x2/10=7/8-2/40=35/40-2/40=33/40</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:42:00 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075465777</guid>
      </item>
      <item>
         <title>VŨ TRÚC QUỲNH ANH</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075468457</link>
         <description><![CDATA[<div>BÀI 3:<br>a)3/5+2/9=27/45+10/45=37/45<br>b)4-5/7=28/7-5/7=23/7<br>c)4/5x10/4=4x10/5x4=40/20=40:2/20:2=20/10=20:5/10:5=4/2=4:2/2:2=2/1=2<br>d)5/6:10/4=5/6x4/10=20/60=20:2/60:2=10/30=10:5/30:5=2/6=2:2/6:2=1/3<br>e)7/8-1/4x2/10=7/8-2/40=35/40-2/40=33/40<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:43:57 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075468457</guid>
      </item>
      <item>
         <title>Mai Hải Yến</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075471767</link>
         <description><![CDATA[<div>a} 3&nbsp; &nbsp; &nbsp; &nbsp;2&nbsp; &nbsp; &nbsp; &nbsp;27&nbsp; &nbsp; 10&nbsp; &nbsp; &nbsp; &nbsp;37<br>&nbsp; &nbsp;--- + --- = --- + --- =&nbsp; ---<br>&nbsp; &nbsp; 5&nbsp; &nbsp; &nbsp; &nbsp; 9&nbsp; &nbsp; &nbsp; 45&nbsp; &nbsp; &nbsp;45&nbsp; &nbsp; &nbsp; 45<br>b} 4-&nbsp; 5&nbsp; &nbsp; &nbsp; 4&nbsp; &nbsp; &nbsp; 5&nbsp; &nbsp; &nbsp; &nbsp;28&nbsp; &nbsp; &nbsp; 5&nbsp; &nbsp; &nbsp; 23<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;--- = --- - --- = --- - --- = ---<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 7&nbsp; &nbsp; &nbsp; &nbsp;1&nbsp; &nbsp; &nbsp; &nbsp;7&nbsp; &nbsp; &nbsp; &nbsp; 7&nbsp; &nbsp; &nbsp; &nbsp;7&nbsp; &nbsp; &nbsp; &nbsp;7<br>c} 4&nbsp; &nbsp; &nbsp;10&nbsp; &nbsp; &nbsp; 16&nbsp; &nbsp; &nbsp;50&nbsp; &nbsp; &nbsp;800&nbsp; &nbsp; &nbsp; 16&nbsp; &nbsp; &nbsp; 4<br>&nbsp; &nbsp;--- x --- = --- x --- =&nbsp; ---- = --- = --- =4<br>&nbsp; &nbsp; 5&nbsp; &nbsp; &nbsp; &nbsp;4&nbsp; &nbsp; &nbsp; 20&nbsp; &nbsp; &nbsp;20&nbsp; &nbsp; &nbsp; 20&nbsp; &nbsp; &nbsp; 20&nbsp; &nbsp; &nbsp; &nbsp;1<br>d} 5&nbsp; &nbsp; &nbsp;10&nbsp; &nbsp; &nbsp; &nbsp;5&nbsp; &nbsp; &nbsp; 4&nbsp; &nbsp; &nbsp; 20<br>&nbsp; &nbsp; --- : --- = --- x --- = ---<br>&nbsp; &nbsp; &nbsp;6&nbsp; &nbsp; &nbsp; 4&nbsp; &nbsp; &nbsp; &nbsp;6&nbsp; &nbsp; &nbsp; &nbsp;10&nbsp; &nbsp; &nbsp;60<br>e} 7&nbsp; &nbsp; &nbsp; 1&nbsp; &nbsp; &nbsp; &nbsp;2        7      2       35    2       33<br>&nbsp; &nbsp;--- - --- x --- = --- - --- = --- - --- = ---<br>    8       4      10      8     40      40    40    40</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:46:32 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075471767</guid>
      </item>
      <item>
         <title>Phương linh</title>
         <author></author>
         <link>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075476398</link>
         <description><![CDATA[<div>a) 2/5 + 2/9&nbsp; &nbsp; &nbsp;2/5 = 2 × 9/5 × 9 = 18/45&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2/9 = 2 × 5/9 × 5 = 10/45&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2/5 + 2/9 = 18/45 + 10/45 = 28/45   b) 4 - 5/7 = 20/7 - 5/7 = 15/7 c) 4/5 × 10/4 = 40/20 = 2/1 =2         d) 5/6 : 10/4 = 5/6 × 4/10 = 20/40 = 1/2  e) 7/8 - 1/4 × 2/10 = 7/8 - 2/40 = 280/320 - 16/320 = 120/320 </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-03 09:49:41 UTC</pubDate>
         <guid>https://padlet.com/duongloan204/uelvgiuf9cz1tze4/wish/2075476398</guid>
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