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      <title>3-4 Math Full Class Lesson Reflection by </title>
      <link>https://padlet.com/hillgrovepoa/34MAFCLR</link>
      <description></description>
      <language>en-us</language>
      <pubDate>2022-03-31 10:28:25 UTC</pubDate>
      <lastBuildDate>2023-03-13 03:28:17 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
      <image>
         <url></url>
      </image>
      <item>
         <title>Format for Lesson Reflection </title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2123349638</link>
         <description><![CDATA[<div>Before each lesson, go to the Math Website or textbook and look through the content.<br><br><strong><em>Before Lesson: </em></strong><br><br><strong>Red:</strong>&nbsp; What am I unsure about? <br><br><strong><em>After Lesson:</em></strong><br><br><strong>Yellow:</strong> What still makes me wonder? <br><br><strong>Green: </strong>Write down the key concepts and ideas that you have learnt for this lesson.&nbsp;<br><br>Do key in the colour before writing your statement.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-31 10:59:47 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2123349638</guid>
      </item>
      <item>
         <title>Example: Map Scale</title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2123349823</link>
         <description><![CDATA[<div>Red: I am not sure how to find area in map scale.<br><br>Yellow:&nbsp; I wonder why I need to square the scale.<br><br>Green:&nbsp; I know that when we want to find area in map scale, the reason why we need to square the length scale is because the units must be in square units in order to find the area.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-03-31 10:59:57 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2123349823</guid>
      </item>
      <item>
         <title>14 April 4.3: Changing the subject of a simple formula</title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129724075</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 01:09:43 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129724075</guid>
      </item>
      <item>
         <title>Anish</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129977045</link>
         <description><![CDATA[<div>The lady was very confusing donno what she saying she was just cancelling here and there and her way of explanation also very confusing If the equation was like 2b<br>+ a you would have to keep what ever is<br>close to b<br>and make b the subject&nbsp;of the<br>equation, i understood some parts<br>of the video but could not<br>understand The rest because of<br>her accent</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:38:51 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129977045</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129978371</link>
         <description><![CDATA[<div>Green</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1650951445/b3a8c36c1b7f6d89ad102286a7247e78/0C449B08_25BF_453A_A42F_24D98DED052B.jpg" />
         <pubDate>2022-04-05 04:40:16 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129978371</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129979615</link>
         <description><![CDATA[<div>Didn't really understand the second half of the video but I do kind of get the idea.<br><br>What I learnt today:<br>Question make a the subject. &nbsp; Example: a+c=b<br>Ans : a=b-c<br>Explanation: the letter c becomes negative because when you move across the = sign, it changes it's sign and in this case it becomes negative while the letter b remains the same</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:41:16 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129979615</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129979749</link>
         <description><![CDATA[<div>Red : I don’t understand what is the video explaining about</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:41:22 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129979749</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129980042</link>
         <description><![CDATA[<div>red: i don’t understand&nbsp;what she is saying and her equation </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:41:42 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129980042</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129980122</link>
         <description><![CDATA[<div>red:i dont understand her equation and her explanation &nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:41:46 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129980122</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>aidilbatricia0805</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129980213</link>
         <description><![CDATA[<div>Red:I don’t seem to understand her equation<br>After class yellow:I understand a bit only.<br>&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:41:52 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129980213</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129980359</link>
         <description><![CDATA[<div>Red :I am unsure how to find x and I don’t understand her equation.<br><br>Yellow :I understand that we need move sign but need more explanations&nbsp;<br><br>Green : I understand that if the term need to change sides ,the sign must change .if the term remains on the same side ,the sign must remain the same&nbsp;<br><br><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:42:03 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129980359</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129980628</link>
         <description><![CDATA[<div>before lesson:<br><br>red: i don't understand anything from the video<br><br>after lesson:<br><br>green: i understand that if the question is " make b the subject ", a + b = c .. the answer would be b = c - a . everything the passes by the equals sign will change signs.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:42:22 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129980628</guid>
      </item>
      <item>
         <title>4.3 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129981619</link>
         <description><![CDATA[<div>Red:I don understand </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:43:29 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129981619</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>joytham161</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129981799</link>
         <description><![CDATA[<div>&nbsp;Red: I don t understand what the lady is teaching and not sure how she cancel and circle the equation.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:43:39 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129981799</guid>
      </item>
      <item>
         <title>4.3 </title>
         <author>chloechin8090</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129981817</link>
         <description><![CDATA[<div>red: i don’t understand the video as it’s quite complicated. </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:43:40 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129981817</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129982852</link>
         <description><![CDATA[<div>Red : I do not understand the question&nbsp; in the video </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:44:41 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129982852</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>kesyeozy</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129982906</link>
         <description><![CDATA[<div>The first part I was not that sure but the second part I understood more<br>Condition for subject of formula: alone,positive,coefficient 1,power 1, numerator. +/- , */# , square/power 2, cube /power3</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:44:44 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129982906</guid>
      </item>
      <item>
         <title>aadi</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129983487</link>
         <description><![CDATA[<div>YELLOW : If the equation is like 2b + a<br>you you have to keep what ever is close to b<br>and make b the subject of the equation, i understand some parts of the video but could not understand other parts because of her accent&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:45:22 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129983487</guid>
      </item>
      <item>
         <title>Gareth</title>
         <author>muhammad_haiziq_sufian</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129983527</link>
         <description><![CDATA[<div>4.1 I can do it but I’m not that sure about the parts that involves fractions</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:45:24 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129983527</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129984957</link>
         <description><![CDATA[<div>red&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:46:53 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129984957</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129985517</link>
         <description><![CDATA[<div>How to know if the number needs to times or divide</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:47:28 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129985517</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129985717</link>
         <description><![CDATA[<div>before lesson:<br><br>i dont think i can understand the way she teach<br><br>after lesson:<br><br>green: i understand that if the question is " make a the subject ", a + b = c .. the answer would be a = c - b . everything the&nbsp;crosses the equals sign WILL change signs to the opposite.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:47:41 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129985717</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129986481</link>
         <description><![CDATA[<div>Yellow:i learnd that u need to divide and times by seeing the M </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:48:29 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129986481</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129986560</link>
         <description><![CDATA[<div>Red: I don’t know how to make x the Subject</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:48:36 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129986560</guid>
      </item>
      <item>
         <title>Haiziq</title>
         <author>muhammad_haiziq_sufian</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129987146</link>
         <description><![CDATA[<div>4.1.I understand how to do the equation but I am still a bit confused about the fraction part</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:49:12 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129987146</guid>
      </item>
      <item>
         <title>4.3: Changing the subject of a simple formula</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129987278</link>
         <description><![CDATA[<div>Red - I don’t understand. Need more&nbsp;explanation.<br><br>After lessons:<br><br>green: i understand that if the question is " make a the subject ", a + b = c .. the answer would be a = c - b . everything the crosses the equals sign WILL change signs to the opposite.<br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:49:20 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129987278</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129987509</link>
         <description><![CDATA[<div>red after watching the video i still dont understanding<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:49:34 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129987509</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129988792</link>
         <description><![CDATA[<div>red&nbsp;idk how</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:50:51 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129988792</guid>
      </item>
      <item>
         <title>Ashidiq</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129989520</link>
         <description><![CDATA[<div>Does it have to be an oppsite symbol/ sign</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:51:23 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129989520</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129989947</link>
         <description><![CDATA[<div>Red I don’t understand the equation </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:51:49 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129989947</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129990177</link>
         <description><![CDATA[<div>Red:i not sure </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:52:02 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129990177</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129990296</link>
