P3 Warm Up by Thitiya Karamooz [Escobedo MS]

10/13 - Write an inequality of the question below.

pathatn — 2020-10-13 19:16:11 UTC

The Desert Taxi Cab Company charges a $1.75 flat rate in addition to $0.65 per mile. Jaelyn has no more than $10 to spend on the ride. How many miles can Jaelyn go without exceeding her amount of money?

sidecharacterindustries — 2020-10-13 19:25:01 UTC

1.75 + 0.65x ≤ 10

Hali Smith

2020-10-13 19:25:32 UTC

1.75+0.65x≤10

Sara rodriguez.

2020-10-13 19:25:56 UTC

1.75+0.65x≤10

Makenzie Best

makenzie372567 — 2020-10-13 19:26:37 UTC

1.75+0.65x ≤10

1.75+0.65x>10

2020-10-13 19:29:24 UTC

Jacob Cyr

2020-10-13 19:29:36 UTC

1.75 + 0.65x ≤ 10

Aryssa Metra

2020-10-13 19:30:13 UTC

1.75 + 0.65x ≤ 10

Evan Lenz

2020-10-13 19:31:16 UTC

1.75 + 0.65x ≤ 10

Vanesa Mendoza

2020-10-13 19:31:21 UTC

1.75+0.65x≤ 10

Emmalee Zygmont

2020-10-13 19:31:21 UTC

1.75+0.65x≤10

Jacen rowles

2020-10-13 19:31:36 UTC

1.75+0.65x ≤10

Victor Camarena

2020-10-13 19:31:41 UTC

1.75+0.65x≤10

Kayli Densley

2020-10-13 19:31:41 UTC

1.75+0.65x ≤ 10

nyliyah love

2020-10-13 19:32:06 UTC

1.75 + 0.65x > 10

Kaleb Riddle

2020-10-13 19:32:09 UTC

1.75+0.65x≤10

2020-10-13 19:32:12 UTC

1.75+0.65x>10

Justin Winter

2020-10-13 19:32:50 UTC

1.75 +0.65x ≤ 10

mohagany mohn

2020-10-13 19:33:00 UTC

1.75+0.65x≤10

katie barillas

2020-10-13 19:33:04 UTC

1.75+0.65x < 10

Jayna Rowles

2020-10-13 19:33:24 UTC

1.75+0.65 ≤10

Johnmark Manalang

2020-10-13 19:33:49 UTC

1.75 + 0.65x ≤ 10

Yzabelle Monato

2020-10-13 19:33:54 UTC

1.75 + 0.65 ≤ 10

Zoe Teves

2020-10-13 19:34:48 UTC

1.75 + 0.65x ≤ 10

1.75 = 0.65x ≤ 10

nicklas_370253 — 2020-10-13 19:36:08 UTC

Ava Mendoza

2020-10-13 19:36:14 UTC

1.75+0.65x>10

Emily Falls

2020-10-13 19:36:21 UTC

1.75+0.65x≤ 10

Special symbols (M2)

sidecharacterindustries — 2020-10-13 19:37:15 UTC

You can copy the below symbols to use in your Warm Up.

≤ ≥  ≮ ≯ ≠ ÷ √ ≈ ½ ∛ ∞

View more characters

Kody Waltens

2020-10-13 19:37:43 UTC

1.75 + 0.65x ≤ 10

Joelle Kimble

2020-10-13 19:37:44 UTC

1.75+0.65x<10

2020-10-13 19:38:18 UTC

≤

Andrew Guzman

2020-10-13 19:39:06 UTC

1.75+0.65≤10

1.75 + 0.65 ≤ 10

2020-10-13 19:41:22 UTC

Ricky T

Makenzie Best

makenzie372567 — 2020-10-13 20:04:34 UTC

5x+4≥19
x≥3

If 5 times a number is increased by 4, the result is at least 19. Write this question in the inequality expression.

pathatn — 2020-10-13 20:04:46 UTC

Aryssa Metra

2020-10-13 20:04:48 UTC

5x + 4 ≥ 19
x ≥ 3

Jacob Cyr

2020-10-13 20:04:50 UTC

5x+4≥19
x ≥ 3

Kayli Densley

2020-10-13 20:05:01 UTC

5x+4≥19
x≥3

Victor Camarena

2020-10-13 20:05:08 UTC

5x+4≥19

x≥3

Evan Lenz

2020-10-13 20:05:15 UTC

5x + 4 ≥ 19

Yzabelle Monato

2020-10-13 20:05:35 UTC

5x + 4 ≥ 19
x ≥ 3

Emmalee Zygmont

2020-10-13 20:05:44 UTC

5x+4≥19
5x≥15
x≥3

Hali Smith

2020-10-13 20:05:45 UTC

5x+4≥19

Jayna Rowles

2020-10-13 20:05:48 UTC

5x+4 ≥19
x ≥3

Kaleb Riddle

2020-10-13 20:06:03 UTC

5x+4≥19

x ≥ 3

Mohagany Mohn

2020-10-13 20:06:04 UTC

5x+4≥19

x≥3

Jacen Rowles

2020-10-13 20:06:04 UTC

5x+4≥19

Andrew Guzman

2020-10-13 20:06:31 UTC

5x+4≥19

5x + 4 ≥ 19

sidecharacterindustries — 2020-10-13 20:06:45 UTC

Johnmark Manalang

2020-10-13 20:07:03 UTC

5x + 4 ≥ 19
x ≥ 3

Vanesa Mendoza

2020-10-13 20:07:04 UTC

5x+4 ≥ 19
x≥3

Special symbols (M2)

sidecharacterindustries — 2020-10-13 20:07:27 UTC

You can copy the below symbols to use in your Warm Up.

