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      <title>Electricity by maria B</title>
      <link>https://padlet.com/barromar020/szmbe42ut0e0</link>
      <description>Made with an open mind</description>
      <language>en-us</language>
      <pubDate>2018-05-07 13:30:06 UTC</pubDate>
      <lastBuildDate>2018-05-10 13:31:17 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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         <url></url>
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      <item>
         <title>1. </title>
         <author>barromar020</author>
         <link>https://padlet.com/barromar020/szmbe42ut0e0/wish/259257386</link>
         <description><![CDATA[<div>Two electric charges with the opposite sign attract (magnets)&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-05-09 13:08:10 UTC</pubDate>
         <guid>https://padlet.com/barromar020/szmbe42ut0e0/wish/259257386</guid>
      </item>
      <item>
         <title>2.</title>
         <author>barromar020</author>
         <link>https://padlet.com/barromar020/szmbe42ut0e0/wish/259257870</link>
         <description><![CDATA[<div>The SI unit for the elcetric charge is the columb </div>]]></description>
         <enclosure url="" />
         <pubDate>2018-05-09 13:09:22 UTC</pubDate>
         <guid>https://padlet.com/barromar020/szmbe42ut0e0/wish/259257870</guid>
      </item>
      <item>
         <title>3.</title>
         <author>barromar020</author>
         <link>https://padlet.com/barromar020/szmbe42ut0e0/wish/259258219</link>
         <description><![CDATA[<div>An important difference between gravitational and electric force is that gravitatioal force will always be  9.81 ( its optional if you want to make it negative, your choice)</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-05-09 13:10:09 UTC</pubDate>
         <guid>https://padlet.com/barromar020/szmbe42ut0e0/wish/259258219</guid>
      </item>
      <item>
         <title>4.</title>
         <author>barromar020</author>
         <link>https://padlet.com/barromar020/szmbe42ut0e0/wish/259259290</link>
         <description><![CDATA[<div>The electric force between two charged spheres is 32N, what will be the magnitude of the force if the size of each charge is is doubled and the distance between them is doubled?&nbsp;<br>F= Kq1q2/d^2<br><br>If each of the charges is doubled the complete answer will be quadrupled&nbsp;<br>If the distance between them is doubled the answer will decrease by four<br>so at the end the answer will remain the same.<br>ex.<br>K= 8.99*10^9<br>F= K(.002)(.002)/4^2 = 2247.5N<br>F= K(.004)(.004)/8^2 =2247.5N<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2018-05-09 13:12:52 UTC</pubDate>
         <guid>https://padlet.com/barromar020/szmbe42ut0e0/wish/259259290</guid>
      </item>
      <item>
         <title>5.</title>
         <author>barromar020</author>
         <link>https://padlet.com/barromar020/szmbe42ut0e0/wish/259269307</link>
         <description><![CDATA[<div>A negative charge of 1E-8 C and a negative charge of 1E-8 C are0.024m apart, what is the attractive force between the particles? <br><br>F=K(1*10^-8) (1*10^-8)/0.024^2 F= 0.0015</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-05-09 13:33:31 UTC</pubDate>
         <guid>https://padlet.com/barromar020/szmbe42ut0e0/wish/259269307</guid>
      </item>
      <item>
         <title>6. </title>
         <author>barromar020</author>
         <link>https://padlet.com/barromar020/szmbe42ut0e0/wish/259272045</link>
         <description><![CDATA[<div>55= K(1.5*10^-6)q2/0.040^2 <br>55=13485q2/0.0016&nbsp; <br>55*0.0016=0.088<br>0.088/13485=q2<br>q2=0.000006526=<mark>6.5*10^-6</mark></div>]]></description>
         <enclosure url="" />
         <pubDate>2018-05-09 13:39:07 UTC</pubDate>
         <guid>https://padlet.com/barromar020/szmbe42ut0e0/wish/259272045</guid>
      </item>
      <item>
         <title>7.</title>
         <author>barromar020</author>
         <link>https://padlet.com/barromar020/szmbe42ut0e0/wish/259278141</link>
         <description><![CDATA[<div>A lamp is connected to a battery of 400V and the current that flows through the circuit is 4A the resistance of the lamp is? <br>R=V/I <br>R=400V/$ <br>R=100</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-05-09 13:52:11 UTC</pubDate>
         <guid>https://padlet.com/barromar020/szmbe42ut0e0/wish/259278141</guid>
      </item>
      <item>
         <title>8.</title>
         <author>barromar020</author>
         <link>https://padlet.com/barromar020/szmbe42ut0e0/wish/259280085</link>
         <description><![CDATA[<div>I=V/R<br>V=I*R<br>V= 4*10&nbsp;<br>V= 40V</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-05-09 13:55:44 UTC</pubDate>
         <guid>https://padlet.com/barromar020/szmbe42ut0e0/wish/259280085</guid>
      </item>
      <item>
         <title>9. </title>
         <author>barromar020</author>
         <link>https://padlet.com/barromar020/szmbe42ut0e0/wish/259294772</link>
         <description><![CDATA[<div>Parallel circuit  </div>]]></description>
         <enclosure url="" />
         <pubDate>2018-05-09 14:22:55 UTC</pubDate>
         <guid>https://padlet.com/barromar020/szmbe42ut0e0/wish/259294772</guid>
      </item>
      <item>
         <title>10.</title>
         <author>barromar020</author>
         <link>https://padlet.com/barromar020/szmbe42ut0e0/wish/259295672</link>
         <description><![CDATA[<div>Rt=1/R1+1R2+1/R3<br>1/23+1/23+1/23=3/23 <br>Get the reciprocal: <br>23/3=7.67 R</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-05-09 14:24:21 UTC</pubDate>
         <guid>https://padlet.com/barromar020/szmbe42ut0e0/wish/259295672</guid>
      </item>
      <item>
         <title>11.</title>
         <author>barromar020</author>
         <link>https://padlet.com/barromar020/szmbe42ut0e0/wish/259598989</link>
         <description><![CDATA[<div>Rt=R1+R4+R23<br>RT=20+20+20=60R</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-05-10 13:13:27 UTC</pubDate>
         <guid>https://padlet.com/barromar020/szmbe42ut0e0/wish/259598989</guid>
      </item>
      <item>
         <title>12.</title>
         <author>barromar020</author>
         <link>https://padlet.com/barromar020/szmbe42ut0e0/wish/259599686</link>
         <description><![CDATA[<div>I=V/R <br>I=10V/20<br>I=O.5A<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2018-05-10 13:15:09 UTC</pubDate>
         <guid>https://padlet.com/barromar020/szmbe42ut0e0/wish/259599686</guid>
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