         <description><![CDATA[<div>Yellow: I can only understand some, like the changing techniques.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 04:52:09 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2129990296</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130015906</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-05 05:17:00 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130015906</guid>
      </item>
      <item>
         <title>Danish</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130015999</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-05 05:17:06 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130015999</guid>
      </item>
      <item>
         <title>Anish</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130017900</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-05 05:18:48 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130017900</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130020171</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-05 05:20:49 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130020171</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>joytham161</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130115738</link>
         <description><![CDATA[<div>I wonder why do we have to bring the sign over?</div>]]></description>
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         <pubDate>2022-04-05 06:45:23 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130115738</guid>
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      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130447550</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-05 11:12:18 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130447550</guid>
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      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130574105</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-05 12:43:51 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130574105</guid>
      </item>
      <item>
         <title>Ashidiq</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130632715</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-05 13:15:01 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130632715</guid>
      </item>
      <item>
         <title>Gareth</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130832119</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1347175727/a696a5c5dcdedaf143dceda9ac1151db/image.jpg" />
         <pubDate>2022-04-05 14:48:24 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130832119</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130881244</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1645455765/b14415deed239e458de9ad0b814e7980/image.jpg" />
         <pubDate>2022-04-05 15:12:08 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130881244</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130904839</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1543896366/c5aba4691e4391a90eff09461f8f8ba2/image.jpg" />
         <pubDate>2022-04-05 15:23:36 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2130904839</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>nurisyaalya14</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131575934</link>
         <description><![CDATA[<div>before lesson:<br><br>red: i don't understand what the video is trying to explain<br><br>after lesson:<br><br>green: i understand that if the question is " make b the subject ", a + b = c .. the answer would be b = c - a . everything the passes by the equals sign will change signs.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-05 23:09:20 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131575934</guid>
      </item>
      <item>
         <title></title>
         <author>kesyeozy</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131814890</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-06 02:18:33 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131814890</guid>
      </item>
      <item>
         <title>Gareth </title>
         <author>ng_yan_chiat_gareth1_1</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131894915</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-06 03:21:06 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131894915</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>joytham161</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131895024</link>
         <description><![CDATA[<div>I wonder why do we have to square root?</div>]]></description>
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         <pubDate>2022-04-06 03:21:14 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131895024</guid>
      </item>
      <item>
         <title>Anish </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131895032</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1208726921/d4d84951407c125f2f5bdb8e8fc39618/image.jpg" />
         <pubDate>2022-04-06 03:21:14 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131895032</guid>
      </item>
      <item>
         <title> Ashidiq </title>
         <author>moham5447f</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131895280</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1571936420/d75462493f3dc8d6aac384ec6141f7cc/992EDD74_B58B_4AD0_9E84_BA8777689B11.jpg" />
         <pubDate>2022-04-06 03:21:28 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131895280</guid>
      </item>
      <item>
         <title>4.3  </title>
         <author>joytham161</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131895809</link>
         <description><![CDATA[<div>I wonder why do we have to change signs?</div>]]></description>
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         <pubDate>2022-04-06 03:21:59 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131895809</guid>
      </item>
      <item>
         <title>Gareth</title>
         <author>ng_yan_chiat_gareth1_1</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131896170</link>
         <description><![CDATA[<div>I have learned more about changing subjects and now have a better understanding of changing of subjects</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-06 03:22:18 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131896170</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>aidilbatricia0805</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131896275</link>
         <description><![CDATA[<div>Yellow : I the condition for the subject of formula and I know I need to change it the the opposite sign but I only know a simple equation for example x + y=p make y the subject y=p - x but if it’s like this question xy=4 I don’t really understand </div>]]></description>
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         <pubDate>2022-04-06 03:22:24 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131896275</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131896296</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1083009048/4cd71b653e452409ac66b2356cc86216/image.jpg" />
         <pubDate>2022-04-06 03:22:26 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131896296</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131896905</link>
         <description><![CDATA[<div>i don’t rlly understand how to change the signs&nbsp;</div>]]></description>
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         <pubDate>2022-04-06 03:22:59 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131896905</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131897523</link>
         <description><![CDATA[<div>Yellow : May be a bit confuse when changing square to power of 2 </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1193624495/323872c78973ffc55cc460625bed1167/image.jpg" />
         <pubDate>2022-04-06 03:23:35 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131897523</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131897989</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1522388307/e1078680da4ce227658e28b1c68f552f/image.jpg" />
         <pubDate>2022-04-06 03:24:03 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131897989</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131898019</link>
         <description><![CDATA[<div>yellow: i am confused about changing from square to the power of 2 and i need more of practices. </div>]]></description>
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         <pubDate>2022-04-06 03:24:04 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131898019</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>muhammad_haiziq_sufian</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131898185</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1262445812/47b64454dabb1915c39275df1db37fd2/058CE233_9AF9_474A_81B2_14FF8081FFE1.jpg" />
         <pubDate>2022-04-06 03:24:15 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131898185</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>kesyeozy</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131898619</link>
         <description><![CDATA[<div>I was not sure with the square root and the dividing part</div>]]></description>
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         <pubDate>2022-04-06 03:24:37 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131898619</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131898882</link>
         <description><![CDATA[<div>sometimes i dont get how to do it when it has fraction or something to the power of something. </div>]]></description>
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         <pubDate>2022-04-06 03:24:52 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131898882</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131898990</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1657803770/d52853b086eafb5e7e8c440fe189a518/0C16F8D4_487F_4744_A885_D502297AF870.jpg" />
         <pubDate>2022-04-06 03:24:58 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131898990</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131899026</link>
         <description><![CDATA[<div>need more practice</div>]]></description>
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         <pubDate>2022-04-06 03:25:00 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131899026</guid>
      </item>
      <item>
         <title>4.3 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131899485</link>
         <description><![CDATA[<div>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;</div>]]></description>
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         <pubDate>2022-04-06 03:25:27 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131899485</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131899526</link>
         <description><![CDATA[<div>Need more practice.</div>]]></description>
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         <pubDate>2022-04-06 03:25:29 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131899526</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131900035</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1262468095/a58c69badcf9ae0b5ee05ae1e77401e8/image.jpg" />
         <pubDate>2022-04-06 03:25:58 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131900035</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131900113</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-06 03:26:01 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131900113</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131900373</link>
         <description><![CDATA[<div>Question: how do we do the question if the subject has 2 or more of it and change the sign&nbsp;<br><br>Question: make b the subject.<br>5/b=2p<br>Solution: since the relation between 5 and b is divide, we do the opposite which is times so when we times on the left, we have to times on the right which means: 2pxb. So the answer is b=2pb</div>]]></description>
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         <pubDate>2022-04-06 03:26:16 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131900373</guid>
      </item>
      <item>
         <title>aadi</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131900417</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1657802402/c7b546fdffeda4419ad92d62ee5f72dd/image.jpg" />
         <pubDate>2022-04-06 03:26:19 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131900417</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131900427</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1284794337/3b0eeea2978215b4faed9340a7d29285/image.jpg" />
         <pubDate>2022-04-06 03:26:20 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131900427</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131900850</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1543896366/3813f8e8928469f041a4a66cb3444b14/image.jpg" />
         <pubDate>2022-04-06 03:26:45 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131900850</guid>
      </item>
      <item>