≤ ≥  ≮ ≯ ≠ ÷ √ ≈ ½ ∛ ∞

View more characters

Kody Waltens

2020-10-13 20:07:50 UTC

5x + 4 ≤ 19

5x + 4 ≥ 19

shelby_329633 — 2020-10-13 20:07:50 UTC

Shelby J

Zoe Teves

2020-10-13 20:08:07 UTC

5x + 4 ≥ 19
x ≥ 3

2020-10-13 20:08:56 UTC

4 ≥

Emily Falls

2020-10-13 20:08:57 UTC

5x+4 ≤ 19
x ≤ 3

Sara R

2020-10-13 20:10:16 UTC

4+5x greater than or equal to 19

katie

2020-10-13 20:12:26 UTC

5x+4 ≤ 19

Justin Winter

2020-10-13 20:12:38 UTC

5x+4≥19

Evan Lenz

2020-10-13 20:13:03 UTC

x ≥ 3

Tristan DeMoure

2020-10-13 20:13:27 UTC

5x+4≥19

2020-10-13 20:13:31 UTC

5x+4≥19

10/14 Warm up

pathatn — 2020-10-14 17:39:23 UTC

Write an inequality of the question below.
If 5 times a number is increased by 4, the result is at least 19. Find the least possible number that satisfies theses conditions.

Special symbols (M2)

pathatn — 2020-10-14 19:25:33 UTC

You can copy the below symbols to use in your Warm Up.

≤ ≥  ≮ ≯ ≠ ÷ √ ≈ ½ ∛ ∞

View more characters

Makenzie Best

makenzie372567 — 2020-10-14 19:25:48 UTC

5x + 4≥ 19
-4 -4
5x ≥ 15
x≥3

Vanesa Mendoza

vanesa_375107 — 2020-10-14 19:26:50 UTC

5x+4 ≥ 19
-4 -4
5x ≥ 15
x ≥ 3
The least possible number for x is 3.

aryssav_2358057 — 2020-10-14 19:27:04 UTC

5x + 4 ≥ 19
- 4 -4
5x ≥ 15
5x/ 5 15/5
x ≥ 3

Sara Rodriguez

2020-10-14 19:28:20 UTC

5x+4 ≥ 19
-4. -4
5x≥ 15
x≥3

Jacob Cyr

2020-10-14 19:28:57 UTC

5x + 4 ≥ 19
-4 -4
5x ≥ 15
x ≥ 3

x ≥ 3

sidecharacterindustries — 2020-10-14 19:29:21 UTC

If 5x + 4 ≥ 19, subtract 4 from both sides to get 5x ≥ 15. Divide to get x ≥ 3. This means that the lowest number that makes the equation true is 3

Andrew Guzman

2020-10-14 19:30:25 UTC

x≥3

Jayna Rowles

jayna366798 — 2020-10-14 19:32:47 UTC

5x+4≥19
-4 -4
5x≥15
x≥3

Yzabelle Monato

2020-10-14 19:32:50 UTC

5x + 4 ≥ 19
5x ≥ 15
x ≥ 3

5x+4≥19

emmalee_234547 — 2020-10-14 19:32:56 UTC

Victor Camarena

victor_357454 — 2020-10-14 19:33:09 UTC

5x+4≥19
-4 -4
5x≥15
x≥3

Kody Waltens

2020-10-14 19:33:15 UTC

5x + 4≥ 19

Kaleb Riddle

kaleb2611008 — 2020-10-14 19:33:35 UTC

5x+4≥19

Kayli Densley

kayli_364518 — 2020-10-14 19:33:37 UTC

5x+4≥19
-4 -4
5x≥15
x≥3

Justin Winter

2020-10-14 19:33:44 UTC

5x+4≥19

Tristan DeMoure

2020-10-14 19:33:53 UTC

1.75 + 0.65x ≤ 10

Special symbols (M2)

sidecharacterindustries — 2020-10-14 19:35:13 UTC

You can copy the below symbols to use in your Warm Up.

≤ ≥  ≮ ≯ ≠ ÷ √ ≈ ½ ∛ ∞

View more characters

Jacen rowles

2020-10-14 19:35:54 UTC

5x+4≥19
X≥3

Emily Falls

emily_364744 — 2020-10-14 19:36:39 UTC

5x+4≥19
-4 -4
5x≥15
x≥3

Mohagany Mohn

2020-10-14 19:36:45 UTC

5x+4≥19
5x≥15
x≥3

x ≥ 3

johnmar_2368193 — 2020-10-14 19:37:18 UTC

5x + 4 ≥ 19
- 4 -4
5x ≥ 15
x ≥ 3

Evan Lenz

evan_360817 — 2020-10-14 19:39:11 UTC

5x+4≥19
x≥3

10/15 Warm up

pathatn — 2020-10-15 15:24:25 UTC

Write an inequality of the question below.

You have just purchased a new cell phone. According to the terms of your agreement, you pay a flat fee of $6 per month, plus $0.04 per minute for calls. If you want your total bill to be no more than $10 for the month, how many minutes can you use?

