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      <title>Electrostatics by MUHAMMAD ARIF BIN JALIL FS</title>
      <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0</link>
      <description>Electrostatic Forces,Charges,Coulomb&#39;s Law &amp; Gauss Law</description>
      <language>en-us</language>
      <pubDate>2020-10-20 03:25:09 UTC</pubDate>
      <lastBuildDate>2024-09-26 09:31:29 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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         <title>Electrostatics Charge</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843479167</link>
         <description><![CDATA[<div>When 2 plastics rods are rubbed with fur, then brought close to one another.What will happen?</div>]]></description>
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         <pubDate>2020-10-20 03:48:25 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843479167</guid>
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      <item>
         <title>Electrostatics Charge</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843481127</link>
         <description><![CDATA[<div>When plastic rod &amp; glass rod are brought near each other?</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-10-20 03:49:55 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843481127</guid>
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      <item>
         <title>Electrostatic charge</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843484416</link>
         <description><![CDATA[<div>What is the SI unit for charge?</div>]]></description>
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         <pubDate>2020-10-20 03:52:27 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843484416</guid>
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      <item>
         <title>Electrostatics Charge</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843486149</link>
         <description><![CDATA[<div>What are the compositions of an atom?</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-10-20 03:53:46 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843486149</guid>
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      <item>
         <title>Electrostatics charge</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843488967</link>
         <description><![CDATA[<div>Magnitude of charge, proton &amp; electron?</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-10-20 03:55:31 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843488967</guid>
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      <item>
         <title>Electrostatics charge</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843490182</link>
         <description><![CDATA[<div>The mass of electron,proton and neutron?</div>]]></description>
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         <pubDate>2020-10-20 03:56:27 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843490182</guid>
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      <item>
         <title>Electrostatics Charge</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843491427</link>
         <description><![CDATA[<div>Define charge of magnitude Q.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-10-20 03:57:21 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843491427</guid>
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      <item>
         <title>Conservation of charge</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843492574</link>
         <description><![CDATA[<div>State the law of conservation of charge.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-10-20 03:58:10 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843492574</guid>
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      <item>
         <title></title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843501068</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://www.youtube.com/watch?v=ectl3po7MuI" />
         <pubDate>2020-10-20 04:04:34 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/843501068</guid>
      </item>
      <item>
         <title>Coulomb’s Law</title>
         <author>has5wb69wi</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858899454</link>
         <description><![CDATA[<div>Coulomb's Law state that electrical force between 2 point charges is directly proportional to the product of the charges and inversely proportional to the square of distance between them.<br>           q<sub>1</sub> q<sub>2</sub></div><div>F = -----------------<br>         4π ε<sub>0</sub> r<sup>2</sup><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2020-10-25 07:12:11 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858899454</guid>
      </item>
      <item>
         <title>Profile</title>
         <author>mohammadfaris</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858905639</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2020-10-25 07:16:10 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858905639</guid>
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      <item>
         <title>Profile Wardina</title>
         <author>wardina0807</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858906219</link>
         <description><![CDATA[<div>Hii everyone! My name is Nur Wardina Syahirah binti Mohamad Fadil. You can call me wardina or Dina. i love singing for sure tp suara tak sedap cuma suka nyanyi hahaha. my prior education was in Pahang Matriculation College (KMPh) </div>]]></description>
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         <pubDate>2020-10-25 07:16:32 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858906219</guid>
      </item>
      <item>
         <title>Profile Jin Xuan</title>
         <author>fionteo1023</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858907875</link>
         <description><![CDATA[<div>Hiii everyone!!! My name is Teo Jin Xuan. You all can also call me fion. My interest is jogging. I have finished my STPM in SMK Dato' Bentara Luar, Batu Pahat, Johor.</div>]]></description>
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         <pubDate>2020-10-25 07:17:33 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858907875</guid>
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         <title>Profile</title>
         <author>teosang</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858908542</link>
         <description><![CDATA[<div>Hello everyone . My name is Teo Jin Sang. You all can call me Jin Sang or Fiona. I love to  eat.I graduate from STPM in SMK Dato' Bentara Luar, Batu Pahat Johor.</div>]]></description>
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         <pubDate>2020-10-25 07:17:59 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858908542</guid>
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      <item>
         <title>Profile Viga</title>
         <author>has5wb69wi</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858908564</link>
         <description><![CDATA[<div>Viganeswaran Rau <br>Interests - Books , Sports, Science<br>Studied at Politeknik Shah Alam</div>]]></description>
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         <pubDate>2020-10-25 07:18:00 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858908564</guid>
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      <item>
         <title>Profile Rico Tan</title>
         <author>ricozen</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858908955</link>
         <description><![CDATA[<div>My name is Rico Tan Zen Chong.<br>You all also could call me Rico.<br>My interest is mountain climbing.<br>Last time I study at SMK Munshi Sulaiman, Batu Pahat for STPM.</div>]]></description>
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         <pubDate>2020-10-25 07:18:11 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858908955</guid>
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      <item>
         <title>Profile Tassvin</title>
         <author>tassvinbarni</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858909274</link>
         <description><![CDATA[<div>hi everyone I am tassvin. i studied stpm at smk batu 8. i love playing badminton and futsal </div>]]></description>
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         <pubDate>2020-10-25 07:18:24 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858909274</guid>
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         <title>Profile</title>
         <author></author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858909369</link>
         <description><![CDATA[<div>Assalamualaikum, hi everyone !</div>]]></description>
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         <pubDate>2020-10-25 07:18:28 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858909369</guid>
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         <title>Profile</title>
         <author>nabil01najmi</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858909393</link>
         <description><![CDATA[<div>Hi everyone, my name is Nabil Najmi Bin Norpiah. You guys can call me nabil, i love to play basketball and badminton, my prior education was in Uitm Dengkil Foundation Studies where i took Foundation in Engineering</div>]]></description>
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         <pubDate>2020-10-25 07:18:29 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858909393</guid>
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      <item>
         <title>Profile Nashrah</title>
         <author>nashrah7</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858909679</link>
         <description><![CDATA[<div>Hi, Assalamualaikum everyone! My name is Nashrah binti Shamsul or you may call me Nashrah. I love to eat... more specifically, love to eat desserts and anything sweets (ya, a sweet tooth I am).&nbsp; Hence, I love baking because I can eat afterwards 😂 My alma mater was Malacca Matriculation College.</div>]]></description>
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         <pubDate>2020-10-25 07:18:37 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858909679</guid>
      </item>
      <item>
         <title>Yet another introduction</title>
         <author>lilihahattl_Teng</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858909993</link>
         <description><![CDATA[<div>Hello<br>I am Teng Ting Li<br>You can call me ttl but don't call me TENG TENG PLEASE.<br>Like everyone here, I love physic<br>since I was a little boy.<br>I finished my STPM at Kolej TIngkatan Enam Seri Putera Fair Park at Ipoh Perak.<br><br><br></div>]]></description>
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         <pubDate>2020-10-25 07:18:50 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858909993</guid>
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         <title></title>
         <author>norathirah3</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858910919</link>
         <description><![CDATA[<div>Hello guys! Nice to mee to you.<br>My name is nor athirah bt mohd sukri. <br>U can call me ira. Im from Kelantan . I love pink and music 😬</div>]]></description>
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         <pubDate>2020-10-25 07:19:20 UTC</pubDate>
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      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858911060</link>
         <description><![CDATA[<div>Assalamualaikum &amp; hello everyonee!!  My name is NOR AINA MUNIRAH BINTI MAD YASIN,can call me Aina🤩 I have finished my study in matriculation which is KMPh( pahang matriculation college))</div>]]></description>
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         <pubDate>2020-10-25 07:19:25 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858911060</guid>
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      <item>
         <title>Nadirah&#39;s profile </title>
         <author>nurnadiirah</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858912636</link>
         <description><![CDATA[<div>Hello guyss my name is Nur Nadirah binti Mohd Nor. I usually go by both nad and naddy as my nicknames. I love fishing and sleeping. But recently i like to do the diamond painting during my free time to release stress. I study at Johore Matriculation College before this hihi. Hope to see you guys soon!!! Byeee</div>]]></description>
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         <pubDate>2020-10-25 07:20:15 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858912636</guid>
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      <item>
         <title>Profile Tay Kuan Yew</title>
         <author>KYTAY0505</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858912959</link>
         <description><![CDATA[<div>Hello everyone! My name is Tay Kuan Yew. I am from Muar, Johor. I studied in High School Muar previously. I like to eat XD hahhhh.</div>]]></description>
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         <pubDate>2020-10-25 07:20:27 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858912959</guid>
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      <item>
         <title>Profile farah nadiah</title>
         <author>nurfarahnadiah26</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858913045</link>
         <description><![CDATA[<div>Assalamualaikum &amp; hii everyone ❤<br>My name is Nur Farah Nadiah Binti Zakaria.You all can call me Farah or maybe Farah Nadiah . Im from Perak . Before this i study at Perak Matriculation College 😊&nbsp; Lastly, I am interested in various activities and things like gardening, cooking and even I am a cat lover&nbsp;😻</div>]]></description>
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         <pubDate>2020-10-25 07:20:30 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858913045</guid>
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      <item>
         <title>Profile ameena suhel</title>
         <author>ameenahsuhelz</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858914360</link>
         <description><![CDATA[<div>Hi everyone! My name is ameenah suhel, you can call me meena or ameena. I loveee to do paintings, drawings and bingeee watch anime!! Any anime fans here? Anddd my prior education was in pahang matriculation college :))))</div>]]></description>
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         <pubDate>2020-10-25 07:21:16 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858914360</guid>
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      <item>
         <title>Profile Najla</title>
         <author>njlanjihah</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858914781</link>
         <description><![CDATA[<div>Hi everyone! My name is Nur Najla Najihah, can call me Najla. Besides that i love physics, my interest also in dancing especially traditional dance like zapin because i used to be one of the college's dancer. I have finished my study at Johor Matriculation College.&nbsp;</div>]]></description>
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         <pubDate>2020-10-25 07:21:30 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858914781</guid>
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      <item>
         <title>Profile </title>
         <author>amiraatirahh1</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858915108</link>
         <description><![CDATA[<div>Hi guys, my name’s Nuramirah Atirah binti Abd Rahman. You can call me Amirah. I love foods. My interest in life is food! Especially chocolates. I studied at Johor Matriculation College before I entered UTM.</div>]]></description>
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         <pubDate>2020-10-25 07:21:42 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858915108</guid>
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      <item>
         <title>Profile Husna</title>
         <author>nurhusnadzamrah01</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858915408</link>
         <description><![CDATA[<div>Hi and very good evening everyone! My name is Nur Husna Binti Dzamrah and everyone can address me as una. Actually, I love doing multiple things. Listening to music, reading books, singing, watching movies, cooking and drawing. Before this, I have been studied at Perak Matriculation College (KMPk)&nbsp;</div>]]></description>
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         <pubDate>2020-10-25 07:21:55 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858915408</guid>
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         <title>profile</title>
         <author>nz_amirh</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858915684</link>
         <description><![CDATA[<div>hi everyone ! my name is Nazatul Amirah binti Masri . you can call me mira or atul ... i love to watch anime and reading manga . quite unique right ? because i am a girl 😂 then i was graduated from johor matriculation college (jmc/kmj) nice to know you guys ! hope we will have a good time together 😊🌻</div>]]></description>
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         <pubDate>2020-10-25 07:22:06 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858915684</guid>
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      <item>
         <title>Profile Sufiyah</title>
         <author>sufiyahrhny</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858915903</link>
         <description><![CDATA[<div>Hi everyone. My name is Sufiyah Raihany binti Kamarulzaman. You guys can call me Sufiyah. Before this i study at Selangor Matriculation College</div>]]></description>
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         <pubDate>2020-10-25 07:22:14 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858915903</guid>
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      <item>
         <title>Profile</title>
         <author></author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858916141</link>
         <description><![CDATA[<div>Hi guys! My full name is Nurul Athirah Husna binti Zarazal. You can call me thira or husna 🤗 so i went to kolej matrikulasi selangor(kms) before this and my interest are more into the arts or editing video😇</div>]]></description>
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         <pubDate>2020-10-25 07:22:23 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858916141</guid>
      </item>
      <item>
         <title>Profile Atiqah</title>
         <author>atiqahyu975</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858916428</link>
         <description><![CDATA[<div>Hellos everyone. My name is Nur Atiqah Binti Mohd Yusoff and you can call me Iqah. I am Tangkak Matriculation College graduates. </div>]]></description>
         <enclosure url="" />
         <pubDate>2020-10-25 07:22:35 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858916428</guid>
      </item>
      <item>
         <title></title>
         <author>aniszakaria0412</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858918873</link>
         <description><![CDATA[<div>Profile Nur Farhanis<br><br>Assalamualaikum and hi everyone.My name is Nur Farhanis bt Zakaria.Im from Terengganu.My previous college wa Pahang Matriculation College</div>]]></description>
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         <pubDate>2020-10-25 07:23:57 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858918873</guid>
      </item>
      <item>
         <title></title>
         <author>blogfarah</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858920654</link>
         <description><![CDATA[<div>Hye Dr. and my friends🤗.My name is Nur Farah Afiqah Binti Asmadi.I’m from Sungai Buloh,Selangor..I was studied in Melacca Matriculation College..</div>]]></description>
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         <pubDate>2020-10-25 07:24:58 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858920654</guid>
      </item>
      <item>
         <title>Profile Fariza Farhana</title>
         <author>farizaffarhana</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858921123</link>
         <description><![CDATA[<div>Hiii everyone and Assalamualaikum ! My name is Siti NorFariza Farhana Binti Mohd Razak.You guys can call me Fariza btw. I love to read comics.heheheh😁. Before this I studied at Penang Matriculation College (KMPP). Nice to meet uolls ^^<br><br><br></div>]]></description>
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         <pubDate>2020-10-25 07:25:18 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858921123</guid>
      </item>
      <item>
         <title>Profile Najiha</title>
         <author>najiharasid01</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858921128</link>
         <description><![CDATA[<div>Hello guys my name is Nur Najiha. You can call me Jieya. My interest actually into sports like running, but not the ball sports hshsh. My prior education was in Johor Matriculation College. Nice to meet you!!!</div>]]></description>
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         <pubDate>2020-10-25 07:25:18 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858921128</guid>
      </item>
      <item>
         <title></title>
         <author>nurainsyafiqah00</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858922117</link>
         <description><![CDATA[<div>Assalamualaikum and hello everyone.<br>My name is Nurainsyafiqah binti Mohd Yusoff.All of you can call me ain.I like to take a picture wherever I go,because I love on photography so much.I also love to read books.Before this,I study at Pahang Matriculation College</div>]]></description>
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         <pubDate>2020-10-25 07:25:52 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858922117</guid>
      </item>
      <item>
         <title>Profile Syazwina</title>
         <author>sitinorsyazwina33</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858922365</link>
         <description><![CDATA[<div>Assalamualaikum , and very good evening 😊 my name is Siti Nor Syazwina Binti Sa-hariff, you can call me wina . My prior education was at Melacca Matriculation College .I love to play with musical instruments like piano and guitar . I also into sports especially netball, tennis and rugby.<br><br></div>]]></description>
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         <pubDate>2020-10-25 07:26:01 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858922365</guid>
      </item>
      <item>
         <title>Profile Uzma Aleeya</title>
         <author>uzmaaleeya</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858924163</link>
         <description><![CDATA[<div>Bonjour everyone! Im Uzma Aleeya, prefer to be called as Uzma✊🏻✨ I was a student at Negeri Sembilan Matriculation College for 19/20 session &amp; I'd love to spend my leisure time with baking🥰 </div>]]></description>
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         <pubDate>2020-10-25 07:27:02 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858924163</guid>
      </item>
      <item>
         <title>Profile Nissa </title>
         <author>nurhanissa</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858924378</link>
         <description><![CDATA[<div>  Assalamualaikum and hello everyone!! <br>My name is Nurhanissa binti abd halim..you guys can call me nissa or hanissa..i love food especially LAKSA PENANG!!!.. I have finished my study in pahang matriculation college(KMPH) </div>]]></description>
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         <pubDate>2020-10-25 07:27:10 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858924378</guid>
      </item>
      <item>
         <title></title>
         <author>dhiyadinie00</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858925365</link>
         <description><![CDATA[<div>Hi!<br><br>My name is NUR DHIYA DINIE BINTI SYAABANI.<br>Call me as DHIYA or DINIE.<br>I'm from Gelugor Penang.<br>My prior education is Penang Matriculation College.<br>I love sports.<br>I love to eat. <br><br><br></div>]]></description>
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         <pubDate>2020-10-25 07:27:47 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858925365</guid>
      </item>
      <item>
         <title></title>
         <author>nabila01</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858925742</link>
         <description><![CDATA[<div>hello everyone!!😊 my name is Nur Nabila Binti Abd Aziz..can call me Nabila..I love reading novels..my prior education was at Penang  matriculation college.</div>]]></description>
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         <pubDate>2020-10-25 07:27:58 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858925742</guid>
      </item>
      <item>
         <title>Profile Nabilah Husna</title>
         <author>nabilahhusna72_nh</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858927274</link>
         <description><![CDATA[<div>Assalamualaikum and hi everyone! Hihi, my name is Nur Nabilah Husna Binti Reymie. You can call me Husna or Nabilah. I came from Pasir Gudang, Johor. My prior education was in UiTM Dengkil where I took Foundation in Science. I love to watch drama and movie. And I love to eat. I love to read comics or novels too.<br><br></div>]]></description>
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         <pubDate>2020-10-25 07:28:54 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858927274</guid>
      </item>
      <item>
         <title>Dr.Muhammad Arif Jalil</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858931314</link>
         <description><![CDATA[<div>Assalamualaikum w.b.t &amp; good evening.I am your physics lecturer. There is nothing much to say about me.Sadly to say this year i am not sure whether we are going to hv a 1st year experience (FYE).If yes then you will know me better. I love to spend my leisure time cycling &amp; playing badminton. As you can see in the picture,these are my PA students,that is your senior in the 2nd year.</div>]]></description>
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         <pubDate>2020-10-25 07:31:17 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858931314</guid>
      </item>
      <item>
         <title></title>
         <author>nurulaqilaho</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858943265</link>
         <description><![CDATA[<div>Assalamualaikum and good evening 😊my name is Nurul Aqilah Binti Othman.You can call me Aqilah.My prior education was at Penang Matriculation College.I love listening to music reading books and meditate(sleeping) </div>]]></description>
