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      <title> Soy un experto  3 - 4C by </title>
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      <description>Sube tu solución a este mural.</description>
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      <pubDate>2020-07-16 03:21:43 UTC</pubDate>
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         <title></title>
         <author>rosaguerra1</author>
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         <pubDate>2020-07-16 03:21:54 UTC</pubDate>
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         <title>Maricarmen</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656267784</link>
         <description><![CDATA[<div>quedan 3/4 de Azúcar en la bolsa </div>]]></description>
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         <pubDate>2020-07-16 18:33:42 UTC</pubDate>
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         <title>Paris</title>
         <author>74191505</author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656319767</link>
         <description><![CDATA[<div>Javier tiene: 1 1/2 kg al principio <br>Pasamos el número mixto a fracción: 1 1/2 = 3/2<br>Luego lo igualamos el denominador con lo que saco:<br>3/2 x 2 = 6/4<br>Restamos: 6/4 - 3/4 = 3/4<br>- Le queda 3/4 de kg en la bolsa de azúcar.</div>]]></description>
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         <pubDate>2020-07-16 19:49:24 UTC</pubDate>
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      <item>
         <title>Adriano Poma</title>
         <author>74671998</author>
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         <description><![CDATA[]]></description>
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         <pubDate>2020-07-16 19:53:25 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656322515</guid>
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      <item>
         <title>Vittoria</title>
         <author>62752536</author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656401915</link>
         <description><![CDATA[<div>A Javier le queda 3/4 kg de azúcar en la bolsa.</div>]]></description>
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         <pubDate>2020-07-16 22:08:20 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656401915</guid>
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      <item>
         <title>cristhian Corcino</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656405490</link>
         <description><![CDATA[<div>Javier tiene 1 1/2 kg de azucar y le saca 3/4<br>restamos <br><br>1 1/2 -3/4 =3/4 le quedo</div>]]></description>
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         <pubDate>2020-07-16 22:15:06 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656405490</guid>
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      <item>
         <title>Matias L.</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656406615</link>
         <description><![CDATA[<div>A Javier le queda 3/4 kg de azúcar :3</div>]]></description>
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         <pubDate>2020-07-16 22:17:23 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656406615</guid>
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         <title>Valentina</title>
         <author>74197598</author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656410109</link>
         <description><![CDATA[<div>A Javier le queda 3/4 de la bolsa de azúcar.</div>]]></description>
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         <pubDate>2020-07-16 22:25:09 UTC</pubDate>
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      <item>
         <title>Luana Sánchez</title>
         <author>74341861</author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656422395</link>
         <description><![CDATA[<div>shshgd Primero paso 1 1/2  a impropia y sale 3/2, luego homogenizamos para poder restar, 6/4 - 3/4= 3/4<br>Respuesta: Quedan 3/4 kg de azucar.</div>]]></description>
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         <pubDate>2020-07-16 22:52:39 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656422395</guid>
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         <title>Renzo Perez</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656423241</link>
         <description><![CDATA[<div>debemos volver 1 1/2  a impropia y sale 3/2, luego homogeneizamos 3/2 para que llegue a 3/4, el múltiplo común es 2 entonces debemos multiplicar 3/2 x 2 = 6/4 , por ultimo debemos restar 6/4 - 3/4 = 3/4.</div>]]></description>
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         <pubDate>2020-07-16 22:54:39 UTC</pubDate>
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      <item>
         <title>Camila Ostolaza</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656447846</link>
         <description><![CDATA[<div>A Javier le queda 3/4 de azúcar<br><br>1 1/2 es equivalente a 3/2,  lo homogenizamos y salio 6/4.<br> 6/4 menos 3/4 es  igual a 3/4<br><br><br></div>]]></description>
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         <pubDate>2020-07-16 23:44:35 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656447846</guid>
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         <title>Flavia canepa</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656967918</link>
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         <pubDate>2020-07-17 15:21:58 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/656967918</guid>
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      <item>
         <title>Joaquín Ojeda Muro</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/657283027</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-07-18 02:54:45 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/657283027</guid>
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      <item>
         <title>Flavia Barzola V.</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/657547884</link>
         <description><![CDATA[<div>Le quedan 3/4 de kilogramo.</div>]]></description>
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         <pubDate>2020-07-18 21:24:57 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/657547884</guid>
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         <title>Ariana</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/657558086</link>
         <description><![CDATA[<div>1 1/2 - 3/2<br><br>                  x 2<br>         3/2     =    6/4<br>                  x 2<br>6/4 - 3/4 = 3/4<br>A Javier le queda 3/4 kilogramos de azúcar.</div>]]></description>
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         <pubDate>2020-07-18 22:11:50 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/657558086</guid>
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      <item>
         <title>Adrian Leonel</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/657845058</link>
         <description><![CDATA[<div>1 1/2 - 3/4 = 3/2 - 3/4 = 6/4 - 3/4 = 3/4</div>]]></description>
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         <pubDate>2020-07-19 19:15:25 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/657845058</guid>
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      <item>
         <title>Camila O.</title>
         <author>74191505</author>
         <link>https://padlet.com/rosaguerra1/ndy1qetbd4x56xlh/wish/680654782</link>
         <description><![CDATA[<div>Poner seguridad a todas las zonas del lugar</div>]]></description>
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         <pubDate>2020-08-14 17:09:16 UTC</pubDate>
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