<?xml version="1.0"?>
<rss version="2.0">
   <channel>
      <title>OPT463 Group 6 (45 degree) by </title>
      <link>https://padlet.com/hliao101/oantee2fsjp4o2qn</link>
      <description>Made with charm</description>
      <language>en-us</language>
      <pubDate>2021-09-10 20:54:00 UTC</pubDate>
      <lastBuildDate>2023-06-11 06:38:01 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
      <image>
         <url></url>
      </image>
      <item>
         <title></title>
         <author>hliao101</author>
         <link>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1731857592</link>
         <description><![CDATA[<var>\\\Psi_1 = a_1e^{i(\vec k_1 \cdot \vec r - wt)}\\\Psi_2 = a_2e^{i(\vec k_2 \cdot \vec r - wt)}\\\Psi_R = \Psi_1 + \Psi_2 = a_1e^{i(\vec k_1 \cdot \vec r - wt)} + a_2e^{i(\vec k_2 \cdot \vec r - wt)}\\</var><div><br></div><var>I_R = |\Psi_1 + \Psi_2|^2 = \Psi_R\Psi_R^{*}\\I_R = a_1^{2}+a_2^{2}+2a_1a_2cos((\vec k_1-\vec k_2) \cdot \vec r)\\</var><div><br></div><var>\vec k_1 \cdot \vec r = kxsin(\theta_1) + kxcos(\theta_1)\\\vec k_2 \cdot \vec r = kxsin(\theta_2) + kxcos(\theta_2)\\</var><div><br></div><var>\phi = (\vec k_1-\vec k_2) \cdot \vec r\\\phi = kx(sin(\theta_1)-sin(\theta_2))+kz(cos(\theta_1)-cos(\theta_2))\\\Delta \phi=2\pi\\</var><div><br><br></div><var>\text{To solve }\Lambda_x:\\\Delta \phi=\phi_b - \phi_b=kx_b(sin(\theta_1)-sin(\theta_2))-kx_a(sin(\theta_1)-sin(\theta_2))\\\Delta \phi=k(sin(\theta_1)-sin(\theta_2))(x_b-x_a)\\2\pi=\frac{2\pi}{\lambda}(sin(\theta_1)-sin(\theta_2))\Lambda_x\\</var><div><br></div><var>\Rightarrow \Lambda_x=\frac{\lambda}{|sin(\theta_1)-sin(\theta_2)|}\\</var><div><br><br></div><var>\text{To solve }\Lambda_z:\\\Delta \phi=\phi_b - \phi_b=kz_b(cos(\theta_1)-cos(\theta_2))-kz_a(sin(\theta_1)-cos(\theta_2))\\\Delta \phi=k(cos(\theta_1)-cos(\theta_2))(z_b-z_a)\\2\pi=\frac{2\pi}{\lambda}(cos(\theta_1)-cos(\theta_2))\Lambda_z\\</var><div><br></div><var>\Rightarrow \Lambda_z=\frac{\lambda}{|cos(\theta_1)-cos(\theta_2)|}\\</var><div><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-09-10 20:56:09 UTC</pubDate>
         <guid>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1731857592</guid>
      </item>
      <item>
         <title>Bisector angle 15 degree</title>
         <author></author>
         <link>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1734583524</link>
         <description><![CDATA[<var><strong>\Psi_{1}</strong>=a<strong>_{1}</strong>e<strong>^{</strong>i<strong>({\vec{</strong>k<strong>_{1}}\cdot</strong> <strong>\vec{</strong>r<strong>}-\omega</strong> t<strong>})}</strong></var><div><br></div><var><strong>\Psi_{1}</strong>=a<strong>_{2}</strong>e<strong>^{</strong>i<strong>({\vec{</strong>k<strong>_{2}}\cdot</strong> <strong>\vec{</strong>r<strong>}-\omega</strong> t<strong>})}</strong></var><div><br></div><var><strong>\Psi_{R}=\Psi_{1}+\Psi_{2}</strong></var><div><br></div><var>I_{R}=<strong>\left|\Psi_{R}\right|
=a_{1}^{2}+a_{2}^{2}+2a_{1}a{2}cos((\vec{k_{1}}-\vec{k_{2}})\cdot\vec{r})</strong></var><div><br></div><var>\phi=(<strong>\vec{k_{1}}-\vec{k_{2}})\cdot\vec{r}</strong></var><div><br></div><var><strong>\vec{</strong>k<strong>_{1}}\cdot</strong> <strong>\vec{</strong>r<strong>}</strong>=k<strong>\hat{</strong>x<strong>}</strong>sin<strong>\theta_{1}\cdot</strong> x<strong>\hat{</strong>x<strong>}+</strong>k<strong>\hat{</strong>z<strong>}</strong>cos<strong>\theta_{1}\cdot</strong> z<strong>\hat{</strong>z<strong>}=kxsin\theta_{1}+kzcos\theta_{1}</strong></var><div><br></div><var><strong>\vec{</strong>k<strong>_{2}}\cdot</strong> <strong>\vec{</strong>r<strong>}</strong>=<strong>kxsin\theta_{2}+kzcos\theta_{2}</strong></var><div><br></div><var><strong>\theta_{1}=60^{\circ}, \theta_{2}=30^{\circ}</strong></var><div><br></div><var><strong>\vec{</strong>k<strong>_{1}}\cdot</strong> <strong>\vec{</strong>r<strong>}=0.87kx+0.5kz</strong></var><div><br></div><var><strong>\vec{</strong>k<strong>_{2}}\cdot</strong> <strong>\vec{</strong>r<strong>}=0.5kx+0.86kz</strong></var><div><br></div><var>For \Lambda_{x}:</var><div><br></div><var>\Delta\phi=\phi_{b}-\phi_{a}=2\pi</var><div><br></div><var>2\pi=<strong>kx_{b}sin\theta_{1}-kx_{b}sin\theta_{2}-(kx_{a}sin\theta_{1}-kx_{a}sin\theta_{2})
=k(sin\theta_{1}-sin\theta_{2})(x_{b}-x_{a})
=\frac{2\pi}{\lambda}(sin\theta_{1}-sin\theta_{2})\Lambda_{x}</strong></var><div><br></div><var><strong>\Lambda_{x}=\frac{\lambda}{\left|sin\theta_{1}-sin\theta_{2}\right|}=\frac{\lambda}{0.37}</strong></var><div><br></div><var>For \Lambda_{z}:</var><div><br></div><var>\Delta\phi=\phi_{b}-\phi_{a}=2\pi</var><div><br></div><var>2\pi=<strong>kz_{b}cos\theta_{1}-kz_{b}cos\theta_{2}-(kz_{a}cos\theta_{1}-kz_{a}cos\theta_{2})
=k(cos\theta_{1}-cos\theta_{2})(z_{b}-z_{a})
=\frac{2\pi}{\lambda}(cos\theta_{1}-cos\theta_{2})\Lambda_{z}</strong></var><div><br></div><var><strong>\Lambda_{z}=\frac{\lambda}{\left|cos\theta_{1}-cos\theta_{2}\right|}=\frac{\lambda}{0.37}</strong></var><div><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-09-13 01:48:32 UTC</pubDate>