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         <pubDate>2020-10-25 07:38:07 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858943265</guid>
      </item>
      <item>
         <title>Profile syahi</title>
         <author>irahsyahirahsalim</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858944027</link>
         <description><![CDATA[<div>Hai, Assalamualaikum and salam sejahtera!<br>My name is Nur Syahirah binti Salim.im from kuala terengganu.You guys can call me syahi ✌️ 🙃 i love to watch movies but usually i spend my leisure by singing 😂 my prior education is penang matriculation college (KMPP) </div>]]></description>
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         <pubDate>2020-10-25 07:38:34 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858944027</guid>
      </item>
      <item>
         <title>Electric field strength</title>
         <author>lilihahattl_Teng</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858957021</link>
         <description><![CDATA[<div>         F<br>E =  -------<br>         Q</div>]]></description>
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         <pubDate>2020-10-25 07:45:59 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858957021</guid>
      </item>
      <item>
         <title></title>
         <author>mohammadfaris</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858959526</link>
         <description><![CDATA[<div>Define<br><br>Charge conservation<br>In isolated system, the NET CHARGE is equal to zero<br><br>Q= quatity of charge<br><br></div>]]></description>
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         <pubDate>2020-10-25 07:47:37 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858959526</guid>
      </item>
      <item>
         <title>What is Coulomb Law?</title>
         <author>atiqahyu975</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858960173</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-10-25 07:48:03 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858960173</guid>
      </item>
      <item>
         <title>Now try to define the electric field strength</title>
         <author>wardina0807</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858962434</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-10-25 07:49:29 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858962434</guid>
      </item>
      <item>
         <title>What is Electrostatic Equilibrium?</title>
         <author>has5wb69wi</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858966790</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-10-25 07:52:04 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858966790</guid>
      </item>
      <item>
         <title>What are the example of conductor and insulator? and semiconductor?</title>
         <author>najiharasid01</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858972642</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-10-25 07:55:22 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858972642</guid>
      </item>
      <item>
         <title></title>
         <author>norathirah3</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858973556</link>
         <description><![CDATA[<div>Define insulator</div>]]></description>
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         <pubDate>2020-10-25 07:55:58 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858973556</guid>
      </item>
      <item>
         <title></title>
         <author>farizaffarhana</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858973969</link>
         <description><![CDATA[<div>What are the characteristics of conductor in electrostatic equilibrium</div>]]></description>
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         <pubDate>2020-10-25 07:56:14 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858973969</guid>
      </item>
      <item>
         <title>What is conservation of charge?</title>
         <author>ricozen</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858974466</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-10-25 07:56:33 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858974466</guid>
      </item>
      <item>
         <title>define free electrons</title>
         <author>nz_amirh</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858979257</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-10-25 07:59:35 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858979257</guid>
      </item>
      <item>
         <title>Relate Electric field strength with coulomb&#39;s law</title>
         <author>lilihahattl_Teng</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858986015</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-10-25 08:03:20 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/858986015</guid>
      </item>
      <item>
         <title>State three type of charged density</title>
         <author>teosang</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/879443250</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-11-01 06:59:57 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/879443250</guid>
      </item>
      <item>
         <title>State the symbol and dimensions of three types of charge densities</title>
         <author>fionteo1023</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/879443337</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-11-01 07:00:01 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/879443337</guid>
      </item>
      <item>
         <title>Relate Newton 2nd Law of motion with the Electric Field</title>
         <author>ricozen</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/879444150</link>
         <description><![CDATA[<div>Show the equation with acceleration.</div>]]></description>
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         <pubDate>2020-11-01 07:00:31 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/879444150</guid>
      </item>
      <item>
         <title>What does it meant by &#39;uniform electric field&#39; ?</title>
         <author>nashrah7</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/879476317</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-11-01 07:21:20 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/879476317</guid>
      </item>
      <item>
         <title>Gauss Law for Electrostatics</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/888886204</link>
         <description><![CDATA[<div>State the difference between Gauss Law &amp; Coulomb's Law</div>]]></description>
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         <pubDate>2020-11-04 06:46:08 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/888886204</guid>
      </item>
      <item>
         <title>Define Gauss Law.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/888895430</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-11-04 06:50:14 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/888895430</guid>
      </item>
      <item>
         <title>Gaussian Surface</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/888904284</link>
         <description><![CDATA[<div>Example of Gaussian Surface.</div>]]></description>
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         <pubDate>2020-11-04 06:54:11 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/888904284</guid>
      </item>
      <item>
         <title>Define electric flux</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/888908363</link>
         <description><![CDATA[<div>An electric flux is the rate of electric fiel d that passes through the plane of a given cross sectional area.</div>]]></description>
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         <pubDate>2020-11-04 06:56:03 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/888908363</guid>
      </item>
      <item>
         <title>Example of flux</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900727244</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-11-08 03:16:17 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900727244</guid>
      </item>
      <item>
         <title>If the plane is perpendicular to the electric field lines,what will happen? how about if the plane is horizontally parallel to the field lines?</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900729862</link>
         <description><![CDATA[<div><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2020-11-08 03:20:13 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900729862</guid>
      </item>
      <item>
         <title>Electric is a scalar or vector quantity?Justify your Answer.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900732147</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2020-11-08 03:23:40 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900732147</guid>
      </item>
      <item>
         <title>Write the full equation of electric flux- Very important. Why sometimes it exist in the integral form?</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900734404</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2020-11-08 03:27:07 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900734404</guid>
      </item>
      <item>
         <title>The flux emerging from a Gaussian surface is proportional to the magnitude of the charge and independent of the shapes,sizes or radius of the surface.State the Gauss Law for electricity.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900737924</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2020-11-08 03:32:35 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900737924</guid>
      </item>
      <item>
         <title>Gauss Law,concept diagram</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900742280</link>
         <description><![CDATA[<div>I will divide the equations into 4 parts.Refer to the equations below:<br>Part 1 &amp; 2: If the area is divided into many small elements over the entire Gaussian Surface.<br>For part 3 &amp; 4:In the limit of continous surface element ,when delta A approaches zero the expression becomes a closed integral function.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/b6c575f89fb7c6ce402c4c7b0dc8b494/electric_flux_and_gauss_law_l.jpg" />
         <pubDate>2020-11-08 03:39:15 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900742280</guid>
      </item>
      <item>
         <title>4 basic cases where Gauss&#39;s Law can be performed.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900751671</link>
         <description><![CDATA[<div> Some examples are single charged particles, uniformly charged sphere, uniform line charge and uniform plane </div>]]></description>
         <enclosure url="" />
         <pubDate>2020-11-08 03:52:22 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900751671</guid>
      </item>
      <item>
         <title>Cases where Gauss law can be performed.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900754631</link>
         <description><![CDATA[<div>1)Point Charge<br>-Refer to equation no 1,flux:<br>Select a Gaussian surface around the charge of radius r, with the charge +q at the center. Hence, Gauss's law yield a closed integral function.<br><br>-Refer to equation no2 :<br>The Gaussian surface is a sphere of area A=4pi.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/37afd6f923b04893203f47d20976790c/Point_Charge.jpg" />
         <pubDate>2020-11-08 03:56:21 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900754631</guid>
      </item>
      <item>
         <title>2)A non-conducting solid sphere.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900772273</link>
         <description><![CDATA[<div>Refer to the graph in the diagram:<br>A uniform distribution of charges in a non-conducting solid sphere showing Gaussian surface &amp; a plot of the electric field along a radial line.The dotted line refers of a conducting sphere.<br><br>For this case,there are 2 cases:<br>1)Regions inside the distribution (0&lt;r&lt;R)<br>Gauss Law, phi=E.dA= q/e<br><br>Select a Gaussian surface inside the distribution (0&lt;r&lt;R).Then, determine the net charge enclosed by the Gaussian Surface:<br>q=Rho x V    <br>  = Rho x (4pi r^3/3)<br>  =(4pi r^3/3) x Rho<br><br>Then,substitute the charge q, into the Gauss law equation above:<br><br>E=Rho x r/3e<br><br>2)Outside the Charge Distribution,(r&gt;R)<br>Select a spherical Gaussian surface with radius (r&gt;R).<br>Equation for q= 4pi x R^3 x Rho/3<br>Equation for E=<br><br></div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/a22e038d63a063119d2c04c28ebe2fb8/Solid_Sphere_of_Charge.jpg" />
         <pubDate>2020-11-08 04:15:48 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/900772273</guid>
      </item>
      <item>
         <title>3) i)Large Sheet of Charges.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/911655228</link>
         <description><![CDATA[<div>Pillbox!</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/c5813c3a1e143b96081b33b193efd273/Pillbox.png" />
         <pubDate>2020-11-11 06:18:55 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/911655228</guid>
      </item>
      <item>
         <title>3ii) Large sheet of charges: The electric field distribution of the surrounding regions of 2 parallel plates.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/911675376</link>
         <description><![CDATA[<div>Parallel Plates.<br>q=sigma x A<br>Gauss Law: Flux= E.dA<br><br></div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/c5c5b30901a5ed7a3504761a6d539bb6/Parallel_Plates.png" />
         <pubDate>2020-11-11 06:27:13 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/911675376</guid>
      </item>
      <item>
         <title>Line Distribution of charges.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/925445181</link>
         <description><![CDATA[<div>Gauss Law: <br>let q = λ l<br>from ɸ = ∮ E · dA = q / ε<sub>0</sub><br>E (2 π r l ) = λ l / ε<sub>0 <br></sub>E = λ l / 2 ε<sub>0 </sub>π r l<br>    = λ / 2 ε<sub>0 </sub>π r</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/4273a96829c4fa515b76ccfffde23682/Gauss_cylinder.jpg" />
         <pubDate>2020-11-16 01:13:51 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/925445181</guid>
      </item>
      <item>
         <title>The relation between Gauss law &amp; coulomb&#39;s law.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/925465534</link>
         <description><![CDATA[<div>Electric force act on a test charge q<sub>1</sub>, <br>F = q<sub>1</sub> x E,<br>The field generated by another point charge q,<br>E= k q / r<sup>2</sup></div>]]></description>
         <enclosure url="" />
         <pubDate>2020-11-16 01:27:50 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/925465534</guid>
      </item>
      <item>
         <title>Electric potential energy</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/925486688</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/adb13caa0f99f04d7229a366bed25785/Electric_Potential_Energy.jpg" />
         <pubDate>2020-11-16 01:42:26 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/925486688</guid>
      </item>
      <item>
         <title>Electric potential energy for a system of point charges</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948905000</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/d0e183d88e08913a1f9c0b620476e5a6/Electric_Potential_Energy_of_System.jpg" />
         <pubDate>2020-11-22 03:16:06 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948905000</guid>
      </item>
      <item>
         <title>Potential energy of a system of point charges</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948909986</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2020-11-22 03:24:31 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948909986</guid>
      </item>
      <item>
         <title>Electric potential for multiple point of charges</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948913840</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/b8c06e144a876142a312043af6474d2b/index2.png" />
         <pubDate>2020-11-22 03:31:08 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948913840</guid>
      </item>
      <item>
         <title>Electric potential V versus distance,r.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948916699</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/d3abc453b29f75b0ae6f565b6cdbd77d/slide_5.jpg" />
         <pubDate>2020-11-22 03:35:59 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948916699</guid>
      </item>
      <item>
         <title>Electrostatic potential energy for a positively cahrged conducting sphere as a function of distance,r</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948918973</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/3c32618a5f9aad21fca7cb1bf27e8a09/23356337902_e661995144_o.png" />
         <pubDate>2020-11-22 03:39:45 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948918973</guid>
      </item>
      <item>
         <title>The relation between the electric field,E &amp; the potential difference,V.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948922505</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/f51a6cc02e970217e9b8093828f1c554/Work___Charge___Potential_Difference_.jpg" />
         <pubDate>2020-11-22 03:45:14 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948922505</guid>
      </item>
      <item>
         <title>Exercise 1 (EP &amp; PE):</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948925074</link>
         <description><![CDATA[<div>The electron in a hydrogen atom at a distance of 0.53 x 10^-10 m from the proton.<br>-What is the electrostatics potential generated by the proton at this distance?<br>-What is the potential energy of the electron?</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-11-22 03:49:01 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948925074</guid>
      </item>
      <item>
         <title>Exercise 2: (PE,WORK,&amp; EP)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948939572</link>
         <description><![CDATA[<div>Given 3 charges ,+q, +2q &amp; -4q are arranged in each corner of an equilateral triangle with sides 10 cm.Determine:<br><br>-Given q = 2 micro Coulomb,determine the electric potential energy of the system.<br>-The work required to remove the charge +q from the system.<br>-The electric potential at the center of the equilateral traingle.<br><br>Hint: Charge +q at the center, -4q on the left &amp; +2q on the right side of the equilateral triangle. Give it a try!!</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-11-22 04:07:23 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948939572</guid>
      </item>
      <item>
         <title>Equipotential Surface</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948956156</link>
         <description><![CDATA[<div>A <strong>surface</strong> all of whose points have the same potential. For <strong>example</strong>, the <strong>surface</strong> of a conductor in electrostatics is an <strong>equipotential surface</strong>. In a force field the lines of force are normal, or perpendicular, to an <strong>equipotential surface.</strong></div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/0a50e59c5cafef8f6d79d5a1300c6bba/maxresdefault.jpg" />
         <pubDate>2020-11-22 04:25:26 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/948956156</guid>
      </item>
      <item>
         <title>Capacitors &amp; Dielectrics.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/949176897</link>
         <description><![CDATA[<div><strong>Capacitance</strong> is the ability of a body to hold an electrical charge. In numerical terms: it is the ratio of the amount of electric charge stored on a conductor to a difference in electric potential.<br>SI unit: <a href="https://en.wikipedia.org/wiki/Farad">farad</a></div><div>Other units: μF, nF, pF</div><div>In SI base units: F = A<sup>2</sup> s<sup>4</sup> kg<sup>−1</sup> m<sup>−2</sup></div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/8e2974e391857b52ebee18c9d58efadc/wx1kzcae1p.jpg" />
         <pubDate>2020-11-22 07:27:02 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/949176897</guid>
      </item>
      <item>
         <title>Exercise (Basic capacitor):</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/949186243</link>
         <description><![CDATA[<div>A 30 micro F capacitor is charged using a battery supplying 24 V. Calculate the amount of charge that can be stored in the capacitor. If another battery supplying 9 V is added to the connection in series,what is the new charge on the capacitor?</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-11-22 07:32:59 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/949186243</guid>
      </item>
      <item>
         <title>Parallel Plate Capacitors</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/949210502</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/5bc2b56f161d45a253f8139778854a99/x1080.jpg" />
         <pubDate>2020-11-22 07:47:38 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/949210502</guid>
      </item>
      <item>
         <title>Exercise (Parallel Plate Capacitors):</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/949219291</link>
         <description><![CDATA[<div>A parallel plate capacitor has two circular pates of diameter 20.0 cm with air gap between them.The plates are separated by a distance of 0.5 cm.<br>-What is the capacitance of the capacitor?<br>-If the two plates are connected to a battery of 1.5 V,how much charge can be stored in the capacitor?<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2020-11-22 07:53:07 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/949219291</guid>
      </item>
      <item>
         <title>The capacitance of two concentric spherical shells.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/950688330</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/5ce2a570ea82e93270492090399c429f/capacitance_of_two_concentric_spherical_shells_l.jpg" />
         <pubDate>2020-11-23 01:13:27 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/950688330</guid>
      </item>
      <item>
         <title>Exercise: A concentric spehers.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/950692128</link>
         <description><![CDATA[<div>A concentric capacitor has its inner radius at 2.0 cm and the outer radius at 10.0 cm.The space between the spheres is filled with air.Determine the capacitance.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-11-23 01:16:06 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/950692128</guid>
      </item>
      <item>
         <title>Capacitors in series and parallel circuits.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/950709826</link>
         <description><![CDATA[<div>Series Combination:<br>-The reciprocal of the equivalent is equal to the sum of the reciprocal of the individual capacitors.<br>-The equivalent capacitance (Ceq) is always less than any of the individual capacitance.<br><br>Parallel Combination:<br>-The equivalent capacitance of a parallel combination is equal to the sum of the individual capacitors.<br>-The equivalent capacitance (Ceq) is always greater than any of the individual capacitance.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/8211ad9687c86ec1a22bebb48ab290aa/Capacitor_Circuit_0.jpg" />
         <pubDate>2020-11-23 01:27:49 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/950709826</guid>
      </item>
      <item>
         <title>Excersise 1 (Capacitors): Three capacitors ,3.0 uF, 5.0 uF &amp; 7.0 uF are connected in series. Determine the equivalent capacitance and the charge stored in each capacitor if a potential difference of 50 V is applied across the combination.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/950719760</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2020-11-23 01:34:06 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/950719760</guid>
      </item>
      <item>
         <title>Exercise 2 (Capacitors): Use the same capacitors in Exercise 1 (Capacitors),but now connected in parallel &amp; then the combination is put across a 50 V potential difference.Determine the equivalent capacitance, the total charge stored in the circuit &amp; the charge in each capacitor.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/950733663</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2020-11-23 01:42:49 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/950733663</guid>
      </item>
      <item>
         <title>Energy Stored in a charged capacitors.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/958797206</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/826f227ed2fda78a565207632054c041/RELATION_OF_ENERGY_STORED_IN_CAPACITOR.png" />
         <pubDate>2020-11-25 06:11:20 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/958797206</guid>
      </item>
      <item>
         <title>Energy stored in charged capacitors (Diagram)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/958805639</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/dd788e3e974514da4060a64342cd7535/Energy_stored.png" />
         <pubDate>2020-11-25 06:15:48 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/958805639</guid>
      </item>
      <item>
         <title>Exercise (Energy stored in a charged capacitors)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/958809636</link>
         <description><![CDATA[<div>A 0.5 uF capacitor is connected across a 60 V voltage supply. How much electric potential energy is stored &amp; what is the charge accumulated on the capacitor? </div>]]></description>
         <enclosure url="" />
         <pubDate>2020-11-25 06:17:54 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/958809636</guid>
      </item>
      <item>
         <title>Electric field energy/energy density.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/958843223</link>
         <description><![CDATA[<div>Work has to be done against the electric field between the plates.The energy required in terms of the energy per unit volume of the space between the plates with area ,A &amp; separation distance,d. Hence energy density is u.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/2d38211d1730a691c998bb3f83a0b119/Energy_density.png" />
         <pubDate>2020-11-25 06:35:49 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/958843223</guid>
      </item>
      <item>
         <title>Charging &amp; discharging of capacitors.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/958862691</link>
         <description><![CDATA[<div>When t(tau) is small?<br>When t (tau) is large?<br>When R is small?<br>When R is large?<br>t=RC time constant/relaxation time.<br>Try to comment the above statement.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/371dfd5e3cce0ee4d1743dfff5ce1ffb/Cjarging_cap.jpg" />
