P4 Warm Up by Thitiya Karamooz [Escobedo MS]

10/13 - Write an inequality of the question below.

pathatn — 2020-10-13 19:19:05 UTC

The Desert Taxi Cab Company charges a $1.75 flat rate in addition to $0.65 per mile. Jaelyn has no more than $10 to spend on the ride. How many miles can Jaelyn go without exceeding her amount of money?

Special symbols (M2)

pathatn — 2020-10-13 20:27:43 UTC

You can copy the below symbols to use in your Warm Up.

≤ ≥  ≮ ≯ ≠ ÷ √ ≈ ½ ∛ ∞

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zayleigh thompson

zayleigh_342470 — 2020-10-13 20:30:26 UTC

10-1.75 divide 0.65

Isabella Garcia

isabella_359019 — 2020-10-13 20:30:45 UTC

$1.75 + $0.65x ≤ 10

Claire Heywood

2020-10-13 20:30:46 UTC

1.75+0.65x ≤10

Wells, Melony $1.75+$0.65x≤$10

2020-10-13 20:30:47 UTC

ava clark

2020-10-13 20:31:22 UTC

 $1.75+$0.65x≤10

Ashleigh Cowsill

2020-10-13 20:31:31 UTC

1.75+0.65X≤10

sophia indaburu

sophia_399146 — 2020-10-13 20:31:44 UTC

$1.75+$0.65x≤$10

Adrianna Guevara

2020-10-13 20:31:58 UTC

ayleen kotis

2020-10-13 20:32:09 UTC

1.75+0.65x ≤10

2020-10-13 20:32:48 UTC

Wells, Melony - 10-÷0.65

margaret breaz

margaret_359734 — 2020-10-13 20:33:06 UTC

1.75 + 0.65x ≤ 10

jaimee stephenson

2020-10-13 20:33:16 UTC

1.75+.65x ≤10

lelan navarro

2020-10-13 20:33:16 UTC

1.75 + 0.65x ≤ 10

Alyndria Kelley

2020-10-13 20:33:27 UTC

1.75+.65x <(< underline)10

Abigail Hanoff

2020-10-13 20:33:27 UTC

1.75 + .65x ≤ 10

Kayla Deyro

2020-10-13 20:33:34 UTC

1.75+0.65x ≤ 10

Dillon Wright

2020-10-13 20:34:14 UTC

 $1.75 + $0.65x ≤ $10

Sophia Daher

2020-10-13 20:34:23 UTC

1.75+.65m≤10

Jonah Jankowski

jonah_2067291 — 2020-10-13 20:34:46 UTC

1.75 + 0.65x ≤ 10

Jack Herrera

2020-10-13 20:35:31 UTC

1.75 + 0.65x

Rapheal Moody

2020-10-13 20:35:43 UTC

1.75+0.65x< or = to 10

Leilani Tyler

2020-10-13 20:35:54 UTC

1.75+0.65x ≤10

Aryanna Turfley-Dow

2020-10-13 20:36:09 UTC

1.75 + 0.65x ≤ 10

Jack Herrera

2020-10-13 20:36:19 UTC

0.65x + 1.75 ≥ 10

Ethan Stamps

2020-10-13 20:36:31 UTC

$1.75+$0.65x ≤ $10

Ivan Ramirez

2020-10-13 20:37:49 UTC

0.65x+1.75≥10

mia barlow

2020-10-13 20:38:54 UTC

1.75 + $0.65x ≤ 10

lillian sherwood

2020-10-13 20:44:59 UTC

$1.75 + $0.65x ≤ 10

Jayden Jackson

2020-10-13 20:45:09 UTC

1.75 + 0.65x ≤ 10

Jack Herrera

2020-10-13 20:52:09 UTC

1.75 + 0.65x ≤ 10

10/14 Warm up

pathatn — 2020-10-14 17:39:32 UTC

Write an inequality of the question below.
If 5 times a number is increased by 4, the result is at least 19. Find the least possible number that satisfies theses conditions.

Special symbols (M2)

pathatn — 2020-10-14 20:19:43 UTC

You can copy the below symbols to use in your Warm Up.

≤ ≥  ≮ ≯ ≠ ÷ √ ≈ ½ ∛ ∞

View more characters

Alyndria Kelley

2020-10-14 20:30:31 UTC

5x+4≥19

Jonah Jankowski

jonah_2067291 — 2020-10-14 20:30:41 UTC

5x + 4 ≥19 The least possible number that satisfies these conditions would be 3.

