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      <title>My fearless stream by LUISA MARIA RAMIREZ RODRIGUEZ</title>
      <link>https://padlet.com/lramir59/n7kxtp4my4g</link>
      <description>Made with a lightning strike of genius</description>
      <language>en-us</language>
      <pubDate>2017-06-06 01:23:39 UTC</pubDate>
      <lastBuildDate>2017-06-07 02:03:57 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
      <image>
         <url></url>
      </image>
      <item>
         <title>COMO RESOLVER UN PROBLEMA </title>
         <author>lramir59</author>
         <link>https://padlet.com/lramir59/n7kxtp4my4g/wish/175313537</link>
         <description><![CDATA[<div><strong>PROBLEMAS GEOMÉTRICOS<br></strong><br></div><ol><li><br>Determinar el lado de un triángulo equilátero cuyo perímetro es igual al de un cuadrado de 12 cm de lado. ¿Serán iguales sus áreas?<br><br></li></ol><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:143,&quot;url&quot;:&quot;https://lh4.googleusercontent.com/JDlqejOexJVl8cQH_v0j6KYZ4wJn2ahMe_dX3H1gRQQYQqdFHkeOTohu5CbXuO2IoudZqojb7SyzBeiq3zZUaivKvZnlQL8CKKnNpoOLU2IuNROnibFX-9ARoXn0mjZX5skQ8Hvpap2YZbJ3Rw&quot;,&quot;width&quot;:123}" data-trix-content-type="image"><img src="https://lh4.googleusercontent.com/JDlqejOexJVl8cQH_v0j6KYZ4wJn2ahMe_dX3H1gRQQYQqdFHkeOTohu5CbXuO2IoudZqojb7SyzBeiq3zZUaivKvZnlQL8CKKnNpoOLU2IuNROnibFX-9ARoXn0mjZX5skQ8Hvpap2YZbJ3Rw" width="123" height="143"><figcaption class="caption"></figcaption></figure></div><div><br>P.Cuadrado = 12 · 4 = 48 cm<br><br></div><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:135,&quot;url&quot;:&quot;https://lh4.googleusercontent.com/73TAZfK8Kv5G3UOGguvArkgKs4328-RoRez8aU4lGus8MsamJOif1rpWjU7W0o7QpYxDLiO4uVE9NHAkK5ZdmWWhtqRP5Kwol2DYrxVr0LSODCY6a5fztY86u3gjdGksTTYZu-37u_TDzaDBKw&quot;,&quot;width&quot;:141}" data-trix-content-type="image"><img src="https://lh4.googleusercontent.com/73TAZfK8Kv5G3UOGguvArkgKs4328-RoRez8aU4lGus8MsamJOif1rpWjU7W0o7QpYxDLiO4uVE9NHAkK5ZdmWWhtqRP5Kwol2DYrxVr0LSODCY6a5fztY86u3gjdGksTTYZu-37u_TDzaDBKw" width="141" height="135"><figcaption class="caption"></figcaption></figure></div><div><br>P. Triángulo = 48 cml = 48 : 3 = 16 cm<br><br></div><div>A = 122 = <strong>144 m²<br></strong><br></div><h1><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:21,&quot;url&quot;:&quot;https://lh6.googleusercontent.com/YT4u39IyMX7On0SFo52EsuK5e8k_yn1X6wOX49-gcP_0A3fuFqmWIwo8WUansNbAuPiy3tR4pXqN1qzobQXCnEB1CbjZnz-6aXs0TsKOeLcoypXm5CVzKRiMK88qE1A-5y00eSOt9TrfmAXmnQ&quot;,&quot;width&quot;:108}" data-trix-content-type="image"><img src="https://lh6.googleusercontent.com/YT4u39IyMX7On0SFo52EsuK5e8k_yn1X6wOX49-gcP_0A3fuFqmWIwo8WUansNbAuPiy3tR4pXqN1qzobQXCnEB1CbjZnz-6aXs0TsKOeLcoypXm5CVzKRiMK88qE1A-5y00eSOt9TrfmAXmnQ" width="108" height="21"><figcaption