Special symbols (M2)

pathatn — 2020-10-15 15:24:33 UTC

You can copy the below symbols to use in your Warm Up.

≤ ≥  ≮ ≯ ≠ ÷ √ ≈ ½ ∛ ∞

View more characters

x≤100

makenzie372567 — 2020-10-15 19:25:22 UTC

6 + 0.04x ≤ 10
-6 -6
0.04/0.04 4/0.04
x≤100

vanesa_375107 — 2020-10-15 19:27:59 UTC

6+0.04x≤10
-6 -6
0.04x≤4
/0.04 /0.04
x≤100

Special symbols (M2)

sidecharacterindustries — 2020-10-15 19:28:37 UTC

You can copy the below symbols to use in your Warm Up.

≤ ≥  ≮ ≯ ≠ ÷ √ ≈ ½ ∛ ∞

View more characters

6+0.04x<_10

sara_364481 — 2020-10-15 19:28:37 UTC

you can use 100 minutes because 10-6 = 4
4/0.04=100

hali smith

2020-10-15 19:28:37 UTC

6 + 0.04x ≤ 10
6 x 100 + 0.04x x 100 ≤10 x 100
600 + 4x ≤ 1000
600 + 4x - 600 ≤ 1000-600
4x ≤ 400
4x/4 ≤ 400/4
x ≤ 100

aryssav_2358057 — 2020-10-15 19:29:50 UTC

6 + 0.04m ≤ 10
-6 -6
0.04m ≤ 4
0.04m/0.04 4/0.04

m ≤ 100

6 + 0.04m ≤ 10

sidecharacterindustries — 2020-10-15 19:29:57 UTC

To stay below $10/month, $4 in minutes must be used or less. Divide to get 100 minutes

6+0.04m≤10

victor_357454 — 2020-10-15 19:30:03 UTC

-6 -6
0.04m≤4
÷0.04 ÷0.04

m≤100

6 + 0.04m ≤ 10

zoe_356184 — 2020-10-15 19:30:59 UTC

-6 -6
0.04m ≤ 4
/0.04 /0.04
m≤100

Yzabelle Monato

2020-10-15 19:31:00 UTC

6 + 0.04m≤10
0.04m≤4
m≤100

kayli_364518 — 2020-10-15 19:31:03 UTC

6+0.04x≤10
-6 -6
0.04x≤4
/0.04 /0.04
x≤100

Evan Lenz

evan_360817 — 2020-10-15 19:32:01 UTC

6 + 0.04x ≤ 10
-6 -6
/0.04 /0.04
x≤100

Jacen Rowles

2020-10-15 19:32:34 UTC

6+0.04m≤10
0.04m ≤4
/0.04 /0.04
m=100

Andrew Guzman

2020-10-15 19:33:13 UTC

6+0.04≤10
-6 -6
0.04≤4

m≤100

Kaleb Riddle

kaleb2611008 — 2020-10-15 19:33:23 UTC

6 + 0.04x ≤ 10

x≤100

Justin Winter

justin_366974 — 2020-10-15 19:33:49 UTC

6+0.04≤ 10

Special symbols (M2)

zoe_356184 — 2020-10-15 19:33:52 UTC

You can copy the below symbols to use in your Warm Up.

≤ ≥  ≮ ≯ ≠ ÷ √ ≈ ½ ∛ ∞

View more characters

jacob2483319 — 2020-10-15 19:34:15 UTC

6 + 0.04x ≤ 10
-6 -6
0.04 ≤ 4
/0.04 /0.04
x ≤ 100

jayna366798 — 2020-10-15 19:34:15 UTC

6+0.04n≤10
-6 -6
0.04n≤4
÷0.04 ÷0.04
n≤100

Kody Waltens

kody356720 — 2020-10-15 19:34:39 UTC

6+0.04x ≤ 10

M

mohagany_1542752 — 2020-10-15 19:34:59 UTC

emily_364744 — 2020-10-15 19:35:00 UTC

6 + 0.04x ≤ 10
-6 -6
0.04x ≤ 10
x ≤ 100

Tristan DeMoure

2020-10-15 19:36:09 UTC

1.75 + 0.65x ≤ 10

2020-10-15 19:36:13 UTC

1.75 + 0.65x ≤ 10

johnmar_2368193 — 2020-10-15 19:37:29 UTC

6 + 0.04m ≤ 10
-6 -6
0.04m ≤ 4
m ≤ 100

Mohagany Mohn

mohagany_1542752 — 2020-10-15 19:41:26 UTC

6+0.04x≤10
-6 -6
0.04x≤4
x≤100

Ricky T

2020-10-15 19:41:46 UTC

6 + 0.04m ≤ 10

2020-10-15 19:41:46 UTC

6+0.04≤ 10

2020-10-15 19:41:46 UTC

6+0.04≤ 10

2020-10-15 19:42:30 UTC

6+0.04≤ 10

10/19 Warm up

pathatn — 2020-10-19 18:27:10 UTC

Please answer all 5 questions by add the comment below the questions.

