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      <title>Compare the new central tendencies (MMM) data by Mr. Migdal</title>
      <link>https://padlet.com/arturmigdal/rw136fbxrjs0</link>
      <description>1. Which central tendency, mean, median or mode was most appropriate or 
representative in the original data set? Justify your choice. 


2. Which central tendency was the most representative for the data set that 
contained the additional At Home Activity? 


3. If we only had the data from the At Home Activity, would that be a good 
representation of the data set? Why or why not? 


4. Which measure of central tendency was most changed by the addition of the 
data set from the At Home Activity? Why do you think may be the case? 
</description>
      <language>en-us</language>
      <pubDate>2016-12-13 20:05:35 UTC</pubDate>
      <lastBuildDate>2025-10-02 13:15:35 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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      <item>
         <title>Rachel</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143732152</link>
         <description><![CDATA[<div>1. For <em>Length of my Shoe in cm, </em>the mean is the most appropriate because the outliers are not very far off from the mean. For <em>Distance I can jump from Standing Position in cm</em>, I would use median because the outliers are far off from the mean and median and mode. Median is the middle of all the numbers, so it is the most appropriate. <em>For Circumference of my Head in cm, </em>I would use the mean, because all the numbers are in around the same range. <br>2. For <em>Length of my Shoe in cm, </em>the median is more appropriate because it gives us the middle number of all the data and doesn't take into consideration the outliers. <em>For Distance I can jump from standing position in cm, </em>the median is more appropriate because it is the middle number of all the data, and excludes the outliers. <em>For Circumference of my Head in cm,</em> I would use the mode because the mode is 55, and that makes more sense than the mean and median do for this set of data. <br>3. No, it wouldn't because people at home are older, and have way different athletic ability and can't do as much in comparison to a group of 12-13 year olds who all have around the same athletic ability. <br>4. For <em>Length of my Shoe in cm,</em> the mean was the most changed, because older people/younger people/animals have a different average shoe size. For <em>Distance I can jump from standing position in cm, </em>the mode was the most changed, because older people/younger people/animals jump differently than us and therefore the most common number will change. For <em>Circumference of my Head in cm,</em> the mean was the most changed, because older people/younger people/animals have a different average head size. .</div>]]></description>
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         <pubDate>2016-12-14 20:51:01 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143732152</guid>
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      <item>
         <title>Kaya</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143756904</link>
         <description><![CDATA[<div>1. I would choose mean for the most appropriate for<strong><em>Length of my shoe in cm </em></strong>because the sizes are all pretty close, and there are not any outliers in the data collected. I would choose mode for <strong><em>Distance in jumping </em></strong>because the number that occurs the most often and the viewers would be able to comprehend what the distance of most people's jumps were. I would choose mean for the <strong><em> Circumference of my head  </em></strong>because when collecting all the data I would be able to view the average cirumfrence of my peers heads.<br>2. I think mode is the most appropriate for the three different measurements/calculations because the outliers are excluded from the whole situation and the numbers that occur the most would also contribute a lot to the mean of the data. In my opinion mode would be the most appropriate choice for all the data.<br>3. I would also think that the mode would be a good data set without the school active because when completing the at home activity more peuples are included in the entire spreadsheet and the mode would help find the measurements most occurring throughout.<br>4. The mean changed the most in <strong><em>Length of my shoe and circumference of my head</em></strong> different age groups/genders/species are all different shapes and sizes, so the mean must have a drastic changed with the additional peuples. The mode changed the most in <strong><em>distance of jumping </em></strong>because like stated above the different age groups/genders/species/and sizes all have a different jumping range. The mode will be affected the most because the most occurring number will not be the same as with our age group. </div>]]></description>
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         <pubDate>2016-12-15 01:52:56 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143756904</guid>
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      <item>
         <title>Heather</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143758172</link>
         <description><![CDATA[<div>1. I would choose mean for the LENGTH OF MY SHOE IN CM as the data represented was all very close. I would choose mode for the DISTANCE IN JUMPING as the data that was given varied and the length that people achieved varied due to different circumstances (size,etc...). There were a few outliers which made the mean not as accurate. I would choose mean for the CIRCUMFERENCE O MY HEAD as the data given was all similar enough. There were not as many outliers and while there were a few that is to be expected. The mode was not much far off, so i think either choosing mode or mean would be acceptable.&nbsp;<br>2. I think that mode would be the most acceptable because there were a few outliers and mean would include all the different numbers which can change the best result drastically. I think that mode would be the best because it will exclude all the outliers and give you a more accurate answer.&nbsp;<br>3. No, because we all asked different people of different ages/sizes. The numbers that were put in varied and were not all in one age group. The representation of the AT HOME DATA would be of many different people and would not give people a general idea that is accurate. Whereas, the data we did in class was a good representation because it would be the average of a group of 12-13 year olds and not have as many outliers.&nbsp;<br>4. The mean in LENGTH OF SHOE changed most because we had outliers with a smaller shoe size so it brought down the average. The mode in DISTANCE IN JUMPING because we asked people with different athletic abilities. WE asked people who could be smaller than us and older/younger which meant that the mode would vary. The mean in the CIRCUMFERENCE OF MY HEAD as we had different outliers which changed our overall average. </div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-15 02:18:55 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143758172</guid>
      </item>
      <item>
         <title>Michael Carvalho</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143828254</link>