class="caption"></figcaption></figure></h1><h1><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:25,&quot;url&quot;:&quot;https://lh3.googleusercontent.com/zMfY2rFWm9amAKzXaqsafKI4jNutVas9yhae1UNqSWagGJOlpJZtCY-bNRNHQVywR8L91bfv3AWWnLz4BNMHvQh9pmkODKrHPf6A4unyisUsQb5_yzmvzIVPS_v9SVW08m2xeuPwNxDP3BkXNQ&quot;,&quot;width&quot;:192}" data-trix-content-type="image"><img src="https://lh3.googleusercontent.com/zMfY2rFWm9amAKzXaqsafKI4jNutVas9yhae1UNqSWagGJOlpJZtCY-bNRNHQVywR8L91bfv3AWWnLz4BNMHvQh9pmkODKrHPf6A4unyisUsQb5_yzmvzIVPS_v9SVW08m2xeuPwNxDP3BkXNQ" width="192" height="25"><figcaption class="caption"></figcaption></figure></h1><h1><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:42,&quot;url&quot;:&quot;https://lh3.googleusercontent.com/SgpYUg1bAdlZq1uP8wev4kD0K_XyUJeVFRDPvRCiYN-2_a6kzBRgF_9D7ZlhxnZiDB6XgJwvohNCTpdjYs152wgFHL8YnrHXzwlrylEbMQ2Nkg8W6yuktmApGGYwJezGWpueCEwTU75O0ZnN6g&quot;,&quot;width&quot;:254}" data-trix-content-type="image"><img src="https://lh3.googleusercontent.com/SgpYUg1bAdlZq1uP8wev4kD0K_XyUJeVFRDPvRCiYN-2_a6kzBRgF_9D7ZlhxnZiDB6XgJwvohNCTpdjYs152wgFHL8YnrHXzwlrylEbMQ2Nkg8W6yuktmApGGYwJezGWpueCEwTU75O0ZnN6g" width="254" height="42"><figcaption class="caption"></figcaption></figure></h1><ol><li><br>Calcular el área de un triángulo equilátero inscrito en una circunferencia de radio 6 cm.<br><br></li></ol><div><br>El centro de la circunferencia es el baricentro. Por tanto:<br><br></div><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:42,&quot;url&quot;:&quot;https://lh6.googleusercontent.com/nyy_GgFmA_vYUUdl7k8c7UuhJ4StpUgEfg542e8Dm3oFWrLtl1J2wtUzTaD9P0jQ11ctLBheBjj_p2qVyRAFZvddCOz7LvbF_q4Tmi6d8qhTFIqEI0bfwUATsKjBVQrqKno1NDTSeld_ZwM5_w&quot;,&quot;width&quot;:274}" data-trix-content-type="image"><img src="https://lh6.googleusercontent.com/nyy_GgFmA_vYUUdl7k8c7UuhJ4StpUgEfg542e8Dm3oFWrLtl1J2wtUzTaD9P0jQ11ctLBheBjj_p2qVyRAFZvddCOz7LvbF_q4Tmi6d8qhTFIqEI0bfwUATsKjBVQrqKno1NDTSeld_ZwM5_w" width="274" height="42"><figcaption class="caption"></figcaption></figure></div><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:147,&quot;url&quot;:&quot;https://lh3.googleusercontent.com/L-_b7qAhDlzJWZEJ3JP1WEMvemTSJEqWz-87OnugmfR6WLYMWn1y0q4qlEedbOWqyDNNlXZcI8h7Bi8edIYMrN0gZlRK5hO4EOhBF5z4AbLMW4qapkf5TK39S1p8HMuVOf4sKha4_Oi9UHCvAw&quot;,&quot;width&quot;:150}" data-trix-content-type="image"><img src="https://lh3.googleusercontent.com/L-_b7qAhDlzJWZEJ3JP1WEMvemTSJEqWz-87OnugmfR6WLYMWn1y0q4qlEedbOWqyDNNlXZcI8h7Bi8edIYMrN0gZlRK5hO4EOhBF5z4AbLMW4qapkf5TK39S1p8HMuVOf4sKha4_Oi9UHCvAw" width="150" height="147"><figcaption class="caption"></figcaption></figure>&nbsp;</div><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:50,&quot;url&quot;:&quot;https://lh5.googleusercontent.com/v6XeYAAmTfNiQK2xhmuzelyWVak6gooPyX1gpW0oyfcleQIdyUkgksPphKreGgOTSW5YJu86jmk0h3e9LN4d4HAgAQIJ8QU1rAsPdbdmcp6zLmfSpAKgvZaEIDtQE5MEhjyTgLEuM53aG8urTw&quot;,&quot;width&quot;:266}" data-trix-content-type="image"><img