https://padlet.com/ekstrandn1727/ln6w9go7oina By: Natalie Ekstrand P. 7 en-us 2017-03-07 01:41:44 UTC 2025-12-10 12:58:23 UTC hello@padlet.com ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158217668 2017-03-07 01:46:27 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158217668 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158219108 1. Draw a line from the center point to point A and extend the line
2. Measure the line of the center point and A and cope the length so that it will be congruent to AA'
3. Repeat for points B and C]]> 2017-03-07 01:58:57 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158219108 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158219757 If the scale factor was 3 then you would copy the length 2 times instead of one for a scale of 2. ]]> 2017-03-07 02:04:42 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158219757 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158220285 -Using Proportional Sides (similar figures)
-Pythagorean Theorem (a^2+b^2=c^2)]]> 2017-03-07 02:11:11 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158220285 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158220439 Look for: 
-Supplementary (180)
-Complementary (90)
Corresponding (congruent)
-Alt Int angles (congruent)
-Same side int. (180)
-Vertical (congruent)
-180 in a triangle 
-360 in a quadrilateral ]]> 2017-03-07 02:13:01 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158220439 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158221659 2017-03-07 02:27:26 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158221659 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158222245 A point in the middle ]]> 2017-03-07 02:34:04 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158222245 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158222287 (x1+x2/2, y1+y2/2)
It's purpose is to determine the middle between two sets of points ]]> 2017-03-07 02:34:34 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158222287 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158222532 2017-03-07 02:37:23 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158222532 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158223481 Sin= opposite/hypotenuse 
cos=adjacent/hypotenuse 
Tan=opposite/adjacent ]]> 2017-03-07 02:46:14 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158223481 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158224197 Trigonometry are just ratios of similar triangles. They can help you solve missing info in right triangles. You need either: side+angle to get a side
side+side to get and angle ]]> 2017-03-07 02:53:27 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158224197 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158224435 the longest side of a right triangle, opposite the right angle]]> 2017-03-07 02:56:25 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158224435 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158224541 next to a given angle]]> 2017-03-07 02:56:47 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158224541 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158224683 the one across from a given angle]]> 2017-03-07 02:58:29 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158224683 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158231008 https://www.youtube.com/watch?v=O74LFU4VmlE
In this video, he uses the acronym SohCahToa and explains how to label a right triangle. He also goes through a sample problem and solves. At the end, he also covers some concepts that we have not yet covered in class, but it is a basic video. ]]> 2017-03-07 04:04:48 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158231008 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158232306 A new concept we learned this module, was separating one triangle into three. There would be a small, medium, and large triangle. We would be given some sides on each triangle, and using proportions we would have to find the remaining unknown sides. All three triangles would be similar, thus making the use of proportions an easy way to find the side lengths ]]> 2017-03-07 04:22:11 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158232306 ekstrandn1727 https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158232849 Find the midpoint:
(-7,14) (15,9)
-7+15/2 = 8/2= 4 
14+9/2= 23/2= 11.5 
Answer: (4,11.5)]]> 2017-03-07 04:31:16 UTC https://padlet.com/ekstrandn1727/ln6w9go7oina/wish/158232849