Sophia Daher

2020-10-14 20:30:50 UTC

5x+4≥19 The least possible number you could use is 3.

Leilani Tyler

2020-10-14 20:30:58 UTC

5x +4 ≥19

isabella_359019 — 2020-10-14 20:31:01 UTC

5x+4≥19

sophia_399146 — 2020-10-14 20:31:52 UTC

5x+4 ≥19
The least possible number that satisfies these conditions would be 3.

Abigail Hanoff

2020-10-14 20:32:17 UTC

5x +4 ≥ 19
X=3

Kayla Deyro

2020-10-14 20:32:56 UTC

5x+4 ≥ 19
The least possible number that satisfies these conditions would be 3.

Ivan Ramirez

2020-10-14 20:33:42 UTC

5x+4≥19

Ashleigh Cowsill

2020-10-14 20:33:53 UTC

5x + 4 ≥ 19

Aryanna Turfley-Dow

2020-10-14 20:34:14 UTC

5x+4≥19

Lelan navarro

2020-10-14 20:34:21 UTC

5x + 4 ≥19

margaret_359734 — 2020-10-14 20:34:33 UTC

5x + 4 ≥ 19

Adrianna Guevara

2020-10-14 20:34:36 UTC

5x+4≥19 x=3

anthony jeeves

2020-10-14 20:34:39 UTC

5x+4≥19

zayleigh_342470 — 2020-10-14 20:34:49 UTC

ava clark

2020-10-14 20:34:58 UTC

5x+4 ≥19

Claire Heywood

2020-10-14 20:35:01 UTC

5x+4≥19

Jayden Jackson

2020-10-14 20:35:22 UTC

5x+4 ≥ 19

kyle kono

2020-10-14 20:36:03 UTC

5x+4 19

5x+4≥19

jaimee_2072823 — 2020-10-14 20:36:09 UTC

mia Barlow

2020-10-14 20:37:09 UTC

5x+4≥19
The least possible number that satisfies these conditions would be 3.

Ethan Stamps

2020-10-14 20:37:48 UTC

5x+4≥19__________x≥3

lillian sherwood

2020-10-14 20:37:52 UTC

≥

Dillon Wright

dillon1240965 — 2020-10-14 20:38:18 UTC

Answer: 5x + 4 ≥ 19
The least possible number that satisfies these conditions would be 3.

Jordan Balinski

jordan_2210385 — 2020-10-14 20:39:24 UTC

1.75+.65x≤10

Rapheal Moody

2020-10-14 20:39:58 UTC

5x + 4 > or equal to 10

10/15 Warm up

pathatn — 2020-10-14 22:16:25 UTC

Write an inequality of the question below.

You have just purchased a new cell phone. According to the terms of your agreement, you pay a flat fee of $6 per month, plus $0.04 per minute for calls. If you want your total bill to be no more than $10 for the month, how many minutes can you use?

Special symbols (M2)

pathatn — 2020-10-14 22:16:30 UTC

You can copy the below symbols to use in your Warm Up.

