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      <title>Шығым есептеу by Газиза Макуаевна</title>
      <link>https://padlet.com/jgm092016/po13w8vvasfa38r6</link>
      <description>Шығымға есептеуле</description>
      <language>en-us</language>
      <pubDate>2020-11-10 16:33:01 UTC</pubDate>
      <lastBuildDate>2024-02-08 04:07:23 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
      <image>
         <url>https://padlet.net/icons/png/1f4da.png</url>
      </image>
      <item>
         <title>2KBr+Cl2=2KCl+Br2</title>
         <author></author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239435091</link>
         <description><![CDATA[<div>m(KCl)=35,76g<br>35,76 - 80%       x- 100%<br>mпр=44,7g    M(KCl)=74.5g/mol<br>n=m/M= 44.7/74.5=0.6mol(KCl)<br>1 -x<br>2 - 0.6m      x(Cl2)=0.3mol<br>V=Vm*n=0.3*22.4=6.72litr</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 04:54:59 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239435091</guid>
      </item>
      <item>
         <title></title>
         <author>samallmasbek</author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239435471</link>
         <description><![CDATA[<div>шығым= 80%<br>m(KCl)=35.76g<br>V(Cl2)=?<br>Cl2+2KBr= 2KCl + Br2<br>шығым=mп/mт&nbsp;<br>mт(KCl)=mп*100%/80%<br>теория масса(KCl)=35.76*100/80=44.7<br>n(KCl)=44,7/74.5 = 0.6 mol<br>n(cl2)=0.3 mol<br>V(Cl2)= 22.4 * 0.3= 6.72 l<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 04:55:12 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239435471</guid>
      </item>
      <item>
         <title>mn/mт=шығым</title>
         <author></author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239436948</link>
         <description><![CDATA[<div>mт(KCl)=35,76*100/80=44,7<br>n(KCl)=44,7/74,5=0.6моль<br>n(Cl2)=0.3моль<br>V(Cl2)=22,4*0,3моль=6.7литр<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 04:56:04 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239436948</guid>
      </item>
      <item>
         <title></title>
         <author>adildariga0</author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239439625</link>
         <description><![CDATA[<div>2KBr+CI2=2KCI+Br2<br>35.76 - 80%<br>x - 100%<br>x=44,7g<br>n(KCI)=44,7/74,5=0,6mol<br> 1 - 2<br>x - 0,6<br>x=0,3mol<br>v(CI2)=0,3*22,4=6,72л<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 04:57:39 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239439625</guid>
      </item>
      <item>
         <title>шыгым=80процент</title>
         <author></author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239442840</link>
         <description><![CDATA[<div>m(KCl)=35.76г<br>V(Cl)=?<strong><br></strong>2KBr + Cl2 = 2KCl + Br2<br>шыгым=mn/mt= 35.76*100/80=44.7<br>n(Cl2)= 0.3 моль<br>n(KCl)= 44.7/74.5 = 0.6моль<br>V(Cl2)= 22.4 * 0.3= 6/72<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 04:59:32 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239442840</guid>
      </item>
      <item>
         <title>2KBr + Cl2 = 2KCl + Br2</title>
         <author></author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239443063</link>
         <description><![CDATA[<div>w=mt/mp*100%<br>mt=mp*100/w=100*35,76=44,7<br>n(KCl)=44,7/75=0.596mol<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 04:59:41 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239443063</guid>
      </item>
      <item>
         <title>2KBr+Cl2=2KCl+Br2</title>
         <author></author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239444307</link>
         <description><![CDATA[<div>m (KCl)= 35.76г<br>шығым=80%<br>V (Cl) = ?<br>шешуі:<br>шығым = mn/mт<br>35.76-80%<br>х-100%<br>х=100*35.76/80=44.7г(шығым)<br>m(KCl)=74.5г/моль<br>n=m/М=44.7/74.5=0.6моль<br>1-х<br>2-0.6<br>х=0.6/2=0.3моль(Сl2)<br>V=Vm*n=0.3*22.4=6.72л<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 05:00:26 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239444307</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239455251</link>
         <description><![CDATA[<div>Cl 2+2 KBr=2KCl+Br2<br>Шыгым=mп/ m т <br>mтеория=mпр * шыгым <br>m(kcl)35,76/0,8=44,7г<br>n(KCl)=44,7 : 74,5=0,6<br>n(Cl)=0,3 моль <br>V=n*22,4=6,72 литр <br><br></div>]]></description>
         <pubDate>2021-02-25 05:06:41 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239455251</guid>
      </item>
      <item>
         <title>%3</title>
         <author>adildariga0</author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239475278</link>
         <description><![CDATA[<div>Na2CO3+2HCI=2NaCI+H2O+CO2<br>n(Na2CO3)=10,6g/106g/mol=0,1mol<br>n(CO2)=0,1mol<br>0,1 - 100%<br>x - 80%<br>x=0,08<br>v(CO2)=0,08*22,4=1,8л</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 05:17:54 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239475278</guid>
