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      <title>Maths : Unit 1 by Holly Jones</title>
      <link>https://padlet.com/hol_cjones/u3oawgvlcje4</link>
      <description>Made with a lightning strike of genius</description>
      <language>en-us</language>
      <pubDate>2019-01-30 12:12:16 UTC</pubDate>
      <lastBuildDate>2024-07-15 06:28:23 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
      <image>
         <url>https://padlet-assets.s3.amazonaws.com/icons/Growing.png</url>
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      <item>
         <title>Integration</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795538</link>
         <description><![CDATA[<div>Method - <mark>Indefinite interval</mark></div><ol><li>Add 1 to index (power)</li><li>Divide by new power</li></ol><div>Method - <mark>Definite interval</mark></div><ol><li>Add 1 to index (power</li><li>Divide by new power</li><li>Substitute in upper limit to integral</li><li>Substitute in lower limit</li><li>Upper limit answer - lower limit answer</li></ol><div><mark>Key Information</mark></div><ul><li>Indefinite interval - no numbers on integral - have to include a constant of integration (+c)</li><li>Definite interval - has number on integral called limits - when we substitute in limits we get a definitive solution</li><li>When integrating we start with f(x). </li><li>After integration we have F(x) </li></ul><div>Method - <mark>Area under a curve</mark></div><ol><li>Use edges of function (area required in graph) as limits</li><li>Integrate function</li><li>Substitute in limits</li><li>Upper limit answer - lower limit answer</li></ol><div>Method - Area between a curve and a line <br>**************</div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795538</guid>
      </item>
      <item>
         <title>Stationary Points</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795539</link>
         <description><![CDATA[<div>Method- <mark>Finding stationary points</mark></div><ol><li>Differentiate the function</li><li>Set the derivative equal to 0 and solve the equation (usually factorise)</li><li>Substitute values into original equation to give two sets of co-ordinates</li></ol><div><mark>Key Information</mark></div><ul><li>A stationary point is a part of the graph where the first derivative is 0</li><li>Maximum - Represents the highest value of the function - change from increasing to decreasing</li><li>Minimum- Represents the lowest value of the function - change from decreasing to increasing</li><li>Inflection - No representation of a value - direction of function doesn’t change</li></ul><div>Method- <mark>Classifying the stationary points </mark></div><ol><li>Differentiate the function</li><li>Set the derivativeequal to 0 and solve the equation (usually factorising)</li><li>Substitute values into original equation to give two sets of co-ordinates (the stationary points)</li><li>Find second derivative</li><li>Substitute x value into second derivative</li></ol><div><mark>Key Information</mark></div><ul><li>If d<sup>2</sup>y / dx<sup>2</sup> &lt; 0 = maximum point</li><li>If d<sup>2</sup>y / dx<sup>2</sup> &gt; 0 = minimum point</li><li>If d<sup>2</sup>y / dx<sup>2 </sup>= 0 = Can’t be classified - consider values either side of stationary points</li></ul>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795539</guid>
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      <item>
         <title>Differentiation</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795540</link>
         <description><![CDATA[<div>Method - <mark>First Principles</mark></div><ol><li>Use Fomula</li><li>Replace each x with (x+h)</li><li>f(x) = original value</li><li>Rearrange to remove fraction</li><li>Imagine h=0, simplify and solve</li></ol><div>Method - <mark>The Quick Way</mark></div><ol><li>Bring the power down</li><li>Subtract 1 from the power</li></ol><div>Eg function= y=ax<sup>n <br></sup>Derivative = n x ax<sup>n-1<br></sup>Method- <mark>Finding the tangent to a curve </mark></div><ol><li>Differentiate the function</li><li>Substitute the x co-ordinate into derivative. (This gives us the gradient of the tangent)</li><li>Use y-y<sub>1</sub>=m(x-x<sub>1</sub>) to find the equation of the tangent</li></ol><div>Method - <mark>Finding the normal to a curve</mark></div><ol><li>Differentiate the function</li><li>Substitute x co-ordinate into derivative to find the gradient of the tangent</li><li>Find the gradient of the normal (-1 / gradient of tangent)</li><li>Use y-y<sub>1</sub>=m(x-x<sub>1</sub>) to find the equation of the normal</li></ol>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795540</guid>
      </item>
      <item>
         <title>Circle Geometry</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795541</link>