≤ ≥  ≮ ≯ ≠ ÷ √ ≈ ½ ∛ ∞

View more characters

Alyndria Kelley

2020-10-15 20:26:58 UTC

6+0.04x≤10 a:150 or ≤ min

Sophia Daher

2020-10-15 20:28:39 UTC

6+0.04x≤10

Claire Heywood

2020-10-15 20:29:44 UTC

6+0.04X≤10

Abigail Hanoff

2020-10-15 20:29:51 UTC

6+0.04x ≤ 10

ayleen kotis

2020-10-15 20:29:51 UTC

6+0.04x≤10

jonah_2067291 — 2020-10-15 20:30:48 UTC

6 + 0.04j ≤ 10

Mia Barlow

2020-10-15 20:31:37 UTC

6+0.04x≤10

zayleigh thompson

zayleigh_342470 — 2020-10-15 20:31:41 UTC

6+0.04x ≤ 10

sophia_399146 — 2020-10-15 20:31:44 UTC

6+0.04x ≤ 10

Ivan Ramirez

2020-10-15 20:31:50 UTC

6+0.04x≤10

isabella_359019 — 2020-10-15 20:31:55 UTC

6+0.04x≤10

ava clark

2020-10-15 20:32:00 UTC

6 + 0.04x ≤ 10

jayden jackson

2020-10-15 20:32:13 UTC

6+0.04x ≤ 10

Kayla Deyro

2020-10-15 20:32:37 UTC

6+0.04x ≤ 10

Ashleigh Cowsill

2020-10-15 20:32:50 UTC

6 + 0.04x ≤ 10

Leilani Tyler

2020-10-15 20:33:04 UTC

6+0.04 ≤10

lelan navarro

2020-10-15 20:33:19 UTC

6+0.04x≤10

2020-10-15 20:33:24 UTC

6+0.04x≤10

jaimee_2072823 — 2020-10-15 20:33:35 UTC

6+0.04≤10

Aryanna Turfley-Dow

2020-10-15 20:34:28 UTC

6+0.04x≤10

6+0.04x < or = 10

2020-10-15 20:35:01 UTC

Rapheal Moody

jessica knaub

2020-10-15 20:35:20 UTC

1.75+0.65x _<10

Ethan Powell

2020-10-15 20:35:35 UTC

6+0.04x≤10

6 + 0.04 ≤ 10

dillon1240965 — 2020-10-15 20:38:52 UTC

Ethan Stamps

2020-10-15 21:14:24 UTC

6+0.04x≤10

10/19 Warm up

pathatn — 2020-10-19 18:26:32 UTC

Please answer all 5 questions by add the comment below the questions.

1) 1 ≤ z ≤ 10

pathatn — 2020-10-19 18:26:38 UTC

A: (1,10)

B: [1,10]

C: [1,10)

D: (1,10]

2) Write the interval notation.

pathatn — 2020-10-19 18:26:43 UTC

11 < y < 21

3) Write the interval notation.

pathatn — 2020-10-19 18:26:48 UTC

9 ≤ z < 19

4) Type in agree or disagree with the interval below. 3 ≤ x ≤ 12

pathatn — 2020-10-19 18:26:54 UTC

(3,12)

5) Type in agree or disagree with the interval below. 7 < x ≤ 15

pathatn — 2020-10-19 18:27:00 UTC

(7,15]

1.75+0.65x ≤10

margaret_359734 — 2020-10-19 20:35:24 UTC

5x+4≥19

margaret_359734 — 2020-10-19 20:35:59 UTC

6+0.04x≤10

margaret_359734 — 2020-10-19 20:36:29 UTC

10/20 Warm up

pathatn — 2020-10-19 22:28:39 UTC

Please expand the post if needed.

Alyndria Kelley

2020-10-20 20:30:03 UTC

The thing the student got wrong was they did not subtract 3 on the right side
A: X=9 or X=-7

lillian sherwood

2020-10-20 20:32:06 UTC

they did not subtract the -3

ayleen kotis

2020-10-20 20:32:15 UTC

they didnt subtract -3

This person didn't +3 on each side before they started solving the equation.

sophia_2204633 — 2020-10-20 20:33:16 UTC

lx-1l-3=5 first +3 from each side. lx-1l=8 then take your absolute value signs away and make your other equation x-1=8 and x-1=-8 then +1 on each side on both equations x=9 and x=-7

Melony Wells

2020-10-20 20:33:58 UTC

The student didn't subtract the -3

Ava Clark

2020-10-20 20:34:01 UTC

The error is that they did not subtract +3 from both sides to isolate the absolute value.

Claire Heywood

2020-10-20 20:34:18 UTC

The person didn't subtract the -3 before solving the problem.

Kayla Deyro

2020-10-20 20:34:43 UTC

The error is that the student did not add 3 to both sides. To solve the problem correctly, the student should start by adding 3 to both sides and getting x-1=8 and x-1=-8 which would then answer to x=-7 or x=9.

sophia_399146 — 2020-10-20 20:35:49 UTC

The student forgot to subtract 3 on the right side.
the correct answer is
x=9 or x=-7

Dillon Wright

2020-10-20 20:36:00 UTC

The person forgot to subtract -3 from both sides of the equation.

Ashleigh cowsill

2020-10-20 20:36:04 UTC

the student didn't subtract 3 from both sides to isolate the absolute value.

Abiagil Hanoff

2020-10-20 20:36:25 UTC

in the first problem they didn;t subtract -4 from both sides like your supposed to. the second one is correct because the person subtract -4 from both sides.

x= 9

Jayden Jackson

2020-10-20 20:36:27 UTC

The person forgot to subtract 3 from both sides

This person didn't +3 on each side before they started solving the equation.

mia3916201 — 2020-10-20 20:36:43 UTC

lx-1l-3=5 first subtract 3 from each side. lx-1l=8 then take your absolute value signs away and make your other equation x-1=8 and x-1=-8 then +1 on each side on both equations x=9 and x=-7

lelan navarro

2020-10-20 20:37:07 UTC

they forgot to subtract 3 from both sides

isabella_359019 — 2020-10-20 20:37:10 UTC

The student forgot to add 3 from both sides of the equation.

