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      <title>8A1_7/10 by Nhạn Đoàn</title>
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      <pubDate>2025-10-01 00:14:33 UTC</pubDate>
      <lastBuildDate>2025-10-07 04:34:39 UTC</lastBuildDate>
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         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621139504</link>
         <description><![CDATA[<p>B (1,1 × 10^4 kg)</p><p>A (3,84 × 10^5 km)</p><p>C (1,5 × 10^8 km)</p><p>B (5 × 10^-5 m)</p><p>Con đếm số</p>]]></description>
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         <pubDate>2025-10-07 04:23:38 UTC</pubDate>
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         <author>chau039847</author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621140125</link>
         <description><![CDATA[<p>a. B </p><p>b. A</p><p>c. C</p><p>d. B</p><p>=&gt; con đếm số 0 và cộng thêm 1 phần lùi số trong tùy câu</p>]]></description>
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         <pubDate>2025-10-07 04:24:22 UTC</pubDate>
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         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621140135</link>
         <description><![CDATA[<p>11000=1,1*10^4, chọn B</p><p>384000=3,84*10^5, chọn A</p><p>150000000=1,5*10^8, chọn C</p><p>0,00005=5*10^-5, chọn B</p><p>con đếm số 0 </p><p><br/></p>]]></description>
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         <pubDate>2025-10-07 04:24:22 UTC</pubDate>
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         <author></author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621140208</link>
         <description><![CDATA[<p>a, 11k kg = 1,1 x 10^4 kg ra B</p><p>b, 384k km = 3,84  x 10^5km ra A</p><p>c, 150tr km = 1,5 x 10^8km ra C</p><p>d, 0,00005 m = 5 x 10^-5m ra B</p><p>con tính bằng cách đếm số 0</p>]]></description>
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         <pubDate>2025-10-07 04:24:28 UTC</pubDate>
         <guid>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621140208</guid>
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      <item>
         <title></title>
         <author>khoi056296</author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621140483</link>
         <description><![CDATA[<p>a) B. 1,1 × 10⁴ kg<br>11 000 = 1.1 × 10⁴.</p><p>b) A. 3,84 × 10⁵ km<br>384 000 = 3.84 × 10⁵.</p><p>c) C. 1,5 × 10⁸ km<br>150 000 000 = 1.5 × 10⁸.</p><p>d)<strong> </strong>B. 5 × 10⁻⁵ m<br>0,00005 = 5 × 10⁻⁵.</p>]]></description>
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         <pubDate>2025-10-07 04:24:51 UTC</pubDate>
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         <title></title>
         <author>long103687</author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621140548</link>
         <description><![CDATA[<p>1.C</p><p>2.A</p><p>3.A</p><p>4.B</p><p>cách làm đếm số 0</p>]]></description>
         <enclosure url="" />
         <pubDate>2025-10-07 04:24:56 UTC</pubDate>
         <guid>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621140548</guid>
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         <title></title>
         <author>chau103815</author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621140623</link>
         <description><![CDATA[<p>a) B</p><p>b) A </p><p>c) C </p><p>d) B</p><p>làm = cách đếm</p>]]></description>
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         <pubDate>2025-10-07 04:25:01 UTC</pubDate>
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         <title></title>
         <author></author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621140636</link>
         <description><![CDATA[<p>1b 2a 3c 4b</p>]]></description>
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         <pubDate>2025-10-07 04:25:02 UTC</pubDate>
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         <title></title>
         <author>duc039853</author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621140679</link>
         <description><![CDATA[<p>a)</p><p>11000=1.1x10000=1.1x10^4</p><p>Chọn B</p><p>b)</p><p>384000=3.84x100000=3.84x10^5</p><p>Chọn A</p><p>c)</p><p>150000000=1.5x100000000=1.5x10^8</p><p>Chọn C</p><p>d)</p><p>0.00005=5x1/100000=5x10^-5</p><p>Chọn B</p>]]></description>
