Área de triângulos e quadriláteros by Otávio Santana https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl Mapa metal en-us 2021-06-10 18:19:46 UTC 2025-04-11 15:28:49 UTC hello@padlet.com https://padlet-uploads.storage.googleapis.com/649278835/45d8e6f6b46803b73190dd227a37fd2a/boroca.jpg Para calcular a área de um trapézio basta somar a base maior e base menor, multiplicar pela altura e depois, basta dividir o resultado por dois. santanacarvalhootavio https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599399077 2021-06-10 18:56:38 UTC https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599399077 Área enzolucasnolasco https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599408297 é a região interna de uma figura, delimitada pelo perímetro para calcular a área de um dos seguintes polígonos: ]]> 2021-06-10 19:01:25 UTC https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599408297 Basta multiplicar a base vezes a altura enzolucasnolasco https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599411345 8x5=40m]]> 2021-06-10 19:02:58 UTC https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599411345 enzolucasnolasco https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599423669 10,8+6,2=17 cm
17x5=85 cm
85 dividido por 2=42,5 cm]]> 2021-06-10 19:09:27 UTC https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599423669 Para calcularmos a área de um losango devemos realizar multiplicação da base vezes a altura e depois dividir o resultado por 2 enzolucasnolasco https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599434751 2021-06-10 19:15:22 UTC https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599434751 Para calcularmos a área de um triangulo devemos realizar multiplicação da base vezes a altura e depois dividir o resultado por 2 enzolucasnolasco https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599449165 2021-06-10 19:23:05 UTC https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599449165 A área do paralelogramo pode ser calculada pela multiplicação da medida de sua base pela medida de sua altura, também chamadas de comprimento e largura. santanacarvalhootavio https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599454885 2021-06-10 19:26:19 UTC https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599454885 enzolucasnolasco https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599486516 2x4=8
8 dividido por 2=4 cm]]> 2021-06-10 19:43:02 UTC https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599486516 enzolucasnolasco https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599493708 9,4x7 =65,8 cm
65,8 dividido por 2=32,9]]> 2021-06-10 19:47:06 UTC https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599493708 enzolucasnolasco https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599504407 6x10=60cm]]> 2021-06-10 19:53:02 UTC https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599504407 enzolucasnolasco https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599543089 2021-06-10 20:14:43 UTC https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599543089 enzolucasnolasco https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599543315 1x1=1m
3x5=15m
2x1=2m
1+15+2=18m]]> 2021-06-10 20:14:51 UTC https://padlet.com/santanacarvalhootavio/ov1kpofs8ifrhbvl/wish/1599543315