https://padlet.com/uob/s02416c8h7wk5q0tbs2g Ask questions here anonymously. Most-liked questions will be answered in Q&A session on Wednesday en-us 2026-09-29 11:00:05 UTC 2026-09-29 12:45:23 UTC hello@padlet.com https://padlet.com/uob/s02416c8h7wk5q0tbs2g/wish/4074618429 Is (A ∧ B) ∨ (C_in ∧ (A ∨ B)) => (A ∧ B) ∨ (C_in ∧ (A ⊕ B)) only for Full Adder Formula? Or we can think about this formula for all other situation?

]]> 2026-09-29 12:05:00 UTC https://padlet.com/uob/s02416c8h7wk5q0tbs2g/wish/4074618429 https://padlet.com/uob/s02416c8h7wk5q0tbs2g/wish/4074623084 The formula says we need log2(N) select bits to choose between N inputs — so the number of select bits depends on how many options we want. But the ALU's control bits (zx, nx, zy, ny, f, no) seem to be a fixed set of 6 bits. Why doesn't the ALU just use log2(N) select bits like a mux does?

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