AP Physics 1 by https://padlet.com/lallr/mulpryivs00m Kin en-us 2018-01-24 02:53:16 UTC 2025-10-24 06:05:46 UTC hello@padlet.com Alden Ng https://padlet.com/lallr/mulpryivs00m/wish/696626051 We're only looking at the vertical component of the balls. The equation for vertical motion x=(a/2)(t)^2 + v_i(t) + h. a is the same because gravity accelerates all objects equally. the first ball drops straight down and has 0 v_i. the second ball gets a push, but the push is parallel to the ground, and so there is no vertical component to the push, therefore the second ball also has v_i of 0. Both balls start from the same height.]]> 2020-08-25 06:22:52 UTC https://padlet.com/lallr/mulpryivs00m/wish/696626051 James Lam https://padlet.com/lallr/mulpryivs00m/wish/696626182 2020-08-25 06:23:02 UTC https://padlet.com/lallr/mulpryivs00m/wish/696626182 Shun Yat https://padlet.com/lallr/mulpryivs00m/wish/696626291 Both balls reach the ground at almost the same time because the time until the ball hits the ground is only decided by height and downward acceleration. The horizontal component of the balls doesn't matter. However, downward acceleration is gravity, and there is also very minimal air resistance because it is a ball shape. The equation for this scenario would be y=vit+1/2at^2, and keep in mind we're only looking at the vertical component. Through this, we know that vi=0, and we can simplify the equation to y=1/2at^2. Acceleration is the same for both balls due to gravity, and the height would be the same because they were both launched by the machine at the same height. Therefore, both balls hit the ground at the same time.]]> 2020-08-25 06:23:09 UTC https://padlet.com/lallr/mulpryivs00m/wish/696626291 Julia Chan https://padlet.com/lallr/mulpryivs00m/wish/696626341 ∆y=1/2at^2. acceleration due to gravity is the same for both balls (the vertical component isn't affected by the horizontal component) and the ∆y is the same, therefore the time it takes to hit the ground is the same.]]> 2020-08-25 06:23:12 UTC https://padlet.com/lallr/mulpryivs00m/wish/696626341 Man Hei https://padlet.com/lallr/mulpryivs00m/wish/696626376 Horizontal velocities do not affect vertical velocities. Despite one ball having an initial X-velocity, both balls still have the same vertical velocity which is zero. Since both balls are experiencing acceleration due to gravity, the time they would take to fall are the same. The equation for time would be ⎷(2H/g), arranged from 𝝙y = ViT + 1/2gT^2 where Vi is zero and acceleration is gravity. ]]> 2020-08-25 06:23:15 UTC https://padlet.com/lallr/mulpryivs00m/wish/696626376 James Lam https://padlet.com/lallr/mulpryivs00m/wish/696626416 The horizontal component doesn't affect the vertical component, and both the balls are released on similar heights and experiencing the same gravity, therefore landing on the ground at similar ground. By using the equation ∆x = vit+1/2at^2, ∆x, a, and vi are constant for both balls, so the time taken for the ball to drop to the ground is the same. ]]> 2020-08-25 06:23:18 UTC https://padlet.com/lallr/mulpryivs00m/wish/696626416 Samuel Cowan https://padlet.com/lallr/mulpryivs00m/wish/696626506 The balls hit the ground at the same time because the the time is determined by Height and Acceleration. However, it is because horizontal velocity has no impact on vertical velocity. The downward acceleration represents gravity which means they are going to hit the ground at the same time. ]]> 2020-08-25 06:23:24 UTC https://padlet.com/lallr/mulpryivs00m/wish/696626506 Eugene Chan https://padlet.com/lallr/mulpryivs00m/wish/696626515 Claim: They both hit the ground at the same time. 

Evidence/Reasoning: One is the vertical component and the other is the horizontal component. 
delta y = vi t + (1/2) at^2. Initially, one of them has a greater horizontal velocity, but both of them have no vertical velocity. 
Therefore, the equation would become delta y = (1/2)at^2. Since the only acceleration both balls have is gravity,x the balls’ vertical 
motion are the same. They reach the ground at the same time because they are traveling the same distance downwards.]]> 2020-08-25 06:23:24 UTC https://padlet.com/lallr/mulpryivs00m/wish/696626515 Janelle Lu https://padlet.com/lallr/mulpryivs00m/wish/696626819 The acceleration due to gravity for both balls is the same and the horizontal component doesn't have an affect. The equation for the vertical component for both balls would be delta y = 1/2at^2. Acceleration here for both balls would be gravity. Therefore, the two balls will land on the ground at about the same time. ]]> 2020-08-25 06:23:43 UTC https://padlet.com/lallr/mulpryivs00m/wish/696626819 Marcus Ho https://padlet.com/lallr/mulpryivs00m/wish/696627009 Because horizontal velocity does not affect vertical velocity, as they are 90degrees apart, and both of them only have the gravity component of their vertical acceleration, which is the same]]> 2020-08-25 06:23:55 UTC https://padlet.com/lallr/mulpryivs00m/wish/696627009 Gabriel Yam https://padlet.com/lallr/mulpryivs00m/wish/696629024 Claim: Both of the balls hit the ground at the same time. 

Initial velocity of both of the balls are zero. They are released from the same height, so they travel the same vertical distance. One ball is launched with a  horizontal velocity, but since we are only looking at the time both balls hit the ground, we aren't concerned with the horizontal velocity. To calculate the timing, we could use the equation dx = vit + 1/2at^2. Since the initial vertical velocity is 0, the equation becomes dx =  1/2at^2. Since acceleration is a fixed variable because both balls are accelerating due to gravity, the time depends on the height. In order to make the timing the same, the height has to be the same. 

Therefore, both balls hit the ground at the same time]]> 2020-08-25 06:26:09 UTC https://padlet.com/lallr/mulpryivs00m/wish/696629024 Enoch Lim https://padlet.com/lallr/mulpryivs00m/wish/696631246  First of all, the ball which falls straight down only has one force acting on it, the force of gravity, so it accelerates at a constant rate towards the ground (assume negligible air resistance). The other ball is launched horizontally. There are two forces acting on this ball. One is the force parallel to the floor (0° angle) and the other is the force of gravity. The amount of time the ball has in the air relates to how quickly it falls. This may or may not be affected by the act of being launched. To find how being launched affects the ball's vertical motion, we use sin (0°) * magnitude of the force, and sin(0) is 0, so the launch has no effect on the vertical motion of the ball. This leaves gravity to act on the ball freely, the same as with the other ball.]]> 2020-08-25 06:28:20 UTC https://padlet.com/lallr/mulpryivs00m/wish/696631246 Zac Tsang https://padlet.com/lallr/mulpryivs00m/wish/696631734 The time until the balls hit the ground is decided only by initial height and downward acceleration.
Because the balls have identical initial height as guaranteed by the setup and identical gravitational acceleration as guaranteed by the Earth, the balls will hit the ground at the same time.
]]> 2020-08-25 06:28:50 UTC https://padlet.com/lallr/mulpryivs00m/wish/696631734