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      <title>Sam and Cristo period 4 by its ya boii chris</title>
      <link>https://padlet.com/cristoc771/mxg7u5sufjy8</link>
      <description>Made with fortitude</description>
      <language>en-us</language>
      <pubDate>2018-01-30 22:28:58 UTC</pubDate>
      <lastBuildDate>2018-02-01 18:18:52 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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         <url></url>
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      <item>
         <title>combustion </title>
         <author>cristoc771</author>
         <link>https://padlet.com/cristoc771/mxg7u5sufjy8/wish/226367088</link>
         <description><![CDATA[<div>1<strong>C</strong><strong><sub>2</sub></strong><strong>H</strong><strong><sub>4</sub></strong><strong>&nbsp; +&nbsp; 3O</strong><strong><sub>2</sub></strong><strong>--&gt;</strong><strong><sub> </sub></strong><strong>&nbsp;2CO</strong><strong><sub>2</sub></strong><strong>&nbsp; +&nbsp; 2H</strong><strong><sub>2</sub></strong><strong>O<br>2CH</strong><strong><sub>3</sub></strong><strong>OH&nbsp; +&nbsp; 3O</strong><strong><sub>2 </sub></strong><strong>&nbsp;---&gt;&nbsp; 2CO</strong><strong><sub>2</sub></strong><strong>&nbsp; +&nbsp; 4H</strong><strong><sub>2</sub></strong><strong>O<br>1C</strong><strong><sub>2</sub></strong><strong>H</strong><strong><sub>5</sub></strong><strong>OH&nbsp; +&nbsp; 3O</strong><strong><sub>2 </sub></strong><strong>&nbsp;---&gt;&nbsp; 2CO</strong><strong><sub>2</sub></strong><strong>&nbsp; +&nbsp; 3H</strong><strong><sub>2</sub></strong><strong>O<br>1Cu</strong><strong><sub>2</sub></strong><strong>SO</strong><strong><sub>4</sub></strong><strong>&nbsp; +&nbsp; 1Zn&nbsp; --&gt;&nbsp; 2Cu&nbsp; + 1ZnSO</strong><strong><sub>4<br>&nbsp; &nbsp;</sub></strong><strong>&nbsp;1C</strong><strong><sub>5</sub></strong><strong>H</strong><strong><sub>8</sub></strong><strong>&nbsp; +&nbsp; 7O</strong><strong><sub>2 </sub></strong><strong>&nbsp;---&gt;&nbsp; 5CO</strong><strong><sub>2</sub></strong><strong>&nbsp; +&nbsp; 4H</strong><strong><sub>2</sub></strong><strong>O<br></strong>As the lists states, we are interested in combustion reactions for two opposite reasons. Sometimes we want to speed it up and sometimes slow it down.<br><strong>Hydrocarbon + oxygen -&gt; CO</strong><strong><sub>2</sub></strong><strong> + H</strong><strong><sub>2</sub></strong><strong>O<br>(combustion/oxidation)</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2018-01-30 22:43:00 UTC</pubDate>
         <guid>https://padlet.com/cristoc771/mxg7u5sufjy8/wish/226367088</guid>
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      <item>
         <title>synthesis</title>
         <author>cristoc771</author>
         <link>https://padlet.com/cristoc771/mxg7u5sufjy8/wish/226611458</link>