1) 1 ≤ z ≤ 10

pathatn — 2020-10-19 18:27:15 UTC

A: (1,10)

B: [1,10]

C: [1,10)

D: (1,10]

2) Write the interval notation.

pathatn — 2020-10-19 18:27:20 UTC

11 < y < 21

3) Write the interval notation.

pathatn — 2020-10-19 18:27:26 UTC

9 ≤ z < 19

4) 3 ≤ x ≤ 12

pathatn — 2020-10-19 18:27:31 UTC

(3,12)

5) 7 < x ≤ 15

pathatn — 2020-10-19 18:27:37 UTC

(7,15]

10/20 Warm up

pathatn — 2020-10-19 22:28:46 UTC

Please expand the post if needed.

The error is that they subtracted -4 instead of using the inver property of addition in Case B. |x-1|-3=5

vanesa_375107 — 2020-10-20 19:28:23 UTC

+3 +3
|x-1|=8 or |x-1|=-8
+1 +1 +1 +1
x=9 x=-7
both are true

They combined -4 and -5 wrong

makenzie372567 — 2020-10-20 19:29:00 UTC

|x-1|-3=5
+3 +3
|x-1|=8
|x-1|=--8 or |x-1|=8
+1 +1 +1 +1
x=-7 x=9

Ix-1I-3=5

sara_364481 — 2020-10-20 19:29:53 UTC

+3 +3
Ix-1I=8 or Ix-1I = -8
add one on both sides
x=9
x=-7
the error is that they subtracted 4 instead of using inverse operations and the first step was supposed to be adding 3 on both sides

| x - 1 | - 3 = 5

sidecharacterindustries — 2020-10-20 19:30:39 UTC

| x - 1 | = 8
x - 1 = 8 or x - 1 = -8
x = 9 or x = -7

|x-1|-3=5

jacen366807 — 2020-10-20 19:31:09 UTC

+3 +3
|x-1|=8
+1 +1
x=9

|x - 1| - 3 = 5

yzabelle_364098 — 2020-10-20 19:32:02 UTC

+3 +3
|x - 1| = 8 or |x - 1| = -8 +1 +1 +1 +1
x = 9 x = -7

|x - 1| -3 = 5

aryssav_2358057 — 2020-10-20 19:32:34 UTC

+3 +3
|x -1| = 8

| x -1 | = -8 or |x-1| = 8
+ 1 + 1 + 1 +1
x = -7 x = 9

| -7 - 1 | = -8 or | 9 -1| = 8

|x-1|-3=5

jayna366798 — 2020-10-20 19:32:40 UTC

+3 +3
|x-1|=8 or |x-1|=-8
+1 +1 +1 +1
x = 9 x = -7

2020-10-20 19:33:15 UTC

[x-1] -3 = 5
+3 +3
[x-1] = 8
+1 +1
x=-7

kayli_364518 — 2020-10-20 19:33:22 UTC

I x - 1 I -3 = 5
+3 +3
x - 1 = 8 or x - 1 = -8
+1 +1 +1 +1
x = 9 x = -7

| x-1 | -3 = 5

kaleb2611008 — 2020-10-20 19:33:22 UTC

+ 3 +3
x-1 = 8 or x - 1 = -8
+1 +1 + 1 +1
x = 9 x = -7

| x-1 | -3 = 5

kody356720 — 2020-10-20 19:33:26 UTC

+3 +3
|x-1| = 8
+1 +1
x = 9

|x-1|-3=5

mohagany_1542752 — 2020-10-20 19:35:10 UTC

+3 +3
x-1= 8 or x-1=-8
+1 +1 +1 +1
x=9 x=-7

|x-1|-3=5

victor_357454 — 2020-10-20 19:35:14 UTC

+3 +3
x - 1 = 8 or x - 1 = -8
+1 +1 +1 +1
x = 9 x = -7

justin_366974 — 2020-10-20 19:36:02 UTC

|x-1|-3=5
+3 +3
|x-1|=8 or x-1=-8
+1 +1 +1 +1
x=9 or x=-7

|x-1|-3=5

andrew_367193 — 2020-10-20 19:37:36 UTC

+3 +3
x-1=8
x - 1 = -8 or x - 1=8
+1 +1 +1 +1
x= -7 x= 9

|x - 1| - 3 = 5

evan_360817 — 2020-10-20 19:39:21 UTC

+3 +3
x - 1 = 8 or x - 1 = -8
x = 9 or x = -7

They combined 3 and 1 to make 4 instead of keeping them seperate

Ix-1I-3=5

hali_2001629 — 2020-10-20 19:39:42 UTC

| x - 1 | = 8
+3 +3
x - 1 = 8 or x - 1=8
x=9 or x=-7

emily_364744 — 2020-10-20 19:40:11 UTC

lx-1l -3 =5
+3 +3
lx-1l=8
x-1=8 x-1=-8
+1 +1 +1 +1
x=9 x=-7

They didn't add 3 on both sides as their first step.

jordyn_361234 — 2020-10-20 19:41:58 UTC

[x-1] -3 = 5
+3 +3
[x-1] = 8
+1 +1
x=-7

| x - 1 | -3 = 5

jacob2483319 — 2020-10-20 19:42:20 UTC

+3 +3
x - 1 = 8 or x - 1 = -8
+1 +1 +1 +1
x = 9 x = -7

johnmar_2368193 — 2020-10-20 19:52:09 UTC

|x-1|-3=5 +3 +3 x - 1 = 8 or x - 1 = -8 +1 +1 +1 +1 x = 9 x = -7

10/21 Warm up

pathatn — 2020-10-21 17:29:50 UTC

4Ix-2I = 8x - 4
The student complete solving this equation and get x = -1 and 1 . Check both answers by substitution into the original equation to be sure that the solutions are not extraneous.