         <description><![CDATA[<div>Method- <mark>Equation of a circle</mark><br>Form 1: (x-a)<sup>2 </sup>+ (x-b)<sup>2 </sup>=r<sup>2</sup><br>Centre = (a,b) <br>Radius= √r<sup>2<br></sup>Form 2 : x<sup>2</sup> + y<sup>2</sup> +2gx + 2fy +c =0 <br>Centre = (-g, -f) (divide 2gx +2fx by 2 and swap signs)<br>Radius = √g<sup>2</sup> +f<sup>2</sup> - c<br>Method - <mark>Points on a circle</mark></div><ol><li>Substitute the coordinates of the given into into the circle equation</li><li>Determine which scenario it lies in</li></ol><div><mark>Key information</mark><br>If the solution is negative, the point lies inside the circle.<br>If the solution is equal to 0, the point lies on the circle.<br>If the solution is positive, the point lies outside the circle. <br>Method - <mark>Circle and line intersect</mark></div><ol><li>Rearrange on equation </li><li>Put changed equation into other</li><li>Simplify and put into form ax<sup>2</sup> + bx + c</li><li>Factorise to find values</li></ol><div><mark>Key information<br></mark>When they intersect twice, there will  be two sets of coordinates<br>Where there is one point of intersection ( a tangent), there is one set of coordinates<br>Method - No points of intersection</div><ol><li>Rearrange one equation</li><li>Put changed equation into other</li><li>Simplify and put into form ax<sup>2</sup> + bx + c = 0</li><li>Use b<sup>2 </sup>- 4ac to prove that there are no real roots and therefore do not intersect</li></ol><div>Method - <mark>Do Circles meet?</mark><br>Find distance between centres (length of line) <br>Find radius of both circles<br><mark>Key Information</mark><br>No points of intersection = C<sub>1</sub>C<sub>2</sub> &gt; r<sub>1</sub> + r<sub>2</sub><br>Two points of intersection =C<sub>1</sub>C<sub>2 </sub>&lt; r<sub>1</sub> + r<sub>2</sub><br>Circles tough externally =C<sub>1</sub>C<sub>2 </sub>= r<sub>1</sub> + r<sub>2</sub><br>Circles touch internally= C<sub>1</sub>C<sub>2</sub> = r<sub>1</sub> - r<sub>2</sub><br>Orthogonal Circles =d<sup>2</sup> = r<sub>1</sub><sup>2 </sup>+  r<sub>2</sub><sup>2</sup><br>(If the tangents are perpendicular at point of intersection they are said to be orthogonal)</div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795541</guid>
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      <item>
         <title>Simultaneous Equations</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795542</link>
         <description><![CDATA[<div>Method- <mark>Using Substitution</mark></div><ol><li>Rearrange one of the equations so that it equals x or y </li><li>Substitute changed equation into other</li><li>Simplify and solve</li><li>Substitute the value into one of the equations to find the other</li></ol><div>Method - <mark>Finding Intersections</mark></div><ol><li>Rearrange one of the equations so that is equals x or y</li><li>Substitute changed equation into other</li><li>Simplify and put into form ax<sup>2</sup> + bx + c</li><li>Factorise</li><li>Substitute the values into one of the equations to find the other</li></ol><div>Method - <mark>Determining the number of solutions</mark><br>Rearrange one of the equations so that it equals x or y <br>Substitue changed equation into other<br>Simplify and put into form ax<sup>2</sup> + bx + c = 0<br>Use b<sup>2 </sup>- 4ac<br><br><mark>Key Information</mark><br>b<sup>2 </sup>- 4ac &gt; 0 Lines intersect at two points<br>b<sup>2 </sup>- 4ac = Lines intersect at one point<br>b<sup>2 </sup>- 4ac &lt; 0 Lines do not intersect</div><div> </div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795542</guid>
      </item>
      <item>
         <title>Laws of Indices </title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795543</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/251754298/f87f10398e3bdba75ff964596117402b/media.jpeg" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795543</guid>
      </item>
      <item>
         <title>Coordinate Geometry</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795545</link>
         <description><![CDATA[<div>Method -  <mark>Equations of lines</mark></div><ol><li>Find gradient</li><li>Use equation: y-y<sub>1</sub> = m(x-x<sub>1</sub>)</li><li>Rearrange to get y=mx+c</li></ol><div>Method -<mark> Intersections</mark></div><ol><li>Solve simultaneous equation</li><li>Substitute value into one equation to find the other</li></ol><div>Key Information<br>Questions may be worded like ' lines l<sub>1</sub> and l<sub>2</sub> intersect at point C. Show C has coordinates (x,y)<br>Method  - <mark>Axis Intersection</mark></div><ol><li>Substitute 0 into the equation at appropriate place</li><li>Simplify and solve</li></ol><div>Key Information<br>When the line crosses they y axis, x=0<br>When the line crosses the x axis, y=0<br>Method - <mark>Angles between two lines</mark></div><ol><li>Plot co-ordinates and form a right angled triangle</li><li>Calculate the lengths of the lines needed/available</li><li>Use SOHCAHTOA to find necessary angle</li></ol>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795545</guid>