         <title>4.3 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131901041</link>
         <description><![CDATA[<div>Yellow: i still dont understand how to change the sign for square root&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-06 03:26:54 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131901041</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131901222</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1657804509/9d07656707c21c64a0575056337d3d70/image.jpg" />
         <pubDate>2022-04-06 03:27:06 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131901222</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131901376</link>
         <description><![CDATA[<div>Im&nbsp;cofuse about the square root question</div>]]></description>
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         <pubDate>2022-04-06 03:27:13 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131901376</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131901756</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-06 03:27:33 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131901756</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131902686</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-06 03:28:29 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131902686</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131903142</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/535824709/e1fe596362130c1a0fc28f1c6b983f69/16492156184073243191428353715063.jpg" />
         <pubDate>2022-04-06 03:28:54 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131903142</guid>
      </item>
      <item>
         <title>Danish</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131903481</link>
         <description><![CDATA[<div>Yellow I can’t really understand but I can understand a bit </div>]]></description>
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         <pubDate>2022-04-06 03:29:15 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131903481</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131904888</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-06 03:30:35 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131904888</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131913978</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-06 03:39:41 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131913978</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131914736</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-06 03:40:24 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2131914736</guid>
      </item>
      <item>
         <title></title>
         <author>kesyeozy</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133757993</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-07 02:05:31 UTC</pubDate>
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      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133758488</link>
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         <pubDate>2022-04-07 02:05:54 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133758488</guid>
      </item>
      <item>
         <title></title>
         <author>Hongxian</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133771217</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-07 02:14:58 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133771217</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133774834</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-07 02:17:29 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133774834</guid>
      </item>
      <item>
         <title>Anish </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133776029</link>
         <description><![CDATA[<div>At first it was hard to understand but slowly got the hang of it<br><br></div>]]></description>
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         <pubDate>2022-04-07 02:18:21 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133776029</guid>
      </item>
      <item>
         <title>Gareth </title>
         <author>ng_yan_chiat_gareth1_1</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133777880</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-07 02:19:40 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133777880</guid>
      </item>
      <item>
         <title></title>
         <author>assyahqirin</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133780926</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-07 02:21:41 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133780926</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133786934</link>
         <description><![CDATA[<div>I'm&nbsp;not sure if I know how to do like in just not confident, I think I need to do more practice</div>]]></description>
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         <pubDate>2022-04-07 02:25:45 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133786934</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133786950</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-07 02:25:46 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2133786950</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>joytham161</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2134204112</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-07 08:27:58 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2134204112</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>joytham161</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2134205843</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-07 08:29:19 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2134205843</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2134213846</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-07 08:35:47 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2134213846</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2134475407</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-07 12:25:52 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2134475407</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>moham5447f</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2134620406</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-07 13:46:01 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2134620406</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>moham5447f</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2134622775</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-07 13:47:10 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2134622775</guid>
      </item>
      <item>
         <title></title>
         <author>chloechin8090</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2137801471</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-10 05:42:52 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2137801471</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2137922915</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-10 10:55:34 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2137922915</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2137923960</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-10 10:57:19 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2137923960</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2137924098</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1083009048/28b3088a5610a921ada069083340652a/image.jpg" />
         <pubDate>2022-04-10 10:57:41 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2137924098</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>assyahqirin</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2137949145</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-10 11:54:20 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2137949145</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2137955271</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-10 12:08:11 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2137955271</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2138004300</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-10 13:43:33 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2138004300</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2138004547</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1262455547/5819bd0789e9c7b83f9c697f281dc95b/image.jpg" />
         <pubDate>2022-04-10 13:43:53 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2138004547</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2138012842</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-10 13:57:24 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2138012842</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2138074931</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-10 15:43:48 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2138074931</guid>
      </item>
      <item>
         <title>Kinda understand</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2138095311</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1663156825/24c2cae6b8d5cb0eb9e92f99f961c226/image.jpg" />
         <pubDate>2022-04-10 16:20:48 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2138095311</guid>
      </item>
      <item>
         <title>5.1 and 5.2: Arc Length and Sector (Pre Lesson)</title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2141971795</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2022-04-13 05:51:32 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2141971795</guid>
      </item>
      <item>
         <title>18 Apr 4.1 and 4.2: Factorisation of algebraic expressions</title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2144854194</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2022-04-15 12:01:34 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2144854194</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>joytham161</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2145813817</link>
         <description><![CDATA[<div>I wonder why do we need to find the radius?</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-17 04:13:55 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2145813817</guid>
      </item>
      <item>
         <title></title>
         <author>kesyeozy</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2145826596</link>
         <description><![CDATA[<div>&nbsp;4.1 Factorisation is about seeing if the 2 numbers has the same common factor.&nbsp;<br>4.2 it is about finding the quadratic expression of two numbers&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-17 04:56:14 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2145826596</guid>
      </item>
      <item>
         <title>4.3</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2145914322</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1285091164/0c5d1ff1f302b06613dc3ca55bd4b412/image.jpg" />
         <pubDate>2022-04-17 09:25:23 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2145914322</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2145963706</link>
         <description><![CDATA[<div>4.1 Green I understand how to factorise when two numbers have the same common factor&nbsp;<br>4.2 Yellow I understand how to do find the quadratic equation but may need more practice </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-17 11:43:58 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2145963706</guid>
      </item>
      <item>
         <title>5.1&amp;5.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2145972077</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-17 12:08:35 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2145972077</guid>
      </item>
      <item>
         <title>Anish 5.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2145985462</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-17 12:37:59 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2145985462</guid>
      </item>
      <item>
         <title>4.1 and 4.2 </title>
         <author>chloechin8090</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146012265</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-17 13:37:54 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146012265</guid>
      </item>
      <item>
         <title>5.1 and 5.2 </title>
         <author>chloechin8090</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146012618</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-04-17 13:38:45 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146012618</guid>
      </item>
      <item>
         <title></title>
         <author>aidilbatricia0805</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146041181</link>
         <description><![CDATA[<div>4.1<br>Green:I understand how to do but I will still practice&nbsp;<br>4.2<br>Yellow:I understand but I will still need a teacher to coach me</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-17 14:37:27 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146041181</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146075062</link>