         <pubDate>2020-11-25 06:46:02 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/958862691</guid>
      </item>
      <item>
         <title>Excersice : A 15.0 uF capacitor is connected to in series to a 1.0 M(Ohm) resistor &amp; a 12 V battery.Determine the time constant, the current &amp; charge accumulation after the charging has progressed for 10.0 second.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/958892908</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2020-11-25 07:00:52 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/958892908</guid>
      </item>
      <item>
         <title>Discharging capacitors</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/978711964</link>
         <description><![CDATA[<div>Discharging capacitors in R-C circuit.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/6a12319a9e018bfb84f9bca3e58d0ab1/What_is_Discharging_a_Capacitor.png" />
         <pubDate>2020-12-02 06:18:08 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/978711964</guid>
      </item>
      <item>
         <title>Exercise (Discharging Capacitors)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/978733049</link>
         <description><![CDATA[<div>A capacitor of capacitance 12.0 uF is charged using a 120 V source to 12.0 uC. It is then connected to a load resistance of 1.0 k(Ohm).Determine:<br><br>-The time constant of the circuit.<br>-The instantaneous current just after the connection.<br>-The current after 5.0 s.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-02 06:31:23 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/978733049</guid>
      </item>
      <item>
         <title>Capacitors with dielectrics.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/978758941</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/f7d49df0750d5a4a68b0d9d6bda5d80d/Capacitors_with_Dielectrics.jpg" />
         <pubDate>2020-12-02 06:46:58 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/978758941</guid>
      </item>
      <item>
         <title>The electric fied in parallel plate capacitor due to the presence of dielectric.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/978765601</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/d11d3f72ad0c8898f22775507a1eade6/cap1.GIF" />
         <pubDate>2020-12-02 06:50:49 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/978765601</guid>
      </item>
      <item>
         <title>The Capacitance of a parallel plate capacitor with dielectric.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/978778687</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/bcbb0c966cb4b4339b81a09512a8987b/156462_sampl7Q28ii_Ist.gif" />
         <pubDate>2020-12-02 06:58:31 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/978778687</guid>
      </item>
      <item>
         <title>Electrical conduction</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1000785211</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/b726d2d0718e1f3b25c60c666a99d377/semiconductors_3_638.jpg" />
         <pubDate>2020-12-09 02:52:45 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1000785211</guid>
      </item>
      <item>
         <title>Current &amp; Drift velocity</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1000789438</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/9b72b78317590706d7a5f81c6b15f851/Drfit_Velocity.png" />
         <pubDate>2020-12-09 02:55:16 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1000789438</guid>
      </item>
      <item>
         <title>Current Density</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1000812588</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/10f0856b19cfcc29af17da4313efe710/Current_density.jpg" />
         <pubDate>2020-12-09 03:08:47 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1000812588</guid>
      </item>
      <item>
         <title>Electrical Conductivity</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1000814310</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/440bf1baa9e8d5a049199120553ac87e/Conductivity.jpg" />
         <pubDate>2020-12-09 03:09:49 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1000814310</guid>
      </item>
      <item>
         <title></title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1000825606</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/712c3f28237a8024dff06a8c1b190f51/ohms_law_formulas.jpg" />
         <pubDate>2020-12-09 03:16:21 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1000825606</guid>
      </item>
      <item>
         <title>Exercise 1 (Current): </title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1012987955</link>
         <description><![CDATA[<div>A cuurent in a piece of wire which makes a complete circuit ia measured to be 1.50 A.<br><br>(1) Determine the amount of charge that pass through a point in the wire after 10.0 s.<br>(b) How many electrons pass the same point after 10.0 s?</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-13 03:15:41 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1012987955</guid>
      </item>
      <item>
         <title>Resistance &amp; Resistivity.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1012992255</link>
         <description><![CDATA[<div>The relation between Resistance &amp; Resistivity.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/50bdf3c863dd07ecb07b82c4ebf669f6/What_are_Resistivity_Laws.png" />
         <pubDate>2020-12-13 03:23:21 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1012992255</guid>
      </item>
      <item>
         <title>Exercise 2 (Current &amp; drift velocity)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1012993621</link>
         <description><![CDATA[<div>A copper wire has a diameter of 2.0 mm &amp; contains 8.5 x 10^28 electrons per cubic meter.If the wire carries a constant current of 5.0 A,what is the drift speed of the electrons?</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-13 03:25:43 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1012993621</guid>
      </item>
      <item>
         <title>Temperature dependence of resistivity.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1012997540</link>
         <description><![CDATA[<div>Alpha = the temperature coefficient of resistivity.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/f7f14133c0b38736914e589e0195bd28/Temp_dependence.png" />
         <pubDate>2020-12-13 03:32:07 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1012997540</guid>
      </item>
      <item>
         <title>Exercise 3: Current Density</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1012999292</link>
         <description><![CDATA[<div>Consider a copper wire with cross sectional area of 2 mm^2. The wire acrries a current of 2.0 A &amp; forms a section of an electrical circuit.<br>(1) How many electrons pass through a section of the wire?<br>(2) What is the current density of the wire?<br>(3) If the wire has 8.5 x 10 ^^28 electrons per m^3,what is the electron drift velocity in the wire?<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-13 03:35:14 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1012999292</guid>
      </item>
      <item>
         <title>Electromotive Force emf</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013007539</link>
         <description><![CDATA[<div>You must be able to differentiate between Emf &amp; PD</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/14a90f846341f714e6f8e779fe3df683/emf_vs_potential_difference.png" />
         <pubDate>2020-12-13 03:50:10 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013007539</guid>
      </item>
      <item>
         <title>Internal Resistance</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013009391</link>
         <description><![CDATA[<div>Relate PD,emf,current &amp; Internal resistance.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/676d01b2ac04869c188acc49a25af6eb/300px_Internal_resistance_svg.png" />
         <pubDate>2020-12-13 03:53:21 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013009391</guid>
      </item>
      <item>
         <title>Exercise 4: Electrical conductivity</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013011902</link>
         <description><![CDATA[<div>A long cylindrical conductor has conductivity σ = 5.88 x 10 ^7 omega^-1 m^-1. Its cross sectional area is 4.0 mm^2.Determine the current density &amp; the electric field acting between two points in the conductor if the conductor passing through it is 5.0 A.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-13 03:57:49 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013011902</guid>
      </item>
      <item>
         <title>Electrical Energy and Power</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013017528</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/049cf8b2ba82f950acf72dfa9f4735a7/GYog0BVRXSn6JVcLB8Jw_29591327116_5205c2180a_o.png" />
         <pubDate>2020-12-13 04:05:51 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013017528</guid>
      </item>
      <item>
         <title>Exercise 5:Resistance &amp; Resistance.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013018331</link>
         <description><![CDATA[<div>A piece of aluminium rod has 2.0 cm diameter &amp; 10 cm long. What is the resistance of the rod at room temperature (20 degree Celcius).</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-13 04:07:26 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013018331</guid>
      </item>
      <item>
         <title>Exercise 6: Variation of resistance with temperature.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013020287</link>
         <description><![CDATA[<div>The resistance of a copper wire at room temeprature (20 degree Celcius) is measured as 30 Ohm.<br>(i) What is its resistance at 100 degree celcius?<br>(ii) What is its resistance at 0 degree celcius?</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-13 04:11:01 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013020287</guid>
      </item>
      <item>
         <title>Resistors: Series + Parallel</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013028447</link>
         <description><![CDATA[<div>Figure shows resistors wired in a combination of series &amp; parallel. We can consider R1 to be the resistance of wires leading to R2 &amp; R3.<br>(1) Find the equivalent resistance of the circuit.<br>(2) What is the potential drop V1 across resistor R1?<br>(3) Find the current I2 through resistor R2.<br>(4) What power is dissipated by R2.<br><br>The diagram to this question will be posted in the whatsapp group.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-13 04:25:32 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013028447</guid>
      </item>
      <item>
         <title>Exercise 7: Internal resistance</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013038833</link>
         <description><![CDATA[<div>A dry cell of 1.5 V has an internal resistance of 0.20 Ohm.What is its terminal voltage when connected across a torchlight which draws a current of 50 mA?</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-13 04:42:59 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013038833</guid>
      </item>
      <item>
         <title>Exercise 8: Internal Resistance</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013047221</link>
         <description><![CDATA[<div>A battery with emf , e = 12.0 V has an internal resistance , r = 2.0 Ohm. When connected in series with an external resistance of 6.0 Ohm,the current in the circuit measures 1.5 A. Analyze &amp; determine the rate of energy conversion in this circuit.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-13 04:56:46 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1013047221</guid>
      </item>
      <item>
         <title>Kirchoff&#39;s law</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014494125</link>
         <description><![CDATA[<div><strong>Kirchhoff's loop rule</strong> states that the sum of all the electric potential differences around a <strong>loop</strong> is zero. It is also sometimes called <strong>Kirchhoff's</strong> voltage law or <strong>Kirchhoff's</strong> second law.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-14 01:17:45 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014494125</guid>
      </item>
      <item>
         <title></title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014495479</link>
         <description><![CDATA[Kirchhoff's Current Law (KCL) is Kirchhoff's first law that deals with the conservation of charge entering and leaving a junction. In other words the algebraic sum of ALL the currents entering and leaving a junction must be equal to zero as: Σ IIN = Σ IOUT.]]></description>
         <enclosure url="" />
         <pubDate>2020-12-14 01:18:31 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014495479</guid>
      </item>
      <item>
         <title>📹Kirchhoff law:An example</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014503846</link>
         <description><![CDATA[<div><br><br></div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/3e051eec7d643b6fc6d99669b41752c2/mesh_current_circuit_diagram_nine.webp" />
         <pubDate>2020-12-14 01:23:24 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014503846</guid>
      </item>
      <item>
         <title>Exercise 9:Electrical Energy &amp; Power</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014509487</link>
         <description><![CDATA[<div>The power rating of a light bulb is 60 W.  How much energy is lost as Joule's heating in 1 hour?</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-14 01:26:28 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014509487</guid>
      </item>
      <item>
         <title>Wheatstone Bridge</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014519070</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2020-12-14 01:32:06 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014519070</guid>
      </item>
      <item>
         <title>📹Wheatstone Bridge</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014519962</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/39847af2db50fffd7c24858326ad0191/7e9a25e4_feba_4b51_b462_8c09496b6d862977596501039952442.png" />
         <pubDate>2020-12-14 01:32:34 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014519962</guid>
      </item>
      <item>
         <title>Exercise 10: Wheatstone bridge</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014521875</link>
         <description><![CDATA[<div>A wheatstone bridge is balanced when R1 = 15 Ohm, R2= 5 Ohm &amp; R3 9 Ohm.Determine the resistance Rx.Try to construct your own diagram for the bridge.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-14 01:33:28 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014521875</guid>
      </item>
      <item>
         <title>Voltage Divider</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014537745</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2020-12-14 01:43:01 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014537745</guid>
      </item>
      <item>
         <title>Exercise 11:Kichhhoff Law</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014543228</link>
         <description><![CDATA[<div>Find the current flowing in the circuit</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-14 01:46:01 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014543228</guid>
      </item>
      <item>
         <title>📹Exercise 10;Kirchoff&#39;s law</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014546240</link>
         <description><![CDATA[<div>Find the currents flowing in the circuit.Hence, determine the power dissipated by the resistors.<br><br></div>]]></description>
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         <pubDate>2020-12-14 01:47:48 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014546240</guid>
      </item>
      <item>
         <title>📹Galvanometer</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014557256</link>
         <description><![CDATA[<div>A <strong>galvanometer</strong> is an electromechanical instrument used for detecting and indicating an electric current. A <strong>galvanometer works</strong> as an actuator, by producing a rotary deflection of a pointer, in response to electric current flowing through a coil in a constant magnetic field.</div>]]></description>
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         <pubDate>2020-12-14 01:53:56 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1014557256</guid>
      </item>
      <item>
         <title>Galvanometer</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033914931</link>
         <description><![CDATA[<div>Moving Coil Galvanometer</div><div>Moving coil galvanometer is an <a href="https://www.toppr.com/bytes/electromagnetism/">electromagnetic</a> device that can measure small values of current. It consists of <a href="https://www.toppr.com/guides/physics/magnetism-and-matter/the-bar-magnet/">permanent horseshoe magnets</a>, coil, soft iron core, pivoted spring, non-metallic frame, scale, and pointer.<br><br><strong>Principle of Moving Coil Galvanometer</strong></div><div><a href="https://www.toppr.com/guides/physics/moving-charges-and-magnetism/torque-current-loop-magnetic-dipole/">Torque</a> acts on a current-carrying coil suspended in the uniform magnetic field. Due to this, the coil rotates. Hence, the deflection in the coil of a moving coil galvanometer is directly proportional to the current flowing in the coil.<br><br><strong>Construction of Moving Coil Galvanometer</strong></div><div>It consists of a rectangular coil of a large number of turns of thinly insulated copper wire wound over a light metallic frame. The coil is suspended between the pole pieces of a horseshoe magnet by a fine phosphor – bronze strip from a movable torsion head. The lower end of the coil is connected to a hairspring of phosphor bronze having only a few turns.</div><div>The other end of the spring is connected to a binding screw. A soft iron cylinder is placed symmetrically inside the coil. The hemispherical magnetic poles produce a radial <a href="https://www.toppr.com/guides/physics/moving-charges-and-magnetism/magnetic-force-and-magnetic-field/">magnetic field</a> in which the plane of the coil is parallel to the magnetic field in all its positions. A small plane mirror attached to the suspension wire is used along with a lamp and scale arrangement to measure the deflection of the coil.<br><strong>Working of Moving Coil Galvanometer</strong></div><div>Let PQRS be a single turn of the coil. A current I flows through the coil. In a radial magnetic field, the plane of the coil is always parallel to the magnetic field. Hence the sides QR and SP are always parallel to the field. So, they do not experience any force. The sides PQ and RS are always perpendicular to the field.</div><div>PQ = RS = <em>l</em>, length of the coil and PS = QR = b, breadth of the coil. Force on PQ, F = BI (PQ) = BI<em>l</em>. According to Fleming’s left-hand rule, this force is normal to the plane of the coil and acts outwards.<br>Force on RS, F = BI (RS) = BI<em>l</em>. This force is normal to the plane of the coil and acts inwards. These two equal, oppositely directed parallel forces having different lines of action constitute a couple and deflect the coil. If there are <em>n</em> turns in the coil, the moment of the deflecting couple = <em>n</em> BI<em>l</em> – b</div><div>Hence the moment of the deflecting couple = <em>n</em>BIA</div><div>The suspension wire twists when the coil deflects. On account of elasticity, a restoring couple is set up in the wire. This couple is proportional to the twist. If θ is the angular twist, then, the moment of the restoring couple = Cθ, where C is the restoring couple per unit twist. At <a href="https://www.toppr.com/guides/chemistry/equilibrium/equilibrium-in-physical-processes/">equilibrium</a>, deflecting couple = restoring couple nBIA = Cθ</div><div>Hence we can write, nBIA = Cθ</div><div>I = (C / nBA) × θ where C is the torsional constant of the spring; i.e. the restoring torque per unit twist. A pointer attached to the spring indicates the deflection θ on the scale.<br>The Sensitivity of Moving Coil Galvanometer</div><div>The sensitivity of a Moving Coil Galvanometer is the ratio of the change in deflection of the galvanometer to the change in current. Therefore we write, Sensitivity = dθ/di. If a galvanometer gives a larger deflection for a small current it is a sensitive galvanometer. The current in Moving Coil galvanometer is: I = (C/nBA) × θ</div><div>Therefore, θ = (nBA/C) × I. Differentiating on both sides wrt I, we have: dθ/di = (nBA/C).</div><div>To sum up, the sensitivity of Moving Coil Galvanometer increases by:</div><ul><li>Increasing the no. of turns and the area of the coil,</li><li>Increasing the magnetic induction and</li><li>Decreasing the couple per unit twist of the suspension fibre.</li></ul><div>Advantages and Disadvantages of Moving Coil Galvanometer</div><div><strong>Advantages</strong></div><ul><li>Sensitivity increases as the value of n, B, A increases and value of k decreases.</li><li>The eddy currents produced in the frame bring the coil to rest quickly, due to the coil wound over the metallic frame.</li></ul><div><strong>Disadvantages</strong></div><ul><li>We cannot change the sensitivity of the galvanometer at will.</li><li>Overloading can damage any type of galvanometer.</li></ul>]]></description>
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         <pubDate>2020-12-20 03:25:35 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033914931</guid>
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      <item>
         <title>Exercise 12: Galvanometer</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033919287</link>
         <description><![CDATA[<div>A galvanometer has resistance of 20 Ohm.The meter has a full-scale deflection of 200 micro-Ampere.<br><br>(i) What is the resistance of a shunt required to be added to the galvanometer n order to build an ammeter with a maximum range of 10.0 A at full-scale reading?<br>(ii) What is the resistance of the ammeter</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-20 03:33:31 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033919287</guid>
      </item>
      <item>
         <title>Voltmeter</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033926341</link>
         <description><![CDATA[<div>Instrument used to measure electric potential difference.<br> Voltmeters measure the electric potential drop across components. The voltmeter is placed in parallel with the component of interest because components in parallel experience the same potential difference. </div>]]></description>
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         <pubDate>2020-12-20 03:46:45 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033926341</guid>
      </item>
      <item>
         <title>Voltmeter</title>
         <author>nabil01najmi</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033928459</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-12-20 03:50:33 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033928459</guid>
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      <item>
         <title>Voltmeter</title>
         <author>nashrah7</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033928460</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-12-20 03:50:33 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033928460</guid>
      </item>
      <item>
         <title>voltmeter</title>
         <author>nz_amirh</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033928536</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-12-20 03:50:42 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033928536</guid>
      </item>
      <item>
         <title>VOLTMETER</title>
         <author>sitinorsyazwina33</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033928643</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-12-20 03:50:55 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033928643</guid>
      </item>
      <item>
         <title>Voltmeter</title>
         <author>fionteo1023</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033928648</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-12-20 03:50:55 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033928648</guid>
      </item>
      <item>
         <title>Voltmeter</title>
         <author>teosang</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033929066</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-12-20 03:51:38 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033929066</guid>
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      <item>
         <title>VOLTMETER</title>
         <author>nurhusnadzamrah01</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033929164</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-12-20 03:51:49 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033929164</guid>
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      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033929547</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/839299279/838846b302e27b4cbdba317d66dd8ba5/volmeter_em_padlet.jpg" />
         <pubDate>2020-12-20 03:52:32 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033929547</guid>
      </item>
      <item>
         <title>Voltmeter</title>
         <author>atiqahyu975</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033929785</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://2.bp.blogspot.com/-Pm5Fys_zO6s/VZ5SXpaFn6I/AAAAAAAAALo/yQIgy9IFBRk/s1600/AC051738l.jpg" />
         <pubDate>2020-12-20 03:52:56 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033929785</guid>
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      <item>
         <title>Exercise 13: Voltmeter</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033929799</link>
         <description><![CDATA[<div>A full scale voltmeter of 10.0 V is constructed by connecting a multiplier of resistance ,R in series with a galvanometer. what is the suitable value of R required? The galvanometer has resistance of 50 Ohm &amp; its full scale deflection is 2.5 x 10^-4  A.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-20 03:52:58 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1033929799</guid>
      </item>
      <item>
         <title>Magnetic Field</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1034956102</link>