1 is correct

makenzie372567 — 2020-10-21 19:24:56 UTC

4|(-1)-2|=8 (-1)-4 4(1)-2|=8(1)-4
4(3)=8-4 4=8-4
12=-12 4=4

emily_364744 — 2020-10-21 19:27:11 UTC

4 |(-1)-2|=8 (-1)-4
12=-12

4 |(1)-2|=8 (1)-4
4=4
x=1

4|x-2|=8x-4

jayna366798 — 2020-10-21 19:30:13 UTC

4|(-1)-2|=8(-1)-4
4(3)=-8-4
12=-12
4|(1)-2|=8(1)-4
4=8-4
4=4
1 is the correct solution.

4|x - 2| = 8x - 4

yzabelle_364098 — 2020-10-21 19:31:05 UTC

4|(-1)-2|=8(-1)-4 4|(1)-2|= 8(1)-4
4(3) = 8 - 4 4 = 8 - 4
12 = -12 4 = 4
x = 1

jordyn_361234 — 2020-10-21 19:32:03 UTC

4|x-2| = 8x - 4
/4 /4
|x-2| = 2x - 1

4lx-2l=8x-4

sara_364481 — 2020-10-21 19:32:12 UTC

4l-1-2l = 8(-1)-4

4l1-2l=8(1)-4
4

4 | x - 2 | = 8x - 4

kaleb2611008 — 2020-10-21 19:32:31 UTC

/4 /4 /4

x-2 = 2x - 1

x - 2 = -2x + 1 x - 2 = 2x - 1
+2x +2x -2x -2x
3x - 2 = 1 -1x - 2 = -1
+2 +2 +2 +2
3x = 3 -1x = 1
/3 /3 /1 /1
x = 1 x = -1

4l(1)-2l = 8(1) - 4 4l(1)-2l = 8(1) - 4

4l-1l = 8 - 4 4l-3l = 8 - 4
/4 /4 /4 /4 /4 /4
l-1l = 2 - 1 -3 = -2 -1
1 =1 -3 = -3

4| x-2 | = 8x -4

aryssav_2358057 — 2020-10-21 19:32:36 UTC

4| -1 - 2 | = 8(-1) - 4
4(3) = -8 -4
12 = -12

4| 1 - 2 | = 8(1) -4
4 = 8-4
4 = 4

kayli_364518 — 2020-10-21 19:32:38 UTC

4 I (-1) -2 I = 8 (-1) -4
4 (3) = -8 -4
12 = -12
4 I (1) -2 I = 8 (1) -4
4 (1) = 8 -4
4 = 4
1 is the correct solution.

4|x-2|=8x-4

jacen366807 — 2020-10-21 19:32:59 UTC

/4 /4
|x-2|=2x-1
-x-2=-1
+2 +2
-x=1
x=-1

4|x - 2| = 8x - 4

victor_357454 — 2020-10-21 19:33:17 UTC

4|(-1) - 2| = 8(-1) - 4
4(3) = -8 - 4
12 = -12

4|(1) - 2| = 8(1) -4
4 = 8 - 4
4=4
x = 1

4|1-2|=8(1)-4

jacob2483319 — 2020-10-21 19:33:59 UTC

4=8-4
4=4
4|(-1)-2|=8(-1)-4
4(3)=-8-4
12=-12
The correct solution is 1.

4Ix-2I = 8x - 4

vanesa_375107 — 2020-10-21 19:36:28 UTC

4|(1)-2|=8(1)-4
4=8-4
4=4 (true)
4|(-1)-2|=8(-1)-4
4(3)=-8-4
12=-12 (false)
1 is the correct solution to this equation.

4|x-2|=8x-4

mohagany_1542752 — 2020-10-21 19:37:04 UTC

4|(1)-2|=8(1)-4
4=8-4
4=4
4|(-1)-2|=8(-1)-4
4(3)=-8-4
12=-12
false 1 is the correct solution

hali_2001629 — 2020-10-21 19:37:34 UTC

4|(1)-2|=8(1)-4
4=8-4
+4 +4
8=8

emmalee_234547 — 2020-10-21 19:37:42 UTC

4I(-1-)2I=8(-1)-4
-12=-12
4I(1)-2I=8(1)-4
-4=4

The student got the correct answer.

4 I x - 2 I = 8x - 4

sidecharacterindustries — 2020-10-21 19:42:52 UTC

4 | 1 - 2 | = 8 - 4

4Ix-2I = 8x - 4

evan_360817 — 2020-10-21 19:46:45 UTC

4 |-1 - 2| = 8 * -1 - 4
12 = 8 * -1 - 4
12 = -12
Not true
4|1 - 2| = 8 * 1 - 4
4 = 8 - 4
4 = 4
Is True

Z

2020-10-21 19:46:53 UTC

Zoe Teves

2020-10-21 19:46:56 UTC

1 is correct

justin_366974 — 2020-10-21 19:54:48 UTC

4|-1-2|=8*-1- 4
12=8*-1- 4
12=-12
Not true
4|1-2|=8*1- 4
4=8-4
4=4
1 is the correct solution

johnmar_2368193 — 2020-10-21 19:54:49 UTC

4|(1)-2|= 8(1)-4
4 = 8 - 4
4 = 4
1 is right.

