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      <title>Soy un experto  3 - 4A by </title>
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      <description>Sube tu solución a este mural.</description>
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      <pubDate>2020-07-15 03:14:16 UTC</pubDate>
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         <title></title>
         <author>rosaguerra1</author>
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         <title>Adrian</title>
         <author>62604603</author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655296368</link>
         <description><![CDATA[<div>1=2/2 +1 /2  = 3/2<br>3/2 = 6/4<br>6/4 - 3/4= 3/4<br>queda 3/4<br><br></div>]]></description>
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         <pubDate>2020-07-15 17:13:17 UTC</pubDate>
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         <title>Valeria</title>
         <author>Valeria241010</author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655329955</link>
         <description><![CDATA[<div>1=2/2 +1 /2  = 3/2<br>3/2 = 6/4<br>6/4 - 3/4= 3/4<br>En la bolsa queda 3/4</div>]]></description>
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         <pubDate>2020-07-15 17:56:35 UTC</pubDate>
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         <title></title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655331997</link>
         <description><![CDATA[<div>Joaquín Alonso<br><br><br>1 1/2 = 6/4<br><br>6/4 - 3/4 = 3/4</div>]]></description>
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         <pubDate>2020-07-15 17:59:20 UTC</pubDate>
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         <title></title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655332356</link>
         <description><![CDATA[<div>Quedan 3/4</div>]]></description>
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         <pubDate>2020-07-15 17:59:45 UTC</pubDate>
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         <title></title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655332638</link>
         <description><![CDATA[1m]]></description>
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         <pubDate>2020-07-15 18:00:07 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655332638</guid>
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      <item>
         <title>leonardo</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655332725</link>
         <description><![CDATA[<div>1=2/2+1/2=3/2=6/4<br>6/4 - 3/4= 3/4  EN la bolsa queda 3/4</div>]]></description>
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         <pubDate>2020-07-15 18:00:15 UTC</pubDate>
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         <title>Dara</title>
         <author>62608946</author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655391063</link>
         <description><![CDATA[<div>3/2-3/4<br>6/4-3/4= 3/4<br>Quedan 3/4 en la bolsa</div>]]></description>
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         <pubDate>2020-07-15 19:20:00 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655391063</guid>
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         <title>Rafael</title>
         <author>76113455</author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655392141</link>
         <description><![CDATA[<div>1=2/2 +1 /2  = 3/2<br>3/2 = 6/4<br>6/4 - 3/4= 3/4<br>En la bolsa queda 3/4<br><br></div>]]></description>
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         <pubDate>2020-07-15 19:21:33 UTC</pubDate>
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         <title>Juan de Dios</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655460782</link>
         <description><![CDATA[<div>1 x 1/2 =3/2 x2 = 6/4 — 3/4= 3/4<br>Queda 3/4 de kilos de azucar</div>]]></description>
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         <pubDate>2020-07-15 21:06:54 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655460782</guid>
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      <item>
         <title>queda 3/4</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655504553</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-07-15 22:30:11 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655504553</guid>
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      <item>
         <title>Flavia Asmat Tafur</title>
         <author>75648974</author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655510742</link>
         <description><![CDATA[<div><br>Azúcar= 1 1/2 Kg.<br>saca para un postre 3/4 de azúcar<br><br>1 1/2 = 3/2 = 6/4 (se multiplica x2 el numerador y el denominador para buscar la fracción equivalente)<br>6/4 - 3/4 = 3/4<br>Rpta: Le queda en la bolsa 3/4 kg de azúcar.</div>]]></description>
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         <pubDate>2020-07-15 22:43:34 UTC</pubDate>
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         <title>Víctor</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655576424</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-07-16 00:46:32 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655576424</guid>
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      <item>
         <title>Mariana</title>
         <author>74332349</author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655577241</link>
         <description><![CDATA[<div>respuesta : 3/4</div>]]></description>
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         <pubDate>2020-07-16 00:47:55 UTC</pubDate>
         <guid>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655577241</guid>
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         <title>Daira Paola</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655577574</link>
         <description><![CDATA[<div>Quedan 3/4  de azúcar en la  bolsa.                                                                                                                                                                                    </div>]]></description>
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         <pubDate>2020-07-16 00:48:25 UTC</pubDate>
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      <item>
         <title>Rodrigo Sánchez</title>
         <author>62499758</author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655641370</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-07-16 02:21:49 UTC</pubDate>
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      <item>
         <title>Ángel</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/655661796</link>
         <description><![CDATA[<div>1= 2/2 + 1/2 = 3/2<br>3/2 = 6/4<br>6/4 - 3/4 = 3/4<br>Quedan  3/4 e la bolsa.</div>]]></description>
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         <pubDate>2020-07-16 02:51:04 UTC</pubDate>
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         <title>Alessandra</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/656397835</link>
         <description><![CDATA[<div>Le queda en la bolsa 3/4 de kilogramos de  azúcar.</div>]]></description>
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         <pubDate>2020-07-16 22:00:05 UTC</pubDate>
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         <title>Daira Chavez</title>
         <author></author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/656419700</link>
         <description><![CDATA[<div>1  1/2= 3/2 (se multiplica x2 el numerador y el denominador para buscar la fracción equivalente)=<br>6/4<br>6/4 -3/4 = 3/4 entonces le queda en la bolsa 3/4 kg de azucar </div>]]></description>
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         <pubDate>2020-07-16 22:46:33 UTC</pubDate>
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         <title></title>
         <author>62559425</author>
         <link>https://padlet.com/rosaguerra1/m47m93cqtm2rhnnz/wish/657817475</link>
         <description><![CDATA[<div>SACA 3/4</div>]]></description>
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         <pubDate>2020-07-19 17:35:38 UTC</pubDate>
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         <title></title>
         <author></author>
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         <description><![CDATA[<div>PADME LUANNA</div>]]></description>
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         <pubDate>2020-07-19 18:38:32 UTC</pubDate>
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