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      <title>Cálculo Integral by JEFFRY  ESPINAL VALLE</title>
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      <description>Ejercicios de aplicaciones de la integral</description>
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      <pubDate>2022-04-26 04:13:29 UTC</pubDate>
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         <title>Ejercicio #18</title>
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         <pubDate>2022-04-26 04:43:26 UTC</pubDate>
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         <pubDate>2022-04-26 04:48:29 UTC</pubDate>
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         <title>Ejercicio #24</title>
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         <title>Ejercicio #40</title>
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         <pubDate>2022-04-27 06:00:01 UTC</pubDate>
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         <pubDate>2022-04-27 06:01:38 UTC</pubDate>
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         <title>Área de la región acotada entre dos gráficas </title>
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         <pubDate>2022-04-27 06:04:23 UTC</pubDate>
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         <pubDate>2022-04-27 06:37:14 UTC</pubDate>
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         <title>Ejercicio #32</title>
         <author>johelgarcia</author>
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         <description><![CDATA[<div><br></div><div><br></div><div><br></div><div><br></div><div><br></div>]]></description>
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         <pubDate>2022-04-27 15:23:06 UTC</pubDate>
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         <title>Movimiento Rectilíneo</title>
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         <pubDate>2022-04-27 16:57:06 UTC</pubDate>
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         <title>Trabajo Colaborativo Unidad IV</title>
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         <title>Ejercicio N°6</title>
         <author>dcpaz</author>
         <link>https://padlet.com/jeffryespinal/lbo8dk50xdee9gpx/wish/2161383861</link>
         <description><![CDATA[<div>f(y) = y^2 +1, Eje y, (-1,2)<br>A=&nbsp; = ∫2, -1 | y^2 +1| dy<br>&nbsp;∫ 2, -1 y^2 +1 dy<br>&nbsp;∫ y^2 dy +&nbsp; ∫ 1dx<br>|y^3/3 +y| x=2, x=-1<br>2^3/3 +2 (-1^3/3(-1))<br>=6<br><br></div>]]></description>
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         <pubDate>2022-04-28 02:06:09 UTC</pubDate>
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         <title>Ejercicio N°15 </title>
         <author>dcpaz</author>
         <link>https://padlet.com/jeffryespinal/lbo8dk50xdee9gpx/wish/2161392847</link>
         <description><![CDATA[<div>y= 5-x, y= 1/2x^2 -2x +1&nbsp;<br>5-x = 1/2x^2 -2x +1<br>5-x - 1/2x^2 + 2x -1 =0<br>1/2x^2 + x + 4=0<br>2(1/2x^2 + x^2 +4 = (2)0<br>-2x 1/2x^2 + 2x + (2) 4=0&nbsp;<br>x^2 + 2x + 8 =0&nbsp;<br>(-1) -x^2(-1)2x(-1)8 =0<br>x^2 + 2x - 8 =0<br>x(x+2)- 4(x + 2)=0<br>(x+2)&nbsp; (x-4) = 0<br>x + 2 = 0 &nbsp; x - 4 = 0<br>x= -2&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; x=4<br>&nbsp;• ∫ 5 − 𝑥 𝑑𝑥&nbsp;<br>&nbsp;∫ 5 𝑑𝑥 ∫ 𝑥 𝑑x&nbsp;<br>5x - x^2/2 = 5x - x^2/2 + C, CER<br>&nbsp;• ∫ 1 2 𝑥 2 − 2𝑥 + 1 𝑑x<br>&nbsp;∫ 1 2 𝑥 2𝑑𝑥 − ∫ 2𝑥 𝑑𝑥 + ∫ 1 𝑑x&nbsp;<br>x^3/6 - x^2 + x, x^3/6 - x^2 + x +C, CER</div>]]></description>
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         <pubDate>2022-04-28 02:13:31 UTC</pubDate>
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