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         <pubDate>2025-10-07 04:25:06 UTC</pubDate>
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         <title></title>
         <author></author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621140718</link>
         <description><![CDATA[<p>ĐẾM số 0</p><p>1B</p><p>2A</p><p>3C</p><p>4B</p>]]></description>
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         <pubDate>2025-10-07 04:25:09 UTC</pubDate>
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         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621140743</link>
         <description><![CDATA[<p><strong>a)</strong> 11 000<br>→ Dời dấu phẩy qua 4 chữ số để còn 1,1<br>→ =1,1×10^4&nbsp;kg</p><p><strong>b)</strong> 384 000<br>→ Dời dấu phẩy 5 chữ số → 3,84<br>→ =3,84×10^5&nbsp;km</p><p><strong>d)</strong> 0,00005<br>→ Dời dấu phẩy 5 chữ số sang phải để được 5<br>→ =5×10^-5&nbsp;m</p><p><br/></p>]]></description>
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         <pubDate>2025-10-07 04:25:12 UTC</pubDate>
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      <item>
         <title></title>
         <author>thanh058250</author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621140870</link>
         <description><![CDATA[<p>A.b</p><p>B.a</p><p>C.c</p><p>D.b</p><p>A-c con tăng </p><p>D con đếm số 0</p><p>Vnnnn</p>]]></description>
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         <pubDate>2025-10-07 04:25:20 UTC</pubDate>
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         <title></title>
         <author></author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621140963</link>
         <description><![CDATA[<p>a,A : </p><p>b,A</p><p>c,C</p><p>d,B</p>]]></description>
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         <pubDate>2025-10-07 04:25:29 UTC</pubDate>
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         <author></author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621141044</link>
         <description><![CDATA[<p>1. 11 000 = 1,1 × 10^4</p><p>2. 384 000 = 3,84 × 10^5</p><ol start="3"><li><p>150 000 000 = 1,5 × 10^8</p></li><li><p><br/></p><p><br/></p><p>0,00005 = 5 × 10^{-5}</p></li></ol>]]></description>
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         <pubDate>2025-10-07 04:25:35 UTC</pubDate>
         <guid>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621141044</guid>
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      <item>
         <title></title>
         <author>thang041973</author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621141272</link>
         <description><![CDATA[<ol><li><p>1,1×104&nbsp;kg <strong>(B)</strong> </p></li><li><p>3,84×105&nbsp;km <strong>(A)</strong> </p></li><li><p>1,5×108&nbsp;km <strong>(C)</strong> </p></li><li><p>5×10−5&nbsp;m <strong>(B)</strong></p></li></ol>]]></description>
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         <pubDate>2025-10-07 04:25:54 UTC</pubDate>
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         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621141533</link>
         <description><![CDATA[<p>Exit ticket</p><p>Câu 1: 1,1 X 10000= 11000</p><p>Câu 2:3,84x 100000= 384000</p><p>Câu 3:1,5 x 100000000= 315000</p><p>Câu 4: b</p>]]></description>
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         <pubDate>2025-10-07 04:26:12 UTC</pubDate>
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         <author>linh038950</author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621141622</link>
         <description><![CDATA[<p>Câu a:<br>Khối lượng của kính viễn vọng Hubble là 11 000 kg. Ta viết lại số 11 000 ở dạng số có nghĩa là 1,1 × 10 mũ 4 kg<br>Kết quả là B</p><p>Câu b:<br>Khoảng cách từ Mặt Trăng đến Trái Đất là 384 000 km. Viết lại số 384 000 ở dạng số có nghĩa là 3,84 × 10 mũ 5 km<br>Kết quả là A</p><p>Câu c:<br>Khoảng cách từ Trái Đất đến Mặt Trời là 150 000 000 km. Viết lại số 150 000 000 ở dạng số có nghĩa là 1,5 × 10 mũ 8 km<br>Kết quả là C</p><p>Câu d:<br>Chiều dài của một tế bào là 0,00005 m. Viết lại số 0,00005 ở dạng số có nghĩa là 5 × 10 mũ âm 5 m.<br>Kết quả là B</p>]]></description>