         <description><![CDATA[<div>5.1 yellow is about measuring the distance of the ark but a little bit unsure<br><br>4.1 red not quite sure and a little bit confusing</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-17 15:52:57 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146075062</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146286109</link>
         <description><![CDATA[<div>4.1 red : <mark>i dont understand on how to take out common factors <br>&nbsp; &nbsp; &nbsp;green : i understand on how to factorise two numbers when have the same common factor </mark><br>4.2 yellow: i understand on how to use box method and cross multiply method and i still need lots of practice&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-17 23:25:27 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146286109</guid>
      </item>
      <item>
         <title>5.1 &amp; 5.2</title>
         <author>aidilbatricia0805</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146346647</link>
         <description><![CDATA[<div>Yellow:I understand how to do but i will need a teacher to coach me</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 00:45:34 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146346647</guid>
      </item>
      <item>
         <title>5.1 &amp; 5.2</title>
         <author>joytham161</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146362687</link>
         <description><![CDATA[<div>.</div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1241727306/074bb3c38273249f8b132dc6627983e9/FF056CF9_F0ED_45C0_A336_2B4548E40194.jpg" />
         <pubDate>2022-04-18 00:59:53 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146362687</guid>
      </item>
      <item>
         <title>4.1 &amp; 4.2</title>
         <author>joytham161</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146371319</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1241727306/40bcbe5b47a2eb92e8d7f373dc5b6e45/18D7771C_1A35_4256_8E67_B6B077E4F13C.jpg" />
         <pubDate>2022-04-18 01:08:16 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146371319</guid>
      </item>
      <item>
         <title>4.1 and 4.2</title>
         <author>Hongxian</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146563668</link>
         <description><![CDATA[<div>Green: I understand that factorization is that you need to take out the square term, linear term and constant term</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:26:04 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146563668</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146568343</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1637648890/ab7b834d9737c3410972aadf808ddb36/ED7D4B2D_7EA8_41D0_80C4_7D1C33A54A66.jpg" />
         <pubDate>2022-04-18 04:31:22 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146568343</guid>
      </item>
      <item>
         <title>Factorisation</title>
         <author>kesyeozy</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146569797</link>
         <description><![CDATA[<div>I understand how to factories the numbers using the box method&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:32:59 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146569797</guid>
      </item>
      <item>
         <title>4.1 and 4.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146571461</link>
         <description><![CDATA[<div>Yellow: <mark>i am still unsure about box method though.</mark><br><br>Green: i understand how to do cross method and box method (kinda).</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:34:57 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146571461</guid>
      </item>
      <item>
         <title>5.1 5.2</title>
         <author>kesyeozy</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146571714</link>
         <description><![CDATA[<div>I don’t understand</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:35:16 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146571714</guid>
      </item>
      <item>
         <title>4.1 &amp; 4.2 </title>
         <author>joytham161</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146573968</link>
         <description><![CDATA[<div>I am clear on how to use the box method to factories and&nbsp; factorisation on common factors.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:38:01 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146573968</guid>
      </item>
      <item>
         <title>4.1 &amp; 4.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146574089</link>
         <description><![CDATA[<div>Green: i understand about taking out common factors and cross multiplication</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:38:10 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146574089</guid>
      </item>
      <item>
         <title>4.1,4.2</title>
         <author>ng_yan_chiat_gareth1_1</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146574277</link>
         <description><![CDATA[<div>Greenish i now have a better understanding of factorising using the cross method&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:38:23 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146574277</guid>
      </item>
      <item>
         <title>Anish 5.1-5.2 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146574746</link>
         <description><![CDATA[<div>I kinda understand it but not all the way </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:39:01 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146574746</guid>
      </item>
      <item>
         <title>5.1 &amp; 5.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146574806</link>
         <description><![CDATA[<div>Red: i dont understand anything</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:39:06 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146574806</guid>
      </item>
      <item>
         <title>4.1 &amp; 4.2 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146574825</link>
         <description><![CDATA[<div>Green : I understand how to take out common factors and do cross multiplication .</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:39:07 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146574825</guid>
      </item>
      <item>
         <title>4.1 4.2</title>
         <author>ng_yan_chiat_gareth1_1</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146575069</link>
         <description><![CDATA[<div>Green i fully understand the cross method for factorising</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:39:28 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146575069</guid>
      </item>
      <item>
         <title>5.1 &amp; 5.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146575293</link>
         <description><![CDATA[<div>Red : I don’t understand anything</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:39:46 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146575293</guid>
      </item>
      <item>
         <title>4.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146575449</link>
         <description><![CDATA[<div>Green:i understand how to factorise ,factorise is based on common factors&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:39:58 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146575449</guid>
      </item>
      <item>
         <title>4.1and 4.2</title>
         <author>muhammad_haiziq_sufian</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146575543</link>
         <description><![CDATA[<div>I understand how to do factorise using box method&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:40:06 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146575543</guid>
      </item>
      <item>
         <title>4.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146576261</link>
         <description><![CDATA[<div>Green :i understand how to use cross multiplication&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:40:55 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146576261</guid>
      </item>
      <item>
         <title>5.1&amp;5.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146577069</link>
         <description><![CDATA[<div>Red:I don’t understand need more examples &amp;explanations&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:41:54 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146577069</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146578469</link>
         <description><![CDATA[<div>4.1 and 4.2&nbsp;<br>I understand the formula to get the answers and know how to factorise the questions&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 04:43:31 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146578469</guid>
      </item>
      <item>
         <title>4.1 &amp; 4.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146863586</link>
         <description><![CDATA[<div>I learnt how to factorise using the box method.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 11:25:41 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146863586</guid>
      </item>
      <item>
         <title>5.1 &amp; 5.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146864880</link>
         <description><![CDATA[<div>I know that chapter 5 involves finding the arc length and its perimeter.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 11:27:51 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146864880</guid>
      </item>
      <item>
         <title>5.1 &amp; 5.2 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146912342</link>
         <description><![CDATA[<div>Red : i don’t understand</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 12:32:17 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146912342</guid>
      </item>
      <item>
         <title>4.1 &amp; 4.2 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146915733</link>
         <description><![CDATA[<div>Green : I only understand a little bit for the working <mark>common factors</mark> and for the cross multiplication I can understand well</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 12:36:24 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146915733</guid>
      </item>
      <item>
         <title>19 Apr Chp 2: Map Scale</title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146970114</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 13:26:32 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146970114</guid>
      </item>
      <item>
         <title>4.1 -4.2 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146985582</link>
         <description><![CDATA[<div>- green <br>both i am able to find the ans as i know the formula about factorise .</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 13:38:44 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146985582</guid>
      </item>
      <item>
         <title>4.3 mistake </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146992475</link>
         <description><![CDATA[<div>This is a common mistake I made I will correct it and won’t make it again , more revisions:) </div>]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1669932260/1a32249885613924c9b9963cde918d30/image.jpg" />
         <pubDate>2022-04-18 13:44:26 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2146992475</guid>
      </item>
      <item>
         <title>4.1 &amp; 4.2</title>
         <author>nurshafika0777</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2147007009</link>
         <description><![CDATA[<div>i can understand abit but sometimes i get confused </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 13:56:30 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2147007009</guid>
      </item>
      <item>
         <title>5.1 &amp; 5.2</title>
         <author>nurshafika0777</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2147011228</link>
         <description><![CDATA[<div>i dont understand </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 14:00:09 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2147011228</guid>
      </item>
      <item>
         <title>4.1 and 4.2 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2147277171</link>
         <description><![CDATA[<div>green: i know how to do the cross multiplication and know how to factorise out common factors</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-18 17:25:09 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2147277171</guid>
      </item>
      <item>
         <title>Chp 2: Map Scale</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2148039995</link>
         <description><![CDATA[<div>Yellow: i wonder why we need to square when we see “area”?<br><br>Green: I understand how to do map scale such as, the distance and the area. To find the area I need to square it.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-19 05:14:39 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2148039995</guid>