         <description><![CDATA[<div>1.The median was most appropriate to represent the original data set because it does not contain unnecessary decimals like the mean did.<br>2. The median was the most appropriate to represent the data with the At Home Activity data set because there were too many decimal places that we didn't need in measuring jumps or head measurements. This is not a scientific measurement where it needs to be so many decimal places far.<br>3. No because there would be too many outliers caused by housepet&nbsp; measurements and other age groups.<br>4. The mode of the distance one can jump and the median and mode of the head circumference. Thisis&nbsp; because of the large age range from smaller siblings to parents and grandparents.</div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-15 13:38:10 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143828254</guid>
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      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143828560</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2016-12-15 13:39:17 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143828560</guid>
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         <title>Solange</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143828561</link>
         <description><![CDATA[<div>1.</div>]]></description>
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         <pubDate>2016-12-15 13:39:17 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143828561</guid>
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         <title>Dominic</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143829148</link>
         <description><![CDATA[<div>1. The median was the best central tendency because usually the mean has useless decimals and the mode is for which is number appears the most which aren't looking for.<br>2. The median would because in the data there were decimals and if we tried to find the mean the decimals would keep on growing.<br>3. This would not be a good representation because there are a lot of different measurements.<br>4.The mode for the distance and the median for the circumference of the head because of the age and the different animals.<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-15 13:41:19 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143829148</guid>
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      <item>
         <title>Gillian</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143829342</link>
         <description><![CDATA[<div>&nbsp;</div><ol><li>Which central tendency, mean, median or mode was most appropriate or&nbsp;<br>&nbsp;representative in the original data set? Justify your choice.&nbsp;</li></ol><div>&nbsp;</div><div>&nbsp;Median because mode was just a number that appeared about twice or three times.&nbsp; Average could have been messed up by all he outliers.&nbsp; Therefore median was the most appropriate in the original data set.</div><ol><li>Which central tendency was the most representative for the data set that <br>&nbsp;contained the additional <em>At Home Activity</em>?&nbsp;</li></ol><div>&nbsp;Still median because mode again was just a number that appeared a couple times and was so far from the median and mean.&nbsp; Average again was messed up by outliers but not as much as the in class one.</div><div>&nbsp;</div><ol><li>If we only had the data from the <em>At Home Activity</em>, would that be a good&nbsp;<br> representation of the data set? Why or why not?&nbsp;</li></ol><div>&nbsp;it doesn't really make a difference</div><div>&nbsp;</div><ol><li>Which measure of central tendency was most changed by the addition of the&nbsp;<br>&nbsp;data set from the At Home Activity? Why do you think may be the case?&nbsp;</li></ol>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-15 13:42:00 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143829342</guid>
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      <item>
         <title>Danielle D</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143829404</link>
         <description><![CDATA[<div>1.&nbsp; I think the mean would be a good representation of the data because for the information of the jumps, the average and the median were pretty far off so the median would probably be the best representation.<br><br>2.&nbsp; The mean would probably be the best representation of the at home data because it shows the general idea of the entire data.<br><br>3.&nbsp; The at home data couldn't represent the entire data because there would be many outliers because many people measured their pets.<br><br>4.&nbsp; I think the averages wo<br><br><br></div>]]></description>
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         <pubDate>2016-12-15 13:42:13 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143829404</guid>
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      <item>
         <title>Isabella</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143829898</link>
         <description><![CDATA[<div>1. I think the central tendency witch was most appropriate or representative in the original data set is the median because there were outliers which chould heve changed the mean by a lot.<br><br>2. The central tendency witch was the most representative for the data set hat contained the additional at home activitiy was also the median.<br><br>3.if we only had the data from the at home activitiy that would not be a good representation of the data set because people all are different.<br><br>4. The measure of central tendency was most changed&nbsp;was the mean becaus et of the outliers</div><div><br></div>]]></description>
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         <pubDate>2016-12-15 13:43:51 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143829898</guid>
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      <item>
         <title>Emilia</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143830053</link>
         <description><![CDATA[<div>1. I would choose mean for 'the length of my shoe in cm' because the outliers don't have as big a difference between the numbers. 'For the distance I can jump', I would choose the median because all the numbers were far off from the other central tendencies. 'For the circumference of my head' I would choose the mean as well because all the numbers are about the same, which would give you the average size of the circumference of everybody's head.&nbsp;<br>2. 'For the length of my shoe' and 'distance I can jump' I would choose the median because it gives you about the middle number for the data. ' For the circumference of my head' I would choose the mode because it shows the number that comes up the most.&nbsp;<br>3. I don't think it is a good representation of the data set because the data is collected from many people/ animals of different ages and different abilities. The data set of only the class, everybody is about the same height / athletic ability, therefore the data is about the same for our class, and different for the data collected from home.&nbsp;<br>4. I think the central tendency that changed the most was the&nbsp;length of my shoe because from the data collected from home, everybody is of different sizes and ages, which would make the data different. </div>]]></description>
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         <pubDate>2016-12-15 13:44:18 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143830053</guid>
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      <item>