Aryanna Turfley-Dow

2020-10-20 20:37:33 UTC

The student did not subtract 3 from both sides of the equation.

Rapheal Moody

2020-10-20 20:38:13 UTC

What the student didn't do in the equation was subtract 3

adrianna guevara

2020-10-20 20:38:54 UTC

they did not subtract 3 from both sided of the equation.

jaimee_2072823 — 2020-10-20 20:39:01 UTC

the student forgot to subtract 3 from both sides

the student forgot to subtract 3 from both sides.

zayleigh_342470 — 2020-10-20 20:40:05 UTC

James Smith

2020-10-20 20:40:18 UTC

The student did not subtract the 3 from both sides

The person did not add 3 to both sides to isolate the absolute value.

jonah_2067291 — 2020-10-20 20:42:41 UTC

|x-1|-3=5
Add 3 to both sides of the equation
|x-1|=8 or |x-1|=-8
Add 1 to both sides
x=9 or x=-7

10/21 Warm up

pathatn — 2020-10-21 17:21:37 UTC

4Ix-2I = 8x - 4
The student complete solving this equation and get x = -1 and 1 . Check both answers by substitution into the original equation to be sure that the solutions are not extraneous.

Alyndria Kelley

2020-10-21 20:31:06 UTC

4(-1)-2l=8(-1)-4
4l-3l=-8-4
12=-12 (wrong)
x=-1 in incorrect
4l(1)-2l=8(1)-4
4l1-2l=8-4
4=4(right)
x=1 is correct

Kayla Deyro

2020-10-21 20:31:15 UTC

4|(-1)-2|=8(-1)-4
4|-3|=-8-4
12=-12 (answer is false)
x=-1 is incorrect

4|(1)-2|=8(1)-4
4|-1|=8-4
4=4 (answer is true)
x=1 is correct

ayleen kotis

2020-10-21 20:31:24 UTC

-1 is incorrect

Aryanna Turfley-Dow

2020-10-21 20:32:05 UTC

Plug in
4|(-1)-2|=8(-1)-4
4|-3|=-8-4
12=-12 false
x = -1 doesn't work when plugged in

4|(1)-2|=8(1)-4
4|-1|=8-4
4=4 true
x = 1 does work when plugged in

ava clark

2020-10-21 20:32:25 UTC

-1 does not work when plugged in
4|(-1)-2|=8(-1)-4
4|-3|=-8-4
12=-12
x=-1 this does not work

1 does work when plugged in
4|(1)-2|=8(1)-4
4|1-2|=8-4
4|1|=4
4=4
x= 1 this does work

Ashleigh Cowsill

2020-10-21 20:32:36 UTC

-1 does not work, but 1 is correct.

Abigail Hanoff

2020-10-21 20:35:03 UTC

4(-1-2)=8-4
4(-3)=-8-4
-12=-12 (when a positive and a negative combined they make a negative)
x=1 is the correct answer

lillian sherwood

2020-10-21 20:36:07 UTC

1 works, -1 dose not. -1 doesn't have a solution

Adrianna Guevara

2020-10-21 20:36:28 UTC

-1 does not work but 1 does

Claire Heywood

2020-10-21 20:36:41 UTC

4|(-1)-2|=8(-1)-4
4|-3|=8-4
12=-12
-1 Does not work

4|(1)-2|=8(1)-4
4|1-2|=8-4
4|1|=4
4=4
x=1 Is correct

Ivan Ramirez

2020-10-21 20:36:52 UTC

1 works, -1 doesn't work

kyle kono

2020-10-21 20:37:25 UTC

Dillon Wright

2020-10-21 20:38:37 UTC

1 does work, but - 1 is not a correct answer

4Ix-2I = 8x (1) - 4

Jayden Jackson

2020-10-21 20:40:00 UTC

1 does work, but - 1 is not a correct answer

-1 doesn't work but 1 does.