      </item>
      <item>
         <title>5.1 &amp; 5.2</title>
         <author>joytham161</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2149957406</link>
         <description><![CDATA[<div>I’m still unclear about arc length and sector</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-20 08:01:37 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2149957406</guid>
      </item>
      <item>
         <title>4.1 and 4.2 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2149988863</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2022-04-20 08:29:08 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2149988863</guid>
      </item>
      <item>
         <title>5.1 and 5.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2150003405</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1669445142/20a7b631612a8d8b3036030d06854905/16504447762291342181124222474205.jpg" />
         <pubDate>2022-04-20 08:41:23 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2150003405</guid>
      </item>
      <item>
         <title>5.1 and 5.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2150021651</link>
         <description><![CDATA[<div>yellow ( i am clear but the rounding up put and the <mark>perimeter </mark>and major sector part oni i dont understand )</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-20 08:58:14 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2150021651</guid>
      </item>
      <item>
         <title>4.1 and 4.2 </title>
         <author>chloechin8090</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2150261771</link>
         <description><![CDATA[<div>Green: I understand how to factories and cross multiplication. </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-20 12:52:19 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2150261771</guid>
      </item>
      <item>
         <title>5.1 and 5.2 </title>
         <author>chloechin8090</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2150262059</link>
         <description><![CDATA[<div>i don’t understand anything. </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-20 12:52:32 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2150262059</guid>
      </item>
      <item>
         <title>4.1 &amp; 4.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2150398327</link>
         <description><![CDATA[<div>Green: I can understand and i need to practice a lot</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-20 14:00:42 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2150398327</guid>
      </item>
      <item>
         <title>5.1 &amp; 5.2 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2150399856</link>
         <description><![CDATA[<div>Red : I don’t understand anything</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-20 14:01:34 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2150399856</guid>
      </item>
      <item>
         <title></title>
         <author>kesyeozy</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2151310857</link>
         <description><![CDATA[<div>I dont fully understand the formula and what to use for it</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-21 02:21:42 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2151310857</guid>
      </item>
      <item>
         <title>5.1 and 5.2</title>
         <author>Hongxian</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2151312293</link>
         <description><![CDATA[<div>I understand that sector and arc length are part of a circle, sectors are part of the area and the arc length are part of the circumference&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-21 02:22:40 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2151312293</guid>
      </item>
      <item>
         <title>Ashidiq </title>
         <author>moham5447f</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2151314126</link>
         <description><![CDATA[<div>5.1, 5.2<br>I don understand what is pie and radius</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-21 02:24:09 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2151314126</guid>
      </item>
      <item>
         <title>5.1 &amp; 5.2</title>
         <author>joytham161</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2151736686</link>
         <description><![CDATA[<div>I understand arc length and sector now and the formula to find arc length is angle over 360 degree multiply by 2pie r.<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-21 08:57:09 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2151736686</guid>
      </item>
      <item>
         <title>5.1&amp;5.2 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2154536232</link>
         <description><![CDATA[<div>Understand how to find the arc length and perimeter</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-23 12:35:36 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2154536232</guid>
      </item>
      <item>
         <title>5.1 and 5.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2155906854</link>
         <description><![CDATA[<div>Yellow: i understand some but not everything.<br><br>Green: i understand the formula such as the pie, major length, minor length and the perimeter is the outline. It needs 2 radius and arc length.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-25 04:45:55 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2155906854</guid>
      </item>
      <item>
         <title></title>
         <author>kesyeozy</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2159659068</link>
         <description><![CDATA[<div>I understand when to use 2piR piR2 and to find the length and area</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-27 03:32:04 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2159659068</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2159974994</link>
         <description><![CDATA[<div>I understand what to do and 2pir but some questions I’m unclear</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-27 08:07:09 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2159974994</guid>
      </item>
      <item>
         <title>5.1 and 5.2</title>
         <author>muhammad_haiziq_sufian</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2160329077</link>
         <description><![CDATA[<div>I understand a little bit but I am still confused about how to do area&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-27 13:05:48 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2160329077</guid>
      </item>
      <item>
         <title>5.1 and 5.2 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2160333561</link>
         <description><![CDATA[<div>green : i understand abit on how to find arc length and perimeter . formula to find perimeter ( 2 radius + arc length )&nbsp;<br>red : i still not quite understand and need more explanation on area of circle </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-04-27 13:08:23 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2160333561</guid>
      </item>
      <item>
         <title>6.1: Pyramid </title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178582541</link>
         <description><![CDATA[<div><strong>Lesson Objective:</strong><br><br></div><ul><li>What are the shapes that make up the pyramid?</li><li>What is the difference between the slant height and perpendicular height?</li></ul><div><br><strong>Volume of Pyramid:</strong></div><ul><li>To find volume which type of height will you use?</li><li>What is the formula to find volume of pyramid?</li></ul><div><br><strong>Surface Area of Pyramid:</strong></div><ul><li>To find area which type of height will you use?</li><li>What is the formula to find area of pyramid?</li><li>What is the thing that you need to take note of when you are finding surface area of pyramid?</li></ul><div><br><br><br></div>]]></description>
         <enclosure url="https://youtu.be/O2wenAIf0H8" />
         <pubDate>2022-05-11 01:50:35 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178582541</guid>
      </item>
      <item>
         <title>6.1: Pyramid </title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178594281</link>
         <description><![CDATA[<div><strong>Lesson Objective:</strong><br><br></div><ul><li>What are the shapes that make up the pyramid?</li><li>What is the difference between the slant height and perpendicular height?</li></ul><div><br><strong>Volume of Pyramid:</strong></div><ul><li>To find volume which type of height will you use?</li><li>What is the formula to find volume of pyramid?</li></ul><div><br><strong>Surface Area of Pyramid:</strong></div><ul><li>To find area which type of height will you use?</li><li>What is the formula to find area of pyramid?</li><li>What is the thing that you need to take note of when you are finding surface area of pyramid?</li></ul><div><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:00:55 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178594281</guid>
      </item>
      <item>
         <title>6.1: Pyramid </title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178595247</link>
         <description><![CDATA[<div><strong>Lesson Objective:</strong><br><br></div><ul><li>What are the shapes that make up the pyramid?</li><li>What is the difference between the slant height and perpendicular height?</li></ul><div><br><strong>Volume of Pyramid:</strong></div><ul><li>To find volume which type of height will you use?</li><li>What is the formula to find volume of pyramid?</li></ul><div><br><strong>Surface Area of Pyramid:</strong></div><ul><li>To find area which type of height will you use?</li><li>What is the formula to find area of pyramid?</li><li>What is the thing that you need to take note of when you are finding surface area of pyramid?</li></ul><div><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:01:40 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178595247</guid>
      </item>
      <item>
         <title>6.1: Pyramid </title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178597632</link>
         <description><![CDATA[<div><strong>Lesson Objective:</strong><br><br></div><ul><li>What are the shapes that make up the pyramid?</li><li>What is the difference between the slant height and perpendicular height?</li></ul><div><br><strong>Volume of Pyramid:</strong></div><ul><li>To find volume which type of height will you use?</li><li>What is the formula to find volume of pyramid?</li></ul><div><br><strong>Surface Area of Pyramid:</strong></div><ul><li>To find area which type of height will you use?</li><li>What is the formula to find area of pyramid?</li><li>What is the thing that you need to take note of when you are finding surface area of pyramid?</li></ul><div><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:03:36 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178597632</guid>
      </item>
      <item>
         <title>6.1: Pyramid </title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178598508</link>
         <description><![CDATA[<div><strong>Lesson Objective:</strong><br><br></div><ul><li>What are the shapes that make up the pyramid?</li><li>What is the difference between the slant height and perpendicular height?</li></ul><div><br><strong>Volume of Pyramid:</strong></div><ul><li>To find volume which type of height will you use?</li><li>What is the formula to find volume of pyramid?</li></ul><div><br><strong>Surface Area of Pyramid:</strong></div><ul><li>To find area which type of height will you use?</li><li>What is the formula to find area of pyramid?</li><li>What is the thing that you need to take note of when you are finding surface area of pyramid?</li></ul><div><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:04:14 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178598508</guid>
      </item>
      <item>
         <title>6.1: Pyramid </title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178599234</link>
         <description><![CDATA[<div><strong>Lesson Objective:</strong><br><br></div><ul><li>What are the shapes that make up the pyramid?</li><li>What is the difference between the slant height and perpendicular height?</li></ul><div><br><strong>Volume of Pyramid:</strong></div><ul><li>To find volume which type of height will you use?</li><li>What is the formula to find volume of pyramid?</li></ul><div><br><strong>Surface Area of Pyramid:</strong></div><ul><li>To find area which type of height will you use?</li><li>What is the formula to find area of pyramid?</li><li>What is the thing that you need to take note of when you are finding surface area of pyramid?</li></ul><div><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:04:50 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178599234</guid>
      </item>
      <item>
         <title>6.1: Pyramid </title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178600055</link>