         <description><![CDATA[<div>A <strong>magnetic field</strong> is a vector <strong>field</strong> that describes the <strong>magnetic</strong> influence on moving electric charges, electric currents, and <strong>magnetic</strong> materials. A charge that is moving in a <strong>magnetic field</strong> experiences a force perpendicular to its own velocity and to the <strong>magnetic field</strong>.</div><div><a href="https://en.wikipedia.org/wiki/Magnetic_field"><br></a><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-21 01:12:08 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1034956102</guid>
      </item>
      <item>
         <title>Magnetic Field Sources</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1034959754</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/f58a187c273b16afb2f52edfb35e7b05/magneitc_sources.png" />
         <pubDate>2020-12-21 01:14:30 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1034959754</guid>
      </item>
      <item>
         <title>Demagnetization &amp; Terrestrial Magnetism.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1034969298</link>
         <description><![CDATA[<div>The process of reducing or removing the magnetism of a ferromagnetic material. The reduction of magnetic induction by the internal field of a magnet.<br><br>How do you demagnetize?<br>A small piece of <strong>steel</strong> can be struck with a hammer to <strong>demagnetize</strong> it. Place the item on a hard, secure, non-metallic surface and hit it sharply a few times with a hammer. The shock of being struck transmits energy through the <strong>steel</strong>, which rearranges the order of its atoms and lowers its magnetic output. <br><br>Terrestrial Magnetism.<br>1 : the <strong>magnetism</strong> of the earth. 2 : a branch of geophysics that deals with the phenomena of the earth's magnetic condition.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-21 01:20:11 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1034969298</guid>
      </item>
      <item>
         <title>Magnetic field produced by current carrying conductor</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1034993770</link>
         <description><![CDATA[<div>The force of magnetism is due to moving charge or some <strong>magnetic</strong> material. Like stationary charges <strong>produce</strong> an electric <strong>field</strong> proportional to the magnitude of charge, moving charges <strong>produce magnetic fields</strong> proportional to the <strong>current</strong>. In other words, a <strong>current carrying conductor produces</strong> a <strong>magnetic field</strong> around it.</div>]]></description>
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         <pubDate>2020-12-21 01:35:20 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1034993770</guid>
      </item>
      <item>
         <title>Fields Due to Currents</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1035002830</link>
         <description><![CDATA[<div>Right hand screw</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/d530ea019456385238c31e32c4f84291/Right_hand_screw.jpg" />
         <pubDate>2020-12-21 01:41:09 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1035002830</guid>
      </item>
      <item>
         <title>Exercise (magnetic field)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1035006167</link>
         <description><![CDATA[<div>A magnetic field of 5.5 x 10^-4 T crosses an xy-plane at an angle of 60 degree.Determine the magnetic flux density or strength of the field.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-21 01:43:14 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1035006167</guid>
      </item>
      <item>
         <title>Exercise: Magnetic field</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1035018425</link>
         <description><![CDATA[<div>Distinguish between the following terms used to describe a magnetic field.<br><br>a) Line<br>b)strength<br>c)Flux density</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-21 01:50:51 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1035018425</guid>
      </item>
      <item>
         <title>Force on a moving Charged Particle in a Uniform Magnetic field.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039406882</link>
         <description><![CDATA[<div>The <strong>magnetic force</strong> on a free <strong>moving charge</strong> is perpendicular to both the velocity of the <strong>charge</strong> and the <strong>magnetic field</strong> with direction given by the right hand rule. The <strong>force</strong> is given by the <strong>charge</strong> times the vector product of velocity and <strong>magnetic field</strong>.</div>]]></description>
         <pubDate>2020-12-23 06:12:36 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039406882</guid>
      </item>
      <item>
         <title>Force on a moving charge in a uniform magnetic field (part 2)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039413493</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/0cf1b2e684d44d38d0c0e9c579b98526/qvb2.png" />
         <pubDate>2020-12-23 06:18:23 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039413493</guid>
      </item>
      <item>
         <title>force on a moving charge in a uniform magnetic field (part 3)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039414973</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-12-23 06:19:45 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039414973</guid>
      </item>
      <item>
         <title>Exercise:Force on a moving charge in a uniform magnetic field</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039416575</link>
         <description><![CDATA[<div>A proton moves with a speed of 1.0 x 10^5 m/s through the earth's magnetic field.When the proton moves eastward, it experiences a maximum magnetic force of 8.8 x 10^-19 N. What is the magnetic strength of the Earth's magnetic field at that location? (State the direction of B )</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-23 06:21:18 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039416575</guid>
      </item>
      <item>
         <title>Exercise:force on a moving charge in a uniform magnetic field</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039427544</link>
         <description><![CDATA[<div> A proton moves along the x-axis with velocity of 4.0 x 10 ^6 m/s. It enters a region where there is a magnetic field of 3.0 T directed at an angle of 50 degree with the x-axis &amp; lying in the x-y plane.Determine the initial force &amp; acceleration experience by the proton.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-23 06:31:56 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039427544</guid>
      </item>
      <item>
         <title>Force on a current carrying Conductor in a uniform magnetic field.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039444121</link>
         <description><![CDATA[<div>If a current-carrying conductor is placed perpendicular to a magnetic field, that conductor will experience a force. This is the principle behind the operation of all electric motors.<em><br></em><br></div><div>In Figure 1(a), a conductor is carrying current away from us, and is placed between the poles of a permanent magnet. The right-hand screw rule gives the direction of the flux lines around this conductor as clockwise, thus they reinforce the flux from the magnet above the conductor and oppose the flux from the magnet below the conductor.<br><br></div><div>The result of the interaction between these fluxes is shown in Figure 1(b). The flux field above the conductor is strong and the lines are compressed. The flux field below the conductor is weak and flux lines are far apart. The tendency for the compressed lines to want to straighten and move further apart will exert a force on the conductor, attempting to push it downwards and out of the field.<br><br></div><div>If the conductor current is reversed, or the magnet poles are reversed, this force will happen in the opposite direction and will push the conductor upwards.<br><br></div>]]></description>
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         <pubDate>2020-12-23 06:46:55 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039444121</guid>
      </item>
      <item>
         <title>Fleming’s Left-hand Rule</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039449957</link>
         <description><![CDATA[<div>Refer to Figure 2(a). This gives an expression for the magnitude of the force on the conductor, and the respective directions of the force, the magnetic field and the current.<br>The conductor is assumed to be perpendicular to the field.<br><br></div><div><strong><em>F = B * i * l<br></em></strong><br></div><div>Where: <strong><em>F</em></strong> = force (newtons, N); <strong><em>B</em></strong> = field flux density (teslas, T )<br> <strong><em>i</em></strong> = current in conductor (amperes, A); <em>l </em>= length of conductor (metres, m)<br><br></div><div>The three directions can be related to each other by using Fleming’s left-hand rule, as depicted in Figure 2(b). Stated in words, this rule is:<br><br></div><div>If the thumb and first two fingers of the left hand are held mutually at right angles to each other, and the <strong><em>f</em></strong>orefinger points in the direction of the magnetic <strong><em>f</em></strong>ield or <strong><em>f</em></strong>lux, and the m<strong><em>i</em></strong>ddle finger points in the direction of the current <strong><em>i </em></strong>, then the thu<strong><em>m</em></strong>b will point in the direction of the <strong><em>m</em></strong>otion.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/adf788469c571cddae0690177af0e6fc/fleming.jpg" />
         <pubDate>2020-12-23 06:52:09 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039449957</guid>
      </item>
      <item>
         <title>(Force on a current carrying conductor in a uniform magnetic field).</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039460423</link>
         <description><![CDATA[<h1>Force on a current in a magnetic field</h1><div>The strength of a magnetic field is usually measured in terms of a quantity called the magnetic flux density of the field, B. A definition of B requires a consideration of the forces produced by electromagnetic fields.<br><br> When a wire carrying a current is placed in a magnetic field the wire experiences a force due to the interaction between the field and the moving charges in the wire. A very good demonstration is the so-called catapult field experiment in which a wire carrying a d.c. current can be made to move in the field of two flat magnets.<br><br></div><div><br></div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/7645d72dba213d92bc2d0d682c206238/1.PNG" />
         <pubDate>2020-12-23 07:01:30 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1039460423</guid>
      </item>
      <item>
         <title>Force on a current carrying conductor in a uniform magnetic field).-Continue</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1043442607</link>
         <description><![CDATA[<div> The fields of the wire, the magnets and the combined fields are shown in Figures 1,2 and 3. Notice that the wire moves away from the area of highest field intensity (where the magnetic field lines are closest) to a region lower intensity. <br> The force F on the wire in Figure 4 can be shown to be proportional to<br>(a) the current on the wire I,<br>(b) the length of the conductor in the field L,<br>(c) the sine of the angle θ that the conductor makes with the field , and<br>(d) the strength of the field - this is measured by a quantity known as the magnetic flux density B of the field. The force is given by the equation: <br><br> Force on current in magnetic field: <br> F = BIL sin θ <br> The units for B are tesla (T). <br> The special case is when the wire is at right angles to the field (that is θ = 90<sup>o</sup>). This gives the greatest force on the wire. (See Figure 5) <br> The flux density of a field of one tesla is therefore defined as the force per unit length on a wire carrying a current of one ampere at right angles to the field. <br><strong>Exercise :</strong><br> Calculate the force on a power cable of length 200 m carrying a current of 200 A in a direction N 300E at a place where the horizontal component of the Earth's magnetic field is 10<sup>-5</sup> T. </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/0ace8c7dd5351c7c533d8b4a3b9cb469/2.png" />
         <pubDate>2020-12-28 01:21:34 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1043442607</guid>
      </item>
      <item>
         <title>Exercise:Force on a current carrying conductor in a uniform magnetic field).</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1043462252</link>
         <description><![CDATA[<div>A wire carries current of 18 A in the direction of east to west is placed horizontally on a location where the earth's magnetic field is directed from south to north.Determine the force on a 40 m length of wire if the magnitude of the Earth's magnetic field is 5.5 x 10^-5 T.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-28 01:34:48 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1043462252</guid>
      </item>
      <item>
         <title>Exercise:Force on a current carrying conductor in a uniform magnetic field).</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1043477702</link>
         <description><![CDATA[<div>A wire has a mass of 1.00 g/cm is placed on a horizontal surface with a coefficient of friction of 0.250. A current of 3A flows eastward inside the wire while it is moved to the north horizontally. Determine the direction &amp; the minimum magnetic field experiences by the wire.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-28 01:45:34 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1043477702</guid>
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      <item>
         <title>Excercise: Biot -Savart Law</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1043490126</link>
         <description><![CDATA[<div>A circular coil consisting of a single loop of wire has a radius of 35.0 cm &amp; carries a current of 30 A.Determine the magnetic field of the wire at the centr of the loop?</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-12-28 01:54:25 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1043490126</guid>
      </item>
      <item>
         <title>📹The Bio-Savart Law</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1043492022</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/8a51797f29535deaf590b2fea787ca65/Statement_of_Biot_Savart_u2019s_Law.jpg" />
         <pubDate>2020-12-28 01:55:53 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1043492022</guid>
      </item>
      <item>
         <title>Magnetic flux density of a circular coil</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049276316</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/96519b17a2b959a7b5aea8cf09909db1/sd.jpg" />
         <pubDate>2021-01-03 03:15:59 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049276316</guid>
      </item>
      <item>
         <title>Magnetic flux density of a very long straight wire</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049277524</link>
         <description><![CDATA[<div>Determine the magnetic field at a point 2.0 cm from a long straight wire carrying a current of 10 A. </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/f88fa652f532dc143daf142cff3bd1a5/magfund042.gif" />
         <pubDate>2021-01-03 03:18:48 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049277524</guid>
      </item>
      <item>
         <title>Magnetic flux density of a very long Solenoid</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049281275</link>
         <description><![CDATA[<div>A solenoid of 200 turns has a length of 20.0 cm.<br>(i) Find the magnetic field inside the solenoid if it carries current of 0.600 A.<br>(ii) If the magnetic field just outside the north pole of the solenoid can be considered has the same value as that calculated in (i), determine the magnitude &amp; direction of the magnetic force acting on an electron moving at 400 m/s from downwards to upwards perpendicularly crossing the magnetic field lines at that location.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/ce22d23bbcbebce12b3cecbc41007688/SOLENOID.png" />
         <pubDate>2021-01-03 03:26:45 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049281275</guid>
      </item>
      <item>
         <title>Forces between two parallel current carrying conductors</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049286676</link>
         <description><![CDATA[<div>Two wires with a weight per unit length of 1.0 x 10^-4 N/m each are positioned parallel to each other above the earth's surface. The wire aligned one above the other in a north south direction to avoid the influence of the Earth's magnetic field. Determine the current in each wire for the lower wire to levitate from the upper wire if they are separated 0.20 m apart.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/eb0dd059cd7a251bdf343e642f0a4a7e/Forces.JPG" />
         <pubDate>2021-01-03 03:38:51 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049286676</guid>
      </item>
      <item>
         <title>Torque on a Current Loop.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049296350</link>
         <description><![CDATA[<div>Figure 2: Top views of a current-carrying loop in a magnetic field. (a) The equation for torque is derived using this view. Note that the perpendicular to the loop makes an angle <em>θ</em> with the field that is the same as the angle between w/2 and F. (b) The maximum torque occurs when<em> θ</em> is a right angle and sin <em>θ </em>= 1. (c) Zero (minimum) torque occurs when θ is zero and sin <em>θ </em>= 0. (d) The torque reverses once the loop rotates past <em>θ</em> = 0. </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/cbfdf664d46833d1b9c95463cf3214d4/Figure_23_08_02a.jpg" />
         <pubDate>2021-01-03 03:55:35 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049296350</guid>
      </item>
      <item>
         <title>Torque on a current loop (part 2)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049300616</link>
         <description><![CDATA[<div>Figure 1: Torque on a current loop. A current-carrying loop of wire attached to a vertically rotating shaft feels magnetic forces that produce a clockwise torque as viewed from above. <br><br><em>Motors</em> are the most common application of magnetic force on current-carrying wires. Motors have loops of wire in a magnetic field. When current is passed through the loops, the magnetic field exerts torque on the loops, which rotates a shaft. Electrical energy is converted to mechanical work in the process. (See Figure 1.) <br><br>Let us examine the force on each segment of the loop in Figure 1 to find the torques produced about the axis of the vertical shaft. (This will lead to a useful equation for the torque on the loop.) We take the magnetic field to be uniform over the rectangular loop, which has width <em>w</em> and height <em>l</em>. First, we note that the forces on the top and bottom segments are vertical and, therefore, parallel to the shaft, producing no torque. Those vertical forces are equal in magnitude and opposite in direction, so that they also produce no net force on the loop. Figure 2 shows views of the loop from above. Torque is defined as <em>τ</em> = <em>rF </em>sin <em>θ</em>, where <em>F</em> is the force, <em>r</em> is the distance from the pivot that the force is applied, and <em>θ</em> is the angle between <em>r</em> and <em>F</em>. As seen in Figure 2(a), right hand rule 1 gives the forces on the sides to be equal in magnitude and opposite in direction, so that the net force is again zero. However, each force produces a clockwise torque. Since <em>r </em>= <em>w</em>/2, the torque on each vertical segment is (<em>w</em>/2)<em>F</em> sin <em>θ</em>, and the two add to give a total torque.</div><div>τ=w2Fsinθ+w2Fsinθ=wFsinθ<br><br> Now, each vertical segment has a length <em>l</em> that is perpendicular to <em>B</em>, so that the force on each is F=IlB</div><div>. Entering <em>F</em> into the expression for torque yields</div><div>τ=wIlBsinθ</div><div>.</div><div>If we have a multiple loop of <em>N</em> turns, we get <em>N</em> times the torque of one loop. Finally, note that the area of the loop is <em>A = wl</em>; the expression for the torque becomes</div><div>τ=NIABsinθ</div><div>.</div><div>This is the torque on a current-carrying loop in a uniform magnetic field. This equation can be shown to be valid for a loop of any shape. The loop carries a current <em>I</em>, has <em>N</em> turns, each of area <em>A</em>, and the perpendicular to the loop makes an angle <em>θ</em> with the field <em>B</em>. The net force on the loop is zero.</div>]]></description>
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         <pubDate>2021-01-03 04:01:44 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049300616</guid>
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      <item>
         <title>Exercise:Torque on a coil</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049305771</link>
         <description><![CDATA[<div> Find the maximum torque on a 100-turn square loop of a wire of 10.0 cm on a side that carries 15.0 A of current in a 2.00-T field. </div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-03 04:08:59 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049305771</guid>
      </item>
      <item>
         <title>J.J. Thomson experiment to determine the specific charge of an electron (cathode ray)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049318840</link>
         <description><![CDATA[<div> The specific charge of an electron can be determined when electron moves in both magnetic field and electric field which are mutually perpendicular to each other so that the net force on the electron is made zero. IN this situation the direction of motion of electron remains perpendicular to both electric and magnetic field.<br> <strong>Construction:</strong><br> <strong> </strong>The experimental setup shown in the figure shows the modern J.J. Thomson experiment to determine the specific charge of the electron. It consists of discharge tube in which two electrodes anode (A) and cathode(C) are present P<sub>1</sub> and P<sub>2</sub> are two parallel electric plates to generate electric field strength (E).<br> <strong>Working Principle: (Theory):</strong><br> When sufficient amount of potential (V) is applied between the two electrodes electrons emitted from the cathode accelerate with velocity ‘v’ then<br> When the charge particle moves under the action of electric field strength (E) it moves towards the +ve plate and finally incident at point O, at fluorescent screen. In case of applying magnetic field only, the charge particle deviate and finally incident at 0<sub>2</sub> as shown in figure.<br> If both magnetic and electric field are applied and their magnitude and direction is adjusted so that the charged particles move without deviation. At this condition charge particle incident at point O at the fluorescent screen,<br> Then,<br> We have<br> Where, B is magnetic field strength. In this case the direction of magnetic field is perpendicular to the direction of the motion of the charged particle.<br> From equation (i) and (ii),<br> We get,Hence, the specific charge at the electron is determined if the values of E, B and V are known.<br> The experimentally obtained specific charge of the electron is 1.7 into 10<sup>11</sup> c/kg. </div>]]></description>
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         <pubDate>2021-01-03 04:22:50 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049318840</guid>
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      <item>
         <title>Exercise: J.J . Thompson </title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049321776</link>
         <description><![CDATA[<div>A charged particle of + 3.0 micro Coulomb has a kinetic energy of 0.10 J. The cahrge is placed in a uniform magnetic field of 0.25 T.If the particle moves in a circular path of radius 3.5 m,determine its mass.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-03 04:25:53 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049321776</guid>
      </item>
      <item>
         <title>Hall effect</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049332175</link>
         <description><![CDATA[<div>Whenever we place a current carrying conductor in a magnetic field, there is a deflection of the charge carriers due influence of magnetic field in the conductor body. We call this typical phenomenon as Hall effect. Edwin Hall in 1879 had first observed the phenomenon, and hence we call this as Hall effect.</div><div>Mainly Lorentz force is responsible for <strong>Hall effect</strong>. All of we know that when we place a <a href="https://www.electrical4u.com/a-current-carrying-conductor-within-a-magnetic-field/">current carrying conductor inside a magnetic field</a>, the conductor experiences a mechanical force to a direction depending upon the direction of <a href="https://www.electrical4u.com/magnetic-field/">magnetic field</a> and the direction of current in the conductor. The <a href="https://www.electrical4u.com/electric-current-and-theory-of-electricity/">electric current</a> means a flow of charge. In metal it is entirely due to the flow of electrons, in <a href="https://www.electrical4u.com/theory-of-semiconductor/">semiconductor</a>, it is due to flow of free electrons as well as holes. In semiconductor, holes move in the direction of conventional current and free electrons move in the opposite of the direction of conventional current. As the electrons have charge, they experience a force while flowing through a <a href="https://www.electrical4u.com/electrical-conductor/">conductor</a> placed inside a magnetic field. Due to this force, the electrons get diverted towards one side of the conducted during flowing. As the following charges get shifted to one side of the conductor, there may be a tiny potential difference appeared across the cross-section of the conductor. We call this entire phenomenon as hall effect.<br><br></div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/d5e2d5d4f129c546a58fba075aa8984a/What_are_the_Applications_of_Hall_Effect.png" />
         <pubDate>2021-01-03 04:36:08 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049332175</guid>
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      <item>
         <title>Hall effect (part 2)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049335011</link>
