Titration Infographic with problem created and solved by Brandon Suris https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k by Brandon Suris en-us 2021-04-27 23:31:49 UTC 2026-01-10 11:00:51 UTC hello@padlet.com Titration Problem created and solved bsuris30 https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1467038862 by Brandon Suris]]> 2021-04-28 01:18:41 UTC https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1467038862 After Equivalence Process bsuris30 https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1467055032 After the process, it begins to reach the endpoint where there is a physical change like the color of the solution changes. Anything that is excess like the acid or base will determine the pH of the substance.]]> 2021-04-28 01:24:19 UTC https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1467055032 bsuris30 https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1471325455 2021-04-28 22:36:46 UTC https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1471325455 There is a sample of 30.0 mL of HCl with 0.155 M being titrated with 220 NaOH. What would the concentration of NaOH be? bsuris30 https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1471364848 2021-04-28 23:00:16 UTC https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1471364848 1st Step bsuris30 https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1471398412 You want to multiply 0.155 M with 0.0300 L(which is also known as 30.0 mL) and then you get 0.00465]]> 2021-04-28 23:20:31 UTC https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1471398412 2nd Step (Last Step) bsuris30 https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1471402566 Now, you want to get the answer from the previous step which is 0.00465 and divide it with 220 HCl but you want to make sure it is in liters instead of mL. So you divide by .220 L and you will get 0.0211 M.]]> 2021-04-28 23:23:07 UTC https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1471402566 Final Answer bsuris30 https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1471406170 So after a couple of problem solving, your answer will be 0.0211 M. In other words, 0.0211 M is the concentration of the substance NaOH (Sodium hydroxide).]]> 2021-04-28 23:25:26 UTC https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1471406170 Before Equivalence Process bsuris30 https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1471497540 You must figure out the moles to be able to divide it by the volume. At this point you will also be getting the volume (acid or base) and adding it to a flask.]]> 2021-04-29 00:14:13 UTC https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1471497540 At Equivalence Process bsuris30 https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1471498977 The point in a titration process where there is enough base or acid to neutralize the solution that's inside the flask.]]> 2021-04-29 00:14:54 UTC https://padlet.com/bsuris30/ooqzbfv3fdcp4j2k/wish/1471498977