         <description><![CDATA[<div><strong>Lesson Objective:</strong><br><br></div><ul><li>What are the shapes that make up the pyramid?</li><li>What is the difference between the slant height and perpendicular height?</li></ul><div><br><strong>Volume of Pyramid:</strong></div><ul><li>To find volume which type of height will you use?</li><li>What is the formula to find volume of pyramid?</li></ul><div><br><strong>Surface Area of Pyramid:</strong></div><ul><li>To find area which type of height will you use?</li><li>What is the formula to find area of pyramid?</li><li>What is the thing that you need to take note of when you are finding surface area of pyramid?</li></ul><div><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:05:31 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178600055</guid>
      </item>
      <item>
         <title>6.1: Pyramid </title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178600320</link>
         <description><![CDATA[<div><strong>Lesson Objective:</strong><br><br></div><ul><li>What are the shapes that make up the pyramid?</li><li>What is the difference between the slant height and perpendicular height?</li></ul><div><br><strong>Volume of Pyramid:</strong></div><ul><li>To find volume which type of height will you use?</li><li>What is the formula to find volume of pyramid?</li></ul><div><br><strong>Surface Area of Pyramid:</strong></div><ul><li>To find area which type of height will you use?</li><li>What is the formula to find area of pyramid?</li><li>What is the thing that you need to take note of when you are finding surface area of pyramid?</li></ul><div><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:05:44 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178600320</guid>
      </item>
      <item>
         <title>6.1: Pyramid </title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178601794</link>
         <description><![CDATA[<div><strong>Lesson Objective:</strong><br><br></div><ul><li>What are the shapes that make up the pyramid?</li><li>What is the difference between the slant height and perpendicular height?</li></ul><div><br><strong>Volume of Pyramid:</strong></div><ul><li>To find volume which type of height will you use?</li><li>What is the formula to find volume of pyramid?</li></ul><div><br><strong>Surface Area of Pyramid:</strong></div><ul><li>To find area which type of height will you use?</li><li>What is the formula to find area of pyramid?</li><li>What is the thing that you need to take note of when you are finding surface area of pyramid?</li></ul><div><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:06:53 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178601794</guid>
      </item>
      <item>
         <title>6.1: Pyramid </title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178603039</link>
         <description><![CDATA[<div><strong>Lesson Objective:</strong><br><br></div><ul><li>What are the shapes that make up the pyramid?</li><li>What is the difference between the slant height and perpendicular height?</li></ul><div><br><strong>Volume of Pyramid:</strong></div><ul><li>To find volume which type of height will you use?</li><li>What is the formula to find volume of pyramid?</li></ul><div><br><strong>Surface Area of Pyramid:</strong></div><ul><li>To find area which type of height will you use?</li><li>What is the formula to find area of pyramid?</li><li>What is the thing that you need to take note of when you are finding surface area of pyramid?</li></ul><div><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:07:54 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178603039</guid>
      </item>
      <item>
         <title>5.1 and 5.2</title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178603320</link>
         <description><![CDATA[<div>I understand that sector and arc length are part of a circle, sectors are part of the area and the arc length are part of the circumference&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:08:08 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178603320</guid>
      </item>
      <item>
         <title>Anish </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178636406</link>
         <description><![CDATA[<div>Banana 🍌 </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:32:14 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178636406</guid>
      </item>
      <item>
         <title>aadi</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178641175</link>
         <description><![CDATA[<div>triangles</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:36:00 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178641175</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178641443</link>
         <description><![CDATA[<div>the base of a pyramid must be a polygon n-sided, closed shape and pyramid can be made out of rectangle square and triangle&nbsp;<br><br>the perpendicular height is from the vertex (tip of pyramid) to the centre of the base of pyramid<br><br>volume of pyramid formula is 1/3 x base x height&nbsp;<br><br>area of a triangle is slant height and if the pyramid is rectangle 2 of the triangle will be long and the other 2 will be short and to find the total surface area is area of triangle + base area (slanted height)<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:36:13 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178641443</guid>
      </item>
      <item>
         <title>6.1</title>
         <author>joytham161</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178641574</link>
         <description><![CDATA[<div>Pyramid is made up of squares, triangles and rectangles.<br>— Base of pyramid must be polygon. N- sided, closed shape<br>— Sides of pyramid one triangles<br><br>-<strong>Slant height</strong> is the perpendicular height of triangles by the side.<br>-<strong>Perpendicular heigh</strong>t is from the vertex (tip of pyramid) to the Center of base of pyramid.<br><br> Volume of pyramid uses perpendicular height<br><br>Formula to find volume of pyramid:<br>1/3 x base area x height<br><br>Area of triangle uses slant height<br>Area of pyramid (total surface of pyramid)&nbsp; depends on the shape and base decides what the area is.<br>Area of triangle+ base area<br>Area depends on the type of base<br>The area of the triangles differently by finding the area of 2 triangles by 2 triangles.<br><br><br><br><br><br><br><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:36:19 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178641574</guid>
      </item>
      <item>
         <title>Anish</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178641777</link>
         <description><![CDATA[<div>Pyramid are made up of triangles, square and rectangles hexagon octagon. The base can be any polygon but the sides can only be a triangle.&nbsp;<br><br>Perpendicular height is from the vertex to the centre of the base of the pyramid. Whereas Slant height is the perpendicular height of the triangle by the side.&nbsp;<br><br><br>The formula to find the volume of a pyramid is 1/3 x base area x perpendicular height.<br><br></div><div>Area of triangle uses slant height to find the volume perpendicular height to find the area area of pyramid depends on the shape of the pyramid and decide what the area is.<br><br>Area of triangle + base area&nbsp;<br>Area depends on the type of base </div><div><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:36:28 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178641777</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178642252</link>
         <description><![CDATA[<div>- Base of a pyramid must be a polygen. N sided, closed shapes like triangles,rectangles, squares and hexagon. &nbsp;<br><br>- The sides of a pyramid is made up of triangles. The slunt height is the perpendicular height of the triangles by the sides. The perpendicular height is from the vortex (Center of the pyramid) to the center of the base of the triangle.<br><br>- Formula to find volume of pyramid: 1/3 x base area x height.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:36:48 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178642252</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178642272</link>
         <description><![CDATA[<div>pyramid is made of square, triangle and rectangle .&nbsp;<br>the base of pyramid must be a polygon. n-sided, closed shape and all the side are made out of triangle&nbsp;<br><br>slant height is the perpendicular height of triangles by the sides.&nbsp;<br>perpendicular height is from the vertex to the centre of the base of pyramid&nbsp;<br><br>volume of pyramid uses perpendicular height&nbsp;<br>formula to find the volume of pyramid : 1/3 x base area x&nbsp;<br>height<br><br>slanted height&nbsp;<br>total surface area of pyramid is depending on the base shape&nbsp;<br>triangles area&nbsp;+ base area ( slanted height )<br>the thing that need to take note when finding surface area of pyramid is the based area and the slant height&nbsp;<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:36:49 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178642272</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178642283</link>
         <description><![CDATA[<div>- Best of pyramid i must be polygon, n-sided, closed shape and pyramid can be made of square and triangle.<br><br>- Perpendicular height is from the vertex (at the tip of the pyramid)&nbsp; to the Center of the base of pyramid.&nbsp;<br><br>-Slant height is the perpendicular height of area triangle by the side.<br><br>-Formula to find volume of pyramid: 1/3 x base area x&nbsp;height <br><br>-The thing that need to take note of is the base area and the slant height&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:36:49 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178642283</guid>
      </item>
      <item>
         <title>6.1l</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178642694</link>
         <description><![CDATA[<div>Pyramid is made up of: polygon and triangle and hexagon rectangle<br><br><br>&nbsp;so from the vertex to the center of the pyramid is the perpendicular height&nbsp;<br><br><br><br><br>1÷3×base area×height<br><br><br>To find the area of the pyramid is find the area base and the area of triangles<br><br><br><br><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:37:09 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178642694</guid>
      </item>
      <item>
         <title>6.1</title>
         <author>kesyeozy</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178642752</link>
         <description><![CDATA[<div>Pyramid is made out of squares, triangles and rectangle the base of pyramid must be a polygon n-sided closed shapes the sides must be triangles.&nbsp; &nbsp;&nbsp;<br><br>&nbsp;The slant height of the pyramid is the side, to find the perpendicular height is from the vertex to the Center of the pyramid.<br><br>1/3*base area*perpendicular height<br><br>To find the area of the triangle we would need to find the slant height and also the base area&nbsp;<br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:37:12 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178642752</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178642794</link>
         <description><![CDATA[<div>Base of pyramid must be a polygon, n-sided and closed shape.<br>Pyramid can be made up of squares , triangles , rectangle and hexagon.<br><br>Slant height is the perpendicular height of triangles by the sides.<br>Perpendicular height and is from the vertex to the center of the base of the pyramid.<br><br>VOULME: 1/3 x base area x height<br><br>Total surface area of pyramid u need to add area of triangle and base area ( slanted height )</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:37:15 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178642794</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178642861</link>
         <description><![CDATA[<div>- Base of pyramid must be polygon n-sided , closed shape and pyramid can be made of square and triangle.&nbsp;<br><br>- Perpendicular height is from the vertex to Center of base pyramid<br><br>- slant height is the perpendicular height of the triangles by the sides<br><br>- for volume the volume of cube over 3 so its 1 over 3 x base area x height<br><br>- &nbsp;the thing that need to take note of is the base area and the slant height <br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:37:18 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178642861</guid>
      </item>
      <item>
         <title>6.1 </title>
         <author>aidilbatricia0805</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178643375</link>