         <description><![CDATA[<div>After applying a <a href="https://www.electrical4u.com/voltage-or-electric-potential-difference/">voltage</a> across it current, “I” starts flowing from left to right that is along the x-direction. We place the metal block in a magnetic field of density “B”. The direction of the magnetic field along the y-axis. Now by Fleming’s Left-Hand Rule, the charge carriers will experience a force depending on both – direction of current and direction of <a href="https://www.electrical4u.com/magnetic-field/">magnetic field</a>. As per Fleming’s rule, the conduction electrons will deflect towards the bottom of the block. As a result, there will be a change in concentration of electrons at upper and lower portion of the block. Consequently, a tiny potential difference appears across the block along the z-axis. The <a href="https://www.electrical4u.com/what-is-electric-field/">electric field</a> created due to this shifting of electrons also opposes the shifting of electrons towards the surface of the metal block. Hence there may be two forces acting on the charge carriers.</div><ol><li>The force due to Hall effect</li><li>The force due to created electric field</li></ol><div>These forces are opposite to each other. After the establishment of the certain electric field due to <strong>Hall effect</strong> the system becomes in equilibrium. At that condition the force acting on the charge carriers (conduction electrons) due to the established electric field and due to Hall effect become same, and opposite. Hence there would not be any further shifting of electrons towards the surface of the block and the system become in an equilibrium condition.<br> Let us concentrate on a single charge carrier moving through a <a href="https://www.electrical4u.com/electrical-conductor/">conductor</a> placed inside a magnetic field.<br> The charge of the charge carrier is e (say)<br> The magnetic flux density of the field is B (say).<br> Now we can write the magnetic force acting on the current carrying conductor of active length L and current I as<br> <br> When the direction of B and I are perpendicular to each other.</div><div>We can rewrite the above equation as<br> <br> Where V is the velocity of the charge passing through the conductor.</div><div>From the above equation, we can write the force acting on a single charge carrier as,<br> <br> Where v is the drift velocity of the charge carriers.<br> Now we can write the field created due to <strong>Hall effect</strong> as, E<sub>H</sub>.<br> Hence, we can write the force acting on the charge carrier due to the field as<br> <br> Now at equilibrium<br> <br> Now we consider N is charge carrier concentration.<br> <br> From equation 1 and 2, we can write<br> <br> We call the term  as the Coefficient of Hall Effect or simply Hall Coefficient. We define Hall Coefficient as the Hall field per unit magnetic field density per unit current density.<br><br><strong>Hall effect</strong> is a very useful phenomenon and helps to<br> Determine the Type of Semiconductor<br> By knowing the direction of the Hall Voltage, one can determine that the given sample is whether <a href="https://www.electrical4u.com/n-type-semiconductor/">n-type semiconductor</a> or <a href="https://www.electrical4u.com/p-type-semiconductor/">p-type semiconductor</a>. This is because Hall coefficient is negative for n-type semiconductor while the same is positive in the case of p-type semiconductor.</div><div>Calculate the Carrier Concentration<br> The expressions for the carrier concentrations of electrons (n) and holes (p) in terms of Hall coefficient are given by<br> </div><div>Determine the Mobility (Hall Mobility)<br> Mobility expression for the electrons (μ<sub>n</sub>) and the holes (μ<sub>p</sub>), expressed in terms of Hall coefficient is given by,<br> <br> Where, σ<sub>n</sub> and σ<sub>p</sub> represent the <a href="https://www.electrical4u.com/electrical-conductivity-of-metal-semiconductor-and-insulator/">conductivity</a> due to the electrons and the holes, respectively.</div><div>Measure Magnetic Flux Density<br> This equation can be readily deduced from the equation of Hall voltage and is given by<br> <br> Further, there are many commercially available types of equipment based on the principle of Hall effect including Hall-effect sensors and Hall-effect probes.</div>]]></description>
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         <pubDate>2021-01-03 04:38:46 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049335011</guid>
      </item>
      <item>
         <title>Exercise : (Hall Effect)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049501204</link>
         <description><![CDATA[<div>A strip of metal has dimension of 1.2 cm wide &amp; 1.5 x 10^-3 cm thick. It carries current of 0.50 A along its length.If the metal contains 5 x 10^22 electrons per cm^3,determine the mean drift velocity of these electrons.</div>]]></description>
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         <pubDate>2021-01-03 07:04:06 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049501204</guid>
      </item>
      <item>
         <title>Electromagnetic Induction.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049508224</link>
         <description><![CDATA[<div>Electromagnetic Induction or Induction is a process in which a <a href="https://www.toppr.com/guides/physics/electric-charges-and-fields/conductors-and-insulators/">conductor</a> is put in a particular position and magnetic field keeps varying or <a href="https://www.toppr.com/guides/magnetic-effects-of-electric-current/magnetic-field-and-magnetic-force/">magnetic field</a> is stationary and a conductor is moving. This produces a Voltage or  EMF (Electromotive Force) across the electrical conductor. Michael Faraday discovered Law of Induction in 1830. <br>Suppose while shopping you go cashless and  your parents use cards. The shopkeeper always scans or swipes the card. Shopkeeper does not take a photo of the card or tap it.  Why does he swipe/scan it? And how does this swiping deduct money from the card? This happens because of the ‘<strong>Electromagnetic Induction</strong>’.</div><div>Can moving objects produce <a href="https://www.toppr.com/guides/physics/electricity/electric-current-and-circuit-diagrams/">electric currents</a>? How to determine a relationship between electricity and magnetism? Can you imagine the scenario if there were no computers, no telephones, no electric lights. The experiments of Faraday has led to the generation of generators and transformers.<br>The induction of an electromotive force by the motion of a conductor across a magnetic field or by a change in magnetic flux in a magnetic field is called <strong>‘Electromagnetic Induction’.</strong></div><div>This either happens when a conductor is set in a moving magnetic field (when utilizing AC power source) or when a conductor is always moving in a stationary magnetic field.<br> This law of electromagnetic induction was found by <strong>Michael Faraday.</strong> He organized a leading wire according to the setup given underneath, connected to a gadget to gauge the voltage over the circuit. So when a bar magnet passes through the snaking, the voltage is measured in the circuit. The importance of this is a way of producing electrical energy in a circuit by using magnetic fields and not just batteries anymore. The machines like generators,  transformers also the motors work on the principle of electromagnetic induction. </div><div> </div>]]></description>
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         <pubDate>2021-01-03 07:10:10 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049508224</guid>
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      <item>
         <title>Faraday&#39;s law</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049522245</link>
         <description><![CDATA[<div> Any change in the magnetic environment of a coil of wire will cause a voltage (emf) to be "induced" in the coil. No matter how the change is produced, the voltage will be generated. The change could be produced by changing the magnetic field strength, moving a magnet toward or away from the coil, moving the coil into or out of the magnetic field, rotating the coil relative to the magnet, etc. </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/98650a66b5dd37f6ed0ea769423ccdf1/farlaw.png" />
         <pubDate>2021-01-03 07:22:55 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049522245</guid>
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      <item>
         <title>Faraday&#39;s law (part 2)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049524962</link>
         <description><![CDATA[<div> Faraday's law is a fundamental relationship which comes from <a href="http://hyperphysics.phy-astr.gsu.edu/hbase/electric/maxeq2.html#c3">Maxwell's equations</a>. It serves as a succinct summary of the ways a <a href="http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elevol.html#c1">voltage</a> (or emf) may be generated by a changing magnetic environment. The induced emf in a coil is equal to the negative of the rate of change of <a href="http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/fluxmg.html#c1">magnetic flux</a> times the number of turns in the coil. It involves the interaction of charge with magnetic field. </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/0a42da938c4d4a13f1b1384b5c30f252/Faradys.png" />
         <pubDate>2021-01-03 07:25:08 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049524962</guid>
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      <item>
         <title>Exercise (Faraday&#39;s Law)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049529956</link>
         <description><![CDATA[<div>A square frame of 20 cm x 20 cm is wrapped with 250 turns of wire. The total resistance of the coil is 2.50 Ohm. The coil is situated in a uniform magnetic field where the plane is perpendicular to the field. Determine the magnitude of the induced e.m.f in the coil when the magnetic field is changed from 0 to 0.600 T in 0.75 s.Calculate the induced current generated when the field is changing.</div>]]></description>
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         <pubDate>2021-01-03 07:29:12 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1049529956</guid>
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      <item>
         <title>Lenz Law</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1050501080</link>
         <description><![CDATA[<div><strong>Lenz’s law of electromagnetic induction</strong> states that the direction of the current induced in a conductor by a changing magnetic field (as per <a href="https://www.electrical4u.com/faraday-law-of-electromagnetic-induction/">Faraday’s law of electromagnetic induction</a>) is such that the <a href="https://www.electrical4u.com/magnetic-field/">magnetic field</a> created by the induced <a href="https://www.electrical4u.com/electric-current-and-theory-of-electricity/">current</a> <strong><em>opposes</em></strong> the initial changing magnetic field which produced it. The direction of this current flow is given by <a href="https://www.electrical4u.com/fleming-left-hand-rule-and-fleming-right-hand-rule/">Fleming’s right hand rule</a>.</div><div>This can be hard to understand at first – so let’s look at an example problem. Remember that when a current is induced by a magnetic field, the magnetic field that this induced current produces will create its own magnetic field. This magnetic field will always be such that it <strong><em>opposes</em></strong> the magnetic field that originally created it. In the example below, if the magnetic field “B” is increasing – as shown in (1) – the <strong><em>induced</em></strong> magnetic field will act in opposition to it.<br>When the magnetic field “B” is decreasing – as shown in (2) – the <strong><em>induced</em></strong> magnetic field will again act in opposition to it. But this time ‘in opposition’ means that it is acting to increase the field – since it is opposing the decreasing rate of change.</div><div>Lenz’s law is based on Faraday’s law of induction. Faraday’s law tells us that a changing magnetic field will induce a current in a <a href="https://www.electrical4u.com/electrical-conductor/">conductor</a>. Lenzs law tells us the <strong><em>direction</em></strong> of this induced current, which <strong><em>opposes</em></strong> the initial changing magnetic field which produced it. This is signified in the formula for Faraday’s law by the negative sign (‘–’).</div><div><br></div><div>This change in the magnetic field may be caused by changing the magnetic field strength by moving a magnet towards or away from the coil, or moving the coil into or out of the magnetic field. In other words, we can say that the magnitude of the EMF induced in the circuit is proportional to the rate of change of <a href="https://www.electrical4u.com/what-is-flux-types-of-flux/">flux</a>.</div><div><br></div><div>Lenz’s Law Formula</div><div><br></div><div><strong>Lenz’s law</strong> states that when an EMF is generated by a change in <a href="https://www.electrical4u.com/magnetic-flux/">magnetic flux</a> according to Faraday’s Law, the polarity of the induced EMF is such, that it produces an induced current whose magnetic field opposes the initial changing magnetic field which produced it</div><div>The negative sign used in Faraday’s law of electromagnetic induction, indicates that the induced EMF (ε) and the change in magnetic flux (δΦ<sub>B</sub>) have opposite signs. The formula for Lenz’s law is shown below:</div><div><br></div><div>Where:</div><ul><li>ε = Induced emf</li><li>δΦ<sub>B</sub> = change in magnetic flux</li><li>N = No of turns in coil</li></ul>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/75a238a2fb241afa8419e2c6d5098a50/lenz_law_of_electromagnetic_induction.png" />
         <pubDate>2021-01-04 01:06:26 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1050501080</guid>
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      <item>
         <title>Induced e.m.f (staright conductor)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1050519319</link>
         <description><![CDATA[<div> When a straight conductor is moved through a magnetic field an emf is induced between its ends. This movement must be in such a direction that the conductor cuts through the lines of magnetic flux, and will be a maximum when it moves at right angles to the field .<br> Let the length of the conductor be L and the flux density of the field be B.<br>If the conductor moves with velocity v at right angles to the field then the flux cut per second will be BvL (since the conductor will sweep out an area vL every second).<br><br>But the rate of cutting flux is equal to the e.m.f. induced in the conductor. Therefore<br><br><br></div><div> E = BL v </div><div><br> If the conductor cuts through the flux at an angle θ ((b) in Figure 1), where θ is the angle between the magnetic field and the direction of motion, the equation becomes<br><br><br></div><div> E = BLvsinθ </div><div><br>You can see that the maximum e.m.f is generated when the conductor moves at right angles to the field. (θ = 90<sup>o</sup> and so sinθ = sin90 = 1). </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/74a6e23cc2585b98cee0ee329caa550e/1.png" />
         <pubDate>2021-01-04 01:17:07 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1050519319</guid>
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         <title>Exercise (emf straight conductor)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1050522410</link>
         <description><![CDATA[<div> 1. Calculate the emf generated between the wing tips of an aircraft that is flying horizontally at 200 ms-1 in a region where the vertical component of the Earth's magnetic field is 4.0 x 10<sup>-5</sup> T , if the aircraft has a wingspan of 25 m. <br><br><br><br><br></div>]]></description>
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         <pubDate>2021-01-04 01:18:52 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1050522410</guid>
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      <item>
         <title>Induced emf for rotating coil</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1050533804</link>
         <description><![CDATA[<div> 2. Calculate the e.m.f. generated between the fixed and the free ends of a helicopter blade 9.45 m long that is rotating at 3.5 revs per second. <br> The vertical component of the Earth's field has a flux density of 4.0 x 10<sup>-5</sup> T. </div>]]></description>
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         <pubDate>2021-01-04 01:25:16 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1050533804</guid>
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         <title>Induced emf &amp; electric field induction (Generators)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1050561365</link>
         <description><![CDATA[<div> The generator coil shown in Figure 1 is rotated through one-fourth of a revolution (from <em>θ</em> = 0º to <em>θ</em> = 90º ) in 15.0 ms. The 200-turn circular coil has a 5.00 cm radius and is in a uniform 1.25 T magnetic field. What is the average emf induced? <br>Hence, calculate the maximum emf, emf<sub>0</sub>, of the generator .</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/1bb66474815893d5d79c522400fedbb1/Figure_24_05_01.jpg" />
         <pubDate>2021-01-04 01:41:59 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1050561365</guid>
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         <title>Electric motors</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1058393940</link>
         <description><![CDATA[<div>A <strong>motor</strong> has coils turning inside magnetic fields, and a coil turning inside a magnetic field <strong>induces</strong> an <strong>emf</strong>. This <strong>emf</strong>, known as the back <strong>emf</strong>, acts against the applied voltage that's causing the <strong>motor</strong> to spin in the first place, and reduces the current flowing through the coils of the <strong>motor</strong>.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/f42b25edb5edffe7d3976b669f7bac59/back.jpg" />
         <pubDate>2021-01-06 06:10:39 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1058393940</guid>
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         <title>Exercise (motor)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1058400428</link>
         <description><![CDATA[<div>A coil has an area of 0.15 m^2. It is rotating 70 revolutions per second with its axis perpendicular to a uniform magnetic field of 0.35 T. If the coil has 1500 turns,determine the maximum voltage induced in the coil.</div>]]></description>
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         <pubDate>2021-01-06 06:14:18 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1058400428</guid>
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         <title>Eddy currents</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1058414856</link>
         <description><![CDATA[<div>According to <a href="https://www.electrical4u.com/lenz-law-of-electromagnetic-induction/">Lenz’s law</a>, a conducting loop when subjected to varying <a href="https://www.electrical4u.com/magnetic-field/">magnetic field</a> gets an emf induced into it causing flow of current in a direction opposing the change causing it. The case goes similar to when instead of a conducting closed loop, the change in magnetic field through a conducting body, say a filament or a slab of magnetic material or non-magnetic material, causes currents to flow into its cross sections at appropriate closed paths.</div><div>These currents are given the name <strong>eddy currents</strong> after the water eddies that are small swirling whirlpools observed in lakes and oceans. These eddy current loops can be both beneficial and undesirable.<br> While they cause undesirable high heat losses in the material such as transformer core, eddy currents find applications in various industrial processes like induction heating, metallurgy, welding, braking etc. This article deals with the theory and applications of eddy current phenomenon. </div>]]></description>
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         <pubDate>2021-01-06 06:23:05 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1058414856</guid>
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         <title>Self Inductance</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1058431787</link>
         <description><![CDATA[<div>Obtain an expression for an inductance L of an N turn solenoid if the length &amp; the cross-sectional area of the solenoid is l and A respectively .Given N = 150, l = 7.0 cm, A = 0.45 cm^2 &amp; the core is air,determine the inductance L. The same solenoid is then wound on an iron core of u = 4000(u -naught).Calculate L of the new solenoid.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/fe03f648e2670b8c214cc4f276aad801/Inductance_Self_Inductance_A.jpg" />
         <pubDate>2021-01-06 06:33:14 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1058431787</guid>
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         <title>Energy stored in an inductor</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1058468081</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/21f2afb5383b228702a4adc3cced7674/lecture_27_inductors_stored_energy_lr_circuits_18_638.jpg" />
         <pubDate>2021-01-06 06:54:52 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1058468081</guid>
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         <title>Excercise: Energy stored in an inductor.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1070537515</link>
         <description><![CDATA[<div>1) Calculate the energy stored in an inductor with L = 75.0 mH, if a current of 3.00 A flows through it.<br>2) An inductor has 300 turns with radius of 5.0 cm.If a current of 0.45 A flows through it,determine the energy stored in the inductor.<br>3) An inductor of L = 4.0 H is connected in series with a 25 V battery &amp; a resistor of 10.0 Ohm. Determine the energy stored in the inductor when the current reaches its maximum value.</div>]]></description>
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         <pubDate>2021-01-10 03:10:49 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1070537515</guid>
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         <title>Mutual Inductance</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1070544089</link>
         <description><![CDATA[<div>Excercise:<br>1)The current in a solenoid changes at a rate 4 A/s. The e.m.f. induced in the nearby coil is 10 mV. Determine the mutual inductance,M in the two coils.</div>]]></description>
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         <pubDate>2021-01-10 03:23:17 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1070544089</guid>
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         <title>Transformer </title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1070554373</link>
         <description><![CDATA[<ul><li>Where:</li><li>  V<sub>P</sub>  –  is the Primary Voltage</li><li>  V<sub>S</sub>  –  is the Secondary Voltage</li><li>  N<sub>P</sub>  –  is the Number of Primary Windings</li><li>  N<sub>S</sub>  –  is the Number of Secondary Windings</li><li>  Φ (phi)  –  is the Flux Linkage</li></ul><div>Notice that the two coil windings are not electrically connected but are only linked magnetically. A single-phase transformer can operate to either increase or decrease the voltage applied to the primary winding. When a transformer is used to “increase” the voltage on its secondary winding with respect to the primary, it is called a <strong>Step-up transformer</strong>. When it is used to “decrease” the voltage on the secondary winding with respect to the primary it is called a <strong>Step-down transformer</strong>.</div><div>However, a third condition exists in which a transformer produces the same voltage on its secondary as is applied to its primary winding. In other words, its output is identical with respect to voltage, current and power transferred. This type of transformer is called an “Impedance Transformer” and is mainly used for impedance matching or the isolation of adjoining electrical circuits.</div><div>The difference in voltage between the primary and the secondary windings is achieved by changing the number of coil turns in the primary winding ( N<sub>P</sub> ) compared to the number of coil turns on the secondary winding ( N<sub>S</sub> ).</div><div>As the transformer is basically a linear device, a ratio now exists between the number of turns of the primary coil divided by the number of turns of the secondary coil. This ratio, called the ratio of transformation, more commonly known as a transformers “turns ratio”, ( TR ). This turns ratio value dictates the operation of the transformer and the corresponding voltage available on the secondary winding.</div><div>It is necessary to know the ratio of the number of turns of wire on the primary winding compared to the secondary winding. The turns ratio, which has no units, compares the two windings in order and is written with a colon, such as 3:1 (3-to-1). This means in this example, that if there are 3 volts on the primary winding there will be 1 volt on the secondary winding, 3 volts-to-1 volt. Then we can see that if the ratio between the number of turns changes the resulting voltages must also change by the same ratio, and this is true.</div><div><br></div>]]></description>
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         <pubDate>2021-01-10 03:41:43 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1070554373</guid>
      </item>
      <item>
         <title>A Transformers Turns Ratio</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1070556838</link>
         <description><![CDATA[<div>Assuming an ideal transformer and the phase angles:  Φ<sub>P</sub> ≡ Φ<sub>S</sub></div><div>Note that the order of the numbers when expressing a transformers <em>turns ratio</em> value is very important as the turns ratio 3:1 expresses a very different transformer relationship and output voltage than one in which the turns ratio is given as: 1:3</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/3c48270875e7f99e5430f7692edd747d/transformer_trans2.gif" />
         <pubDate>2021-01-10 03:45:49 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1070556838</guid>
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      <item>
         <title>Exercises: Transformer.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1070558120</link>
         <description><![CDATA[<div>1) An electric generator produces 100 A at 4500 V. A "step up" transformer is used to increase the voltage to 240 000 V before it is sent on high voltage transmission line to a city. The total resistance of the transmission line is 40.0 ohm.<br>(i) Determine the lost in power in percentage.<br>(ii) If the voltage were not stepped up, calculate the lost of the original power in the transmission line.</div>]]></description>