         <title>Haily</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143830888</link>
         <description><![CDATA[<div>1. In my opinion I think that the median would be the right one to<br>Chose because there would be so many outliers if it was mean<br>2.i think that for this data it would also be the median because the median shows the number that is in the middle from all the data collected&nbsp;<br>3.no because there were so many outliers in there too. Alot&nbsp; measured their cats or dogs and that can make the data lower or higher.<br>4. I think it was the mean because the mean can actually change if there was either a very small or a very big number.</div>]]></description>
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         <pubDate>2016-12-15 13:47:21 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143830888</guid>
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      <item>
         <title>Arjun</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143831039</link>
         <description><![CDATA[<div>1. I believe that the central tendency that is the most appropriate for this situation is median because this central tendency is not affected by the outliers of the data because the outliers are ordered to both ends of the data set and when calculating and they will cancel each other out when coming to the median and if they do not the median ill not be drastically affected.<br><br>2. I believe that the median is still the most accurate representation of the data because it is not massively affected by the outliers in the data.<br><br>3. If we only had the at home data I do believe it would not be an accurate representation because of the data given the fact theta the majority of the data is from a targeted group of adults meaning the data is pretty biased.<br><br>4. The message that was&nbsp;most changed was the mean because of the fact the new outliers drastically affected the mean&nbsp;</div>]]></description>
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         <pubDate>2016-12-15 13:47:47 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143831039</guid>
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      <item>
         <title>Natalia</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143832335</link>
         <description><![CDATA[<div>1. In my opinion the appropriate central tendency is the median because the outliers don't make a big difference so it wouldn't affect the median.&nbsp;<br>2. I would still say the median because the outliers don't affect the median as much.&nbsp;<br>&nbsp;3.&nbsp; No, because no one has the same shoe size or the same distance in jumping or the circumference so that will not be the appropriate central tendency. &nbsp;<br>4. </div>]]></description>
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         <pubDate>2016-12-15 13:52:23 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143832335</guid>
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      <item>
         <title>Alexa</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143832521</link>
         <description><![CDATA[<div>1. The median because the outliers don't make a big difference unlike the outliers that mad the average(mean) or the mode.<br>2. I would say the median again.<br>3. No because everyone has different sizes of shoes, distance they can jump, and circumference of their head. Some people also measured their pets and little siblings, that created a few outliers.<br>4. The mean because the outliers changed the average for at home activity quite a lot, so the average for both activities changed.</div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-15 13:52:57 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143832521</guid>
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      <item>
         <title>irene</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143832882</link>
         <description><![CDATA[<div>1)- I think the median is the most effective representation as among all the sizes it states the total average which sums it all up pretty well.The mode is also correct, but it gives just the most frequent number without counting all the other different sizes. nonetheless, the mode still is a good viable option to use, and I think that both the median and the mode are good central tendencies.<br><br>2)-the median is a good central tendency as the numbers given are simple and exact, and includes all the sizes given instead of picking just a chosen few.&nbsp;<br><br>4)- the mode in the jumping distance between the 2 data sets has changed the most as the first data set has a mode of 176 while the At Home Activity has a mode of 103. I think this is because in the first data set all the distances are from 12-13 year olds, thus causing a higher mode. Whereas in the At Home Activity the distances includes ones from much older people who can't jump as high, thus causing a lower mode. </div>]]></description>
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         <pubDate>2016-12-15 13:54:17 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143832882</guid>
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      <item>
         <title>Emily</title>
         <author>074538075</author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143833650</link>
         <description><![CDATA[<div>1. In my opinion the central tendency that was most appropriate or representative in the original data was the median because unlike the mean, it did not contain unnecessary decimals. Also, the mean (average) could be messed up by all the outliers.&nbsp;<br>2. I still think that the median is the most effective central tendency because the mean has useless numbers, and the mode isn't effective because it is just the number that occurs the most.&nbsp;<br>3. No, I don't think that would be a good representation of the data set because there were people of all ages being measured and people also measured their pets. Therefore, there would be a lot of outliers.&nbsp;<br>4. The mesure of the central tendency that was most changed by the addition of the data set from the At Home Activity is the mode because </div>]]></description>
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         <pubDate>2016-12-15 13:57:06 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143833650</guid>
      </item>
      <item>
         <title>Solange</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143835807</link>
         <description><![CDATA[<div>1. I think that the appropriate central tendency is the median because the median would not be that affected by the outliers.</div>]]></description>
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         <pubDate>2016-12-15 14:04:24 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/143835807</guid>
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      <item>
         <title>Danielle D</title>
         <author></author>
         <link>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/144308019</link>
         <description><![CDATA[<div>4.&nbsp; I think the average was most affected by the addition of the data set from the At Home Activity because&nbsp;there were many outliers because some people measured pets.</div>]]></description>
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         <pubDate>2016-12-19 14:08:31 UTC</pubDate>
         <guid>https://padlet.com/arturmigdal/rw136fbxrjs0/wish/144308019</guid>
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