https://padlet.com/sawamukail/talgebratalk Making mistakes is the most useful thing to do in math. en-us 2016-10-26 15:24:43 UTC 2025-11-01 16:19:48 UTC hello@padlet.com https://padlet-assets.s3.amazonaws.com/icons/Templeball.png https://padlet.com/sawamukail/talgebratalk/wish/133412496 I see the shape growing because on each side, there is one being added. There are 3 sides I think the number of squares will be 298. The pattern is:
1. The case number minus 1
case 4 - 1 = 3
2. That number times 3
3 x 3 =  9
3. And add 1
9 + 1 = 10
So, case 4 is 10.]]> 2016-10-26 17:25:10 UTC https://padlet.com/sawamukail/talgebratalk/wish/133412496 https://padlet.com/sawamukail/talgebratalk/wish/133412579 I think the answer is 400. However there are some things that other people are doing that also make sense. This was my thinking process. So each time  the amount increases 3 times. 1 on top and 1 left and right. However, you already have 1 block as the base which makes it 1 cube staying there each time. So if you multiply 3 (cubes) times 100 then you get three hundred. Then counting that block that has always been at the bottom as the base, if you add that to 300 then you would get 301.]]> 2016-10-26 17:25:21 UTC https://padlet.com/sawamukail/talgebratalk/wish/133412579 https://padlet.com/sawamukail/talgebratalk/wish/133412606 Case on will be 301 there is one added to the top and to both sides (left and right). It would be 301 instead of 300 because of the single cube at the beginning.

Because:
3 x 100 + 1 = 301
the one is like before the first cube in case1]]> 2016-10-26 17:25:26 UTC https://padlet.com/sawamukail/talgebratalk/wish/133412606 ciullaa https://padlet.com/sawamukail/talgebratalk/wish/133412640 I see that in every case it has 3 more than the case before it, (except for the first case). in case 100 I think there will be 298 squares, because 3x99=297 297+1=298. I'm adding the one because of the one I took from the 100 (to get the 99)]]> 2016-10-26 17:25:32 UTC https://padlet.com/sawamukail/talgebratalk/wish/133412640 https://padlet.com/sawamukail/talgebratalk/wish/133412764 I see the shape growing 3 cubes each Case, and that the first case is just 1 cube, so the expression would be: 
(n x 3) + 1 
So the answer to the second question would be 298 instead of 301 because there is an extra cube/square in the center of all of it that counts as 1 case, which still counts as a cube, so it would be: (99 x 3) + 1 = 297 + 1 = 298]]> 2016-10-26 17:25:53 UTC https://padlet.com/sawamukail/talgebratalk/wish/133412764 https://padlet.com/sawamukail/talgebratalk/wish/133412778 1. It grows up one and out two every time
2. 97x3+1=298 squares ]]> 2016-10-26 17:25:56 UTC https://padlet.com/sawamukail/talgebratalk/wish/133412778 https://padlet.com/sawamukail/talgebratalk/wish/133412835 I see that every case is growing by 2 across and 1 up. So on case 100 there will be 300 squares because 3 x 100 = 300.]]> 2016-10-26 17:26:05 UTC https://padlet.com/sawamukail/talgebratalk/wish/133412835 https://padlet.com/sawamukail/talgebratalk/wish/133412848 Each time the shape gets bigger you have to add 3 more cube on each side. 
I predict the amount of cubes for case 100 will be 298 because 99 x 3 + 1 = 298  ]]> 2016-10-26 17:26:08 UTC https://padlet.com/sawamukail/talgebratalk/wish/133412848 https://padlet.com/sawamukail/talgebratalk/wish/133412895 it is growing by 3 The answer would be 301 because  3 x 100 + 1= 301

]]> 2016-10-26 17:26:13 UTC https://padlet.com/sawamukail/talgebratalk/wish/133412895 https://padlet.com/sawamukail/talgebratalk/wish/133412926  There will be 300 squares by case 100 because every time the boxes increase by 3 boxes ]]> 2016-10-26 17:26:18 UTC https://padlet.com/sawamukail/talgebratalk/wish/133412926 https://padlet.com/sawamukail/talgebratalk/wish/133412982 It has more than 3 in each cases.It would probably be close to 300 because every time it increases by 3 so in case 100 it will be close to that number area

]]> 2016-10-26 17:26:28 UTC https://padlet.com/sawamukail/talgebratalk/wish/133412982 https://padlet.com/sawamukail/talgebratalk/wish/133413032 1.  Shape growing 3 cubes each case.

