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      <title>Repaso de áreas y perímetros by </title>
      <link>https://padlet.com/florgarro/u1vt4meq2c7304jw</link>
      <description></description>
      <language>en-us</language>
      <pubDate>2022-12-14 01:54:50 UTC</pubDate>
      <lastBuildDate>2022-12-14 14:36:42 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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      <item>
         <title>Resuelve el siguiente reto, recuerda explicar como resolviste el reto y muestra su procedimiento </title>
         <author>florgarro</author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2419981622</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-12-14 01:57:46 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2419981622</guid>
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      <item>
         <title>Halla el perímetro de la siguiente figura, recuerda explicar el procedimiento de como lo realizaste.</title>
         <author>florgarro</author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2419991663</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-12-14 02:08:39 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2419991663</guid>
      </item>
      <item>
         <title>Paula</title>
         <author>78118240</author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420592995</link>
         <description><![CDATA[<div>&nbsp;Reto 1&nbsp; 6+6+4+4 igual 20<br>Rpta&nbsp; el perimetro es 20 cm <br><br>Reto 2 &nbsp; 14 +0 igual 14&nbsp;<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Rpta &nbsp; Su area es 14 de la figura <br><br></div>]]></description>
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         <pubDate>2022-12-14 14:09:49 UTC</pubDate>
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      <item>
         <title>ISABELLA</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593112</link>
         <description><![CDATA[<div>Perímetro:<br>6x2=12 +&nbsp;RPTA: El perimetro del rectangulo es 20 cm.<br>4x2= 8<br>&nbsp; &nbsp; &nbsp; &nbsp; ----<br>&nbsp; &nbsp; &nbsp; &nbsp; 20<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;</div>]]></description>
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         <pubDate>2022-12-14 14:09:55 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593112</guid>
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      <item>
         <title>ROBBIE</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593149</link>
         <description><![CDATA[<div>rpta 1 es 20 el perimetro porque 6+6+4+4=20 cm es el total</div>]]></description>
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         <pubDate>2022-12-14 14:09:57 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593149</guid>
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      <item>
         <title>Fernanda</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593202</link>
         <description><![CDATA[<div>Perímetro= 6+4+6+4=20 cm<br><br>Área=5+5+3+1=14 u<sup>2<br>(Los dos triángulos hacen 1)</sup></div>]]></description>
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         <pubDate>2022-12-14 14:09:59 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593202</guid>
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      <item>
         <title>Anjhely </title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593213</link>
         <description><![CDATA[<div>1&nbsp;<br>6 + 6 + 4 + 4 = 20<br>Rpta= El perimetro del rectángulo es 20 cm.<br><br>2<br>3 + 0.5 [ triangulo] + 0.5 = 4<br>4 + 5 + 5 = 14<br>Rpta= El área de la figura es 14 unidades cuadradas.</div>]]></description>
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         <pubDate>2022-12-14 14:10:00 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593213</guid>
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      <item>
         <title>Michelle</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593217</link>
         <description><![CDATA[<div>PERIMETRO :<br>6 x 2 = 12&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;12 + 8 = 20<br>4 x 2 =&nbsp; 8<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; RPTA : El perímetro es 20.<br><br>Área :&nbsp;<br>como hay dos triángulos equivalen&nbsp; a un cuadrado.<br>5+5+3+1= 14  <br><br></div>]]></description>
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         <pubDate>2022-12-14 14:10:00 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593217</guid>
      </item>
      <item>
         <title>katia</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593364</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2022-12-14 14:10:07 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593364</guid>
      </item>
      <item>
         <title>matthaus</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593491</link>
         <description><![CDATA[<div>6 mas 4 mas 6 mas 4 igual a 20 cm RPTA el perimetro del rectangulo&nbsp; es 20cm&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;<br><br>2 RPTA el area del cuadrilatero es 14 unidades cuadradas&nbsp;<br><br><br>termine<br><br></div>]]></description>
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         <pubDate>2022-12-14 14:10:11 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593491</guid>
      </item>
      <item>
         <title>joao</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593564</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-12-14 14:10:14 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593564</guid>
      </item>
      <item>
         <title>Uriel</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593586</link>
         <description><![CDATA[<div>1._ 6 más 6 del otro lado de abajo y más 4 del lado de la derecha que era el mismo lado de la izquierda nos daría 20</div><div><br><br>2._ ay 2 triángulos que formaría una unidad cuadrada y hay 13 cuadrados así que 13 unidades cuadradas más una unidad cuadrada de los triángulos es igual a 14 <br><br><br><br><br></div>]]></description>
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         <pubDate>2022-12-14 14:10:15 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593586</guid>
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      <item>
         <title>Samir Mathias Argandoña Portilla.</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593648</link>
         <description><![CDATA[<div>Reto1&nbsp;<br>4x2=8&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 12+<br>6x2=12&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 8<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; ---<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 20&nbsp; &nbsp; &nbsp;rpta: el perimetro total&nbsp; es&nbsp; 20.<br><br><br>reto2<br><br>area: 14   rpta: el area del trapecio es 14 unidades cuadradas.<br><br></div>]]></description>