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         <pubDate>2021-01-10 03:48:03 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1070558120</guid>
      </item>
      <item>
         <title>Exercise (part2 ): Transformers.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1070567320</link>
         <description><![CDATA[<div>1) A ""step up"transformer increases volatge of 80 V to 180 V. What is the value of the current in the secondary coil with respect to the primary coil, assuming the transformer is 100 percent efficient.<br>2) The secondary coil of a transformer has 1800 turns &amp; the primary coil of the same transformer has 120 turns. The input voltage &amp; the output current of the transformer are 120 V &amp; 8.0 A respectively. Calculate the volatge of the secondary coil &amp; also the current in the primary coil.</div>]]></description>
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         <pubDate>2021-01-10 04:01:43 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1070567320</guid>
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      <item>
         <title>Back e.m.f in D.C. Motor</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1070589242</link>
         <description><![CDATA[<div>When the current-carrying conductor placed in a magnetic field, the torque induces on the conductor, the torque rotates the conductor which cuts the flux of the magnetic field. According to the Electromagnetic Induction Phenomenon <strong>“when the conductor cuts the magnetic field, EMF induces in the conductor”</strong>.</div><div><br></div><div>The Fleming right-hand rule determines the direction of the induced EMF.</div><div>According to Fleming Right Hand Rule, if we hold our thumb, middle finger and index finger of the right hand by an angle of 90°, then the index finger represents the direction of the magnetic field. The thumb shows the direction of motion of the conductor and the middle finger represents the emf induces on the conductor.</div><div>On applying the right-hand rule in the figure shown below, it is seen that<strong> the direction of the induced emf is opposite to the applied voltage.</strong> Thereby the emf is known as the <em>counter emf or back emf</em>.</div><div>The back emf is developed in series with the applied voltage, but opposite in direction, i.e., the back emf opposes the current which causes it.</div>]]></description>
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         <pubDate>2021-01-10 04:26:01 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1070589242</guid>
      </item>
      <item>
         <title>Back e.m.f (part 2)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1081669432</link>
         <description><![CDATA[<div>The magnitude of the back emf is given by the same expression shown below:</div><div>(Refer to part 3)</div><div>Where E<sub>b</sub> is the induced emf of the motor known as Back EMF, A is the number of parallel paths through the armature between the brushes of opposite polarity. P is the number of poles, N is the speed, Z is the total number of conductors in the armature and ϕ is the useful flux per pole.<br> <br>A simple conventional circuit diagram of the machine working as a motor is shown in the diagram <br>In this case, the magnitude of the back emf is always less than the applied voltage. The difference between the two is nearly equal when the motor runs under normal conditions.</div><div>The current induces on the motor because of the main supply. The relation between the main supply, back emf and armature current is given as E<sub>b </sub>= V – I<sub>a</sub>R<sub>a</sub>.</div>]]></description>
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         <pubDate>2021-01-13 06:12:33 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1081669432</guid>
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      <item>
         <title>em.f motor eqn compressor</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1081675119</link>
         <description><![CDATA[<div>part 3</div>]]></description>
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         <pubDate>2021-01-13 06:15:40 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1081675119</guid>
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      <item>
         <title>Advantages of Back Emf in DC Motor</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1081687462</link>
         <description><![CDATA[<div>1. The back emf opposes the supply voltage. The supply voltage induces the current in the coil which rotates the armature. The electrical work required by the motor for causing the current against the back emf is converted into mechanical energy. And that energy is induced in the armature of the motor. Thus, we can say that <strong>energy conversion in the DC motor is possible only because of the back emf.</strong></div><div>The mechanical energy induced in the motor is the product of the back emf and the armature current, i.e., E<sub>b</sub>I<sub>a</sub>.</div><div>2. The back emf makes the DC motor self-regulating machine, i.e.,<strong> the back emf develops the armature current according to the need of the motor.</strong> The armature current of the motor is calculated as:</div><div>Let’s understand how the back emf makes motor self-regulating.</div><ul><li>Consider the motor is running at no-load condition. At no load, the DC motor requires small torque for controlling the friction and windage loss. The motor withdraws less current. As the back emf depends on the current their value also decreases. The magnitude of the back EMF is nearly equal to the supply voltage.</li><li>If the sudden load is applied to the motor, the motor becomes slow down. As the speed of the motor decreases, the magnitude of their back emf also falls down. The small back emf withdraw heavy current from the supply. The large armature current induces the large torque in the armature, which is the need of the motor. Thus, the motor moves continuously at a new speed.</li><li>If the load on the motor is suddenly reduced, the driving torque on the motor is more than the load torque. The driving torque increases the speed of the motor which also increases their back emf.  The high value of back emf decreases the armature current. The small magnitude of armature current develops less driving torque, which is equal to the load torque. And the motor will rotate uniformly at the new speed.</li></ul>]]></description>
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         <pubDate>2021-01-13 06:22:49 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1081687462</guid>
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      <item>
         <title>Exercise (back e.m.f)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1081689624</link>
         <description><![CDATA[<div>The resistance of coils in a motor is 15 Ohm &amp; the motor is supplied by a volatge of 150 V. The back e.m.f of the motor as it is operating at its maximum speed is 80 V. Determine the current of the coils when the motor is running at the maximum speed.</div>]]></description>
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         <pubDate>2021-01-13 06:23:59 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1081689624</guid>
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      <item>
         <title>Exercise 2: Back e.m.f</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1081706917</link>
         <description><![CDATA[<div>The current in coils of a motor is 4 A when it is rotating at a maximum speed but its value is 11 A at the time when it is first turned on. If the volatge suppled to the motor is 120 V, determine the back e.m.f and the resistance of coils.</div>]]></description>
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         <pubDate>2021-01-13 06:33:35 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1081706917</guid>
      </item>
      <item>
         <title>Alternating Current or AC</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1081720658</link>
         <description><![CDATA[<div><strong>AC:</strong> An electric current that continually reverses direction.</div><div>The AC is the short form for Alternating Current, in which the electric charge reverses direction at regular intervals to produce alternate positive and negative values of the same magnitude.</div><div>The alternating current follows a sine waveform where the voltage increases steadily from zero, rising to the maximum positive peak voltage. It then reverses and drops down through zero into negative direction until it reaches the negative peak value, which is equal to the positive in magnitude and only different in polarity. The voltage reverses again and climbs toward the zero point to complete one cycle. This process repeats at the rated frequency of either the 50 HZ or 60 HZ (cycles per second).<br>The rate of reversing direction is quantified by the number of complete cycles per second and is known as the frequency. The two commonly used frequency standards for domestic and industrial applications are the 50 Hertz which is used in most parts of the world, and 60 Hertz used in the USA and some other regions.</div><div>The other frequency is 400 Hz this is used in aircrafts, spacecraft, marine, military and other sensitive applications where light equipment and higher motor speeds are desired.</div><div>The ac is generated using hydro, diesel, steam or wind turbines. Other sources are the renewable energy sources such as the solar; however, some of these produces the direct current and must be inverted to alternating current before being fed into the grid.</div><div>The alternating current is the common form of electrical power generated and distributed due its ease of generation and distribution. The alternating voltage is easily stepped up and down to suit any required voltage level. To minimize power losses in the conductors, the electrical power is transmitted at high voltages and low currents. This is later stepped down at the distribution and consumer level to suit the consumer’s needs.</div><div>Majority of electrical and electronic equipment use ac power at either 220-240 volts or 110-120V for domestic and office applications, and 415V for industrial. However, most of the equipment and especially all electronics use external or internal power supply units to convert the ac into the appropriate direct current (DC) required by the electronic devices and circuits.</div><div>Ac is normally supplied to equipment using three wires</div><ul><li>The hot wire transmits the power.</li><li>Neutral provides a return path for the current in the hot wire. It is also connected to the earth.</li><li>The third wire is the ground which is also connected to the earth, this is connected to the metallic parts of the equipment to provide safety and eliminate electric shock hazards.</li></ul>]]></description>
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         <pubDate>2021-01-13 06:41:14 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1081720658</guid>
      </item>
      <item>
         <title>Phasor Diagrams and Phasor Algebra</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1081747517</link>
         <description><![CDATA[<div> Phasor Diagrams are a graphical way of representing the magnitude and directional relationship between two or more alternating quantities .<br> Sinusoidal waveforms of the same frequency can have a Phase Difference between themselves which represents the angular difference of the two sinusoidal waveforms. Also the terms “lead” and “lag” as well as “in-phase” and “out-of-phase” are commonly used to indicate the relationship of one waveform to the other with the generalized sinusoidal expression given as: A<sub>(t)</sub> = A<sub>m</sub> sin(ωt ± Φ) representing the sinusoid in the time-domain form. <br>But when presented mathematically in this way it is sometimes difficult to visualise this angular or phasor difference between two or more sinusoidal waveforms. One way to overcome this problem is to represent the sinusoids graphically within the spacial or phasor-domain form by using <strong>Phasor Diagrams</strong>, and this is achieved by the rotating vector method.</div><div>Basically a rotating vector, simply called a “<strong>Phasor</strong>” is a scaled line whose length represents an AC quantity that has both magnitude (“peak amplitude”) and direction (“phase”) which is “frozen” at some point in time.</div><div>A phasor is a vector that has an arrow head at one end which signifies partly the maximum value of the vector quantity ( V or I ) and partly the end of the vector that rotates.</div><div>Generally, vectors are assumed to pivot at one end around a fixed zero point known as the “point of origin” while the arrowed end representing the quantity, freely rotates in an <strong>anti-clockwise</strong> direction at an angular velocity, ( ω ) of one full revolution for every cycle. This anti-clockwise rotation of the vector is considered to be a positive rotation. Likewise, a clockwise rotation is considered to be a negative rotation.</div><div>Although the both the terms vectors and phasors are used to describe a rotating line that itself has both magnitude and direction, the main difference between the two is that a vectors magnitude is the “peak value” of the sinusoid while a phasors magnitude is the “rms value” of the sinusoid. In both cases the phase angle and direction remains the same.</div><div>The phase of an alternating quantity at any instant in time can be represented by a phasor diagram, so phasor diagrams can be thought of as “functions of time”. A complete sine wave can be constructed by a single vector rotating at an angular velocity of ω = 2πƒ, where ƒ is the frequency of the waveform. Then a <strong>Phasor</strong> is a quantity that has both “Magnitude” and “Direction”.</div><div>Generally, when constructing a phasor diagram, angular velocity of a sine wave is always assumed to be: ω in rad/sec. </div>]]></description>
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         <pubDate>2021-01-13 06:54:36 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1081747517</guid>
      </item>
      <item>
         <title>Phasor Diagram</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094601805</link>
         <description><![CDATA[<div> Phasor Diagrams are a graphical way of representing the magnitude and directional relationship between two or more alternating quantities .<br><br>Sinusoidal waveforms of the same frequency can have a Phase Difference between themselves which represents the angular difference of the two sinusoidal waveforms. Also the terms “lead” and “lag” as well as “in-phase” and “out-of-phase” are commonly used to indicate the relationship of one waveform to the other with the generalized sinusoidal expression given as: A<sub>(t)</sub> = A<sub>m</sub> sin(ωt ± Φ) representing the sinusoid in the time-domain form. <br><br>But when presented mathematically in this way it is sometimes difficult to visualise this angular or phasor difference between two or more sinusoidal waveforms. One way to overcome this problem is to represent the sinusoids graphically within the spacial or phasor-domain form by using <strong>Phasor Diagrams</strong>, and this is achieved by the rotating vector method.</div><div>Basically a rotating vector, simply called a “<strong>Phasor</strong>” is a scaled line whose length represents an AC quantity that has both magnitude (“peak amplitude”) and direction (“phase”) which is “frozen” at some point in time.</div><div>A phasor is a vector that has an arrow head at one end which signifies partly the maximum value of the vector quantity ( V or I ) and partly the end of the vector that rotates.</div><div>Generally, vectors are assumed to pivot at one end around a fixed zero point known as the “point of origin” while the arrowed end representing the quantity, freely rotates in an <strong>anti-clockwise</strong> direction at an angular velocity, ( ω ) of one full revolution for every cycle. This anti-clockwise rotation of the vector is considered to be a positive rotation. Likewise, a clockwise rotation is considered to be a negative rotation.</div><div>Although the both the terms vectors and phasors are used to describe a rotating line that itself has both magnitude and direction, the main difference between the two is that a vectors magnitude is the “peak value” of the sinusoid while a phasors magnitude is the “rms value” of the sinusoid. In both cases the phase angle and direction remains the same.</div><div>The phase of an alternating quantity at any instant in time can be represented by a phasor diagram, so phasor diagrams can be thought of as “functions of time”. A complete sine wave can be constructed by a single vector rotating at an angular velocity of ω = 2πƒ, where ƒ is the frequency of the waveform. Then a <strong>Phasor</strong> is a quantity that has both “Magnitude” and “Direction”.</div><div>Generally, when constructing a phasor diagram, angular velocity of a sine wave is always assumed to be: ω in rad/sec.</div>]]></description>
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         <pubDate>2021-01-17 03:11:25 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094601805</guid>
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      <item>
         <title>Phasor Diagram of a Sinusoidal Waveform.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094604369</link>
         <description><![CDATA[<div>As the single vector rotates in an anti-clockwise direction, its tip at point A will rotate one complete revolution of 360<sup>o</sup> or 2π representing one complete cycle. If the length of its moving tip is transferred at different angular intervals in time to a graph as shown above, a sinusoidal waveform would be drawn starting at the left with zero time. Each position along the horizontal axis indicates the time that has elapsed since zero time, t = 0. When the vector is horizontal the tip of the vector represents the angles at 0<sup>o</sup>, 180<sup>o</sup> and at 360<sup>o</sup>.</div><div>Likewise, when the tip of the vector is vertical it represents the positive peak value, ( +Am ) at 90<sup>o</sup> or π/2 and the negative peak value, ( -Am ) at 270<sup>o</sup> or 3π/2. Then the time axis of the waveform represents the angle either in degrees or radians through which the phasor has moved. So we can say that a phasor represent a scaled voltage or current value of a rotating vector which is “frozen” at some point in time, ( t ) and in our example above, this is at an angle of 30<sup>o</sup>.</div><div>Sometimes when we are analysing alternating waveforms we may need to know the position of the phasor, representing the Alternating Quantity at some particular instant in time especially when we want to compare two different waveforms on the same axis. For example, voltage and current. We have assumed in the waveform above that the waveform starts at time t = 0 with a corresponding phase angle in either degrees or radians.</div><div>But if a second waveform starts to the left or to the right of this zero point or we want to represent in phasor notation the relationship between the two waveforms then we will need to take into account this phase difference, Φ of the waveform.</div>]]></description>
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         <pubDate>2021-01-17 03:17:07 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094604369</guid>
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      <item>
         <title>Phasor Diagram of a Sinusoidal Waveform</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094605885</link>
         <description><![CDATA[<div> The phasor diagram is drawn corresponding to time zero ( t = 0 ) on the horizontal axis. The lengths of the phasors are proportional to the values of the voltage, ( V ) and the current, ( I ) at the instant in time that the phasor diagram is drawn. The current phasor lags the voltage phasor by the angle, Φ, as the two phasors rotate in an <em>anticlockwise</em> direction as stated earlier, therefore the angle, Φ is also measured in the same anticlockwise direction. </div>]]></description>
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         <pubDate>2021-01-17 03:20:38 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094605885</guid>
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      <item>
         <title>Phasor diagram of a sinusoidal waveform.(Continue)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094606702</link>
         <description><![CDATA[<div>If however, the waveforms are frozen at time, t = 30<sup>o</sup>, the corresponding phasor diagram would look like the one shown on the right. Once again the current phasor lags behind the voltage phasor as the two waveforms are of the same frequency.</div><div>However, as the current waveform is now crossing the horizontal zero axis line at this instant in time we can use the current phasor as our new reference and correctly say that the voltage phasor is “leading” the current phasor by angle, Φ. Either way, one phasor is designated as the <em>reference</em> phasor and all the other phasors will be either leading or lagging with respect to this reference.</div>]]></description>
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         <pubDate>2021-01-17 03:22:33 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094606702</guid>
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      <item>
         <title>Exercise 1:(Phasor)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094607196</link>
         <description><![CDATA[<div>Explain the following statement: "the voltage across a capacitance lags the current by 90 degrees."</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-17 03:23:37 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094607196</guid>
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      <item>
         <title>Root- Mean Square(r.m.s) Values</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094616334</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/e6144512d19ed9beb5db3376295d8556/nrjyX.png" />
         <pubDate>2021-01-17 03:41:43 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094616334</guid>
      </item>
      <item>
         <title>Exercise (r.m.s)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094617203</link>
         <description><![CDATA[<div>1) A light bulb which uses an average power of 50 W is connected to a 50 Hz power source. If the r.m.s volatge of the power source is 120 V, determine the resistance of the light bulb.<br>2) A heating element is connected to an a.c. volatge source of an r.m.s volateg of 110 V. If an r.m.s current of 8.0 A occurs, determine the resistance &amp; the average power input in the heating element.</div><div><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-17 03:43:25 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094617203</guid>
      </item>
      <item>
         <title>Phasor Diagram for Pure Resistive Circuits.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094629698</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://www.youtube.com/watch?v=A_tNf7fAqEI" />
         <pubDate>2021-01-17 04:03:25 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094629698</guid>
      </item>
      <item>
         <title>Impedance,Resistance and reactance-Difference</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094638558</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://www.youtube.com/watch?v=mKAI1NrX_JA" />
         <pubDate>2021-01-17 04:14:37 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094638558</guid>
      </item>
      <item>
         <title>Exercise: (capacitive reactance)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094640387</link>
         <description><![CDATA[<div>A capacitor of 10.0 micro F is connected to an a.c. generator which produces an r.m.s volatage of 200 V at a frequency of 50 Hz. Determine the capacitive reactance and the r.m.s current in the circuit.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-17 04:16:38 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094640387</guid>
      </item>
      <item>
         <title>Exercise: (Inductive reactance)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094652010</link>
         <description><![CDATA[<div>In an a.c. circuit an inductor of 30 mH is connected to a voltage source with r.m.s value of 160 V. If the frequency of the a.c. is 60 Hz ,determine the inductive reactance and the r.m.s current in the circuit.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-17 04:28:52 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094652010</guid>
      </item>
      <item>
         <title>Exercises:</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094654349</link>
         <description><![CDATA[<div>1) The capacitive reactance of an a.c circuit at 129 Hz is 30 Ohm. If the frequency of the a.c is changed to 15 000 Hz,determine the capacitive reactance of the capacitor.<br><br>2) In a purely capacitive a.c. circuit, the peak value of the voltage source , V0 = 150 V.If the angular frequency ,omega, of the a.c is 140 rad/s and a capacitor of C= 5 micro F is connected in series to the voltage source,determine the r.m.s current in the circuit.<br><br>3) The r.m.s voltage of 120 V is supplied to a purely inductive circuit.At a frequency of 50 Hz the r.m.s current is 15 A. Determine the inductance &amp; also find the frequency of the circuit if the r.m.s current is reduced to 7.50 A.<br><br>4) An inductor has 60 Ohm reactance at 50 Hz. If the inductor is then connected to a 100 Hz source which has an r.m.s voltage of 120 V,calculate the peak current.<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-17 04:31:26 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1094654349</guid>
      </item>
      <item>
         <title>RC Circuit</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1096435156</link>
