3RO IGLESIAS by HENRY PAUL BUJAICO CRISPIN

Crsitopher Raul Rios Zamora

e60906602 — 2021-11-23 16:20:08 UTC

sen(a+b)=sena.cosb+cosa.cosb
cos(a+b)=cosa.cosb-sena-senb
tan(a+b)=(tana+tanb)/(1-tana.tanb)

Italo Andre Zamora Lopez

2021-11-23 16:21:10 UTC

sen(a+b)=senA.cosB+cosA.cosB
cos(a+b)=cosA.cosB-senA-senB
tan(a+b)=tana+tanb/1-tana.tanb

Luis Fernando Jacobi Pisfil

e61225366 — 2021-11-23 16:21:34 UTC

cos(2@) = cos^2@ - sen^2@
cos(2@) = 2cos^2@-1
cos(2@) = 1-2sen^2@
tan(2@)= 2tan@ / 1-tan^2@

Fabrizio Victor Barrial Taipe

e61032517 — 2021-11-23 16:21:40 UTC

Cos(2α)=cos2α-sen2α
cos(2α)=2 cos2α-1
cos(2α)=1- 2sen2α
tan(2α)=2tanα/1-tan2α

Maria Canaza Pérez

2021-11-23 16:21:41 UTC

sen2a=sena*cosa
cos2a=cos^2a-sen^2a
tan2a=(2tana)/1-tan^2a

Samira Delgado

e60960869 — 2021-11-23 16:21:43 UTC

1)sen2x=2senx.cox
2)cos2x=cos*2x-seen*2x
3)tan2x=2tanx/1-tan*2x

Nicolas Prado Lizarbe

2021-11-23 16:21:45 UTC

Cos(2a)=cos2a-sen2a
cos(2a)=2 cos2a-1
cos(2a)=1- 2sen2a
tan(2a)=2tana/1-tan2a

Rebeca Cuba Taboada

2021-11-23 16:22:12 UTC

sen2x=2senx cosx
cos2x=cos2x-sen2x
tan2x=2tanx/1-tan2 x
cos2x= 1-2sen2x / cos2x=2cos2x - 1

Paredes Quispe Jesús Ean

e70963208 — 2021-11-23 16:22:16 UTC

sen(α+β)=senα.cosβ+cosα.senβ
sen(α+α)=senα.cosα+cosα.senα
tan(2α)=2tanα/1-tan2α)

DANIELA SANCHEZ

2021-11-23 16:22:31 UTC

sen(A+B)=senA*cosB+cosA*senB
sen(A+A)=senA*cosA+cosA*senA
sen(2A)=2senA*cosA
---------------------------------
cos(2A)= cos2A - sen2A
cos(2A)=2cos2-1
cos(2A)= 1-2sen2A

Lipe Marcelo Mariajesus

e60946503 — 2021-11-23 16:22:52 UTC

sen2x=2senx-cosx
cos2x = cos²x-sen²x
tan2x = 2tanx/1-tan²x

Nardy Ocaris

2021-11-23 16:23:24 UTC

•sen(a+b)=sena.cosb+cosa.senb
•sen(a+a)=sena.cosa+cosa.cosa
•sen(2a)=2sena.cosa
•cos(2a)=cos²a-sen²a
•cos(2a)=2cos²a-1
•cos(2a)=1-sen²a

Mendoza Fátima

e60919922 — 2021-11-23 16:24:41 UTC

sen(2α)=2.senα.cosα
cos(2α)=cos²α-sen²α
tan(2α)=(2tanα)/(1-tan²α)

Enzo Torvisco

e70597912 — 2021-11-23 16:25:33 UTC

senx+y < senx.cosy+cosx.cosy

cosx+y
tanx+y

Camila Varela Maita

2021-11-23 16:26:17 UTC

sen(a+b)=sena.cosb+cosa.senb
cos(a+b)=cosa.cosb-sena.senb
tan(2a)= 2tana/1-tan2a

ALEJANDRO RODRIGUEZ

2021-11-23 16:27:03 UTC

Sen(a+b)=sen(a).cos(b)+sen(b).cos(a)
Cos(a+b)=cos(a).cos(b)-sen(a).sen(b)
Tan(a+b)=[tan(a)+tan(b)]/[1-tan(a).tan(b)]

Luis Angel Huacahausi Gutierrez

2021-11-23 16:32:12 UTC

cos(2β)=cos2β-sen2β
cos(2β)=2cos2β-1
cos(2β)=1-2sen2β
tan(2β)=2tanβ/1-tan2β

Rodrigo Huambachano Sinchi

2021-11-23 16:39:19 UTC

Cos(2a)=cos2a-sen2a
cos(2a)=2 cos2a-1
cos(2a)=1- 2sen2a
tan(2a)=2tana/1-tan2a

Daniel Vilca

2021-11-24 19:46:28 UTC

sen(a+b)=sena.cosb+cosa.senb
sen(a+a)=sena.cosa+cosa.sena
sen(2a)=2sena.cosa
cos(2a)= cos2a - sen2a
cos(2a)=2cos2-1
cos(2a)= 1-sen2a