Period 7 Universal Law of Gravitation by Thomas E Clark https://padlet.com/tec430/pza1zhjd4iyd Please List 5 key points from the article PLUS show work from problems a, b, and c at the end of the article in the Padlet Link. en-us 2016-11-18 16:07:52 UTC 2023-04-19 15:48:31 UTC hello@padlet.com Tamera https://padlet.com/tec430/pza1zhjd4iyd/wish/138848786 1) All objects attract each other with a force of gravitational attraction.
2) Gravitational attraction is directly dependent upon the masses of both objects.
3) Gravitational force is inversely proportional to the square of the distance between two objects.
4) More separation between objects will result in weaker gravitational force.
5) The constant G is the universal gravitation constant. It is 6.673 x 10^-11 N m^2/kg^2
a) Fgrav= ((6.673 x 10^-11 N m^2/kg^2)(100 kg)(5.98 x 10^24))/(6.38 x 10^6 m)^2===> 980.350 N

b) Fgrav= ((6.673 x 10^-11 N m^2/kg^2)(40kg)(5.98 x 10^24))/(6.38 x 10^6 m)^2==> 392.140 N

c) Fgrav= ((6.673 x 10^-11 N m^2/kg^2)(70kg)(5.98 x 10^24))/(6.60 x 10^6 m)^2===> 641.258 N]]> 2016-11-18 23:21:30 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/138848786 Sakshi https://padlet.com/tec430/pza1zhjd4iyd/wish/138849023 1. The universal gravitational equation states that force of gravitational attraction is proportional to the masses of the two objects and inversely proportional to the square of the distance between the centers of the objects. 
2. The greater the mass the greater an attraction an object will have for another object. 
3. G is the universal gravitational constant and it is equal to 6. 673 x 10^-11 Nm^2/kg
4. When two objects are separated from each other, the gravitational force decreases. 
5. The gravitational force is inversely proportional to the distance between the two objects. 
a.  Fgrav= G*m1*m2/d^2
Fgrav= 6. 673 x 10^-11 Nm^2/kg *100 kg *5.98 x1024 kg/(
6.38 x 106 m)^2
=980N
b. Fgrav=  6. 673 x 10^-11 Nm^2/kg * 40 kg * 5.98 x1024 kg/ (6.38 x 106 m)^2=392N
c. Fgrav= 6. 673 x 10^-11 Nm^2/kg*70 kg*5.98 x1024 kg/(6.60 x 106 m)^2=641N]]> 2016-11-18 23:28:13 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/138849023 Diana https://padlet.com/tec430/pza1zhjd4iyd/wish/138849251 1. All objects are attracted to each other with a force of gravitational attraction. 
2. The force of attraction directly depends upon the masses of both objects and is inversely proportional to the square of distance that separates their centers. 
3. If the mass of one object doubles, the gravitational attraction will double. If the mass of both objects doubles, then gravitational attraction will quadrupled. 
4. If the distance between two objects doubles, then the gravitational attraction between them will decrease x4. 
5. G is the universal gravitation constant and is equal to 6..67 x 10^-11N*m^2/kg^2
a. ((G)(100)(5.98 x 10^24))/(6.38 x 10^6)^2
=980 N
b.  ((G)(40)(5.98 x 10^24))/(6.38 x 10^6)^2
=392N
c. ((G)(70)(5.98 x 10^24))/(6.60 x 10^6)^2
=641 N]]> 2016-11-18 23:36:25 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/138849251 Komal https://padlet.com/tec430/pza1zhjd4iyd/wish/138849259 1. Fg = [G (m1*m2)]/r^2
2. More massive objects attract each other with more gravitational force.
3. G = 6.673 * 10^(-11) Nm^2/kg^2
4. Gravitational interactions exist between all objects with an intensity that is directly proportional to the product of their masses. 
5. All object have a gravitational attraction, but it is usually only noticed as the objects become larger.
a. F=G(100)(5.98*10^24)/
(6.38*10^6)^2 = 980 N
b. F = G(40)((5.98*10^24)/
(6.38*10^6)^2 = 392 N
c. F = G(70)(5.98*10^24)/
(6.60*10^6)^2 = 641 N ]]> 2016-11-18 23:36:36 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/138849259 Jose https://padlet.com/tec430/pza1zhjd4iyd/wish/138849272 1)Gravity forces are responsible for the newton drawls an importance of gravity upon distance. 
2)  ]]> 2016-11-18 23:36:53 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/138849272 Alex https://padlet.com/tec430/pza1zhjd4iyd/wish/138849281 1.  Fgrav= ((6.673 x 10^-11 N m^2/kg^2)(40kg)(5.98 x 10^24))/(6.38 x 10^6 m)^2==> 392.140 N]]> 2016-11-18 23:37:11 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/138849281 Ruth https://padlet.com/tec430/pza1zhjd4iyd/wish/138849288 1) The gravitational force is directly proportional to the mass of both interactive objects. more massive objects will interact with each other with a greater gravitational force