sophia_2204633 — 2020-10-21 20:40:29 UTC

4l(1)-2l=8(1)-4
4-8=8-4
l-4l=4
4=4
4l(-1)-2l=8(-1)-4
-4-8=-8-4
12=-12

1 will work but -1 will not work when plugged into the original equation: 4|x-2|=8x-4

jonah_2067291 — 2020-10-21 20:42:28 UTC

4 |1-2| = 8(1)-4
4 |-1| = 8-4
4=4
x=1
4 |(-1)-2| = 8(-1) - 4
4 |-3| = -8 - 4
12=-12
x=-1

sophia_399146 — 2020-10-21 20:43:27 UTC

-1 is incorrect

4|-1-2|=8(-1)-4
4|-3|=-8-4
12=-12
x=-1 does not work
4|1-2|=8(1)-4
4|1-2|=8-4
4|-1|=4
4=4
x=1 does work

jaimee_2072823 — 2020-10-21 20:43:38 UTC

4|1-2|=8x-4

4 |x-2| = 8x-44 |-1-2| = 8(-1)-44 |-3| =- 8-412 = -12 (the answer is false)x= -1 is incorrect4 |1-2| = 8(1)-44 |-1| = 8-44 = 4x=1 is correct

zayleigh_342470 — 2020-10-21 20:43:56 UTC

4Ix-2I = 8x - 4

ethan_1705709 — 2020-10-21 20:44:26 UTC

4I-1-2I = 8x - 4
-4-8=-8-4

-1 does work

4I1-2I = 8x - 4
4-8=8-4
-1 doesn't work

mia3916201 — 2020-10-21 20:53:18 UTC

4|(-1)-2|=8(-1)-4
4|-3|=-8-4
12=-12 (answer is false)
x=-1 is incorrect

4|(1)-2|=8(1)-4
4|-1|=8-4
4=4 (answer is true)
x=1 is correct

Melony Wells

2020-10-21 20:54:20 UTC

1 works but -1 does not work
4|(-1)-2|=8(-1)-4
4|-3|=-8-4
12=-12 (answer is false)
x=-1 is incorrect

4|(1)-2|=8(1)-4
4|-1|=8-4
4=4 (answer is true)
x=1 is correct

isabella_359019 — 2020-10-21 20:55:08 UTC

4 |x-2| = 8x-4
4 |-1-2| = 8(-1)-4
4 |-3| =- 8-4
12 = -12 (the answer is false)
x= -1 is incorrect

4 |1-2| = 8(1)-4
4 |-1| = 8-4
4 = 4
x=1 is correct

James Smith

2020-10-21 21:05:51 UTC

1 works and -1 does not work

10/26 Warm up

pathatn — 2020-10-26 18:19:00 UTC

3l3x + 2l = 9x
Find the value of x.

3l3x+21=9x

alyndria_297352 — 2020-10-26 20:31:06 UTC

3x+2=3x l 3x+2=-3x
-3x -3x +3x +3x
2=0 2=6x
2 divided by 6x
x=--1/3

Abigail Hanoff

2020-10-26 20:32:47 UTC

3[3x+2] /3=9x/3
[3x+2]-3x=3x-3x
2=0x
3x+2-2=3x-2
3x-3x=3x-3x-2
0x=-2
-2 or 2

sophia_399146 — 2020-10-26 20:33:23 UTC

3x+2=3x | 3x+2=-3x
-3x -3x +3x +3x

2=0 2=6x

3l3x + 2l = 9x

claire24103471 — 2020-10-26 20:35:06 UTC

3x+2=3x 3x+2=-3x
-3x -3x -3x -3x
2=0 2=-6x
2 divided by 6x
No solution

3 |3x + 2| = 9x

jonah_2067291 — 2020-10-26 20:35:08 UTC

3x + 2 = 3x or 3x + 2 = -3x
-3x -3x or -3x -3x
2=0 or 2=-6x
(Divide by -6 on both sides)
No solution -1/3 = x
There are no solutions

ashleigh_369604 — 2020-10-26 20:35:11 UTC

3 I 3x+2 I = 9x
3x+2=3x or 3x + 2= -3x
-3x -3x -3x -3x
2=0x 2= -6x
divide -6x both sides
no solution -1/3=x

isabella_359019 — 2020-10-26 20:35:26 UTC

3x + 2= 3x
-3x -3x
2=0
no solution

3x + 2= -3x
-3x -3x
-6\ 2 = -6x \ -6
-1/3 = x

3|3x+2|=9x

kayla_380174 — 2020-10-26 20:35:48 UTC

3x+2=3x (subtract 3x from both sides)
2=0 (no solution)

or

3x+2=-3x (subtract 2 from both sides)
3x=-3x-2 (add 3x to both sides)
6x=-2 (divide 6 from both sides)