         <guid>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1734583524</guid>
      </item>
      <item>
         <title>Bisector angle 30 degrees</title>
         <author></author>
         <link>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1735425161</link>
         <description><![CDATA[<var><var><strong>\theta_{1}=75^{\circ}, \theta_{2}=15^{\circ}</strong></var></var><div><br></div><var><var><strong>\vec{</strong>k<strong>_{1}}\cdot</strong> <strong>\vec{</strong>r<strong>}=0.97kx+0.26kz</strong></var></var><div><br></div><var><var><strong>\vec{</strong>k<strong>_{2}}\cdot</strong> <strong>\vec{</strong>r<strong>}=0.26kx+0.97kz</strong></var></var><div><br></div><var>For \Lambda_{x}:</var><div><br></div><var>\Delta\phi=\phi_{b}-\phi_{a}=2\pi</var><div><br></div><var>2\pi=<strong>kx_{b}sin\theta_{1}-kx_{b}sin\theta_{2}-(kx_{a}sin\theta_{1}-kx_{a}sin\theta_{2})
=k(sin\theta_{1}-sin\theta_{2})(x_{b}-x_{a})
=\frac{2\pi}{\lambda}(sin\theta_{1}-sin\theta_{2})\Lambda_{x}</strong></var><div><br></div><var><strong>\Lambda_{x}=\frac{\lambda}{\left|sin\theta_{1}-sin\theta_{2}\right|}=\frac{\lambda}{0.71}</strong></var><div><br><br></div><var>For \Lambda_{z}:</var><div><br></div><var>\Delta\phi=\phi_{b}-\phi_{a}=2\pi</var><div><br></div><var>2\pi=<strong>kz_{b}cos\theta_{1}-kz_{b}cos\theta_{2}-(kz_{a}cos\theta_{1}-kz_{a}cos\theta_{2})
=k(cos\theta_{1}-cos\theta_{2})(z_{b}-z_{a})
=\frac{2\pi}{\lambda}(cos\theta_{1}-cos\theta_{2})\Lambda_{z}</strong></var><div><br></div><var><strong>\Lambda_{z}=\frac{\lambda}{\left|cos\theta_{1}-cos\theta_{2}\right|}=\frac{\lambda}{0.71}</strong></var>]]></description>
         <enclosure url="" />
         <pubDate>2021-09-13 08:25:25 UTC</pubDate>
         <guid>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1735425161</guid>
      </item>
      <item>
         <title>Bisector Angle = 75 degree</title>
         <author>hliao101</author>
         <link>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1736249040</link>
         <description><![CDATA[<var>
\\
\theta_f= 75 ^{\circ}
\\
\theta_1= 120 ^{\circ}
\\
\theta_2= -30 ^{\circ}</var><div><br></div><var>\\\Lambda_x=\frac{\lambda}{|sin(120 ^{\circ})-sin(-30 ^{\circ})|}\\ = 0.732\lambda\\</var><div><br></div><var>\Lambda_z=\frac{\lambda}{|cos( 120^{\circ})-cos( -30^{\circ})|}\\ = 0.732\lambda\\</var>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1338921361/e2838c2da735a2fb8a0c8cc9a8f9c5be/image.png" />
         <pubDate>2021-09-13 14:19:59 UTC</pubDate>
         <guid>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1736249040</guid>
      </item>
      <item>
         <title>Bisector Angle = 105 degree</title>
         <author>hliao101</author>
         <link>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1736249969</link>
         <description><![CDATA[<var>
\\
\theta_f= 105^{\circ}
\\
\theta_1=  150^{\circ}
\\
\theta_2=  -60^{\circ}
\\</var><div><br></div><var>\Lambda_x=\frac{\lambda}{|sin( 150^{\circ})-sin( -60^{\circ})|}\\ = 0.732\lambda\\</var><div><br></div><var>\\
\Lambda_z=\frac{\lambda}{|cos( 150^{\circ})-cos( -60^{\circ})|}\\ = 0.732\lambda\\</var>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1338921361/3b11e78fc3d58a17cabc221532235b93/image.png" />
         <pubDate>2021-09-13 14:20:14 UTC</pubDate>
         <guid>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1736249969</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1737395180</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1341695234/db11025ba8ae7d62fe7239e2e194dd72/bisector.pdf" />
         <pubDate>2021-09-13 21:10:58 UTC</pubDate>
         <guid>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1737395180</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1737558643</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1343996538/60b2f9949dbabc75d093539e293d2698/Wave_Optics_Group_Project.pdf" />
         <pubDate>2021-09-13 23:15:32 UTC</pubDate>
         <guid>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1737558643</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1737594588</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1343996538/6f7330b5e16fb0febd4b4d71046cbb4f/Lambda_x.png" />
         <pubDate>2021-09-13 23:41:11 UTC</pubDate>
         <guid>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1737594588</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1737594755</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1343996538/5740f87a7f4b339dbb68da8ce6244d3c/Lambda_z.png" />
         <pubDate>2021-09-13 23:41:17 UTC</pubDate>
         <guid>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1737594755</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1737607512</link>
         <description><![CDATA[<div>To create a function for fringe spacing in terms of bisector angle:<br><br></div><var>\Lambda_x = \frac{\lambda}{|\sin(\theta_1)-\sin(\theta_2)|}\\

