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      <title>Advanced Year 2 - moving forward with Common Problem by Tricia Phaneuf</title>
      <link>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8</link>
      <description>Made with no regrets, whatsoever...sharing our ideas about approaching the Fun Problem</description>
      <language>en-us</language>
      <pubDate>2020-08-23 18:13:07 UTC</pubDate>
      <lastBuildDate>2024-10-16 17:25:45 UTC</lastBuildDate>
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         <title>Zoe, Eliot, Kodiak</title>
         <author></author>
         <link>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697856991</link>
         <description><![CDATA[<div>So far our group has come up with n= 2 or 4 with solutions of -11 and 13. We used the method of trial and error.</div>]]></description>
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         <pubDate>2020-08-25 16:57:16 UTC</pubDate>
         <guid>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697856991</guid>
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         <title>Teagan, Isa, Lucy</title>
         <author>teagan_heller</author>
         <link>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697868233</link>
         <description><![CDATA[<div>We first factored the problem and ended with (n-3)(n+9). Then we started looking at prime numbers in general and what it means to be a prime number.</div>]]></description>
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         <pubDate>2020-08-25 17:00:19 UTC</pubDate>
         <guid>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697868233</guid>
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         <title>Alison, Noah, Miel</title>
         <author>mielwewerka1</author>
         <link>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697870113</link>
         <description><![CDATA[<div>We found that when n=-10 the solution is 13</div>]]></description>
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         <pubDate>2020-08-25 17:00:47 UTC</pubDate>
         <guid>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697870113</guid>
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         <title>Miel</title>
         <author>mielwewerka1</author>
         <link>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697877159</link>
         <description><![CDATA[<div>I made it into the function f(n)=n^2-6n-27. I graphed it and i got a parabola that passes through ((3,0) (-9,0) (0, -27) and (-3,-36). I have no idea what to do with this information</div>]]></description>
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         <pubDate>2020-08-25 17:02:41 UTC</pubDate>
         <guid>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697877159</guid>
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         <title>Zoe, Eliot, Kodiak</title>
         <author>eliot_patton</author>
         <link>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697877962</link>
         <description><![CDATA[<div>We were also wondering how to solve this (other than trial and error) and what it would look like on a graph.</div>]]></description>
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         <pubDate>2020-08-25 17:02:53 UTC</pubDate>
         <guid>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697877962</guid>
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         <title>Imani, Ella, Sam</title>
         <author></author>
         <link>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697879294</link>
         <description><![CDATA[<div>Our group was mostly working with trial and error but we found that -3 was the bottom </div>]]></description>
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         <pubDate>2020-08-25 17:03:11 UTC</pubDate>
         <guid>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697879294</guid>
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         <title></title>
         <author>mychalbishop</author>
         <link>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697896337</link>
         <description><![CDATA[Miel
I made it into the function f(n)=n^2-6n-27. I graphed it and i got a parabola that passes through ((3,0) (-9,0) (0, -27) and (-3,-36). I have no idea what to do with this information
]]></description>
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         <pubDate>2020-08-25 17:07:08 UTC</pubDate>
         <guid>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697896337</guid>
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      <item>
         <title>Noah</title>
         <author>noahliming1</author>
         <link>https://padlet.com/triciaphaneuf2/o11tpu4kgvg1p2h8/wish/697908104</link>
         <description><![CDATA[<div>I used substitution and trial and error to find that -10,-4,-2,2,4 all work</div>]]></description>
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         <pubDate>2020-08-25 17:09:58 UTC</pubDate>
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