-1/3=x

Answer: No Solution

3|3x+2|=9x

james_372599 — 2020-10-26 20:37:19 UTC

There is no solution

Rapheal Moody

2020-10-26 20:37:26 UTC

3x + 2= 3x 3x+2=-3x
-3x -3x +3x +3x
2=0 2=6

3l3x+21=9x

zayleigh_342470 — 2020-10-26 20:38:29 UTC

adrianna guevara

adrianna_369038 — 2020-10-26 20:40:07 UTC

3|3x+2|=9x
3x+2=3x or 3x+2=-3x
-3x on both sides
2=0 2=-6
no solution

3l3x+2l=9x

sophia_2204633 — 2020-10-26 20:40:15 UTC

3x+2=3x 3x+2=-3x
-3 -3 -2 -2
2=0 3x=-3x-2
6x=-2
6 6
x=-1/3
x=no solution

3|3x+2|=9x

ethan_1705709 — 2020-10-26 20:40:15 UTC

3x+2=3x
-3x -3x
2=0 No solution

3x+2=-3x
-3x -3x
2\-6=-6x\-6
-1\3=x

ava_365235 — 2020-10-26 20:40:42 UTC

3x + 2= 3x or 3x+2=-3x
-3x -3x +3x +3x
2=0 2=6
no solution

3|3x + 2| = 9x

aryanna_139181 — 2020-10-26 20:41:01 UTC

x3x+2=3x
-3x -3x
2=0 or no solution

or

3x +2= -3x
+3x +3x
6x=2
6x/6=2/2
x=-1/3

kyle kono

2020-10-26 20:42:17 UTC

3|3x+2|=9x

anthony_379480 — 2020-10-26 20:42:36 UTC

no solution

2020-10-26 20:43:30 UTC

kyle kono

Jayden Jackson

2020-10-26 20:43:32 UTC

3|3x+2|=9x

3x+2=3x

-3x -3x

2=0 No solution

3x+2=-3x

-3x -3x

2\-6=-6x\-6

dillon1240965 — 2020-10-26 20:44:20 UTC

3x + 2 = 3x | 3x + 2 = -3x
-3x -3x +3x +3x
2=0 2=6x

ivan_360570 — 2020-10-26 20:44:32 UTC

3x+2=3x | 3x+2=-3x
-3x -3x +3x +3x
2=0 2=-6

lelan_369905 — 2020-10-26 20:46:05 UTC

3x+2=3x 3x+2=-3x
-3 -3 -3 -3
2=0 2=-6
x=no solution

3l3x+2l=9

melony_2202099 — 2020-10-26 20:46:13 UTC

This problem does not have a solution.

3|3x+2|=9x

3x+2=3x

-3x -3x

2=0 No solution

3x+2=-3x

-3x -3x

2\-6=-6x\-6

3|3x+2|=9x

mia3916201 — 2020-10-26 21:12:24 UTC

3x+2=3x (subtract 3x from both sides)
2=0 (no solution)

or

3x+2=-3x (subtract 2 from both sides)
3x=-3x-2 (add 3x to both sides)
6x=-2 (divide 6 from both sides)

-1/3=x

Answer: No Solution

10/27 Warm up

pathatn — 2020-10-27 19:23:20 UTC

|x+1|<3
Find the value of x.