2.  298]]> 2016-10-26 17:26:36 UTC https://padlet.com/sawamukail/talgebratalk/wish/133413032 shimatanis https://padlet.com/sawamukail/talgebratalk/wish/133413129 No.1...It grows by 3 cubes each time. One of the top one of the right one of the left
No.2 ...298 ]]> 2016-10-26 17:26:52 UTC https://padlet.com/sawamukail/talgebratalk/wish/133413129 https://padlet.com/sawamukail/talgebratalk/wish/133413152 The shape gets bigger each time. It will be 301 because there is an extra cube in the middle 

]]> 2016-10-26 17:26:55 UTC https://padlet.com/sawamukail/talgebratalk/wish/133413152 https://padlet.com/sawamukail/talgebratalk/wish/133413153 Every time the shape is growing on both sides, we are adding 3 each time.  And then there is an extra 1 so it will be 298]]> 2016-10-26 17:26:55 UTC https://padlet.com/sawamukail/talgebratalk/wish/133413153 https://padlet.com/sawamukail/talgebratalk/wish/133413234 I think that it will be around ]]> 2016-10-26 17:27:05 UTC https://padlet.com/sawamukail/talgebratalk/wish/133413234 https://padlet.com/sawamukail/talgebratalk/wish/133413349 99 x 3= 297
297 + 1= 298

Every case the number increases by 3 starting from one. Therefore, 99 cases plus 1 will be the answer. There will be 298 squares in case 100]]> 2016-10-26 17:27:23 UTC https://padlet.com/sawamukail/talgebratalk/wish/133413349 https://padlet.com/sawamukail/talgebratalk/wish/133413510 It is growing by 3 every case so if you multiply 1 less case number you want to find by 3 and then you add one you will  get how many cubes are in the case. 99x3= 297. Then you have to add 1 because there is one extra cube in each case so it will be 297+1=298]]> 2016-10-26 17:27:47 UTC https://padlet.com/sawamukail/talgebratalk/wish/133413510 https://padlet.com/sawamukail/talgebratalk/wish/133413783 The shapes keep adding 3 each time it gets bigger and there is one extra. I predict it will be 301. ]]> 2016-10-26 17:28:35 UTC https://padlet.com/sawamukail/talgebratalk/wish/133413783 https://padlet.com/sawamukail/talgebratalk/wish/133413820 Every time the shape gets bigger you are adding 3 to  it. In case 100 there will be 298 squares.

]]> 2016-10-26 17:28:44 UTC https://padlet.com/sawamukail/talgebratalk/wish/133413820 https://padlet.com/sawamukail/talgebratalk/wish/133413946 I think that at Case 100 there will be 298 because for example on Case 3 there is 6 in total for all sides and then 1 cube on the bottom. So in Case 100 there would be 99 on the 3 sides and 1 cube on the bottom. (99 x 3) + 1]]> 2016-10-26 17:29:12 UTC https://padlet.com/sawamukail/talgebratalk/wish/133413946 https://padlet.com/sawamukail/talgebratalk/wish/133414072 298]]> 2016-10-26 17:29:40 UTC https://padlet.com/sawamukail/talgebratalk/wish/133414072 https://padlet.com/sawamukail/talgebratalk/wish/133414253 The shapes are growing 3 cubes each case. I think that there would be about 300 squares in case 100.]]> 2016-10-26 17:30:15 UTC https://padlet.com/sawamukail/talgebratalk/wish/133414253 https://padlet.com/sawamukail/talgebratalk/wish/133414817 1. 99x3=297
2. 297+1=298
When we get to 100 cases we would use 298 squares. ]]> 2016-10-26 17:31:44 UTC https://padlet.com/sawamukail/talgebratalk/wish/133414817 https://padlet.com/sawamukail/talgebratalk/wish/133414958 The answer would be 297 and 298]]> 2016-10-26 17:32:09 UTC https://padlet.com/sawamukail/talgebratalk/wish/133414958