         <description><![CDATA[<div>1<strong>P</strong><strong><sub>4</sub></strong><strong>&nbsp; +&nbsp; 3O</strong><strong><sub>2</sub></strong><strong>&nbsp; --&gt; &nbsp; 2P</strong><strong><sub>2</sub></strong><strong>O</strong><strong><sub>3<br></sub></strong><strong>&nbsp;2NH</strong><strong><sub>3</sub></strong><strong>&nbsp; +&nbsp; 1H</strong><strong><sub>2</sub></strong><strong>SO</strong><strong><sub>4</sub></strong><strong>&nbsp; --&gt; 1(NH</strong><strong><sub>4</sub></strong><strong>)</strong><strong><sub>2</sub></strong><strong>SO</strong><strong><sub>4<br></sub></strong><strong>1SO</strong><strong><sub>2</sub></strong><strong>&nbsp; +&nbsp; 1H</strong><strong><sub>2</sub></strong><strong>O&nbsp; ---&gt;&nbsp; 1H</strong><strong><sub>2</sub></strong><strong>SO</strong><strong><sub>3<br></sub></strong><strong>1Li</strong><strong><sub>2</sub></strong><strong>O&nbsp; +&nbsp; 1CO</strong><strong><sub>2</sub></strong><strong>&nbsp; ---&gt;&nbsp; 1Li</strong><strong><sub>2</sub></strong><strong>CO</strong><strong><sub>3<br></sub></strong><strong>2C</strong><strong><sub>5</sub></strong><strong>H</strong><strong><sub>5</sub></strong><strong>&nbsp; +&nbsp; 1Fe&nbsp; ---&gt;&nbsp; 1Fe(C</strong><strong><sub>5</sub></strong><strong>H</strong><strong><sub>5</sub></strong><strong>)</strong><strong><sub>2<br></sub></strong><strong>A + B -&gt; AB (synthesis)<br>All of these chemical equations belong in the synthesis category because all of these equations have started out separated  and the end result was one product.&nbsp;</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2018-01-31 15:27:40 UTC</pubDate>
         <guid>https://padlet.com/cristoc771/mxg7u5sufjy8/wish/226611458</guid>
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      <item>
         <title>decomposition </title>
         <author>cristoc771</author>
         <link>https://padlet.com/cristoc771/mxg7u5sufjy8/wish/226631782</link>
         <description><![CDATA[<div>1<strong>MgCO</strong><strong><sub>3---&gt;</sub></strong><strong>&nbsp; 1MgO&nbsp; + 1CO</strong><strong><sub>2<br></sub></strong><strong>2NO</strong><strong><sub>2</sub></strong><strong> ---&gt;&nbsp; 2O</strong><strong><sub>2</sub></strong><strong>&nbsp; + 1N</strong><strong><sub>2</sub></strong></div><div>1<strong>Ba(OH)</strong><strong><sub>2</sub></strong><strong>&nbsp; ---&gt;1BaO&nbsp; +&nbsp; 1H</strong><strong><sub>2</sub></strong><strong>O<br>2KClO</strong><strong><sub>3</sub></strong><strong>&nbsp; ---&gt;&nbsp; 2KCl&nbsp; +&nbsp; 3O</strong><strong><sub>2<br></sub></strong><strong>2HgO&nbsp; ---&gt;&nbsp; 2Hg&nbsp; + 1O</strong><strong><sub>2<br></sub></strong><strong>these chemical equations all go into decomposition because, all equations start out as one compound then separate into two compounds (elements) this is similar to synthesis but in reverse.</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2018-01-31 15:56:56 UTC</pubDate>
         <guid>https://padlet.com/cristoc771/mxg7u5sufjy8/wish/226631782</guid>
      </item>
      <item>
         <title>single replacement </title>
         <author>cristoc771</author>
         <link>https://padlet.com/cristoc771/mxg7u5sufjy8/wish/226659105</link>