      </item>
      <item>
         <title>шығым=80%</title>
         <author></author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239477434</link>
         <description><![CDATA[<div>Na2CO3+2HCl=2NaCl+H2O=CO2<br>m(Na2CO3)=10.6г<br>M(Na2CO3)=106г/моль<br>V(CO2)=?<br>n(Na2CO3)=m/M=10.6/106=0.1моль<br>n(CO2)=0.1моль<br>0.1-100%<br>х-80%<br>х=80*0.1/100=0.08<br>V=0.08*22.4=1.79=1.8л</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 05:19:12 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239477434</guid>
      </item>
      <item>
         <title>Na2CO3 +2HCl=2NaCl+H2O+CO2</title>
         <author>samallmasbek</author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239477573</link>
         <description><![CDATA[<div>n(NaCO3)=10.6/106=0.1 mol<br>n(co2)=0.1 mol<br>V(co2)=22.4*0.1=2.24 l<br>шығым=Vп/Vт<br>Vт= шығым *vп=80/100 *2.24=1.8l<br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 05:19:18 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239477573</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239479637</link>
         <description><![CDATA[<div>Na2Co3+ 2HCl = 2NaCl + H20 + CO2<br>Шығым=mп/mт<br>10,6г-80%<br>х-100%<br>mт(NaCO3)1060/80=13,25г<br>n=m/M=13,25/106=0,125<br>n(CO2)=0,125моль&nbsp;<br>V=n*V=2,8л&nbsp;<br><br><br><br></div>]]></description>
         <pubDate>2021-02-25 05:20:27 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239479637</guid>
      </item>
      <item>
         <title>m(Na2CO3)=10,6g</title>
         <author></author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239480985</link>
         <description><![CDATA[<div>Na2CO3+2HCl=2NaCl+H2O+CO2<br>шығым=80%<br>шығым=Vп/Vт<br>n(NaCo3)=10,6g/106=0.1моль<br>n(CO2)=0.1моль<br>V(CO2)=22,4*0.1моль=2.24<br>Vт=шығым*Vп=80%/100*2.24=1.8литр</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 05:21:18 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239480985</guid>
      </item>
      <item>
         <title>NH3+ HCl = NH4CL</title>
         <author></author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239485848</link>
         <description><![CDATA[<div>n(NH3)=3.4/17=0.2mol<br>n(NH3)=n(NH4CL)<br>mt=n*M=0.2*53=10.6g<br>w=mp/mt*100%=9g/10.6g*100%=84.9%</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 05:24:03 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239485848</guid>
      </item>
      <item>
         <title>NH3+HCl=NH4Cl</title>
         <author></author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239486759</link>
         <description><![CDATA[<div>m(NH3)=3,4g  M(NH3)=17g/mol<br>n=0.2 mol<br>mп(NH4Cl)=9g    n(NH4Cl)=0.2mol<br>mт=m*M=0.2*53.5=10.7g<br>n=mпр/mт=9/10.7=0.84=84%<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 05:24:34 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239486759</guid>
      </item>
      <item>
         <title>NH3+HCl=NH4Cl</title>
         <author></author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239490378</link>
         <description><![CDATA[<div>M(NH3)=17г/моль<br>mп(NH4Cl)=9г<br>n=0.2 моль<br>m(NH3)=3,4г<br>mт=9*0.2=1.8г<br>n=mпр/mт<br>n=9/1,8=5<br>mт= m*M<br>mt= 0.2*53.5=10.7г<br>n= mпр/mт<br>n= 9/10.7=0.84= 84%<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 05:26:42 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239490378</guid>
      </item>
      <item>
         <title>%2</title>
         <author>adildariga0</author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239497109</link>
         <description><![CDATA[<div>NH3+HCI=NH4CI<br>n(NH3)=3,4/17=0,2mol<br>n(NH4CI)=0,2mol<br>mпр(NH4CI)=0,2*53,5=10,7g<br>шығым=9g/10,7g*100%=84,1%</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 05:30:15 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239497109</guid>
      </item>
      <item>
         <title>2NH3 +2HCl=2NH4Cl+H2</title>
         <author>samallmasbek</author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239498998</link>
         <description><![CDATA[<div>n(NH3)=3.4/18=0.18 mol<br>n(NH4Cl) = 0.2 mol<br>m(NH4Cl)= 0.2 * 53.4=9.6 g<br>шыгым= m/m*100%=9/9.6*100%=93%</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 05:31:17 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239498998</guid>
      </item>
      <item>
         <title>NH3+HCl=NH4Cl</title>
         <author></author>
         <link>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239510937</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2021-02-25 05:37:51 UTC</pubDate>
         <guid>https://padlet.com/jgm092016/po13w8vvasfa38r6/wish/1239510937</guid>
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