src="https://lh5.googleusercontent.com/v6XeYAAmTfNiQK2xhmuzelyWVak6gooPyX1gpW0oyfcleQIdyUkgksPphKreGgOTSW5YJu86jmk0h3e9LN4d4HAgAQIJ8QU1rAsPdbdmcp6zLmfSpAKgvZaEIDtQE5MEhjyTgLEuM53aG8urTw" width="266" height="50"><figcaption class="caption"></figcaption></figure></div><div><br></div><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:46,&quot;url&quot;:&quot;https://lh5.googleusercontent.com/oZ6T9CK14E9apfgtcm94--TUnmL0SPz05AP6GfOdZzs-hG4QNtl9a94Bn6lUuuLEArQIepaldv9nxmOew1cgtRGVYlrDfeoBq3pvTPmb_hXvgWx1MQVI2ZFLsSTmsVnBtVNn302E52o7bgPsAA&quot;,&quot;width&quot;:358}" data-trix-content-type="image"><img src="https://lh5.googleusercontent.com/oZ6T9CK14E9apfgtcm94--TUnmL0SPz05AP6GfOdZzs-hG4QNtl9a94Bn6lUuuLEArQIepaldv9nxmOew1cgtRGVYlrDfeoBq3pvTPmb_hXvgWx1MQVI2ZFLsSTmsVnBtVNn302E52o7bgPsAA" width="358" height="46"><figcaption class="caption"></figcaption></figure></div><div><br></div><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:42,&quot;url&quot;:&quot;https://lh5.googleusercontent.com/iupDwUYJmS1Zm5vI-yWO0jOCEwLafgsePGgFZnuezRg5xFimV5fPd2uNMzBLP6KATzUo3CKfxKVSvvnfRPC_b97bVjynBYJT2XRaoE41SkvHPvvnw_UCv0xqT0_GYe1jkDrTswL6cfC1ug_bJg&quot;,&quot;width&quot;:218}" data-trix-content-type="image"><img src="https://lh5.googleusercontent.com/iupDwUYJmS1Zm5vI-yWO0jOCEwLafgsePGgFZnuezRg5xFimV5fPd2uNMzBLP6KATzUo3CKfxKVSvvnfRPC_b97bVjynBYJT2XRaoE41SkvHPvvnw_UCv0xqT0_GYe1jkDrTswL6cfC1ug_bJg" width="218" height="42"><figcaption class="caption"></figcaption></figure></div><ol><li><br>Dado un triángulo equilátero de 6 m de lado, hallar el área de uno de los sectores determinado por la circunferencia circunscrita y por los radios que pasan por los vértices.<br><br></li><li>El centro de la circunferencia es el <a href="http://www.vitutor.com/geo/eso/pl_5.html#bar"><strong>baricentro</strong></a>. Por tanto:<br><br></li></ol><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:42,&quot;url&quot;:&quot;https://lh4.googleusercontent.com/03DgQGXvIeWmNHkRGicMREWhCEYSOWNhLAdcwmmDajfyWm4ZuQpqdluZ2Trp7y9TjwU9-6JUPqXOJUOmumJPiSiW0Mu96MLB-QxC_0Qg5L97x6WayIKC3CdY7ftqRxcLZdGS5hohNoI9E_mz8g&quot;,&quot;width&quot;:70}" data-trix-content-type="image"><img src="https://lh4.googleusercontent.com/03DgQGXvIeWmNHkRGicMREWhCEYSOWNhLAdcwmmDajfyWm4ZuQpqdluZ2Trp7y9TjwU9-6JUPqXOJUOmumJPiSiW0Mu96MLB-QxC_0Qg5L97x6WayIKC3CdY7ftqRxcLZdGS5hohNoI9E_mz8g" width="70" height="42"><figcaption class="caption"></figcaption></figure></div><div><br></div><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:151,&quot;url&quot;:&quot;https://lh6.googleusercontent.com/kHWi3ZTXWfUy-tVPGy32cy2rbK9ATw_c3RvRvSArsMcwlKuZl_0E5wRj2eDIY8tCvYkFyFv1kLOacXilZLBNsIQNbdSFVI7vtZ1EfWpQGsSkUdSOKK_hjE-1BOivLY3C736ufNRbjgRKYkp2XA&quot;,&quot;width&quot;:165}" data-trix-content-type="image"><img