         <description><![CDATA[<div>3<strong>H</strong><strong><sub>2</sub></strong><strong>CO</strong><strong><sub>3</sub></strong><strong> +&nbsp; 2Al&nbsp; ---&gt;&nbsp; 3H</strong><strong><sub>2 </sub></strong><strong>&nbsp;+ 1Al</strong><strong><sub>2</sub></strong><strong>(CO</strong><strong><sub>3</sub></strong><strong>)</strong><strong><sub>3<br></sub></strong><strong>2Al&nbsp; + 1Fe</strong><strong><sub>2</sub></strong><strong>O</strong><strong><sub>3</sub></strong><strong>&nbsp; ---&gt; 2Fe&nbsp; +&nbsp; 1Al</strong><strong><sub>2</sub></strong><strong>O</strong><strong><sub>3<br></sub></strong><strong>1Ca&nbsp; +&nbsp; 2HCl&nbsp; ---&gt; 1CaCl</strong><strong><sub>2</sub></strong><strong>&nbsp; +&nbsp; 1H</strong><strong><sub>2<br></sub></strong><strong>1Cl</strong><strong><sub>2</sub></strong><strong>&nbsp; + 1KI&nbsp; ---&gt;&nbsp; 1KCl&nbsp; +&nbsp; 1I</strong><strong><sub>2<br></sub></strong><strong>1C</strong><strong><sub>6</sub></strong><strong>H</strong><strong><sub>12</sub></strong><strong>&nbsp; +&nbsp; 9O</strong><strong><sub>2 </sub></strong><strong>&nbsp;---&gt;6CO</strong><strong><sub>2</sub></strong><strong>&nbsp; +&nbsp; 6H</strong><strong><sub>2</sub></strong><strong>O<br>these are all single replacement, because if you look at the last chemical equation you can see that hydrogen switches places</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2018-01-31 16:38:24 UTC</pubDate>
         <guid>https://padlet.com/cristoc771/mxg7u5sufjy8/wish/226659105</guid>
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      <item>
         <title>double replacement </title>
         <author>cristoc771</author>
         <link>https://padlet.com/cristoc771/mxg7u5sufjy8/wish/226675811</link>
         <description><![CDATA[<div>1<strong>AgNO</strong><strong><sub>3</sub></strong><strong>&nbsp; +1 NaBr&nbsp; ---&gt;&nbsp; 1NaNO</strong><strong><sub>3</sub></strong><strong>&nbsp; +&nbsp; 1AgBr<br>2KI&nbsp; +&nbsp; 1Pb(NO</strong><strong><sub>3</sub></strong><strong>)</strong><strong><sub>2</sub></strong><strong>&nbsp; ---&gt; 1PbI</strong><strong><sub>2</sub></strong><strong>&nbsp; +&nbsp; 2KNO</strong><strong><sub>3<br></sub></strong><strong>2Al(OH)</strong><strong><sub>3</sub></strong><strong>&nbsp; +&nbsp; 3H</strong><strong><sub>2</sub></strong><strong>SO</strong><strong><sub>4</sub></strong><strong>---&gt;1Al</strong><strong><sub>2</sub></strong><strong>(SO</strong><strong><sub>4</sub></strong><strong>)</strong><strong><sub>3</sub></strong><strong>&nbsp; + 6H</strong><strong><sub>2</sub></strong><strong>O<br>1CaCl</strong><strong><sub>2 </sub></strong><strong>&nbsp;+&nbsp; 1Na</strong><strong><sub>2</sub></strong><strong>SO</strong><strong><sub>4</sub></strong><strong>&nbsp; ---&gt; 1CaSO</strong><strong><sub>4</sub></strong><strong>&nbsp; + 2NaCl</strong> <br>1<strong>MgCl</strong><strong><sub>2</sub></strong><strong>&nbsp; +&nbsp; 2NH</strong><strong><sub>4</sub></strong><strong>OH&nbsp; ---&gt;1Mg(OH)</strong><strong><sub>2</sub></strong><strong>&nbsp; +&nbsp; 2NH</strong><strong><sub>4</sub></strong><strong>Cl<br>these chemical equations&nbsp; are all double replacement,&nbsp; because if you look at the last question MgCl both switched places in the final products all the equations switch both the elements around to make a new product in the final product.&nbsp;</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2018-01-31 17:04:33 UTC</pubDate>
         <guid>https://padlet.com/cristoc771/mxg7u5sufjy8/wish/226675811</guid>
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