         <description><![CDATA[<div> A resistor-capacitor circuit, or RC circuit, is a circuit with a resistor and capacitor connected in series. The capacitor in the circuit stores energy and the resistor changes the charge and discharge rate of the capacitor. These circuits are most commonly used for filtering the waveform and are used to create low-pass, high-pass, and band-pass filters. <br><br>RC Circuit Formulas</div><div> RC circuits have several characteristics, including a time constant, energy storage, charge, impedance, capacitive reactance, characteristic frequency, and angular frequency. Calculating each of these characteristics of the circuit can be done using the following formulas. </div><div><br>Time Constant Formula</div><div> The time constant, expressed as tau (τ) is the time it takes in seconds for the capacitor in the RC circuit to reach 63.2% charge. The formula to calculate the time constant is: </div><div>τ = RC</div><div> The time constant τ is equal to the resistance R in ohms times the capacitance C in farads. The capacitor will reach a 63.2% charge in τ, 86.5% in 2τ, and 99.3% in 5τ. </div><div><br>Energy Formula</div><div> The energy stored in the fully charged capacitor in an RC circuit can be found using the formula: </div><div>E = CV<sup>2</sup>2</div><div> The <a href="https://www.inchcalculator.com/convert/energy/">energy</a> E in <a href="https://www.inchcalculator.com/convert/from-joule/">joules</a> is equal to the <a href="https://www.inchcalculator.com/convert/capacitance/">capacitance</a> C in <a href="https://www.inchcalculator.com/convert/from-farad/">farads</a> times the <a href="https://www.inchcalculator.com/convert/voltage/">voltage</a> V squared, divided by two. </div>]]></description>
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         <pubDate>2021-01-18 01:18:12 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1096435156</guid>
      </item>
      <item>
         <title>RC circuit (part 2)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1096440569</link>
         <description><![CDATA[<div>Charge Formula</div><div> The maximum charge in the resistor capacitor circuit can be found using the formula: </div><div>Q = CV</div><div> The charge Q in coulombs is equal to the capacitance C in farads times the voltage V. </div><div><br>Current Formula</div><div> The maximum current of the RC circuit can be found using <a href="https://www.inchcalculator.com/ohms-law-calculator/">Ohm’s Law</a>. The formula is: </div><div>I = VR</div><div> The current I in amps is equal to the voltage V divided by the resistance R in ohms. </div><div><br>Characteristic Frequency Formula</div><div> The characteristic frequency, often called the ordinary or cyclic frequency, of the circuit can be found using this formula: </div><div>f = 1/2πRC</div><div> The frequency f in hertz is equal to 1 divided by 2 times π times the resistance R in ohms times the capacitance C in farads. </div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-18 01:23:58 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1096440569</guid>
      </item>
      <item>
         <title>RC circuit (part 3)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1096442250</link>
         <description><![CDATA[<div>Angular Frequency Formula</div><div> The angular frequency of the circuit can be found with the formula: </div><div>ω = 2πf</div><div> The angular frequency ω in radians per second is equal to 2 times π times the characteristic frequency f in hertz. </div><div><br>Impedance Formula</div><div> The impedance of an RC circuit can be found using a few formulas: </div><div>Z = R + 1/jωC<br> |Z| = √(R<sup>2</sup> + 1/(ωC)<sup>2</sup>)</div><div> Where j is the imaginary unit, Z is the impedance in ohms, R is the resistance in ohms, C is the capacitance in farads, and ω is the angular frequency in rad/s. </div><div>Capacitive Reactance Formula</div><div> The capacitive reactance of an RC circuit can be found using the formula: </div><div>X = 1/ωC</div><div> The capacitive reactance X is equal to 1 divided by the angular frequency ω times the capacitance C. </div><div>Phase Difference Formula</div><div> This formula expresses the phase difference between total voltage and total current. </div><div>φ = tan<sup>-1</sup>(-1/ωCR)</div><div> φ is the phase difference, ω is the angular frequency, C is the capacitance, and R is the resistance.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-18 01:25:48 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1096442250</guid>
      </item>
      <item>
         <title>Exercise: RC</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1096443862</link>
         <description><![CDATA[<div>A capacitor of 1500  micro F is connected to 2.5 V, 0.45 A lamp &amp; a 60 Hz supply in series.Determine the r.m.s voltage supply to the lamp,the voltage across the capacitor &amp; the resistor respectively.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-18 01:27:33 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1096443862</guid>
      </item>
      <item>
         <title>Resistance And Inductance (RL)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1096455943</link>
         <description><![CDATA[<div>https://www.youtube.com/watch/_A6fCgQdS2Q</div>]]></description>
         <pubDate>2021-01-18 01:41:56 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1096455943</guid>
      </item>
      <item>
         <title>Exercise RL :</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1096458237</link>
         <description><![CDATA[<div>An inductor of 3.0 H has a resistance of 70 Ohm. It is connected in series with a resistor of 450 Ohm and an alternating voltage supply of 240 V &amp; frequency of 60 Hz.Determine the r.m.s current in the circuit &amp; the phase between the applied voltage &amp; the current in the circuit.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-18 01:44:33 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1096458237</guid>
      </item>
      <item>
         <title>RCL : Resistance,capacitance &amp; inductance.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104306435</link>
         <description><![CDATA[<div>https://www.youtube.com/watch?v=6ieUk3Rm1yY</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-20 06:16:32 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104306435</guid>
      </item>
      <item>
         <title>Exercise RCL</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104317384</link>
         <description><![CDATA[<div>Determine the impedance, r.m.s current &amp; phase angle between the current &amp; voltage of a series RCL a.c. circuit which consists of a resistor with R = 200 Ohm, an inductor L = 0.8 H &amp; a capacitor with C = 3.80 micro F. The alternating voltage supply is 150 V at 60 Hz.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-20 06:21:02 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104317384</guid>
      </item>
      <item>
         <title>Resonance in Series RLC circuit (part 2)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104343088</link>
         <description><![CDATA[<ol><li>When a <a href="https://www.electrical4u.com/electric-current-and-theory-of-electricity/">current</a> flows in an inductor, energy gets stored in <a href="https://www.electrical4u.com/magnetic-field/">magnetic field</a>.</li><li>When a capacitor is charged, energy gets stored in static electric field.</li></ol><div>The magnetic field in the inductor is built by the current, which is provided by the discharging capacitor. Similarly, the capacitor is charged by the current produced by collapsing magnetic field of inductor and this process continues on and on, causing electrical energy to oscillate between the magnetic field and the <a href="https://www.electrical4u.com/what-is-electric-field/">electric field</a>. In some cases, at certain frequency called resonant frequency, the <a href="https://www.electrical4u.com/electrical-reactance/">inductive reactance</a> of the circuit becomes equal to capacitive reactance which causes the electrical energy to oscillate between the electric field of the capacitor and magnetic field of the inductor. This forms a harmonic oscillator for current. In RLC circuit, the presence of resistor causes these oscillation to die out over period of time and is called damping effect of resistor.</div><div><br></div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/c6f51d1df05f40f2bb724df561cb7b3e/rrlcc.gif" />
         <pubDate>2021-01-20 06:32:57 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104343088</guid>
      </item>
      <item>
         <title>Resonance in Series RLC circuit</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104343544</link>
         <description><![CDATA[<div> Consider a <a href="https://www.electrical4u.com/rlc-circuit/">RLC circuit</a> in which <a href="https://www.electrical4u.com/types-of-resistor/">resistor</a>, <a href="https://www.electrical4u.com/what-is-inductor-and-inductance-theory-of-inductor/">inductor</a> and <a href="https://www.electrical4u.com/what-is-capacitor/">capacitor</a> are connected in series across a <a href="https://www.electrical4u.com/voltage-or-electric-potential-difference/">voltage</a> supply. This <a href="https://www.electrical4u.com/series-rlc-circuit/">series RLC circuit</a> has a distinguishing property of resonating at a specific frequency called resonant frequency.<br><br></div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/db4ac42cf2f8b0c9c25204c160306191/What_is_the_Resonance_in_Series_RLC_Circuit.png" />
         <pubDate>2021-01-20 06:33:11 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104343544</guid>
      </item>
      <item>
         <title>Variation in Inductive Reactance and Capacitive Reactance with Frequency</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104367934</link>
         <description><![CDATA[<div> The inductive reactance X<sub>L</sub> = 2πfL means inductive reactance is directly proportional to frequency (X<sub>L</sub> and prop ƒ). When the frequency is zero or in case of DC, inductive reactance is also zero, the circuit acts as a short circuit; but when frequency increases; inductive reactance also increases. At infinite frequency, inductive reactance becomes infinity and circuit behaves as open circuit. It means that, when frequency increases inductive reactance also increases and when frequency decreases, inductive reactance also decreases. So, if we plot a graph between inductive reactance and frequency, it is a straight line linear curve passing through origin as shown in the figure above. </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/2d49f8649e6b3649c63a0d4decc145c4/rrlcc_2.gif" />
         <pubDate>2021-01-20 06:43:36 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104367934</guid>
      </item>
      <item>
         <title>Variation of Capacitive Reactance Vs Frequency.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104378777</link>
         <description><![CDATA[<div> From the formula of capacitive reactance X<sub>C</sub> = 1 / 2πfC that, frequency and capacitive reactance are inversely proportional to each other. In case of DC or when frequency is zero, capacitive reactance becomes infinity and circuit behaves as open circuit and when frequency increases and becomes infinite, capacitive reactance decreases and becomes zero at infinite frequency, at that point the circuit acts as short circuit, so the capacitive reactance increases with decease in frequency and if we plot a graph between capacitive reactance and frequency, it is an hyperbolic curve as shown in figure above. </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/0944fd2e45a6b92d3dfc0d51930cef34/rrlcc_3.gif" />
         <pubDate>2021-01-20 06:48:08 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104378777</guid>
      </item>
      <item>
         <title>Inductive Reactance and Capacitive Reactance Vs Frequency.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104390598</link>
         <description><![CDATA[<div> it can be concluded that the inductive reactance is directly proportional to frequency and capacitive reactance is inversely proportional to frequency, i.e at low frequency X<sub>L</sub> is low and X<sub>C</sub> is high but there must be a frequency, where the value of inductive reactance becomes equal to capacitive reactance. Now if we plot a single graph of inductive reactance vs frequency and capacitive reactance vs frequency, then there must occur a point where these two graphs cut each other. At that point of intersection, the inductive and capacitive reactance becomes equal and the frequency at which these two reactances become equal, is called resonant frequency, f<sub>r</sub>. <br><br> At resonant frequency, X<sub>L</sub> = XC<br><br>PLEASE FIND THE RELATED EQUATIONS FOR XL = XC !<br> <br> </div><div><br></div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/84be0857898ac5f9b33edcbb3ff8f07d/rrlcc_41.gif" />
         <pubDate>2021-01-20 06:53:04 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104390598</guid>
      </item>
      <item>
         <title>From XL = XC,</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104414162</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/ddea6605c8dd7e145a1a59e2c7c8a973/20210120_145949.jpg" />
         <pubDate>2021-01-20 07:02:18 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1104414162</guid>
      </item>
      <item>
         <title>Exercise: Series Resonance &amp; damping Oscillation.</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117743914</link>
         <description><![CDATA[<div>A series RCL circuit has R = 180 Ohm, L = 25 mH, V = 30 V &amp; 2(pi)f = 5.5 x 10^3 /s. Determine the capacitance value for a maximum r.m.s current. Determine also the maximum r.m.s current in the circuit.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-24 03:08:23 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117743914</guid>
      </item>
      <item>
         <title></title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117750407</link>
         <description><![CDATA[Power Triangle and Power Factor]]></description>
         <enclosure url="" />
         <pubDate>2021-01-24 03:19:26 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117750407</guid>
      </item>
      <item>
         <title>📹Power Triangle &amp; Power Factor</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117751220</link>
         <description><![CDATA[<div>In an AC circuit, the voltage and current waveforms are sinusoidal so their amplitudes are constantly changing over time. Since we know that power is voltage times the current (P = V*I), maximum power will occur when the two voltage and current waveforms are lined up with each other. That is, their peaks and zero crossover points occur at the same time. When this happens the two waveforms are said to be “in-phase”.</div><div>The three main components in an AC circuit which can affect the relationship between the voltage and current waveforms, and therefore their phase difference, by defining the total impedance of the circuit are the resistor, the capacitor and the inductor.</div><div>The impedance, (Z) of an AC circuit is equivalent to the resistance calculated in DC circuits, with impedance given in ohms. For AC circuits, impedance is generally defined as the ratio of the voltage and current phasor’s produced by a circuit component. Phasor’s are straight lines drawn in such a way as to represents a voltage or current amplitude by its length and its phase difference with respect to other phasor lines by its angular position relative to the other phasor’s.</div><div>AC circuits contain both resistance and reactance that are combined together to give a total impedance (Z) that limits current flow around the circuit. But an AC circuits impedance is not equal to the algebraic sum of the resistive and reactive ohmic values as a pure resistance and pure reactance are 90<sup>o</sup> out-of-phase with each other. But we can use this 90<sup>o</sup> phase difference as the sides of a right angled triangle, called an impedance triangle, with the impedance being the hypotenuse as determined by Pythagoras theorem.</div>]]></description>
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         <pubDate>2021-01-24 03:20:44 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117751220</guid>
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      <item>
         <title></title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117755830</link>
         <description><![CDATA[Real Power in AC Circuits

Real power (P), also known as true or active power, performs the “real work” within an electrical circuit. Real power, measured in watts, defines the power consumed by the resistive part of a circuit. Then real power, (P) in an AC circuit is the same as power, P in a DC circuit. So just like DC circuits, it is always calculated as I2*R, where R is the total resistive component of the circuit.
resistance phasor

As resistances do not produce any phasor difference (phase shift) between voltage and current waveforms, all the useful power is delivered directly to the resistance and converted to heat, light and work. Then the power consumed by a resistance is real power which is fundamentally the circuits average power.

To find the corresponding value of the real power the rms voltage and current values are multiplied by the cosine of the phase angle, Φ as shown.
 

Real Power   P = I2R = V*I*cos(Φ)  Watts, (W)
 

But as their is no phase difference between the voltage and the current in a resistive circuit, the phase shift between the two waveforms will be zero (0). ]]></description>
         <enclosure url="" />
         <pubDate>2021-01-24 03:28:40 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117755830</guid>
      </item>
      <item>
         <title>Exercise : Power &amp; Power Fcator</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117756274</link>
         <description><![CDATA[<div>A 45 Ohm resistor is connected to a 25 micro Farad capacitor &amp; to a 50 Hz, 100 V r.m.s source. Determine the power factor &amp; the average power delivered to the circuit.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-24 03:29:21 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117756274</guid>
      </item>
      <item>
         <title>Exercise: Power &amp; Power factor</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117759861</link>
         <description><![CDATA[<div>1) Determine the energy stored in an inductor with L = 70 mH, if a current of 3A flows through it.<br><br>2) A 45 Ohm resistor is connected to a 0.35 mH inductor &amp; to a 50 Hz, 100 V r.m.s source.Determine the power factor &amp; the average power delivered to the circuit.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-24 03:34:48 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117759861</guid>
      </item>
      <item>
         <title>Rectification</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117772540</link>
         <description><![CDATA[<div>A <strong>rectifier</strong> is an electrical device that <a href="https://en.wikipedia.org/wiki/Electric_power_conversion">converts</a> <a href="https://en.wikipedia.org/wiki/Alternating_current">alternating current</a> (AC), which periodically reverses direction, to <a href="https://en.wikipedia.org/wiki/Direct_current">direct current</a> (DC), which flows in only one direction. The reverse operation is performed by the <a href="https://en.wikipedia.org/wiki/Power_inverter">inverter</a>. </div><div>The process is known as <em>rectification</em>, since it "straightens" the direction of current. Physically, rectifiers take a number of forms, including <a href="https://en.wikipedia.org/wiki/Thermionic_diode">vacuum tube diodes</a>, wet chemical cells, <a href="https://en.wikipedia.org/wiki/Mercury-arc_valve">mercury-arc valves</a>, stacks of copper and selenium oxide plates, <a href="https://en.wikipedia.org/wiki/Semiconductor_diode">semiconductor diodes</a>, <a href="https://en.wikipedia.org/wiki/Silicon-controlled_rectifier">silicon-controlled rectifiers</a> and other silicon-based semiconductor switches. Historically, even synchronous electromechanical switches and motors have been used. Early radio receivers, called <a href="https://en.wikipedia.org/wiki/Crystal_radio">crystal radios</a>, used a "<a href="https://en.wikipedia.org/wiki/Cat%27s-whisker_detector">cat's whisker</a>" of fine wire pressing on a crystal of <a href="https://en.wikipedia.org/wiki/Galena">galena</a> (lead sulfide) to serve as a point-contact rectifier or "crystal detector". </div><div>Rectifiers have many uses, but are often found serving as components of DC <a href="https://en.wikipedia.org/wiki/Power_supplies">power supplies</a> and <a href="https://en.wikipedia.org/wiki/High-voltage_direct_current">high-voltage direct current</a> power transmission systems. Rectification may serve in roles other than to generate direct current for use as a source of power. As noted, <a href="https://en.wikipedia.org/wiki/Detector_(radio)">detectors</a> of <a href="https://en.wikipedia.org/wiki/Radio">radio</a> signals serve as rectifiers. In gas heating systems <a href="https://en.wikipedia.org/wiki/Flame_rectification">flame rectification</a> is used to detect presence of a flame. </div><div>Depending on the type of alternating current supply and the arrangement of the rectifier circuit, the output voltage may require additional smoothing to produce a uniform steady voltage. Many applications of rectifiers, such as power supplies for radio, television and computer equipment, require a <em>steady</em> constant DC voltage (as would be produced by a <a href="https://en.wikipedia.org/wiki/Battery_(electricity)">battery</a>). In these applications the output of the rectifier is smoothed by an <a href="https://en.wikipedia.org/wiki/Electronic_filter">electronic filter</a>, which may be a <a href="https://en.wikipedia.org/wiki/Capacitor">capacitor</a>, <a href="https://en.wikipedia.org/wiki/Choke_(electronics)">choke</a>, or set of capacitors, chokes and <a href="https://en.wikipedia.org/wiki/Resistor">resistors</a>, possibly followed by a <a href="https://en.wikipedia.org/wiki/Voltage_regulator">voltage regulator</a> to produce a steady voltage. </div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-24 03:52:57 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117772540</guid>
      </item>
      <item>
         <title>Half Wave Rectification</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117774819</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2021-01-24 03:55:50 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117774819</guid>
      </item>
      <item>
         <title>📹Half Wave Rectification</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117776743</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/e51502823cb2819336050f2b28e43ac7/900px_Halfwave_rectifier_en_svg.png" />
         <pubDate>2021-01-24 03:58:10 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117776743</guid>
      </item>
      <item>
         <title></title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117776935</link>
         <description><![CDATA[In half-wave rectification of a single-phase supply, either the positive or negative half of the AC wave is passed, while the other half is blocked. Mathematically, it is a step function (for positive pass, negative block): passing positive corresponds to the ramp function being the identity on positive inputs, blocking negative corresponds to being zero on negative inputs. Because only one half of the input waveform reaches the output, mean voltage is lower. Half-wave rectification requires a single diode in a single-phase supply, or three in a three-phase supply. Rectifiers yield a unidirectional but pulsating direct current; half-wave rectifiers produce far more ripple than full-wave rectifiers, and much more filtering is needed to eliminate harmonics of the AC frequency from the output. ]]></description>
         <enclosure url="" />
         <pubDate>2021-01-24 03:58:24 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117776935</guid>
      </item>
      <item>
         <title>Full-wave rectification</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117778521</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2021-01-24 04:00:18 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117778521</guid>
      </item>
      <item>
         <title>📹Full wave rectification</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117780249</link>
         <description><![CDATA[<div> full-wave rectifier converts the whole of the input waveform to one of constant polarity (positive or negative) at its output. Mathematically, this corresponds to the <a href="https://en.wikipedia.org/wiki/Absolute_value">absolute value</a> function. Full-wave rectification converts both polarities of the input waveform to pulsating DC (direct current), and yields a higher average output voltage. Two diodes and a center tapped <a href="https://en.wikipedia.org/wiki/Transformer">transformer</a>, or four diodes in a <a href="https://en.wikipedia.org/wiki/Diode_bridge">bridge configuration</a> and any AC source (including a transformer without center tap),  Single semiconductor diodes, double diodes with a common cathode or common anode, and four- or six-<a href="https://en.wikipedia.org/wiki/Diode_bridge">diode bridges</a> are manufactured as single components. <br><br></div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/55a06e0489e7ad9281e6a9979e720b4a/900px_Fullwave_rectifier_en_svg.png" />
         <pubDate>2021-01-24 04:02:26 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117780249</guid>
      </item>
      <item>
         <title>Exercise : Rectification</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117796336</link>
         <description><![CDATA[<div> The applied input a.c. power to a half-wave rectifier is 100 watts. The d.c. output power obtained is 40 watts.<br> (i) What is the rectification efficiency ?<br> (ii) What happens to remaining 60 watts? </div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-24 04:17:32 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117796336</guid>
      </item>
      <item>
         <title>Exercise 2 : Rectification</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117798383</link>
         <description><![CDATA[<div> An a.c. supply of 230 V is applied to a half-wave rectifier circuit through a<br> transformer of turn ratio 10 : 1. Find (i) the output d.c. voltage and (ii) the peak inverse voltage. Assume the diode to be ideal.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/9dcc2459c7435eb91eab6d23a5221fc7/31.png" />
         <pubDate>2021-01-24 04:19:09 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117798383</guid>
      </item>
      <item>
         <title>Exercise 3: Rectification</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117800339</link>
         <description><![CDATA[<div>A crystal diode having internal resistance r<sub>f </sub>= 20Ω is used for half-wave rectification. If the applied voltage v = 50 sin ω t and load resistance R<sub>L</sub>= 800 Ω, find :<br> (i) Im, Idc, Irms (ii) a.c. power input and d.c. power output (iii) d.c. output voltage (iv) efficiency of rectification.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-24 04:20:51 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117800339</guid>
      </item>
      <item>
         <title>Exercise: Half Wave Rectifier</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117813416</link>
