The reactions are REDOX: Justify using the strategy of loss and gain of electrons by Subhoshree Chatterjee https://padlet.com/subhoshree15/2021Grade9B Hydrogen Revision en-us 2021-09-08 09:43:06 UTC 2025-11-23 02:25:04 UTC hello@padlet.com room 1 https://padlet.com/subhoshree15/2021Grade9B/wish/1726921685 Cu2+SO42-      +    Zn    ----> Zn2+SO42-      +     Cu

Zn(s)+CuSO4(aq)→ZnSO4(aq)+Cu(s)
 
oxidation: ZnSO4(aq)                                         
reduction: Cu(s)

]]> 2021-09-09 04:11:19 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726921685 Kavin Upreti(Room 2) kavinmanas https://padlet.com/subhoshree15/2021Grade9B/wish/1726926514 Zn+2 O-2 + CO ---> Zn+CO2

Zn is getting reduced from Zn+2 to Zn0, which means 2 electrons are added to it.

C is getting oxidized from C-2 to C+4, which means we remove 6 electrons from it.


]]> 2021-09-09 04:13:13 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726926514 Riya (Group 4) https://padlet.com/subhoshree15/2021Grade9B/wish/1726927734 CuSO4 + Zn ----> ZnSO4 + Cu

Cu^+2 (SO4)^-2 + Zn^0 ----> Zn^+2 (SO4)^-2 + Cu^0

Half reaction:

Cu^+2 +2e- ----> Cu^0 (GER - Reduction)
Zn^0 - 2e- ------> Zn^+2 ( LEO - Oxidation)

Oxidizing agent : CuSO4
Reducing Agent: Zn]]> 2021-09-09 04:13:45 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726927734 Krrish Deokar(Group 3) krrishdeokarwebsites https://padlet.com/subhoshree15/2021Grade9B/wish/1726928760 Step 1: Balanced equation
Step 2: It is redox as
Cu0 - 2e = Cu2+(Oxidation)
Cu2+ 2e = Cu(Reduction)
Zn0 - 2e = Zn2+(Oxidation)
Zn2+ + 2e= Zn(Reduction)

OA ---> CuSO4
RA ---> Zn]]> 2021-09-09 04:14:16 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726928760 Group 4 (Sonia) jainsonia289 https://padlet.com/subhoshree15/2021Grade9B/wish/1726932127 Given Equation:
ZnO + CO --> Zn + CO2

Ionic Equation:
Zn+2 O-2 + C+2 O-2 --> Zn0 + C+4 O-2

Half Reactions
Zn+2 + 2e- --> Zn0  (RA - gain of electrons)
C+2 - 2e- --> C+4      (OA - loss of electrons)

Oxidising agent --> ZnO
Reducing agent --> CO

Since oxidation and reduction is taking place simultaneously, the given equation is a redox reaction.]]> 2021-09-09 04:15:47 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726932127 Navya M Grp4 https://padlet.com/subhoshree15/2021Grade9B/wish/1726933824 S0 - 4e- ---> S4+ (oxidation half-reaction)
O + 2e- ---> O2- (reduction half-reaction)
2O0 + 4e- ---> 2O2-
S0 + O2- ---> S4+ 2O2- ]]> 2021-09-09 04:16:30 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726933824 Room 1 https://padlet.com/subhoshree15/2021Grade9B/wish/1726937226 Zn + 2 O -2  + C-2 O-2 ---> Zn + 0 + C+ 4  O2

ZnO is getting reduced
CO is getting oxidised 
CO is reducing agent 
ZnO is oxidising agent 


]]> 2021-09-09 04:18:05 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726937226 room 1 ericsohal2006 https://padlet.com/subhoshree15/2021Grade9B/wish/1726937670 2 NH3 (g) + 3 Cl2 (g) → N2 (g) + 6 HCl (g)
This is an oxidation-reduction (redox) reaction:

6 Cl0 + 6 e- → 6 Cl-1 (reduction)

2 N-3 - 6 e- → 2 N0 (oxidation)


]]> 2021-09-09 04:18:19 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726937670 Room 3 (Avni Verma) https://padlet.com/subhoshree15/2021Grade9B/wish/1726938253 ZnO is losing oxygen hence it is being reduced. CO is being oxidized by accepting oxygen to form CO2. 