Warm up

alyndria_297352 — 2020-10-27 20:30:26 UTC

lx+1l<3
-3-4Answer:-4

Adrianna Guevara

adrianna_369038 — 2020-10-27 20:30:31 UTC

|x+1|<3
-3-1 from all sides
-4

|x+1|<3

kayla_380174 — 2020-10-27 20:31:56 UTC

-3-4Answer: -4

|x+1|<3

claire24103471 — 2020-10-27 20:33:11 UTC

-3-1 -1 -1
-4

l x+1 l<3

sophia_2204633 — 2020-10-27 20:33:25 UTC

-3-1 -1 -1
-4

sophia_399146 — 2020-10-27 20:33:40 UTC

|x+1|<3
x+1-1<3-1 x+1-1>-3-1
x<2 x>-4
Answer: -4

lx+1l<3

ava_365235 — 2020-10-27 20:33:43 UTC

-3-1 -1 -1
-4

|x+1|<3

jonah_2067291 — 2020-10-27 20:33:55 UTC

-3Subtract 1 from all sides
-4

isabella_359019 — 2020-10-27 20:34:17 UTC

|x+1|<3
-3-1 -1 -1
-4

Ix+1 < 3

ashleigh_369604 — 2020-10-27 20:34:23 UTC

-3 < x +1 < 3
-1 -1 -1
-4

Abigail Hanoff

abigail_356736 — 2020-10-27 20:36:08 UTC

[x+1]<3
-3-1-4

Jayden Jackson

2020-10-27 20:36:30 UTC

|x+1|<3

-3

-3
melony_2202099 — 2020-10-27 20:36:32 UTC

-3-4the answer is -4

lx+1l<3

anthony_379480 — 2020-10-27 20:37:51 UTC

-3-1 -1 -1
-4

dillon1240965 — 2020-10-27 20:40:31 UTC

| x + 1 | = 3x
-3 < x -1 < 3

zayleigh_342470 — 2020-10-27 20:40:39 UTC

lx+1l<3
-3-1 -1 -1
-4

Ix + 1I <3

rapheal_380379 — 2020-10-27 20:46:31 UTC

-3

aryanna_139181 — 2020-10-27 21:25:05 UTC

x+1 l<3 -3

|x+1 l<3

aryanna_139181 — 2020-10-27 21:25:23 UTC

-3-1 -1 -1
-4

lelan_369905 — 2020-10-27 21:34:24 UTC

-3-1 -1 -1
-4

mia3916201 — 2020-10-28 01:04:21 UTC

|x+1|<3
-3-1 from all sides
-4

10/28 Warm up

pathatn — 2020-10-28 18:28:07 UTC

|x-4|<3
Find the value of x.

Warm Up

adrianna_369038 — 2020-10-28 20:27:06 UTC

|x-4|<3
-3+4 all sides
1

10/28 warm up

alyndria_297352 — 2020-10-28 20:27:18 UTC

lx-4l<3
-3add 4 all sides
Answer:1

lx-4l<3

sophia_2204633 — 2020-10-28 20:29:51 UTC

-3+4 +4 +4
1

|x-4|<3

jonah_2067291 — 2020-10-28 20:30:10 UTC

-3(add 4 to all sides)
1

|x-4|<3

claire24103471 — 2020-10-28 20:30:54 UTC

-3+4 +4 +4
1

|x-4|<3

isabella_359019 — 2020-10-28 20:31:27 UTC

-3+4 +4 +4
1

|x-4|<3

ayleen_364935 — 2020-10-28 20:31:43 UTC

-3+4 +4 +4
1

|x-4|<3

kayla_380174 — 2020-10-28 20:31:54 UTC

-31>x>7 (add 4 to all sides)
Answer: 1

lx-4l<3

ava_365235 — 2020-10-28 20:32:13 UTC

-3+4 +4 +4
1

|x-4|<3

ivan_360570 — 2020-10-28 20:33:02 UTC

-31

Ix-4I<3

zayleigh_342470 — 2020-10-28 20:33:12 UTC

-3+4 +4 +4
1

lx-4l<3

ashleigh_369604 — 2020-10-28 20:33:52 UTC

-3+4 +4 +4
1

lx-4l<3

abigail_356736 — 2020-10-28 20:33:52 UTC

-3-3+41

|x-4|<3

sophia_399146 — 2020-10-28 20:34:13 UTC

-3+4 +4 +4
1

Ix-4I<3

rapheal_380379 — 2020-10-28 20:35:26 UTC

-3

lx-4l<3

melony_2202099 — 2020-10-28 20:35:52 UTC

-3(add 4 to all sides)
1

lx-4l<3

anthony_379480 — 2020-10-28 20:36:08 UTC

-3+4 +4 +4
1

|

jaimee_2072823 — 2020-10-28 20:36:47 UTC

-3+4 +4 +4
1

Jayden Jackson

2020-10-28 20:40:24 UTC

lx-4l<3
-3
+4 +4 +4
1

margaret_359734 — 2020-10-28 20:40:47 UTC

-3+4 +4 +4
1

raheem389003 — 2020-10-28 20:40:55 UTC

lx-4l<3
-3
+4 +4 +4
1

|x-4|<3

ethan_1705709 — 2020-10-28 20:43:18 UTC

-3<|x-4|<3
+4 +4 +4

1

jaimee_2072823 — 2020-10-28 20:45:12 UTC
lx-4l<3

jaimee_2072823 — 2020-10-28 20:45:13 UTC
lx-4l<3

jaimee_2072823 — 2020-10-28 20:45:13 UTC
lx-4l<3

lelan_369905 — 2020-10-28 21:11:31 UTC

lx-4l<3
-3
+4 +4 +4
1

dillon1240965 — 2020-10-28 21:11:39 UTC

|x-4|<3
-3<|x-4|<3
+4 +4 +4
1

aryanna_139181 — 2020-10-28 23:48:57 UTC

|x-4|<3
-3+4 all sides
1

10/28 Warm up

pathatn — 2020-10-29 17:16:57 UTC

|p + 2| + 4 < 10
Find the value of p.