\Lambda_x = \frac{\lambda}{|\sin(\alpha + \theta_f)-\sin(\alpha - \theta_f)|}\\

\Lambda_x = \frac{\lambda}{|\sin(\alpha)\cos(\theta_f) + \cos(\alpha)\sin(\theta_f) - \sin(\alpha)\cos(\theta_f) + \cos(\alpha)\sin(\theta_f)|}\\

\Lambda_x = \frac{\lambda}{|2\cos(\alpha)\sin(\theta_f)|}</var><div><br><br></div><var>\Lambda_z = \frac{\lambda}{|\cos(\theta_1)-\cos(\theta_2)|}\\

\Lambda_z = \frac{\lambda}{|\cos(\alpha + \theta_f)-\cos(\alpha - \theta_f)|}\\

\Lambda_z = \frac{\lambda}{|\cos(\alpha)\cos(\theta_f) - \sin(\alpha)\sin(\theta_f) - \cos(\alpha)\cos(\theta_f) - \sin(\alpha)\sin(\theta_f)|}\\

\Lambda_x = \frac{\lambda}{|-2\sin(\alpha)\sin(\theta_f)|}</var><div><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-09-13 23:49:21 UTC</pubDate>
         <guid>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1737607512</guid>
      </item>
      <item>
         <title>Presentation</title>
         <author></author>
         <link>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1739254136</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1341688771/54b05f2d2f432ce641d0de60a6d48a9e/Group_HW.mp3" />
         <pubDate>2021-09-14 12:33:45 UTC</pubDate>
         <guid>https://padlet.com/hliao101/oantee2fsjp4o2qn/wish/1739254136</guid>
      </item>
   </channel>
</rss>