src="https://lh6.googleusercontent.com/kHWi3ZTXWfUy-tVPGy32cy2rbK9ATw_c3RvRvSArsMcwlKuZl_0E5wRj2eDIY8tCvYkFyFv1kLOacXilZLBNsIQNbdSFVI7vtZ1EfWpQGsSkUdSOKK_hjE-1BOivLY3C736ufNRbjgRKYkp2XA" width="165" height="151"><figcaption class="caption"></figcaption></figure>&nbsp;</div><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:26,&quot;url&quot;:&quot;https://lh5.googleusercontent.com/uCeB4ZXD4wyxMeydnDHjHysTtwsg7miRsxN88VvzCh25Ng5_rHYg5keBhNIJWQfU_CFroDUCMLAr5XDG0oF5gsbVJQWq3lSZZfQNQljKeJjs3kbHSOHVw04xmEI7CxYiVVugC5GuOlHJx0_7Lw&quot;,&quot;width&quot;:194}" data-trix-content-type="image"><img src="https://lh5.googleusercontent.com/uCeB4ZXD4wyxMeydnDHjHysTtwsg7miRsxN88VvzCh25Ng5_rHYg5keBhNIJWQfU_CFroDUCMLAr5XDG0oF5gsbVJQWq3lSZZfQNQljKeJjs3kbHSOHVw04xmEI7CxYiVVugC5GuOlHJx0_7Lw" width="194" height="26"><figcaption class="caption"></figcaption></figure></div><div><br></div><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:42,&quot;url&quot;:&quot;https://lh5.googleusercontent.com/udsk13mbQ8iVJNyqZsdX2b0moLphYTNtswFzS1oK8cCWeE-4Xno0W6KcQ6bgVATcud6IcSVD8Rc-Gz7WsTlqnJo195zIczc_Dz2YFWHYmtwRS2hpbgJs37T0_6jzrEibdB5jKtYIcVV8tsyGXA&quot;,&quot;width&quot;:186}" data-trix-content-type="image"><img src="https://lh5.googleusercontent.com/udsk13mbQ8iVJNyqZsdX2b0moLphYTNtswFzS1oK8cCWeE-4Xno0W6KcQ6bgVATcud6IcSVD8Rc-Gz7WsTlqnJo195zIczc_Dz2YFWHYmtwRS2hpbgJs37T0_6jzrEibdB5jKtYIcVV8tsyGXA" width="186" height="42"><figcaption class="caption"></figcaption></figure></div><div><br></div><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:44,&quot;url&quot;:&quot;https://lh4.googleusercontent.com/TK5KIDxmJ4k3HWX4t6JGOrbHytF-H2AkB3vlf-k7sr21gBT7o3dywxP8RS-IF6kSHzKoJXkJPKvpadqoaWznJgCgl9IvcOWCDgxiflC9CzoZtHEd1qBpuXipQBMV9ZsXcA3hhukSHwW6fPx-5g&quot;,&quot;width&quot;:261}" data-trix-content-type="image"><img src="https://lh4.googleusercontent.com/TK5KIDxmJ4k3HWX4t6JGOrbHytF-H2AkB3vlf-k7sr21gBT7o3dywxP8RS-IF6kSHzKoJXkJPKvpadqoaWznJgCgl9IvcOWCDgxiflC9CzoZtHEd1qBpuXipQBMV9ZsXcA3hhukSHwW6fPx-5g" width="261" height="44"><figcaption class="caption"></figcaption></figure></div><div><br></div><div><strong>PROBLEMAS ALGEBRAICOS<br></strong><br></div><ol><li><br>Un padre tiene 35 años y su hijo 5. ¿Al cabo de cuántos años será la edad del padre tres veces mayor que la edad del hijo?<br><br></li></ol><div><br>Años <figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:16,&quot;url&quot;:&quot;https://lh3.googleusercontent.com/mfVB2RA6s8fsOgsj4m_6NcSL4NeQQncyaKOf4GGu-82XaGIxjS8L9sfnjVRPhH9-UBUfQk8fWcU6EwF0Ha5C5IJV3ihq2w_c1AFaIcXXLaHkJyI1k7MXtZgXDka89RteXuorUTlhpqHkTrYnRg&quot;,&quot;width&quot;:20}" data-trix-content-type="image"><img src="https://lh3.googleusercontent.com/mfVB2RA6s8fsOgsj4m_6NcSL4NeQQncyaKOf4GGu-82XaGIxjS8L9sfnjVRPhH9-UBUfQk8fWcU6EwF0Ha5C5IJV3ihq2w_c1AFaIcXXLaHkJyI1k7MXtZgXDka89RteXuorUTlhpqHkTrYnRg" width="20" height="16"><figcaption class="caption"></figcaption></figure> x<br><br></div><div><br>35 + x = 3 · (5 + x )<br><br></div><div><br>35 + x = 15 + 3 · x<br><br></div><div><br>20 = 2 · x&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;x = 10<br><br></div><div><br>Al cabo de <strong>10 años</strong>.