         <description><![CDATA[<div><mark>Base</mark> of pyramid must be a polygon,n-shape,close shape.<br>Pyramid can be made up of squares and triangles.<br><mark>Side</mark> of pyramid are triangles.<br><br>Slant height is the perpendicular height of triangles(AREA) by the side.<br>Perpendicular(VOL OF PYRAMID)height is from the verter (the tip of the pyramid) to the center of the base pyramid.<br><br>Volume = 1/3 x Base area x height.<br><br>Total surface area = area of triangle + base area (slanted height)<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:37:42 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178643375</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178644204</link>
         <description><![CDATA[<div>Pyramid can be made Out of square rectangle triangle&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:38:21 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178644204</guid>
      </item>
      <item>
         <title>6.1</title>
         <author>moham5447f</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178645086</link>
         <description><![CDATA[<div>Pyramid is made of shapes except circle&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:39:02 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178645086</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178645296</link>
         <description><![CDATA[<div>Triangle square rectangle hexagon <br>Base of pyramid must be a polygon n sided closed shape Side of pyramid are triangle <br>Slant height is the perpendicular height of triangle by the side<br><br>Perpendicular height is from the vertex (tip of pyramid) to the Center of base of pyramid <br><br>Vol of pyramid <br><strong>Volume = l × w × h</strong> , where l is length, w is width and h is height.</div><div>Find total surface area&nbsp;adding all the areas on the surface: the areas of the base, top, and lateral surfaces (sides) of the object.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:39:11 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178645296</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178647178</link>
         <description><![CDATA[<div>Base of pyramid must be a polygon a n-sided closed shape . Pyramids can be made up of triangles , squares and rectangles .<br><br>Slant height is the perpendicular height of triangles by the sides whereas a perpendicular height is from the vertex ( the tip of the pyramid ) to the centre of the base of the pyramid .<br><br>To find the volume of the pyramid , you must use this formula which is 1/3 x base area x height<br><br>The total surface area depending on the base shape formula is area of the triangle + base area ( slanted height ) </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:40:42 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178647178</guid>
      </item>
      <item>
         <title>6.1 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178647450</link>
         <description><![CDATA[<div>Triangle for pyramid can be square below can be different , eg hexagon . Must have coners<br><br>To find area of triangle use (half x b x h ) <br><br>&nbsp;For vol of cube use one out of three x base area x height&nbsp; Vol of pyramid <br><strong>Volume = l × w × h</strong> , where l is length, w is width and h is height.<br><br>Slant height is the perpendicular height of the side triangles, perpendicular height is from the vertex(tip of pyramid) to the base.<br><br>Total surface base<br>Rectangular base 1 rectangle base 2triangle (long) 2triangle (short)&nbsp;<br>Squares base&nbsp; is 4 triangles 1square base<br>Find total surface area adding all the areas on the surface: the areas of the base, top, and lateral surfaces (sides) of the object.<br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:40:55 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178647450</guid>
      </item>
      <item>
         <title>6.1 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178648156</link>
         <description><![CDATA[<div>Pyramid base must be a polygon. N-sided, closed shape like triangle square, hexagon. The base must have sides&nbsp;<br><br>When the vortex touches the centre of the base of pyramid it is called perpendicular height&nbsp;<br>And the slant height is the perpendicular height of triangles by the side&nbsp;<br><br>To find the volume if pyramid we need to use perpendicular and to find the cube/base we need to use the format which is volume of cube divided by 3&nbsp;<br><br>For triangle u need to add area of triangle and base. And u need to use slant height. The base decides what the area is&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:41:30 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178648156</guid>
      </item>
      <item>
         <title>6.1 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178649010</link>
         <description><![CDATA[<div>-Pyramid is made up of either triangles, rectangles, or square. Base of pyramid must be a polygon, n-sided closed shape.<br><br>-Slant height is the perpendicular height of triangles by the side.&nbsp;<br><br>-Perpendicular height is from the vertex (tip of pyramid) to the Center of the base of pyramid.&nbsp;<br><br>-Formula to find volume of the pyramid: 1/3&nbsp; x base area x height&nbsp;<br><br>-The total surface area is depend on the base shape formula. Area of the triangle + base area and the (slanted height)<br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:42:05 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178649010</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178649561</link>
         <description><![CDATA[<div>Triangles,square,hexagon,rectangle&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:42:31 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178649561</guid>
      </item>
      <item>
         <title>6.1</title>
         <author>moham5447f</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178649923</link>
         <description><![CDATA[<div>Base of pyramid must be a polygon n-sided, closed shape</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:42:51 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178649923</guid>
      </item>
      <item>
         <title>aadi</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178650858</link>
         <description><![CDATA[<div>the base of the pyrimid can be any polygon except for a circle and the sides of the pyramid can only be a triangle<br><br>slant height is the perpendicular height of triangles by the side.<br>perpendicular height is from the vertex<br><br>to find the volume of the pyramid is 1/3 x base area x height<br><br>slanted height uses the perpendicular height</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:43:37 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178650858</guid>
      </item>
      <item>
         <title>6.1</title>
         <author>ng_yan_chiat_gareth1_1</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178651091</link>
         <description><![CDATA[<div>&nbsp;A pyramid must have triangles but the base must either be a circle or a hexagon.<br><br>Pyramids are made out of triangle,square,circle,rectangle<br><br>You use berpenticular height and the formula for volume is 1/2 x b x b height<br><br>&nbsp;Find the surface area to find all the surface area of the pyramid and add them together to find the total surface area</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:43:47 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178651091</guid>
      </item>
      <item>
         <title>6.1 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178651204</link>
         <description><![CDATA[<div>Pyramids are made up of squares, triangles and rectangles.<br>The base of the pyramid must be a polygon.<br>Slant height is the perpendicular height of triangles by the side.<br>Perpendicular height is from the vertex(tip of pyramid) to the centre of the base of the pyramid.<br>Volume of pyramid 1/3 x base area x height<br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:43:52 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178651204</guid>
      </item>
      <item>
         <title>6.1</title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178652159</link>
         <description><![CDATA[<div>the base of a pyramid must be a polygon and the sides must be a triangle<br><br>slant height is&nbsp; the perpendicular height of triangles by the side&nbsp;<br><br>to find volume of pyramid is 1/3 x base are x height&nbsp;<br><br>area of triangle uses slant height, if the base is different the triangles are oso different </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:44:32 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178652159</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178653041</link>
         <description><![CDATA[<div>It must have a polygon and flat surface for the base of the pyramid and the side is triangle &nbsp;<br><br>the difference between slant and perpendicular height is perpendicular height is measured for the vertex to the Center of the base and slant is by the side&nbsp;<br><br>the formula for volume is 1 over 3 x base x perpendicular height&nbsp;<br><br>&nbsp;To find the Total surface area u need to find slant height and base</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:45:11 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178653041</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178663150</link>
         <description><![CDATA[<div>From the vertex form the middle is the perpendicular height is from the tip of the vertex to the center of base of the pyramid&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:53:01 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178663150</guid>
      </item>
      <item>
         <title>6.1</title>
         <author>Hongxian</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178665301</link>
         <description><![CDATA[<div>Pyramids sides are made of triangles and the base of pyramids are made of polygon n-sided, closed shapes.&nbsp;<br><br>Slant height is the perpendicular height of the side triangles, perpendicular height is from the vertex(tip of pyramid) to the base.<br><br>The volume of a pyramid is one-third of a cube you just need to find the area of a cube then divide by three.<br><br>Find the area of the triangle(lxbxh) and the square(lxb or lxl). You need to take note of the base.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 02:54:45 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178665301</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178681222</link>
         <description><![CDATA[<div><br><br>pyramid is made of rectangle and triangles.<br><br>to find volume of pyramid 1/3 x base area x height.<br><br>total surface of pyramid triangles + base area (slanted height)<br><br><br><br><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 03:07:13 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178681222</guid>
      </item>
      <item>
         <title>Pyramid</title>
         <author>moham5447f</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178681592</link>
         <description><![CDATA[<div>Sides of pyramid are triangle</div><div>&nbsp;<br>Slant height is perpendicular height of triangle by the sides<br><br></div><div>Perpendicular height is from a vortex to the Center of the pyramid<br><br>1/3*base area*height</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 03:07:31 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178681592</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178682879</link>
         <description><![CDATA[<div>1/3 x base area x height&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 03:08:35 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178682879</guid>
      </item>
      <item>
         <title>6.1 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178685844</link>
         <description><![CDATA[<div>Triangle,square,hexagon,rectangle&nbsp;<br><br>From the vertex from the middle is the perpendicular height is form the tip of the vertex of the Center of the base<br><br>1/3 x base x height&nbsp;<br>Total of the surface area is base x height x the slant height then u get the answer and u need to find the base of the area .</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 03:11:03 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178685844</guid>
      </item>
      <item>
         <title>6.1 </title>
         <author>muhammad_haiziq_sufian</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178686425</link>
         <description><![CDATA[<div>Pyramid are made out of mostly triangle but the base area the pyramid can be n-sided,closed shape or any other shape but not any circle like shapes&nbsp;<br><br></div><ul><li>Slant height is the perpendicular height of the triangles by the video&nbsp;</li><li>Perpendicular height is from the vertex to the Center of the base of the pyramid</li></ul><div>We will use the vector as it always in the Center of the pyramid and the formula i am using 1/3 x base area x height&nbsp;<br><br>&nbsp;I will use the vector for the height and the formula is to find all area of every shape in the pyramid then pus them all together and to note base area of the pyramid&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 03:11:31 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178686425</guid>