Warm up from 10/20

emmalee_234547 — 2020-10-21 20:24:48 UTC

The student subtracted 4 instead of 3.
Ix-1I-3=5
+3=+3
Ix-1I=8
+1=+1
x=9

Jadee Ferrin

2020-10-21 22:09:18 UTC

4Ix-2I = 8x - 4

4|(1)-2|=8(1)-4
4=8-4
4=4 (true)
4|(-1)-2|=8(-1)-4
4(3)=-8-4
12=-12 (false)
There is 1 correct one

10/26 Warm up

pathatn — 2020-10-26 18:18:43 UTC

3l3x + 2l = 9x
Find the value of x.

3|3x+2|=9x 3|3x+2|=-9x

makenzie372567 — 2020-10-26 19:29:26 UTC

/3 /3 /3 /3
|3x+2|=3x |3x+2|=-3x
-2 -2 -2 -2
3x=3x-2 3x=-3x-2
-3x -3x -3x -3x
0=-2 0=-6x-2
no solution. +2 +2
2=-6x
/6 /6
x=-1/3

3l3x + 2l = 9x

jacen366807 — 2020-10-26 19:29:59 UTC

/3 /3
l3x + 2l = 3x
-3x -3x
2=0

3|3x+2|=9x

vanesa_375107 — 2020-10-26 19:30:11 UTC

/3 /3
|3x+2|=3x or |3x+2|=-3x
-2 -2 -2 -2
3x=3x-2 3x=-3x-2
-3x -3x -3x -3x
0=-2 0=-6x-2
+2 +2
2=-6x
/6 /6
1/3=-x or x=-1/3
none the correct answer and one has no solution?

3|3x+2|=9x

victor_357454 — 2020-10-26 19:30:59 UTC

/3 /3
|3x+2|=3x
3x+2=3x or 3x+2=-3x
-3x -3x -3x -3x
2=0 2=-6x
x=-1/3

3l3x+2l=9x

sara_364481 — 2020-10-26 19:31:12 UTC

divide by 3 on both sides

3 |3x + 2| = 9

jordyn_361234 — 2020-10-26 19:31:23 UTC

3/ 3/
|3x + 2| = 3
-2 -2
3x + 2 = 3x | 3x + 2 = -3x

3l3x + 2l = 9x

emily_364744 — 2020-10-26 19:31:31 UTC

/3 /3
3x+2=3x or 3x+2=-3x
3x+2=3x
-3x -3x
2=0
-2 -2
0=-2- no solution

3x+2=-3x
+3x +3x
6x+2=0
-2 -2
6x=-2
/6 /6
x=-1/3- no solution
3|3(-1/3)+2|=9(-1/3)
3|-1+2|=-3
3|1|=-3
3=-3

3|3x+2|=9x

yzabelle_364098 — 2020-10-26 19:31:48 UTC

/3 /3
3x+2=3x or 3x+2=-3x
-3x -3x -3x -3x
2=0 2=-6x
no solution x=-1/3
x=-1/3

3|3x+2|=9x

jayna366798 — 2020-10-26 19:32:05 UTC

/3 /3
3x+2=3x or 3x+2=-3x -3x -3x -3x -3x
2=0 2=-6x
/-6 /-6
No Solution -1/3=x

hali_2001629 — 2020-10-26 19:32:08 UTC

3|3x+2|=9x
/3 /3
|3x+2|=3x
-2 -2
|3x|=1x
/3 /3
x=-3

kayli_364518 — 2020-10-26 19:32:51 UTC

3 I 3x + 2 I = 9x
/3 /3
3x + 2 = 3x or 3x + 2 = -3x
-2 -2 -2 -2
3x = 3x -2 3x = -3x -2
-3x -3x +3x +3x
0 = -2 6x = -2
/6 /6
x = -1/3

3 | 3x + 2 | = 9x

aryssav_2358057 — 2020-10-26 19:36:09 UTC

/3 /3
| 3x + 2 | = 3x

3x + 2 = 3x or 3x + 2 = -3x
-3x -3x -3x -3x
2=0 2 = -6x
/-6 /-6
-1/3 = x

3|3x + 2|=9x

evan_360817 — 2020-10-26 19:37:15 UTC

/3 /3
3x + 2 = 3x or 3x + 2 = -3x
2 = 0 or 2 = -6x
1/3 = -x

No solution or x = -1/3
No solution or No solution

3|3x+2|=9x

jacob2483319 — 2020-10-26 19:37:29 UTC

/3 /3
|3x+2|=3x or |3x+2|=-3x
-2 -2 -2 -2
|3x|=3x-2 |3x|=-3x-2
2=0 2=-6x
x=-1/3

3l3x + 2l = 9x

sidecharacterindustries — 2020-10-26 19:37:33 UTC

3x + 2 = 3x or 3x + 2 = -3x
2 = 0 or 2 = -6x
-1/3 = x₁

3l3x + 2l = 9x

kaleb2611008 — 2020-10-26 19:40:25 UTC

/3 /3
|3x+2|=3x or |3x+2|=-3x
-2 -2 -2 -2
3x=3x-2 3x=-3x-2
-3x -3x -3x -3x
0=-2 0=-6x-2
+2 +2
2 = 6x
/6 /6
1/3=-x or x=-1/3
No Solution

