1. #include <stdio.h>

int main() {

    int x = 5;

    x++; 

    printf("x = %d\n", x); 

    return 0;

}

Output:

Explaination:

2. #include <stdio.h>

int main() {

    int a = 5, b = 3, result;

    result = a++ + --b; 

    printf("a = %d, b = %d, result = %d\n", a, b, result);

    return 0;

}

Output:

 Explaination:

6

In this code first we initialize x and assign value 5 after this we have post increment operator so the value increase by 1 and the output it generates will be 6

Output 2

7

Initialize both a and b and assign them values a=5 and b=7 so now the result we need is to add both values but before that there as post increment operator with a which increments 1 in a and it becomes 6 and we have pre decrement with b so the value becomes 2

due to post increment we use the value of a before increment and due to pre decrement we use the value after the decrement so the result will be 7 as 5+2=7

x=6

Explanation: in this program post increment operator is used so the initialized value of x ( which is 5) will get increment by 1 and gets print .Here x++ was a stand alone statement so it was first assigned and then incremented because of post increment operator

Output 2:

a=6,b=2, result=7

Explanation: here a will be used as 5 and then becomes 6 because a++ is a post increment operator and b will be used as 2 as --b is a pre increment operator so 5+2=7 would be the results but because of post increment a will be printed as 6 in the output.

In this program, x is declared and initialized by the value of 5.

Increment operator is used as x++

Which means that the value wil be incremented by 1.

Then, printf statement is used to print the value of x on screen.

So the output will be :-

X=6

Output of second program :-

In this program, a is declared and initialized by the value of 5. Similarly, b is declared and initialized by the value of 3.

Then, result is initialized by a++ + - - b which means that the value of a is incremented by 1 and becomes 6in the memory but 5 will be assign to result as increment operator is used after a. b will be decremented by 1 and becomes 2. So the vaule as a whole that will be assigned to result is 7 as result = 5+ 2

Then, the printf statement is used to print the output on screen. As \n is used so each will be printed on seperate line.

The output will be:-

a=6

b=2

result= 7

.

6

Explanation :

In this program, we have initialized the variable x and assigned a value 5 to it. After this, we have used post increment operator i.e. the variable will be assigned and then incremented by 1. Then, we have used the print function to print the output.

Output 2 :

a=6,b=2, result=7

Explanation :

In this program, first we have initialized the variables a, b and result and assigned the values 5,3 to a and b respectively. Here a post increment operator is used with a and pre decrement operator is used with b. The sum of output of both operators is assigned to result. Thus , the value of a will be assigned first and then incremented and the value of b will be decremented first and then assigned . Hence the output of result will be 7. At last we have used the print function to print the values of a ,b and result.