Half reactions 
Zn-2+ 2e--->Zn0
C-2+ 2e---->C+4

the oxidizing agent is ZnO and the reducing agent is CO

THE FOLLOWING CAN BE CALLED A REDOX REACTION AS SiIMULTANEOUSLY BOTH OXIDATION AND REDUCTION IS TAKING PLACE.
Hence, justified. 

]]> 2021-09-09 04:18:34 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726938253 Mahir (Room 2) https://padlet.com/subhoshree15/2021Grade9B/wish/1726938414 -(Cu)+2 (So4)-2   +   (Zn)0 ------> (Zn)+2 (SO4)-2 + (Cu)0

-Cu+2 +2e- -----> Cu0 [Reduction]
-Zn0 -2e- ------> Zn+2 [Oxidation]

Oxidizing Agent: CuSO4
Reducing Agent: Zn]]> 2021-09-09 04:18:39 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726938414 Group 3 - Anika agrnika211 https://padlet.com/subhoshree15/2021Grade9B/wish/1726940858 S0 + 2O0 -----> S+4  2O-2

Half Reactions:
S0 - 4e- -----> S+4
O0 + 2e- ------> O-2
2O0 + 4e- ------> 2O-2

Sulphur is getting oxidised while, oxygen is getting reduced hence,
OA = O2      RA = S 

Thus, this reaction is redox. ]]> 2021-09-09 04:19:48 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726940858 Group 4(Vedangi) https://padlet.com/subhoshree15/2021Grade9B/wish/1726941990 2 NH3  + 3 Cl2 -------> N2 + 6 HCl

6 Cl0 + 6 e- --------> 6 Cl-1
(reduction)
2 N-3 - 6 e- -------->  2 N0 
(oxidization)

]]> 2021-09-09 04:20:19 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726941990 group 4 - shaan https://padlet.com/subhoshree15/2021Grade9B/wish/1726944284 Zn+2HCl ---> ZnCl2+H2

Zn=Zn
H - 2e-=H2
Cl - 2e-=Cl2

this is a oxidation reaction as hydrogen is being removed from chlorine 

OA= HCl
RA= Zn

]]> 2021-09-09 04:21:22 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726944284 Group 2 Antranig pathakantranig https://padlet.com/subhoshree15/2021Grade9B/wish/1726945326 S - 4e- ----> S4+
O +2e- ----> O2-
20 + 4e- ----> (O2) -4
Oxygen is getting reduced
Sulphur is getting Oxidised
Reducing Agent - Sulphur
Oxidising Agent - Oxygen
Hence, this is a Redox



]]> 2021-09-09 04:21:52 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726945326 https://padlet.com/subhoshree15/2021Grade9B/wish/1726948308 2 NH3 + 3 Cl2 → N2 + 6 HCl
This is an oxidation-reduction reaction:

6 Cl0 + 6 e- → 6 Cl-1 reduction

2 N-3 - 6 e- → 2 N0 - oxidiation

]]> 2021-09-09 04:23:17 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726948308 Aashman Grewal (group 2 ) aashmangrewal https://padlet.com/subhoshree15/2021Grade9B/wish/1726950381 2021-09-09 04:24:13 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726950381 Shlok Vira (Grp 1) https://padlet.com/subhoshree15/2021Grade9B/wish/1726955803 Zn+HCl-->ZnCl2+H2

Ionic equation: Zn0+H+1 Cl-1--> Zn2 Cl-1+H2 0
Zn is getting reduced as it is gaining  a Chlorine. 
HCl is getting oxidized as it is losing Hydrogen ]]> 2021-09-09 04:26:43 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726955803 Group1 https://padlet.com/subhoshree15/2021Grade9B/wish/1726956286 Sulphur is getting oxidised as there is an addition of oxygen atoms and oxygen is getting reduced as there is an addition of electronegative ion.
Oxidising agent is O2(Oxygen) and Reducing agent is S(Sulphur)]]> 2021-09-09 04:26:57 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726956286 Utsang(ROOM 4) UtsangSinha https://padlet.com/subhoshree15/2021Grade9B/wish/1726959164 S0 + O20-->S4 + O22-
Sulphur is being oxidized by oxygen. (LEO)
Oxygen is being reduced.  (GEO)
S0 - 4e- --> S4 (GEO)
O0 +2e- --> O22-(LEO)
Reducing agent: Sulphur
Oxidizing agent: Oxygen


]]> 2021-09-09 04:28:16 UTC https://padlet.com/subhoshree15/2021Grade9B/wish/1726959164