3|3x + 2| = 9x

zoe_356184 — 2020-10-26 19:42:07 UTC

/3 /3

3x + 2 = 3x or 3x + 2 = 3x
-2 -2 -2 -2
2 = -6x
/6 /6

No solution x= - 1/3

jayna366798 — 2020-10-26 19:49:05 UTC

3x=3x-2

3x+2=3x 3x+2=-3x

kate_360328 — 2020-10-26 19:55:08 UTC

-2 -2 -2 -2
3x=3x-2 3x=-3x-2
-3x -3x +3x +3
0 is not -2 6x=-2
No solution /6 /6
x=-1/3
No solution

3|3x+2|=9x

justin_366974 — 2020-10-26 19:55:20 UTC

/3 /3
3x+2=3x or 3x+2=-3x
-3x -3x -3x -3x
2=0 or 2=-6x
no solution or x=-1/3

3|3x+2|=9x/3 /3|3x+2|=3x3x+2=3x or 3x+2=-3x-3x -3x -3x -3x2=0 2=-6x x=-1/3

jadee_367569 — 2020-10-26 19:59:28 UTC

johnmar_2368193 — 2020-10-26 20:17:01 UTC

3 l3x + 2l = 9x
/3 /3

3x + 2 = 3x 3x + 2 = -3x
-2 -2 -2 -2
3x = 3x - 2 3x = -3x - 2
-3x -3x +3x +3x
0=-2 6x = -2
No solution /6 /6
x = 1/3
No solution = 3 = -3

3 |3x + 2| = 9x

ricky_359108 — 2020-10-26 20:24:44 UTC

/3 /3

3x + 2 = 3x 3x + 2 = -3x
-2 -2 -2 -2
3x = 3x - 2 3x =-3x = 2
-3x -3x -3x -3x
2 = 0 2 =-6x
No solution /6 /6
x = -1/3

10/27 Warm up

pathatn — 2020-10-27 18:16:15 UTC

|x+1|<3
Find the value of x.

|x+1|<3

makenzie372567 — 2020-10-27 19:23:48 UTC

-3-1 -1 -1
-4

lx+1l<3

sara_364481 — 2020-10-27 19:24:11 UTC

-3subtract 1
-4

|x+1|<3

jacob2483319 — 2020-10-27 19:28:08 UTC

-3-1 -1 -1

| x + 1 | < 3

aryssav_2358057 — 2020-10-27 19:29:04 UTC

-3 < x + 1 < 3
-1 -1 -1
-4 < x < 2

lx+1l<3

johnmar_2368193 — 2020-10-27 19:29:11 UTC

-3 < x + 1 < 3
-1 -1 -1
-4 < x < 2

|x+1|<3

emily_364744 — 2020-10-27 19:29:38 UTC

-3-1 -1 -1
-4

jadee_367569 — 2020-10-27 19:29:56 UTC

lx+1l<3
-3- 1
-4

kayli_364518 — 2020-10-27 19:30:03 UTC

I x + 1 I < 3
-3 < x + 1 < 3
-1 -1 -1
-4 < x < 2

|x+1|<3

jacen366807 — 2020-10-27 19:30:24 UTC

-3<|x+1|<3
-1 -1 -1
-4

|x+1|<3 and |x+1|>-3

victor_357454 — 2020-10-27 19:30:33 UTC

-3x+1>-3
-1 -1 -1 -1 -1 -1
-4x>-4

|x+1|<3

jayna366798 — 2020-10-27 19:31:03 UTC

-3-1 -1 -1
-4

|x+1|<3

yzabelle_364098 — 2020-10-27 19:31:03 UTC

-3-1 -1 -1
-4

hali_2001629 — 2020-10-27 19:31:29 UTC

|x+1|<3
-3-1 -1 -1
-4

|x+1|<3

vanesa_375107 — 2020-10-27 19:32:42 UTC

-3-1 -1 -1
-4

|x+1|<3

sidecharacterindustries — 2020-10-27 19:32:43 UTC

-3

|x + 1| <3

jordyn_361234 — 2020-10-27 19:34:18 UTC

-3 < x + 1 < 3
-1 -1 -1
-4 < x < 2

I x + 1 I < 3

kaleb2611008 — 2020-10-27 19:35:49 UTC

-3 < x + 1 < 3
-1 -1 -1
-4 < x < 2

|x+1|<3

evan_360817 — 2020-10-27 19:35:49 UTC

-3 < x + 1 < 3
-1 -1 -1
-4 < x < 2

|x+1|<3

zoe_356184 — 2020-10-27 19:36:05 UTC

-3-1 -1 -1
-4 < x < 2

|x+1|<3

justin_366974 — 2020-10-27 19:37:42 UTC

-3-1 -1 -1
-4

|x+1|<3

ricky_359108 — 2020-10-27 19:40:40 UTC

-3-1 -1 -1
-4

|x+1|<3

kody356720 — 2020-10-27 19:44:08 UTC

-3-1 -1 -1
-4

|x+1|<3

kate_360328 — 2020-10-27 20:49:15 UTC

-1 -1 -1
-4

10/28 Warm up

pathatn — 2020-10-28 18:27:59 UTC

|x-4|<3
Find the value of x.