         <description><![CDATA[<div>A half-wave rectifier is used to supply 50V d.c. to a resistive load of 800 Ω. The<br> diode has a resistance of 25 Ω. Calculate a.c. voltage required.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-24 04:32:12 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117813416</guid>
      </item>
      <item>
         <title>Exercise : Full wave rectifier</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117814925</link>
         <description><![CDATA[<div>A full-wave rectifier uses two diodes, the internal resistance of each diode may<br> be assumed constant at 20 Ω. The transformer r.m.s. secondary voltage from centre tap to each end of secondary is 50 V and load resistance is 980 Ω. Find : (i) the mean load current (ii) the r.m.s. value of load current.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-01-24 04:33:31 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117814925</guid>
      </item>
      <item>
         <title>Exercise: Rectifier</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117816797</link>
         <description><![CDATA[<div> In the centre-tap circuit shown in Fig. 2, the diodes are assumed to be ideal<br> i.e. having zero internal resistance. Find :(i) d.c. output voltage(ii) peak inverse voltage (iii) rectification efficiency.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/694bddff43a4fc61803547ac1591a943/46.png" />
         <pubDate>2021-01-24 04:35:02 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1117816797</guid>
      </item>
      <item>
         <title>Maxwell&#39;s Equation :Introduction</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1119916543</link>
         <description><![CDATA[<div> Maxwell's Equations are a set of 4 complicated equations that describe the world of electromagnetics. These equations describe how electric and magnetic fields propagate, interact, and how they are influenced by objects. </div><div> James Clerk Maxwell [1831-1879] was an Einstein/Newton-level genius who took a set of known experimental laws (Faraday's Law, Ampere's Law) and unified them into a symmetric coherent set of Equations known as Maxwell's Equations. Maxwell was one of the first to determine the speed of propagation of electromagnetic (EM) waves was the same as the speed of light - and hence to conclude that EM waves and visible light were really the same thing. </div><div> Maxwell's Equations are critical in understanding <a href="http://www.antenna-theory.com">Antennas</a> and Electromagnetics. They are formidable to look at - so complicated that most electrical engineers and physicists don't even really know what they mean. Shrouded in complex math (which is likely so "intellectual" people can feel superior in discussing them), true understanding of these equations is hard to come by. </div><div> This leads to the reason for this website - an intuitive tutorial of Maxwell's Equations. I will avoid if at all possible the mathematical difficulties that arise, and instead describe what the equations mean. And don't be afraid - the math is so complicated that those who do understand complex vector calculus still cannot apply Maxwell's Equations in anything but the simplest scenarios. For this reason, intuitive knowledge of Maxwell's Equations is far superior than mathematical manipulation-based knowledge. To understand the world, you must understand what equations mean, and not just know mathematical constructs. I believe the accepted methods of teaching electromagnetics and Maxwell's Equations do not produce understanding. And with that, let's say something about these equations. </div><div> Maxwell's Equations are laws - just like the law of gravity. These equations are rules the universe uses to govern the behavior of electric and magnetic fields. A flow of electric current will produce a magnetic field. If the current flow varies with time (as in any wave or periodic signal), the magnetic field will also give rise to an electric field. Maxwell's Equations shows that separated charge (positive and negative) gives rise to an electric field - and if this is varying in time as well will give rise to a propagating electric field, further giving rise to a propgating magnetic field. </div>]]></description>
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         <pubDate>2021-01-25 01:09:59 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1119916543</guid>
      </item>
      <item>
         <title>Gauss Law (1st case):</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1119935868</link>
         <description><![CDATA[<div> Gauss' Law is the first of <a href="http://www.maxwells-equations.com">Maxwell's Equations</a> which dictates how the Electric Field behaves around electric charges. Gauss' Law can be written in terms of the <a href="http://www.maxwells-equations.com/density/electric-flux.php">Electric Flux Density</a> and the <a href="http://www.maxwells-equations.com/pho/charge-density.php">Electric Charge Density</a><br><br>The symbol delta is the <a href="http://www.maxwells-equations.com/divergence.php">divergence operator</a>. </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/165bab389ef6bed89861b92ef83a195e/gauss_law.gif" />
         <pubDate>2021-01-25 01:24:13 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1119935868</guid>
      </item>
      <item>
         <title>Gauss Law (1st case, part 2)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1119943780</link>
         <description><![CDATA[<div> Equation [1] is known as Gauss' Law in point form. That is, Equation [1] is true at any point in space. That is, if there exists electric charge somewhere, then the divergence of <strong>D</strong> at that point is nonzero, otherwise it is equal to zero. </div><div> To get some more intuition on Gauss' Law, let's look at Gauss' Law in integral form. To do this, we assume some arbitrary volume (we'll call it <em>V</em>) which has a boundary (which is written <em>S</em>). Then integrating Equation [1] over the volume <em>V</em> gives Gauss' Law in integral form: </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/28d3e1c0bcd0b5c64e8bed6a7dd0288e/gauss_law_integral.gif" />
         <pubDate>2021-01-25 01:30:18 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1119943780</guid>
      </item>
      <item>
         <title>Gauss Law (1st case,part 3)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1119949605</link>
         <description><![CDATA[<div>Equation [2] states that the amount of charge inside a volume <em>V</em> (=) is equal to the total amount of Electric Flux (<strong>D</strong>) exiting the surface <em>S</em>. That is, to determine the Electric Flux leaving the region <em>V</em>, we only need to know how much electric charge is within the volume. We rewrite Equation [2] with more of the terms defined in Equation [3]: </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/b121ff925d9105d12eb5c7ea51e5f641/integral_explained.gif" />
         <pubDate>2021-01-25 01:34:40 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1119949605</guid>
      </item>
      <item>
         <title>Gauss&#39; Law for Magnetic Fields</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1119960736</link>
         <description><![CDATA[<div>First, observe both of Gauss' Laws, written in Equation [1]: <br>You see that both of these equations specify the <a href="http://www.maxwells-equations.com/divergence.php">divergence</a> of the field in question. For the top equation, we know that Gauss' Law for Electric Fields states that the divergence of the <a href="http://www.maxwells-equations.com/density/electric-flux.php">Electric Flux Density <strong>D</strong></a> is equal to the volume <a href="http://www.maxwells-equations.com/pho/charge-density.php">electric charge density</a>. But the second equation, Gauss' Magnetism law states that the divergence of the <a href="http://www.maxwells-equations.com/density/magnetic-flux.php">Magnetic Flux Density (<strong>B</strong>)</a> is zero. </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/4067c93e0b5553f33a88c5cfd85f3f10/gauss_laws.png" />
         <pubDate>2021-01-25 01:42:58 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1119960736</guid>
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      <item>
         <title>The 3rd Maxwell&#39;s Equation</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1119969228</link>
         <description><![CDATA[<div> The meaning of the 3rd of Maxwell's Equations, <strong>Faraday's Law</strong>, which is given in Equation [1]: </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/1bb655ac64f1faf7ae34c81586abcb2c/faradays_law.gif" />
         <pubDate>2021-01-25 01:49:03 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1119969228</guid>
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      <item>
         <title>The 3rd Maxwell&#39;s Equation (PART 2)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1119972851</link>
         <description><![CDATA[<div>Faraday was a scientist experimenting with circuits and magnetic coils way back in the 1830s. His experiment setup, which led to Farday's Law, is shown in Figure 1: <br> The experiment itself is somewhat simple. When the battery is disconnected, we have no electric current flowing through the wire. Hence there is no magnetic flux induced within the Iron (Magnetic Core). The Iron is like a highway for Magnetic Fields - they flow very easily through magnetic material. So the purpose of the core is to create a path for the Magnetic Flux to flow. </div><div> When the switch is closed, the electric current will flow within the wire attached to the battery. When this current flows, it has an associated magnetic field (or magnetic flux) with it. When the wire wraps around the left side of the magnetic core (as shown in Figure 1), a magnetic field (magnetic flux) is induced within the core. This flux travels around the core. So the Magnetic Flux produced by the wired coil on the left exists within the wired coil on the right, which is connected to the ammeter. </div><div> Now, a funny thing happens, which Faraday observed. When he closed the switch, then current would begin flowing and the ammeter would spike one way (say measuring +10 Amps on the other side). But this was very brief, and the current on the right coil would go to zero. When the switch was opened, the measured current would spike to the other side (say -10 Amps would be measured), and then the measured current on the right side would again be zero. </div><div> Faraday figured out what was happening. When the switch was initially changed from open to closed, the magnetic flux within the magnetic core increased from zero to some maximum number (which was a constant value, versus time). When the flux was increasing, there existed an induced current on the opposite side. </div><div> Similarly, when the switch was opened, the magnetic flux in the core would decrease from it's constant value back to zero. Hence, a decreasing flux within the core induced an opposite current on the right side. </div>]]></description>
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         <pubDate>2021-01-25 01:51:57 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1119972851</guid>
      </item>
      <item>
         <title>The 3rd Maxwell&#39;s equation (Part 3)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130041312</link>
         <description><![CDATA[<div>Faraday figured out that a changing Magnetic Flux within a circuit (or closed loop of wire) produced an induced <em>EMF</em>, or voltage within the circuit. In Equation [2],  is the Magnetic Flux within a circuit, and <em>EMF</em> is the electro-motive force, which is basically a voltage source. Equation [2] then says that the induced voltage in a circuit is the opposite of the time-rate-of-change of the magnetic flux.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/6d3365aee0d51b4e322d26a6cd75328d/lenz_law.gif" />
         <pubDate>2021-01-27 06:10:36 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130041312</guid>
      </item>
      <item>
         <title>The 3rd Maxwell&#39;s equation (part4)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130048955</link>
         <description><![CDATA[<div>We know that the rate of change of the total magnetic flux is equal to the opposite of the <em>EMF</em>, or the electric force within the wire. The total magnetic flux is simply the integral (or sum) of the <strong>B</strong> field over the area enclosed by the wire: </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/b5d41b4eeeb8665ddd4c9aaac4a0dd4e/magnetic_flux.png" />
         <pubDate>2021-01-27 06:14:05 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130048955</guid>
      </item>
      <item>
         <title>The 3rd maxwell&#39;s equation -5</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130060263</link>
         <description><![CDATA[<div>To find the total <em>EMF</em> induced around the whole circuit, we sum up over the length of the wire the <em>EMF</em> produced at each point. This is known as a line integral. This is written as:</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/90c13ce8f9dc0c6bd0804bec09be39e3/emf.png" />
         <pubDate>2021-01-27 06:19:13 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130060263</guid>
      </item>
      <item>
         <title>The 3rd Maxwell&#39;s Equation-7</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130065554</link>
         <description><![CDATA[<div>Now, recall that the <a href="http://maxwells-equations.com/fields/electric.php">Electric Field is directly related to force from electric charges</a>. And Voltage is also defined as the sum (integral) of the Electric Field across a path [recall that the E-field is measured in Volts/meter]. Hence, the E-field is actually the spatial-derivative of voltage (E-field is equal to the rate of change of the voltage with respect to distance). </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/665dfeba6b965badea407a1fda45df6c/voltage.gif" />
         <pubDate>2021-01-27 06:21:39 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130065554</guid>
      </item>
      <item>
         <title>The 3rd Maxwell&#39;s Equation-Part 8</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130070393</link>
         <description><![CDATA[<div>Hence, Equations [4] and [5] tell us that the differential amount of <em>EMF</em> at any point along the circuit (<em>dEMF</em> in [4]) is equal to the <strong>E</strong> field at that location. Therefore: </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/2679f8061cc1969b594ba67cb1969ab5/emf_efield.png" />
         <pubDate>2021-01-27 06:23:48 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130070393</guid>
      </item>
      <item>
         <title>The 3rd Maxwell&#39;s Equation-Part 9</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130083129</link>
         <description><![CDATA[<div>Now, a mathematician named Stokes figured out that integrating (averaging) of a field around a loop is exactly equivalent to integrating the <a href="http://www.maxwells-equations.com/curl/curl.php">curl</a> of the field within the loop. The curl is the measure of the rotation of a field, so the curl of a vector field within a surface should be related to the integral of a field around a loop that encloses the surface.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/109660098/5caf70020e2fdc119a6e371e91e9c5de/stokes.gif" />
         <pubDate>2021-01-27 06:29:29 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130083129</guid>
      </item>
      <item>
         <title>The 3rd Maxwell&#39;s Equation- Part 10</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130087242</link>
         <description><![CDATA[<div> If we replace Farday's Law of Equation [2], with the terms we found in Equation [3] and Equation [7], then we get: <br><br>In Equation [8], we note that if we have two integrals over surfaces, and the surfaces can be however we choose, then the quantities we integrate must also be the same. And this is how we obtained Faraday's Law in final form, as listed on Maxwell's Equations.</div>]]></description>
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         <pubDate>2021-01-27 06:31:07 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130087242</guid>
      </item>
      <item>
         <title>The 4th Maxwell&#39;s Equation</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130102444</link>
         <description><![CDATA[<div>The meaning of the last of Maxwell's Equations, <strong>Ampere's Law</strong>, which is given in Equation [1]: <br><br>Ampere was a scientist experimenting with forces on wires carrying electric current. He was doing these experiments back in the 1820s, about the same time that Farday was working on <a href="http://www.maxwells-equations.com/faraday/faradays-law.php">Faraday's Law</a>. Ampere and Farday didn't know that there work would be unified by Maxwell himself, about 4 decades later. </div>]]></description>
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         <pubDate>2021-01-27 06:35:23 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130102444</guid>
      </item>
      <item>
         <title>The 4th Maxwell&#39;s Equation (Part 2)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130112927</link>
         <description><![CDATA[<div>Ampere's Law, which relates a electric current flowing and a magnetic field wrapping around it: <br><br> Equation [2] can be explained: Suppose you have a conductor (wire) carrying a current, <em>I</em>. Then this current produces a <a href="http://www.maxwells-equations.com/fields/magnetic.php">Magnetic Field</a> which circles the wire. </div><div> The left side of Equation [2] means: If you take any imaginary path that encircles the wire, and you add up the Magnetic Field at each point along that path, then it will numerically equal the amount of current that is encircled by this path (which is why we write  for encircled or enclosed current). </div>]]></description>
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         <pubDate>2021-01-27 06:38:51 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130112927</guid>
      </item>
      <item>
         <title>The 4th Maxwell&#39;s Equation (Part 3)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130127799</link>
         <description><![CDATA[<div>If we are adding up a constant value for the magnetic field (we'll call it <em>H</em>), then the left side of Equation [2] becomes simple: <br>Hence, we have figured out what the magnitude of the <strong>H</strong> field is. And since <em>r</em> was arbitrary, we know what the H-field is everywhere. Equation [3] states that the Magnetic Field decreases in magnitude as you move farther from the wire (due to the 1/r term). </div>]]></description>
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         <pubDate>2021-01-27 06:44:45 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130127799</guid>
      </item>
      <item>
         <title>Mathematical Expression for Ampere&#39;s Law</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130138729</link>
         <description><![CDATA[<div>On the right side equality in Equation [4], we have used Stokes' Theorem to change a line integral around a closed loop into the <a href="http://www.maxwells-equations.com/curl/curl.php">curl</a> of the same field through the surface enclosed by the loop (<em>S</em>). </div>]]></description>
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         <pubDate>2021-01-27 06:49:01 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130138729</guid>
      </item>
      <item>
         <title>Mathematical Expression For Ampere&#39;s Law (Part 2)</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130151805</link>
         <description><![CDATA[<div>We can also rewrite the total current () as the surface integral of the <a href="http://maxwells-equations.com/density/current.php">Current Density (<strong>J</strong>)</a>: </div>]]></description>
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         <pubDate>2021-01-27 06:54:04 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130151805</guid>
      </item>
      <item>
         <title>Mathematical Expression for Ampere&#39;s Law- Part 3</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130155874</link>
         <description><![CDATA[<div>So now we have the original Ampere's Law (Equation [2]) rewritten in terms of surface integrals (Equations [4] and [5]). Hence, we can substitute them together and get a new form for Ampere's Law: <br>Now, we have a new form of Ampere's Law: the curl of the magnetic field is equal to the <a href="http://maxwells-equations.com/density/current.php">Electric Current Density</a>. </div>]]></description>
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         <pubDate>2021-01-27 06:55:35 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130155874</guid>
      </item>
      <item>
         <title>Displacement Current Density ( Ampere&#39;s Law)-Part 1</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130165126</link>
         <description><![CDATA[<div>the <a href="http://www.maxwells-equations.com/divergence.php">divergence</a> of the <a href="http://www.maxwells-equations.com/curl/curl.php">curl</a> of any vector field is always zero: </div>]]></description>
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         <pubDate>2021-01-27 06:59:05 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130165126</guid>
      </item>
      <item>
         <title>Displacement Current Density (Ampere&#39;s Law)-Part 2</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130174966</link>
         <description><![CDATA[<div>So let's take the divergence of Ampere's Law as written in Equation [6]: <br>If the divergence of <strong>J</strong> is always zero, this means that the electric current flowing into any region is always equal to the electric current flowing out of the region (no divergence).</div>]]></description>
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         <pubDate>2021-01-27 07:02:42 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130174966</guid>
      </item>
      <item>
         <title>Displacement Current Density (Ampere&#39;s Law)-Part 3</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130200866</link>
         <description><![CDATA[<div>This seems somewhat reasonable, as electric current in circuits flows in a loop. But let's look what happens if we put a capacitor in the circuit: <br>Now, we know from electric circuit theory that if the voltage is not constant (for example, any periodic wave, such as the 60 Hz voltage that comes out of your power outlets) then current will flow through the capacitor. That is, we have <strong>I</strong> not equal to zero in Figure 3. </div>]]></description>
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         <pubDate>2021-01-27 07:12:25 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130200866</guid>
      </item>
      <item>
         <title>Displacement Current Density -Part 4</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130253351</link>
         <description><![CDATA[<div>However, a capacitor is basically two parallel conductive plates separated by air. Hence, there is no conductive path for the current to flow through. This means that no electric current can flow through the air of the capacitor. This is a problem if we think about Equation [8]. To show it more clearly, let's take a volume that goes through the capacitor, and see if the divergence of <strong>J</strong> is zero: <br><br>n Figure 4, we have drawn an imaginary volume in red, and we want to check if the divergence of the current density is zero. The volume we've chosen, has one end (labeled side 1) where the current enters the volume via the black wire. The other end of our volume (labeled side 2) splits the capacitor in half. </div><div> We know that the current flows in the loop. So current enters through Side 1 of our red volume. However, there is no electric current that exits side 2. No current flows within the air of the capacitor. This means that current enters the volume, but nothing leaves it - so the divergence of <strong>J</strong> is not zero. We have just violated our Equation [8], which means the theory does not hold. And this was the state of things, until Maxwell came along. </div>]]></description>
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         <pubDate>2021-01-27 07:29:57 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130253351</guid>
      </item>
      <item>
         <title>Displacement Current density-Part 5</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130297343</link>
         <description><![CDATA[<div>Maxwell knew that the Electric Field (and <a href="http://www.maxwells-equations.com/density/electric-flux.php">Electric Flux Density (<strong>D</strong>)</a> was changing within the capacitor. And he knew that a time-varying magnetic field gave rise to a solenoidal Electric Field (i.e. this is Farday's Law - the curl of E equals the time derivative of <strong>B</strong>). So, why is not that a time varying <strong>D</strong> field would give rise to a solenoidal <strong>H</strong> field (i.e. gives rise to the curl of <strong>H</strong>). The universe loves symmetry, so why not introduce this term? And so Maxwell did, and he called this term the <em>displacement current density</em>: </div>]]></description>
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         <pubDate>2021-01-27 07:44:02 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130297343</guid>
      </item>
      <item>
         <title>Displacement Current Density-Part 6</title>
         <author>arifjalil</author>
         <link>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130306024</link>
         <description><![CDATA[<div>This term would "fix" the circuit problem we have in Figure 4, and would make Farday's Law and Ampere's Law more symmetric. This was Maxwell's great contribution. And you might think it is a weak contribution. But the existance of this term unified the equations and led to understanding the propagation of electromagnetic waves, and the proof that all waves travel at the same speed (the speed of light)! And it was this unification of the equations that Maxwell presented, that led the collective set to be known as Maxwell's Equations. So, if we add the displacement current to Ampere's Law as written in Equation [6], then we have the final form of Ampere's Law: </div>]]></description>
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         <pubDate>2021-01-27 07:46:37 UTC</pubDate>
         <guid>https://padlet.com/arifjalil/prn74dx3zlzqzhk0/wish/1130306024</guid>
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