      </item>
      <item>
         <title>6.1</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178711396</link>
         <description><![CDATA[<div>Pyramids are made up of squares, triangles and rectangles.<br>The <strong>base</strong> of the pyramid must be a polygon.<br><br><strong>Slant height</strong> is the perpendicular height of triangles by the side.<br><br><strong>Perpendicular height</strong> is from the vertex(tip of pyramid) to the centre of the base of the pyramid.<br><br><strong>Volume</strong> of pyramid 1/3 x base area x height<br><br><strong>Total surface</strong> <strong>Area </strong>depends on the base shape FORMULA: area of triangle+base area (slanted height)</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-11 03:32:53 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2178711396</guid>
      </item>
      <item>
         <title>6.2: Cones</title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2180310853</link>
         <description><![CDATA[<div>Complete SLS Assignment for 17 May RHBL.<br><br>Go to the Math Website and look through all the videos on Chp 6.2:<br><br><strong>Pre-Lesson Objective:</strong></div><ul><li>Derive the formula to find volume of cone.</li><li>Derive the formula to find surface area of cone.</li><li>Complete Workbook 3B Activity 2 pg 9.<br>Post the page up onto Padlet by 17 May.</li></ul><div><br>Post any questions that you may have on Padlet by 17 May.<br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-12 00:51:40 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2180310853</guid>
      </item>
      <item>
         <title>6.1 </title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2187225680</link>
         <description><![CDATA[<div>Pyramids are made up of triangles, rectangles and squares&nbsp;<br>Slant height is&nbsp; the height of triangles by the side&nbsp;<br>Perpendicular height is the vertex (tip of the pyramid) to the centre of the base of the pyramid&nbsp;<br>Volume of the pyramid is 1/3 x base area x height&nbsp;<br>Total surface area depends on the base shape Formula is area of  the triangle + base area (slanted height) </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-17 08:25:37 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2187225680</guid>
      </item>
      <item>
         <title>6.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190462178</link>
         <description><![CDATA[<div>1. sector<br>2. 1/3π²h<br>3. πr²<br>4. πr</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-19 02:00:13 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190462178</guid>
      </item>
      <item>
         <title>6.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190467015</link>
         <description><![CDATA[<div>1.sector<br>2.1/3pie2h<br>3.pie2<br>4.pie r l</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-19 02:03:18 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190467015</guid>
      </item>
      <item>
         <title>6.2</title>
         <author>assyahqirin</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190467685</link>
         <description><![CDATA[<div>1. sector<br>2. 1/3 x base area x height&nbsp;<br>3. &nbsp;pie r square&nbsp;<br>4. pie r l</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-19 02:03:45 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190467685</guid>
      </item>
      <item>
         <title>6.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190467972</link>
         <description><![CDATA[<div>1. What is the shape of a cone?<br>Ans: sector<br><br>2. What is the formula to find volume of cone?<br>Ans: 1/3xbase area x height&nbsp;<br><br>3.&nbsp; What is the base area of a cone?<br>Ans: pie x r x r<br><br>4. What is the formula to find curved surface area of cone?<br>Ans: pie x r x l</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-19 02:03:56 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190467972</guid>
      </item>
      <item>
         <title>6.2</title>
         <author>joytham161</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190468010</link>
         <description><![CDATA[<div>1. What is the shape/net of a cone?<br>&nbsp; &nbsp; - Sector<br>2. What is the formula to find the volume of cone?<br>&nbsp; &nbsp;- 1/3 x base area x height<br><br>3. What is the base area of a cone?<br>&nbsp; &nbsp; - pie r square<br><br>4. What is the formula to find curved surface area of cone?</div><div>&nbsp; &nbsp; - pie r l&nbsp;</div><div><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-19 02:03:58 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190468010</guid>
      </item>
      <item>
         <title>6.2 </title>
         <author>cheeqh2007</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190471318</link>
         <description><![CDATA[<div>1. Sector&nbsp;<br>2. 1/3 x Base Area x Height&nbsp;<br>3. Pie r square&nbsp;<br>4. Pie x r x l&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-19 02:06:06 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190471318</guid>
      </item>
      <item>
         <title>6.2 Cones</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190480159</link>
         <description><![CDATA[<div>1. the shape of a cone is made out of sector<br><br>2. 1/3 x height x pie x r to the power of 2<br><br>3. circle<br><br>4. pie r l</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-19 02:11:41 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190480159</guid>
      </item>
      <item>
         <title>6.2 cones</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190481008</link>
         <description><![CDATA[<div>1. the shape of a cone is made out of sector<br><br>2. 1/3 x height x pie x r to the power of 2<br><br>3. circle<br><br>4. pie r l</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-19 02:12:14 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190481008</guid>
      </item>
      <item>
         <title>6.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190491585</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://padlet-uploads.storage.googleapis.com/1705874088/94c41fff0b89682d9ecef113ec1c3699/image.jpg" />
         <pubDate>2022-05-19 02:18:57 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190491585</guid>
      </item>
      <item>
         <title>6.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190498848</link>
         <description><![CDATA[<div>1)What is the shape net of the cone=sector,radius connect to form cone<br>2)1/3xBase areaxhight<br>3) pie r 2<br>4)pie xRxL</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-19 02:23:33 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190498848</guid>
      </item>
      <item>
         <title>6.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190499306</link>
         <description><![CDATA[<div>1. What is the shape/net of a cone?<br>- Sector<br><br>2. What is the formula for the volume of the cone?<br>- 1/3 x ( pi x r square ) x height<br><br>3. What is the base area of a cone?<br>- Circle<br><br>4. What is the formula to find curved surface area of the cone?<br>- ( pi x r x l )</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-19 02:23:53 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190499306</guid>
      </item>
      <item>
         <title>6.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190499319</link>
         <description><![CDATA[<div>1. What is the shape/net of a cone?<br>-sector,radius connect to form cone&nbsp;<br><br>2. What is the formula to find volume of cone?<br>-1/3 x pie r2x height&nbsp;<br><br>3. What is the base area of a cone?<br>-pie r square&nbsp;<br>-circle<br><br>4. What is the formula to find curved surface area of cone&nbsp;<br>-pie r L</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-19 02:23:54 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190499319</guid>
      </item>
      <item>
         <title>6.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190503087</link>
         <description><![CDATA[<div>1. What is the shape/net of a cone?<br>- Sector<br><br>2. What is the formula for the volume of the cone?<br>- 1/3 x ( pi x r square ) x height<br><br>3. What is the base area of a cone?<br>- Circle<br><br>4. What is the formula to find curved surface area of the cone?<br>- ( pi x r x l )</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-19 02:26:27 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2190503087</guid>
      </item>
      <item>
         <title>4.3</title>
         <author>hillgrovepoa</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2198916648</link>
         <description><![CDATA[<div>I know to change subject of formula, i must make sure letter is on one side and satisfy the 5 conditions.&nbsp; Alone, positive, coefficient 1, numerator and power 1.&nbsp;<br><br>Sign must be opposite sign when we change the sides.&nbsp; Eg: LHS add, move to RHS minus<br><br>Opposite sign<br>multiply and divide<br>add and subtract<br>square and square root<br>cube and cube root.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-25 06:38:26 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2198916648</guid>
      </item>
      <item>
         <title>6.2</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2235060056</link>
         <description><![CDATA[<div>1. What is the shape/net of a cone?<br>- Sector<br><br>2. What is the formula for the volume of the cone?<br>- 1/3 x ( pi x r square ) x height<br><br>3. What is the base area of a cone?<br>- Circle<br><br>4. What is the formula to find curved surface area of the cone?<br>- ( pi x r x l )</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-07-01 11:25:27 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2235060056</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2258728158</link>
         <description><![CDATA[<div>I&nbsp;was very careless with my questions and never read prop</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-08-11 03:40:18 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2258728158</guid>
      </item>
      <item>
         <title>Anish</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2258740043</link>
         <description><![CDATA[<div>I make a lot of careless mistakes and the questions were hard to understand and I got the formulas right but just missed the ^2&nbsp;<br><br>Q1: the question was hard to understand and I forgot how to do<br><br>2bii: I accidentally plus 3 cause I thought I needed to&nbsp;<br><br>3D: I mixed up the formulas and divided by 2 instead of 10<br><br>4a I calculated 4 sides instead of 5&nbsp;<br><br>5a&amp;b: I forgot the formulas&nbsp;<br><br>5c I calculated area not TSA&nbsp;<br><br>6B,C,D: I did not understand the questions and forgot the formulas&nbsp; &nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-08-11 03:47:29 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2258740043</guid>
      </item>
      <item>
         <title>T3 WA</title>
         <author></author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2258746281</link>
         <description><![CDATA[<div>Q1) I got it wrong because I forgot to put the pie beside 196<br>I will learn from this by being more careful and double checking my work<br><br>Q3c) I got it wrong because I didn’t take the two middle positions add them together and divide them by 2<br><br>Q4a,b,c) I got it wrong as I used the wrong height and tried to find base area when it was already given and I forgot to cube root<br>I will learn from this by practicing questions that are similar to this<br><br>Q5a,b,c) I got it wrong as I forgot the formula for c.s.a and used the wrong number for Pythagoras therym and used the wrong formula to find the volume<br>I will learn from this by doing 5 questions a day that requires the formula so that I can remember it<br><br>Q6b,d) I did not use the Calculator value and forgot the formula to find the paint required to paint tree blades&nbsp;<br>I will learn from this by being more careful and looking through my work clearly <br><br><br>I will learn from my mistakes by revising more and practicing questions so that I will not make the same mistake in the future &nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-08-11 03:51:18 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2258746281</guid>
      </item>
      <item>
         <title></title>
         <author>kesyeozy</author>
         <link>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2258763491</link>
         <description><![CDATA[<div>I had a lot of careless mistakes<br><br>Q1) I put cube instead of square&nbsp;<br><br>Q3c and d) I calculate wrongly<br><br>Q4c) I put the wrong number&nbsp;<br><br>Q5) I make a a lot of careless mistake&nbsp;<br><br>Q6) careless</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-08-11 04:03:50 UTC</pubDate>
         <guid>https://padlet.com/hillgrovepoa/34MAFCLR/wish/2258763491</guid>
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