|x-4|<3

makenzie372567 — 2020-10-28 19:24:50 UTC

-3+4 +4 +4
1 < x < 7

johnmar_2368193 — 2020-10-28 19:25:55 UTC

l x - 4 l < 3

lx-4l<3

sara_364481 — 2020-10-28 19:27:01 UTC

-3add four
1

|x - 4| < 3

aryssav_2358057 — 2020-10-28 19:28:28 UTC

-3< |x-4| < 3
+4 +4 +4
1 < x < 7

|x - 4| < 3

jordyn_361234 — 2020-10-28 19:28:44 UTC

-3 < x - 4 < 3
+4 +4 +4
1 < x < 7

| x - 4 | < 3

sidecharacterindustries — 2020-10-28 19:29:02 UTC

-3 < x - 4 < 3
x₁>1, x₂<7

|x-4|<3

yzabelle_364098 — 2020-10-28 19:30:06 UTC

-3+4 +4 +4
1

|x-4|<3

jacob2483319 — 2020-10-28 19:30:26 UTC

-3add 4
1

|x-4|<3

jayna366798 — 2020-10-28 19:30:31 UTC

-3+4 +4 +4
1 < x < 7

|x-4|<3

victor_357454 — 2020-10-28 19:30:33 UTC

-3+4 +4 +4
1

|x-4|< 3

andrew_367193 — 2020-10-28 19:31:37 UTC

-3 < -4 < 3

|x-4|<3

vanesa_375107 — 2020-10-28 19:31:37 UTC

-3+4 +4 +4
1(1,7)?

|x-4|<3

evan_360817 — 2020-10-28 19:31:40 UTC

-3+4 +4 +4
1 < x < 7

hali_2001629 — 2020-10-28 19:32:18 UTC

|x - 4| < 3
-3< |x-4| < 3
+4 +4 +4
1 < x < 7

|x-4|<3

emily_364744 — 2020-10-28 19:32:32 UTC

-3+4 +4 +4
1

lx-4l<3

justin_366974 — 2020-10-28 19:32:35 UTC

-3+4 +4 +4
1

kayli_364518 — 2020-10-28 19:32:36 UTC

I x - 4 I < 3
-3 < x - 4 < 3
+4 +4 +4
1 < x < 7

|x-4|<3

mohagany_1542752 — 2020-10-28 19:38:36 UTC

-3<1x-4<3
+4 +4 +4
1

|x-4|<3

ricky_359108 — 2020-10-28 19:39:39 UTC

|x-4|< 3

kody356720 — 2020-10-28 19:40:17 UTC

-3 +4 +4 +4
1

| x - 4 | <3

jacen366807 — 2020-10-28 19:40:25 UTC

-3+4 +4 +4
1

|x-4|<3

zoe_356184 — 2020-10-28 19:41:33 UTC

-3+4 +4 +4
1

10/28 Warm up

pathatn — 2020-10-29 17:17:06 UTC

|p + 2| + 4 < 10
Find the value of p.

-6
makenzie372567 — 2020-10-29 19:24:06 UTC

-2 -2 -2
-8

yzabelle_364098 — 2020-10-29 19:28:00 UTC

-6-2 -2 -2
-8

+

johnmar_2368193 — 2020-10-29 19:29:00 UTC

-6
emily_364744 — 2020-10-29 19:29:02 UTC

-2 -2 -2
-8

-6
vanesa_375107 — 2020-10-29 19:29:39 UTC

-2 -2 -2
-8

jadee_367569 — 2020-10-29 19:29:44 UTC

-6
-2 -2 -2
-8

-6
jacob2483319 — 2020-10-29 19:29:52 UTC

Subtract 2
-8

-6 < p + 2 < 6

evan_360817 — 2020-10-29 19:31:08 UTC

-6 < p + 2 < 6
-2 -2 -2
-8 < p < 4

-6
jayna366798 — 2020-10-29 19:31:39 UTC

-2 -2 -2
-8

-6
victor_357454 — 2020-10-29 19:31:40 UTC

-2 -2 -2
-8

-6
sara_364481 — 2020-10-29 19:33:36 UTC

subtract 2
-8

-6 < + 2 < 6

jacen366807 — 2020-10-29 19:33:37 UTC

-2 -2 -2
-8 < p < 4

|p+2|+4<10

zoe_356184 — 2020-10-29 19:33:57 UTC

-6-2 -2 -2
-8

-6 < p + 2 < 6

sidecharacterindustries — 2020-10-29 19:34:03 UTC

-2
-8 < p < 4

-6
mohagany_1542752 — 2020-10-29 19:34:10 UTC

-2 -2 - 2

-8

kayli_364518 — 2020-10-29 19:35:08 UTC

-6 < p + 2 < 6
-2 -2 -2
-8 < p < 4

justin_366974 — 2020-10-29 19:35:50 UTC

-6-2 -2 -2
-8

-6 < P + 2 < 6

jordyn_361234 — 2020-10-29 19:37:18 UTC

-2 -2 -2
-8 < P < 4

-

2020-10-29 19:41:31 UTC

-6
kate_360328 — 2020-10-29 21:33:07 UTC

-2 -2 -2
-8

jadee_367569 — 2020-11-10 20:39:19 UTC
-6 < P + 2 < 6 -2 -2 -2 -8 < P < 4

last

sidecharacterindustries — 2020-11-19 19:02:49 UTC

lol

nig

sidecharacterindustries — 2020-12-06 07:08:35 UTC