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      <item>
         <title>Coordinate Geometry</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795546</link>
         <description><![CDATA[<div>Label Co-ordinates (X<sub>1</sub> , Y<sub>1</sub>) (X<sub>2</sub> , Y<sub>2</sub>)</div>]]></description>
         <enclosure url="http://www.mastertuitioncentre.com/uploads/7/6/2/0/7620652/8005598_orig.png" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795546</guid>
      </item>
      <item>
         <title>Combing inequalities with Nature of Roots</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795548</link>
         <description><![CDATA[<div>Method</div><ol><li>Find a= b= c=</li><li>Put into equation b<sup>2 </sup>- 4ac</li><li>Expand brackets</li><li>Put into form ax<sup>2</sup> + bx + c</li><li>Factorise</li></ol>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795548</guid>
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      <item>
         <title>Quadratic Inequalities</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795549</link>
         <description><![CDATA[<div>Method</div><ol><li>Rearrange into ax<sup>2</sup> + bx + c</li><li>Factorise the expression</li><li>Sketch the function </li><li>Decide which part of the graph contains the solution</li><li>Write the inequality solution  </li></ol>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795549</guid>
      </item>
      <item>
         <title>Unit 2</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795551</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet.com/padlets/qag7ydkyhqjn" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795551</guid>
      </item>
      <item>
         <title>Graph Sketching</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795553</link>
         <description><![CDATA[<div>Method - Linear Graph</div><ol><li>Substitute x values until you find the trend</li><li>Plot and join with a straight line.</li></ol><div>Method - Quadratic graphs</div><ol><li>Factorise function and set each bracket to 0</li><li>solve to find 2 values of x (where the graph crosses the x axis)</li><li>Determine the graph shape using x<sup>2 </sup>coefficient.</li></ol>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795553</guid>
      </item>
      <item>
         <title>Nature of Roots</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795555</link>
         <description><![CDATA[<div>Method</div><ol><li>Use equation : b<sup>2 </sup>- 4ac</li><li>Decide which of the 3 states it fits with thereofre determining the number of real roots</li></ol><div>3 States<br>b<sup>2 </sup>- 4ac &gt; 0 Two real roots<br>b<sup>2 </sup>- 4ac = 0  One real root<br>b<sup>2 </sup>- 4ac &lt; 0 No real roots</div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795555</guid>
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      <item>
         <title>Minimum and Maximum Values</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795557</link>
         <description><![CDATA[<div>Method<br>Express in form a(x+b)<sup>2 </sup>+c  (complete the square)<br>C= minimum/maximum value<br>b x -1 = x when it occurs<br><br>Key Information<br>-x<sup>2 </sup>graphs have maximum values<br>x<sup>2 </sup>graphs have minimum values<sup><br></sup><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795557</guid>
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      <item>
         <title>Quadratic Formula</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795559</link>
         <description><![CDATA[<div>Method</div><ol><li>Rearrange into ax<sup>2</sup> + bx + c</li><li>Use formula :</li></ol>]]></description>
         <enclosure url="https://padletuploads.blob.core.windows.net/prod/251754298/d14fdc50fff8a6f118f216d26ee9280e/media.jpeg" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795559</guid>
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      <item>
         <title>Complete the square</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795560</link>
         <description><![CDATA[<div>Method</div><ol><li>Rearrange the quadratic into format ax<sup>2</sup> + bx + c = 0</li><li>Use the formula :</li></ol>]]></description>
         <enclosure url="https://padletuploads.blob.core.windows.net/prod/251754298/2fa10541d35beb4f09b6f59f41af6b53/media.jpeg" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795560</guid>
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      <item>
         <title>Factorising Quadratic Equations</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795561</link>