<br><br></div><ol><li><br>Si al doble de un número se le resta su mitad resulta 54. ¿Cuál es el número?<br><br></li></ol><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:42,&quot;url&quot;:&quot;https://lh6.googleusercontent.com/FbNaf7cfGTb9KCDMgHU7pkr8jeEDflFuacyD52hgiiFQJdgqZEj2vy4V9UNc9pfySy1dHyztBrf--sWAXzB_oBExWdYfgSSJeF3Yh-mRMkrAgibZWgE4ux0ZkEi4CsX3eqencpjuBI__mrFhJg&quot;,&quot;width&quot;:96}" data-trix-content-type="image"><img src="https://lh6.googleusercontent.com/FbNaf7cfGTb9KCDMgHU7pkr8jeEDflFuacyD52hgiiFQJdgqZEj2vy4V9UNc9pfySy1dHyztBrf--sWAXzB_oBExWdYfgSSJeF3Yh-mRMkrAgibZWgE4ux0ZkEi4CsX3eqencpjuBI__mrFhJg" width="96" height="42"><figcaption class="caption"></figcaption></figure></div><div><br><br></div><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:18,&quot;url&quot;:&quot;https://lh4.googleusercontent.com/28x-I8tg4ohES3xryzqpRK4DkAt2SRvvHoPEBVRTa8X1UZMqB44Dw1Auku44EqqAifrxdOojBgu7o1N6sc9lt7dLWYWKCQM1mWHIhPGyoA75bkB-OkqcmNzqfJq3qe0635qJIQqy7cZ0LJpbQA&quot;,&quot;width&quot;:344}" data-trix-content-type="image"><img src="https://lh4.googleusercontent.com/28x-I8tg4ohES3xryzqpRK4DkAt2SRvvHoPEBVRTa8X1UZMqB44Dw1Auku44EqqAifrxdOojBgu7o1N6sc9lt7dLWYWKCQM1mWHIhPGyoA75bkB-OkqcmNzqfJq3qe0635qJIQqy7cZ0LJpbQA" width="344" height="18"><figcaption class="caption"></figcaption></figure></div><div><br><br></div><ol><li><br>La base de un rectángulo es doble que su altura. ¿Cuáles son sus dimensiones si el perímetro mide 30 cm?<br><br></li></ol><div><br>Altura <figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:16,&quot;url&quot;:&quot;https://lh3.googleusercontent.com/mfVB2RA6s8fsOgsj4m_6NcSL4NeQQncyaKOf4GGu-82XaGIxjS8L9sfnjVRPhH9-UBUfQk8fWcU6EwF0Ha5C5IJV3ihq2w_c1AFaIcXXLaHkJyI1k7MXtZgXDka89RteXuorUTlhpqHkTrYnRg&quot;,&quot;width&quot;:20}" data-trix-content-type="image"><img src="https://lh3.googleusercontent.com/mfVB2RA6s8fsOgsj4m_6NcSL4NeQQncyaKOf4GGu-82XaGIxjS8L9sfnjVRPhH9-UBUfQk8fWcU6EwF0Ha5C5IJV3ihq2w_c1AFaIcXXLaHkJyI1k7MXtZgXDka89RteXuorUTlhpqHkTrYnRg" width="20" height="16"><figcaption class="caption"></figcaption></figure> x<br><br></div><div><br>Base <figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:16,&quot;url&quot;:&quot;https://lh3.googleusercontent.com/mfVB2RA6s8fsOgsj4m_6NcSL4NeQQncyaKOf4GGu-82XaGIxjS8L9sfnjVRPhH9-UBUfQk8fWcU6EwF0Ha5C5IJV3ihq2w_c1AFaIcXXLaHkJyI1k7MXtZgXDka89RteXuorUTlhpqHkTrYnRg&quot;,&quot;width&quot;:20}" data-trix-content-type="image"><img