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         <pubDate>2022-12-14 14:10:17 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593648</guid>
      </item>
      <item>
         <title>Xiomara</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593724</link>
         <description><![CDATA[<div>6+6+4+4=20<br><br>Rpta: El perímetro de la figura es 20 cm</div>]]></description>
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         <pubDate>2022-12-14 14:10:20 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593724</guid>
      </item>
      <item>
         <title>mikkel</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593783</link>
         <description><![CDATA[<div>perimetro:<br>P=6cm + 6cm + 4cm +4cm<br>P=20cm<br>RPTA:el perimetro es igual a 20cm.<br><br>area:<br>A=5+5+3+0.5+0.5<br>A=14</div>]]></description>
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         <pubDate>2022-12-14 14:10:23 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593783</guid>
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      <item>
         <title>Mathiassd</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593878</link>
         <description><![CDATA[<div>1<br>12+<br>&nbsp; 8<br>----<br>20<br>Rpta: El perímetro del rectángulo es en total 20 cm.</div>]]></description>
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         <pubDate>2022-12-14 14:10:27 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593878</guid>
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      <item>
         <title>6+6=12    4+4=8      12+8=20    RPTA: SU PERIMETRO ES DE 20 CM EN TOTAL        2: A 14 RPTA: EL AREA ES DE 14 CM</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593987</link>
         <description><![CDATA[<div>LUCIANA</div>]]></description>
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         <pubDate>2022-12-14 14:10:31 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420593987</guid>
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      <item>
         <title>Ariana </title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420594155</link>
         <description><![CDATA[<div>6+6+4+4=20<br>El perime tro de la figura es 20 cm.<br>2:el area es 14.<br>5+5=10+3+1/2+1/2=14</div>]]></description>
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         <pubDate>2022-12-14 14:10:37 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420594155</guid>
      </item>
      <item>
         <title>Mateo</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420594452</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2022-12-14 14:10:50 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420594452</guid>
      </item>
      <item>
         <title>jukari</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420594572</link>
         <description><![CDATA[<div>6+6+4+4= 20<br><br><br>2<br>area&nbsp; en el rectangulo hay dos triangulos&nbsp; y si lo juntamos seria un cuadrado entonces<br>4+4+6+1=20<br><br><br><br></div>]]></description>
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         <pubDate>2022-12-14 14:10:55 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420594572</guid>
      </item>
      <item>
         <title>Thiago</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420596198</link>
         <description><![CDATA[<div>&nbsp;Reto 1&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 6+6+4+4=20.&nbsp; Rpta:El perimotro de la figura morada es 20cm&nbsp; &nbsp;Reto 2&nbsp; rpta: el area total es 14 de la figura verde&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;</div>]]></description>
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         <pubDate>2022-12-14 14:12:08 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420596198</guid>
      </item>
      <item>
         <title>AITOR</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420597127</link>
         <description><![CDATA[<div>1-.6+4+6+4=20cm<br>2-.a=14<br>rpta: el perimetro es 20cm<br>rpta:el area es de 14cm</div>]]></description>
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         <pubDate>2022-12-14 14:12:48 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420597127</guid>
      </item>
      <item>
         <title>Renzo</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420598427</link>
         <description><![CDATA[<div>RPTA:en el perímetro del rectángulo es 20 cm<br>6+6+4+4<br>RPtA.<br>5+5+3+1<br>2 triangulos son 1 cuadrado<br>area:14&nbsp;</div>]]></description>
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         <pubDate>2022-12-14 14:13:46 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420598427</guid>
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      <item>
         <title>Mathias</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420601548</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-12-14 14:16:01 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420601548</guid>
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      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420606423</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-12-14 14:19:27 UTC</pubDate>
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      <item>
         <title>joao</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420614298</link>
         <description><![CDATA[<div>rpta:<br>el perimetro de la figura es 20 cm</div>]]></description>
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         <pubDate>2022-12-14 14:24:55 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420614298</guid>
      </item>
      <item>
         <title>joao</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420616681</link>
         <description><![CDATA[<div>el area de la figura es 14</div>]]></description>
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         <pubDate>2022-12-14 14:26:21 UTC</pubDate>
         <guid>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420616681</guid>
      </item>
      <item>
         <title>Xiomara</title>
         <author></author>
         <link>https://padlet.com/florgarro/u1vt4meq2c7304jw/wish/2420621602</link>
         <description><![CDATA[<div>reto 2<br>rpta : EL AREA DE LA FIGURA ES 14 PORQUE HAY 2TRIANGULOS Y 13 CUADRADOS<br><br><br></div>]]></description>
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         <pubDate>2022-12-14 14:29:44 UTC</pubDate>
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         <title></title>
         <author></author>
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         <pubDate>2022-12-14 14:30:22 UTC</pubDate>
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