         <description><![CDATA[<div>Method</div><ol><li>Put into form ax<sup>2</sup> + bx + c</li><li>a x c = ?</li><li>Find factors of ?</li><li>Choose factors that add/subtract to make b</li><li>Rewrite equations with factors as b</li><li>Factorise a + 1/2b and 1/2b + c</li><li>Write repeated brackets and outer terms in brackets</li></ol>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795561</guid>
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      <item>
         <title>Solving Equations</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795563</link>
         <description><![CDATA[<div>Method</div><ol><li>Express in the form a(x+b)<sup>2 </sup>+c  (complete the square)</li><li>Rearrange to find x</li></ol>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795563</guid>
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      <item>
         <title>Specification</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795565</link>
         <description><![CDATA[]]></description>
         <enclosure url="http://www.wjec.co.uk/qualifications/mathematics/mathematics-gce-a-as/wjec-gce-maths-spec-from-2017-eng.pdf?language_id=1" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795565</guid>
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      <item>
         <title>Factorising Polynomials</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795567</link>
         <description><![CDATA[<div>Method</div><ol><li>Divide highest power of x by highest power of x in divisor</li><li>Multiply back ‘new’ element in top by divisor and write underneath</li><li>Subtract two lines</li><li>Repeat process until you are left with a single number</li></ol>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795567</guid>
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      <item>
         <title>Cast Diagrams</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795568</link>
         <description><![CDATA[<div>Method</div><ol><li>Rearrange into form sin θ </li><li>Find the angle</li><li>Choose quadrants where solutions exist, draw them in</li><li>Measure, anticlockwise, the angle from the x axis to each line</li><li>These are the solutions</li></ol>]]></description>
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         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795568</guid>
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         <title>Angle of a triangle</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795570</link>
         <description><![CDATA[<div>1/2 absinC</div>]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795570</guid>
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      <item>
         <title>Algebraic Division</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795572</link>
         <description><![CDATA[<div><mark>Roots of an equation</mark></div><ul><li>The root of an equation is where the curve crosses the x axis</li></ul><div><mark>Factor Theorem</mark></div><ul><li>A polynomial f(x) has factor (x-a) if and not if f(a)=0</li><li>If (x-a) is a factor, x=a is a root of the equation f(x)</li></ul><div><mark>Remainder Theorem</mark></div><ul><li>When a polynomial f(x) is divided by (ax-b) the remainder is f(b/a)</li><li>You replace x in your original equation with b/a and then calculate the appropriate value.</li></ul>]]></description>
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         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795572</guid>
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         <title>Cosine Rule</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795574</link>
         <description><![CDATA[<div>Useful when we have all 3 sides and are finding a missing angle OR when we have 2 sides and an enclosed angle and are aiming to find the third side.</div>]]></description>
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         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795574</guid>
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      <item>
         <title>Sine Rule</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795576</link>
         <description><![CDATA[<div>Useful when we have an angle and an opposite side and are given another side/angle</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/251754298/2ae7b7a73174e61f8f64c9d32eb9a0e4/media.jpeg" />
         <pubDate>2019-01-30 12:12:39 UTC</pubDate>
         <guid>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795576</guid>
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         <title>Trigonometry Graphs</title>
         <author>hol_cjones</author>
         <link>https://padlet.com/hol_cjones/u3oawgvlcje4/wish/325795577</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2019-01-30 12:12:40 UTC</pubDate>
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