src="https://lh3.googleusercontent.com/mfVB2RA6s8fsOgsj4m_6NcSL4NeQQncyaKOf4GGu-82XaGIxjS8L9sfnjVRPhH9-UBUfQk8fWcU6EwF0Ha5C5IJV3ihq2w_c1AFaIcXXLaHkJyI1k7MXtZgXDka89RteXuorUTlhpqHkTrYnRg" width="20" height="16"><figcaption class="caption"></figcaption></figure> 2x<br><br></div><div><br>2 · x + 2 · 2x = 30&nbsp; &nbsp; &nbsp; &nbsp; 2x + 4x = 30&nbsp; &nbsp; &nbsp; 6x = 30&nbsp; &nbsp; &nbsp;<strong>&nbsp;x = 5<br></strong><br></div><div><br>Altura <figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:16,&quot;url&quot;:&quot;https://lh3.googleusercontent.com/mfVB2RA6s8fsOgsj4m_6NcSL4NeQQncyaKOf4GGu-82XaGIxjS8L9sfnjVRPhH9-UBUfQk8fWcU6EwF0Ha5C5IJV3ihq2w_c1AFaIcXXLaHkJyI1k7MXtZgXDka89RteXuorUTlhpqHkTrYnRg&quot;,&quot;width&quot;:20}" data-trix-content-type="image"><img src="https://lh3.googleusercontent.com/mfVB2RA6s8fsOgsj4m_6NcSL4NeQQncyaKOf4GGu-82XaGIxjS8L9sfnjVRPhH9-UBUfQk8fWcU6EwF0Ha5C5IJV3ihq2w_c1AFaIcXXLaHkJyI1k7MXtZgXDka89RteXuorUTlhpqHkTrYnRg" width="20" height="16"><figcaption class="caption"></figcaption></figure><strong>5 cm<br></strong><br></div><div><br>Base <figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:16,&quot;url&quot;:&quot;https://lh3.googleusercontent.com/mfVB2RA6s8fsOgsj4m_6NcSL4NeQQncyaKOf4GGu-82XaGIxjS8L9sfnjVRPhH9-UBUfQk8fWcU6EwF0Ha5C5IJV3ihq2w_c1AFaIcXXLaHkJyI1k7MXtZgXDka89RteXuorUTlhpqHkTrYnRg&quot;,&quot;width&quot;:20}" data-trix-content-type="image"><img src="https://lh3.googleusercontent.com/mfVB2RA6s8fsOgsj4m_6NcSL4NeQQncyaKOf4GGu-82XaGIxjS8L9sfnjVRPhH9-UBUfQk8fWcU6EwF0Ha5C5IJV3ihq2w_c1AFaIcXXLaHkJyI1k7MXtZgXDka89RteXuorUTlhpqHkTrYnRg" width="20" height="16"><figcaption class="caption"></figcaption></figure><strong>10 cm<br></strong><br></div><div><strong><br>PROBLEMAS NUMERICOS<br></strong><br></div><ol><li>Manuel ha hecho 105 fotos y su hermana Clara ha hecho 28 fotos más que él. Cuántas fotos han hecho entre los dos?</li></ol><div><br>● <strong>COMPRENDE</strong>.<br><br></div><div>Pregunta ▶ ¿Cuántas fotos han hecho entre los dos?</div><div>Datos ▶ Manuel ha hecho 105 fotos.</div><div>Clara ha hecho 28 fotos más que Manuel.</div><div><br>● <strong>PIENSA</strong>.<br><br></div><div>1. º Hay que hallar las fotos que ha hecho Clara.</div><div>&nbsp;Sumamos 28 a las fotos que ha hecho Manuel.</div><div>2. º Hay que hallar las fotos que han hecho en total.</div><div>&nbsp;Sumamos las fotos que han hecho ambos.</div><div><strong><br>● CALCULA</strong>.<br><br></div><div><br>1. º 105 + 1 28 = 133&nbsp; 2. º 105 * 133 = 238<br><br></div><div><br>Solución: Entre los dos han hecho 238 fotos.<br><br></div><div><strong><br>● COMPRUEBA.<br></strong><br></div><div>133 - 28 = 105 ▶ Clara ha hecho 28 fotos menos que Manuel.</div><div>105 + 133 = 238 ▶ Entre los dos han hecho 238 fotos.