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         <pubDate>2025-10-07 04:26:20 UTC</pubDate>
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         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621142030</link>
         <description><![CDATA[<p>A. 11000 kg = 1,1 x 10000kg = 1,1 x10^4=&gt; B</p><p><br/></p><p>B. 384000km= 3,84 x100000km= 3,84 x 10 ^5km=&gt; A</p><p><br/></p><p>C. 150000000KM =1,5 x 100000000km= 1,5 x 10^8 km =&gt;C</p><p><br/></p><p>D. 0,00005m= 5x0,00001m = 5x10^-5m =&gt; B</p><p><br/></p>]]></description>
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         <pubDate>2025-10-07 04:26:49 UTC</pubDate>
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         <title></title>
         <author>quan040016</author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621142395</link>
         <description><![CDATA[<p>a, 11000 = 11 x 10^3 = 1,1 x 10^4 ==&gt; B</p><p>b, 384000 = 384 x 10^3 = 3,84 x 10^5 ==&gt; A</p><p>c, 150000000 = 15 x 10^7 = 1,5 x 10^8 ==&gt; C</p><p>d, Đếm số 0 = 5 x 10^-5 ==&gt; B</p>]]></description>
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         <pubDate>2025-10-07 04:27:18 UTC</pubDate>
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         <title></title>
         <author></author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621142678</link>
         <description><![CDATA[<p>1.B :1,1x10 mu 4 =11=110=1100=11000</p><p>2.A:3,84x10 mu 5=34,8=348=3480=348000</p><p>3.C:1,5 x 10 mu9=1500000000</p><p>4.B:5 x 10 mu -5=0,00005</p>]]></description>
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         <pubDate>2025-10-07 04:27:39 UTC</pubDate>
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         <title></title>
         <author></author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621143321</link>
         <description><![CDATA[<p>BACB</p><p>con đếm số 0</p>]]></description>
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         <pubDate>2025-10-07 04:28:27 UTC</pubDate>
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         <title></title>
         <author></author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621143756</link>
         <description><![CDATA[<p>1, B </p><p>11 000 = 1,1 × 10 mũ 4</p><p>2,A </p><p>384 000 = 3,84 × 10 mũ 5</p><p>3,C</p><p>150 000 000 = 1,5 × 10 mũ 8</p><p>4,B</p><p>0,00005 = 5 × 10 mũ âm 5</p>]]></description>
         <enclosure url="" />
         <pubDate>2025-10-07 04:28:59 UTC</pubDate>
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         <title></title>
         <author></author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621143930</link>
         <description><![CDATA[<p>a, B</p><p>b,A</p><p>c,C</p><p>d,B</p><p><br/></p>]]></description>
         <enclosure url="" />
         <pubDate>2025-10-07 04:29:09 UTC</pubDate>
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         <title></title>
         <author>Nguyentienminh2012</author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621144557</link>
         <description><![CDATA[<p>a, B</p><p>Đánh thêm dấu phấy ở phía giữa số 11 =&gt; 1,1</p><p>Đếm số và biến 10000 =&gt; 10^4</p><p>b, A</p><p>Đánh thêm dấu phẩy ở hàng trăm =&gt; 3,84</p><p>Đếm số và biến 300000 =&gt; 10^5</p><p>c, C</p><p>Đánh thêm dấu phẩy ở phía giữa số 15 =&gt; 1,5</p><p>Đếm số và biến 100000000 =&gt; 10^8</p><p>d,B</p>]]></description>
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         <pubDate>2025-10-07 04:29:50 UTC</pubDate>
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         <title></title>
         <author></author>
         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621144558</link>
         <description><![CDATA[<p>a, B</p><p>b, A</p><p>c, C</p><p>d, B</p>]]></description>
         <enclosure url="" />
         <pubDate>2025-10-07 04:29:50 UTC</pubDate>
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         <link>https://padlet.com/nhandt96/q0cjcxka3ji519r7/wish/3621144986</link>
         <description><![CDATA[<p>1.b</p><p>2.a</p><p>3.c</p><p>4.b</p>]]></description>
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         <pubDate>2025-10-07 04:30:22 UTC</pubDate>
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