2)Fg=[G(m1*m2)]r^2]]> 2016-11-18 23:37:29 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/138849288 Alex https://padlet.com/tec430/pza1zhjd4iyd/wish/138849304 1. ]]> 2016-11-18 23:38:10 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/138849304 Caitlin https://padlet.com/tec430/pza1zhjd4iyd/wish/138849363 2016-11-18 23:39:37 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/138849363 Chisondi https://padlet.com/tec430/pza1zhjd4iyd/wish/138849575 1.)Universal Gravitation Equation]]> 2016-11-18 23:46:21 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/138849575 RACHEL https://padlet.com/tec430/pza1zhjd4iyd/wish/138849605
1. Distance is not the only factor that affects the magnitude of a gravitational force
2. Newton's Equation - Fnet=M times A
3.  All objects attract each other with a force of gravitational attraction because gravity is universal]]> 2016-11-18 23:47:19 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/138849605 Bonny https://padlet.com/tec430/pza1zhjd4iyd/wish/138898104 1. Fnet=ma
Net force is affected by an object's mass and acceleration. 
2. Gravity is universal. All objects attract each other with a force of gravitational attraction.
3. The equation Fgrav=G m1xm2/(d^2) shows that a direct proportion between the force of gravity between two objects and their masses. It also shows an inverse proportion between gravitational force and the distance between the two objects. 
4. "G" is the constant of proportionality and is always 6.673 x 10^-11 Nm^2/kg^2. 
5. There can be deviation, or small perturbations that affect the gravitational pull between two objects.
a. F= ((6.673 x 10^-11 Nm^2/kg^2)(100)kg(5.98x10^24)kg)/(6.38x10^6)^2m= 980.3495445N
b.F=((6.673 x 10^-11 Nm^2/kg^2)(100kg)x(5.98x10^24kg))/(6.38x10^6m)^2)=392.1398178N
c.((6.673 x 10^-11 Nm^2/kg^2)(70kg)(5.98x10^24kg))/((6.60x10^6)^2m)= 641.2575298N]]> 2016-11-19 21:30:25 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/138898104 Hiwot https://padlet.com/tec430/pza1zhjd4iyd/wish/138899474 1)      Distance is not the only variable affecting the magnitude of a gravitational force
2)      the force of gravity  between  earth and any other object is directly proportional to the mass of the earth and to the mass of the object, but inversely proportional to the square of the distance that separates the centers of the earth and the object
3)  All objects attract each other with a force of gravitational attraction.
4)  more separation distance will result in weaker gravitational forces
5)  Gravitational interactions exist
between all objects with an intensity that is directly proportional to the
product of their masses; universal gravitation  G = 6.673 x 10-11 N m2/kg2
   Fg=[G(m1*m2)]r^2
A)    Fgrav= ((6.673 x 10^-11 N m^2/kg^2)(100 kg)(5.98 x
10^24))/(6.38 x 10^6 m)^2 = 980 N
B)    Fgrav= ((6.673
x 10^-11 N m^2/kg^2)(40kg)(5.98 x 10^24))/(6.38 x 10^6 m)^2=  392 N 
C)     Fgrav=
((6.673 x 10^-11 N m^2/kg^2)(70kg)(5.98 x 10^24))/(6.60 x 10^6 m)^2=  641 N 
]]> 2016-11-19 21:59:18 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/138899474 Catlan https://padlet.com/tec430/pza1zhjd4iyd/wish/138903520 1.  All objects attract each other with a force of gravitational attraction
2. Gravitational force is inversely proportional to the square of the separation distance between the two interacting objects
3. Gravitational force is directly proportional to the mass of both interacting objects
4. G = 6.673 x 10^-11 N m^2/kg^2 (G is the universal gravitation constant)
5. Net force = mass x acceleration
A. F= (6.673 x 10^-11)(100)(5.98*10^24)/
(6.38*10^6)^2 = 980 N 
B. F = (6.673 x 10^-11)(40)(5.98*10^24)/
(6.38*10^6)^2 = 392 N
C. F = (6.673 x 10^-11)(70)(5.98*10^24)/
(6.60*10^6)^2 = 641 N]]> 2016-11-20 00:39:54 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/138903520 Yohe https://padlet.com/tec430/pza1zhjd4iyd/wish/139213400 1) All objects attract each other with a force of gravitational attraction.
2) Forces causing something to accelerate is due to the mass of the object.
3) Main Formula: Fgravity equals G imes M1 times M2 all over D squared, where G represents universal gravitation.
4) Since gravitational force is proportional to the mass of both interacting objects, more massive objects will attract each other.
5)If the separation distance between two objects is tripled, then the factor of gravitational attraction is lowered by a factor of 9.