</div><div><br></div><ol><li>En un parque de atracciones han hecho un estudio sobre sus visitantes para mejorar su servicio. Han representado en un gráfico los visitantes que han tenido en una semana.</li></ol><div><br></div><div>La dirección del parque sabe que un tercio de los visitantes totales fueron mayores de 18 años. El parque tiene 50 atracciones distintas. La entrada para los menores de 12 años cuesta 15 € y la entrada para los mayores de 12 años cuesta 6 € más. A los grupos de más de 20 personas se les rebaja 1 € en la entrada de cada persona.</div><div><br></div><div>¿Cuántos visitantes tuvo el parque el viernes, sábado y domingo más que en el resto de la semana?</div><div><br></div><div><figure class="attachment attachment-preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:881,&quot;url&quot;:&quot;https://lh3.googleusercontent.com/Y5Z7I_c2moJPpnZFLc6YHdbO8qRZeR0UOSigyIt_FykMz3Pt6U_1HymcTgqn0FwOjFOnvl6tmt4e0XkxuVhGAvRhjltnc_CzCVDM0oXFE4CiPpdSRIkc6GXqoA6j0D2F82EVdNNNM3mAbbJbNA&quot;,&quot;width&quot;:1134}" data-trix-content-type="image"><img src="https://lh3.googleusercontent.com/Y5Z7I_c2moJPpnZFLc6YHdbO8qRZeR0UOSigyIt_FykMz3Pt6U_1HymcTgqn0FwOjFOnvl6tmt4e0XkxuVhGAvRhjltnc_CzCVDM0oXFE4CiPpdSRIkc6GXqoA6j0D2F82EVdNNNM3mAbbJbNA" width="1134" height="881"><figcaption class="caption"></figcaption></figure></div><div><br></div><div>Visitantes V – S – D: 350 + 500 + 300 = 1.150<br><br></div><div>Visitantes L – M – X – J: 150 + 200 + 250 + 200 = 800<br><br></div><div>Diferencia de visitantes: 1.150 - 800 = 350<br><br></div><div>Solución: Tuvo 350 visitantes más.<br><br></div><ol><li>Elena ha escrito en un papel tres números consecutivos. Ha retado a sus amigos a que adivinen cuáles son y como pista les ha dicho que la suma de los tres es igual a 27. ¿Qué números son?.</li></ol><div><br></div><ul><li>Comenzamos probando con el 3, el 4 y el 5.</li></ul><div>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 3 +4 + 5 = 12</div><div>Como el resultado, 12, es menor que 27, probamos con</div><div>números más altos. Por ejemplo, 11, 12 y 13.</div><div><br></div><div>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 11 + 12 + 13 = 36</div><div>En este caso, nos hemos pasado de 27.</div><div>Probamos con números más bajos que 11, 12 y 13</div><div>pero mayores que 3, 4 y 5.</div><div>Probamos con 8, 9 y 10.</div><div>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;8 + 9 + 10 = 27</div><div>El resultado es 27, la suma que buscábamos.</div><div>Solución: Los números son 8, 9 y 10.<br><br></div><div><br>Nombre: LUISA MARIA RAMIREZ RODRIGUEZ&nbsp;<br>Tutor: JUAN SALAMANCA &nbsp;<br>CORPORACIÓN UNIVERSITARIA IBEROAMERICANA </div>]]></description>
         <enclosure url="" />
         <pubDate>2017-06-06 02:48:19 UTC</pubDate>
         <guid>https://padlet.com/lramir59/n7kxtp4my4g/wish/175313537</guid>
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