|p+2|+4<10

jonah_2067291 — 2020-10-29 20:29:22 UTC

-6(subtract 2 from all sides)
-8

|p+2|+4<10

claire24103471 — 2020-10-29 20:30:19 UTC

-6-2 -2 -2
-8

|p+2|+4<10

ivan_360570 — 2020-10-29 20:30:49 UTC

-6-2 from all sides
-8

sophia_399146 — 2020-10-29 20:31:06 UTC

|p+2|+4<10
-6-2 -2 -2
-8

Ip+2I+4<10

zayleigh_342470 — 2020-10-29 20:31:20 UTC

-6-8

|p+2|+4<10

isabella_359019 — 2020-10-29 20:32:00 UTC

-6< p+2 < 6
-2 -2 -2
-8 < p < 4

lp+2l+4<10

ashleigh_369604 — 2020-10-29 20:32:41 UTC

-6-2 from all sides

-8

lp+2l+4<10

alyndria_297352 — 2020-10-29 20:33:39 UTC

-6<

|p+2|+4<10

ava_365235 — 2020-10-29 20:33:51 UTC

-6-2 -2 -2
-8

|p+2|+4<10

margaret_359734 — 2020-10-29 20:34:09 UTC

-6-2 -2 -2
-8

lp+2l+4<10

melony_2202099 — 2020-10-29 20:34:34 UTC

lp+2l+4<10
(-2 both sides)
-8

Ip+2I + 4<10

rapheal_380379 — 2020-10-29 20:34:43 UTC

-6

melony_2202099 — 2020-10-29 20:35:08 UTC
|p+2|+4<10 -6

lp+2l+4<10

sophia_2204633 — 2020-10-29 20:35:45 UTC

-6-2 -2 -2
-8

Ip+2I+4<10

abigail_356736 — 2020-10-29 20:36:00 UTC

[p+2]+4-4<10-4
-6

|p+2|+4<10

kayla_380174 — 2020-10-29 20:37:53 UTC

-6(subtract 2 from all sides)
-8Answer: -8

|p + 2| + 4 < 10

ethan_1705709 — 2020-10-29 20:38:06 UTC

|p + 2| < 6
-6 < |p + 2| < 6
-2 -2 -2
-8 < p < 4

|p+2|+4<10

adrianna_369038 — 2020-10-29 20:40:54 UTC

lp+2l+4<10

jayden813579 — 2020-10-29 20:42:37 UTC

-6
-2 -2 -2
-8

|p+2|+4<10

aryanna_139181 — 2020-10-29 20:55:42 UTC

-6< p+2 < 6
-2 -2 -2
-8 < p < 4

lelan_369905 — 2020-10-29 21:02:22 UTC
-6< p+2 < 6 -2 -2 -2 -8 < p < 4

dillon1240965 — 2020-10-29 21:03:59 UTC

l p + 2 l + 4 < 10
-6 < p + 2 < 6
-2 -2 -2
-8 < p < 4

mia3916201 — 2020-10-31 05:13:49 UTC
In this lesson you will learn: Solve absolute value inequalities in one variable. Graph the solution to an absolute value inequality on a number line. Solve and graph absolute value inequalities in real world contexts.

mia3916201 — 2020-10-31 05:13:49 UTC
In this lesson you will learn: Solve absolute value inequalities in one variable. Graph the solution to an absolute value inequality on a number line. Solve and graph absolute value inequalities in real world contexts.

mia3916201 — 2020-10-31 05:13:49 UTC
In this lesson you will learn: Solve absolute value inequalities in one variable. Graph the solution to an absolute value inequality on a number line. Solve and graph absolute value inequalities in real world contexts.

mia3916201 — 2020-10-31 05:13:50 UTC
In this lesson you will learn: Solve absolute value inequalities in one variable. Graph the solution to an absolute value inequality on a number line. Solve and graph absolute value inequalities in real world contexts.

mia3916201 — 2020-10-31 05:13:50 UTC
In this lesson you will learn: Solve absolute value inequalities in one variable. Graph the solution to an absolute value inequality on a number line. Solve and graph absolute value inequalities in real world contexts.