A) Fgrav=(6.673 x 10^-11 N m^2 divided by Kg^2) (100kg)(5.598x10^24) all over (6.38x10^6m)^2 equals 980N
B) Fgrav= (6.673
x 10^-11 N m^2/kg^2)(40kg)(5.98 x 10^24) all over (6.38 x 10^6 m)^2 equals 392 N 
C)  Fgrav= (6.673 x 10^-11 N m^2/kg^2)(70kg)(5.98 x 10^24) all over (6.60 x 10^6 m)^2 equals  641 N 
]]> 2016-11-21 20:30:40 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/139213400 Caitlin https://padlet.com/tec430/pza1zhjd4iyd/wish/140232533 1. Newton's law of universal gravitation is about the universality of gravity. 
2. All objects attract each other with a force of gravitational attraction force of gravitational attraction is directly dependent upon the masses of both objects and inversely proportional to the square of the distance that separates their centers.
3. Fgrav = m•g
4. Gravitational interactions don't just exist between the earth and other objects.
5. Gravitational forces are only recognizable as the masses of objects become large. 
a. F= (6.673x10^-11N m^2/kg^2)(100)(5.98x10^24 kg)/((6.38x10^6 m)^2) =980 N
b.F= (6.673x10^-11 N m^2/kg^2)(40 kg)(5.98x10^24)/((6.38x10^6 m)^2)= 392 N
c. F= (6.673x10^-11 N m^2/kg^2)(70kg)(5.98x10^24)/((6.60x10^6 m)^2)=641 N

]]> 2016-11-28 16:22:31 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/140232533 Ruth https://padlet.com/tec430/pza1zhjd4iyd/wish/140364748 1) The gravitational force is directly proportional to the mass of both interactive objects. more massive objects will interact with each other with a greater gravitational force
2)Fg=[G(m1*m2)]r^2
3) Gravitational interactions exist between all objects with an intensity that is directly proportional to the product of their masses.
4)If the mass of one of the objects is tripled, then the force of gravity between them is tripled. 
5)distance of separation becomes much more influential when a significant variation is made.
A. Fgrav=g*m1*m2/d^2
Fgrav=6.67*10^-11 
NM^2/kg*100kg*5.98*1024kg/(6.8*106m)^2=980n
B. Fgrav=6.67*10^-11NM^2/kg*40kg*5.98*1024kg/(6.38*106m)^2=392N
C. Fgrav=6.67*10^-11 NM^2/kg*70kg*5.98*1024kg/(6.6*106m)^2=641N

]]> 2016-11-28 23:21:54 UTC https://padlet.com/tec430/pza1zhjd4iyd/wish/140364748