Surface area - Cuboid and cube by https://padlet.com/lathajoy68/l137uopswr40 Made with a wink and a smile en-us 2017-09-24 06:19:09 UTC 2023-03-15 02:22:25 UTC hello@padlet.com GROUP 1 Qn5. A cubical box has each edge 10cm and another cuboidal box has 12 cm long 10cm wide and 8 cm high. Which box has the greater lateral surface area and by how much? lathajoy68 https://padlet.com/lathajoy68/l137uopswr40/wish/607657760




]]> 2020-06-02 20:27:22 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/607657760 GROUP 2 lathajoy68 https://padlet.com/lathajoy68/l137uopswr40/wish/607659532 Qn 2. 
The length, breadth and height of a room are 5m,4m and 3m respectively. Find the cost of white washing the walls of the room and the ceiling at the rate of  AED 7.50 per m2
]]> 2020-06-02 20:28:36 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/607659532 GROUP 3 lathajoy68 https://padlet.com/lathajoy68/l137uopswr40/wish/607661117 Qn 3. 
The floor of a rectangular hall has a perimeter 250 m.If the cost of painting the four walls at the rate of AED 10  per m2 is AED 15000, find the height of the hall.
]]> 2020-06-02 20:29:48 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/607661117 Abhishek Biju (grp 1) abhijitbiju3210 https://padlet.com/lathajoy68/l137uopswr40/wish/608536144 LSA of Cube :-  4a^2
                       = 4 x 10 ^2
                       = 4 x 100
                       = 400 cm^2
LSA of Cuboid :- 2 (lh + bh)
                        = 2 ( 12x8 + 10x8 )
                        = 2 ( 96 + 80)
                        =  2 x (176)
                        = 352 cm^2

Therefore the cube has more LSA than the Cuboid by 48cm^2 .]]> 2020-06-03 09:41:26 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608536144 GROUP 2 https://padlet.com/lathajoy68/l137uopswr40/wish/608537353 2020-06-03 09:42:04 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608537353 Correct Answer for Group 3 https://padlet.com/lathajoy68/l137uopswr40/wish/608538280 Perimeter: 250 m
lateral surface area: 2h (l + b)
= 250 h
Cost of painting: 10 x 250h
Cost of painting= 2500h 
2500h = 15000
h= 15000/2500
h = 6 metres

- BY: Group 3 Leader - Dalvin Thomas]]> 2020-06-03 09:42:36 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608538280 Steve sumesh paul ( group 3) stevesumeshpaul2005 https://padlet.com/lathajoy68/l137uopswr40/wish/608540063 Lateral surface area = 2 x height (length + wide)
perimeter = 2( length + width)
length + wide = 125
area costing of 
lateral surface are painting = 15000/10=1500
m^2

height =1500/250=6 m 

]]> 2020-06-03 09:43:41 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608540063 Group-2 https://padlet.com/lathajoy68/l137uopswr40/wish/608542675 Length=5m
Breadth=4m
Height=3m
Rate of whitewash=7.50AED per m²
LSA+l*b=4 walls of the room+ceiling.
LSA+l*b=2*(l+b)h+l*b
=2*(5+4)*3+5*4
=2*9*3+20
=54+20
=74m
LSA+l*b=74m²
74*7.50AED=Price of whitewashing.
=555AED for whitewshing all four walls+celing.

Answer=555AED for whitewshing all four walls+celing.
]]> 2020-06-03 09:45:05 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608542675 Shreyansh sharma https://padlet.com/lathajoy68/l137uopswr40/wish/608544230

The L.S.A. of the cube is 400 cm² 
The L.S.A. of the cuboid is 352 cm²
Therefore the L.S.A. of the cube is 48 cm²cm bigger than the cuboid

The calculations 
L.S.A. OF THE CUBE =4 × a²
=4×10×10=400
L.S.A. of the cuboid = 2( l+b ) h 
=2 (12+10) 8
= 44 × 8 = 352]]> 2020-06-03 09:45:52 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608544230 Shaikh Mohammed Rehan (Grp 1) https://padlet.com/lathajoy68/l137uopswr40/wish/608545017 LSA of cube = 400
LSA of cuboid = 352

Therefore LSA of cube is greater by 48 cm]]> 2020-06-03 09:46:18 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608545017 Group 3 FAZLU https://padlet.com/lathajoy68/l137uopswr40/wish/608545472 2020-06-03 09:46:36 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608545472 Humaid Khan group 1 https://padlet.com/lathajoy68/l137uopswr40/wish/608545605 L.S.A of cube=4a² =4x(10)² =400cm² L.S.A if cuboid=2(l+b)h =2x(12+10)x8 =360cm² => L.S.A of cube >L.S.A of cuboid by 40cm²]]> 2020-06-03 09:46:40 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608545605 Nevin group 1 https://padlet.com/lathajoy68/l137uopswr40/wish/608545786
CUBE

LSA 4a^2
40cm^2
400cm

CUBOID

LSA 2(l+b)h
2(12+10)8
44×8
352cm

Therefore cube has a larger LSA of 400cm]]> 2020-06-03 09:46:47 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608545786 Group 1 Mohammed Owais Qadri https://padlet.com/lathajoy68/l137uopswr40/wish/608547560 The cube box with each edge 10 cm wide has more LSA than the other cuboidal box.
LSA OF CUBE = 400
LSA OF CUBOID = 384



]]> 2020-06-03 09:47:33 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608547560 Joy Rai (Group 1) https://padlet.com/lathajoy68/l137uopswr40/wish/608548550 L.S.A
Cube= 4 x (10)^2
          = 4 x 100
          = 400m^2

Cuboid= 2 (12 + 10) x 8
             = 44 x 8
             =  352m^2

= The cube has the greater lateral surface by 48m
                            

]]> 2020-06-03 09:48:05 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608548550 9m group 3 https://padlet.com/lathajoy68/l137uopswr40/wish/608549435 naeem,dalvin,shivadatt,alan,
aidan, aadhi,athul,joseph,
joshua ,mithun,noel,steve , fazalu .
Area of four walls = 2lh + 2bh = 2(l + b) h
Perimeter of the floor of hall = 2(l + b)
Perimeter of the floor of hall = 250 m
Therefore, 2(l + b) = 250 mPutting this value in the formula of Area of four walls we get,
Area of four walls = 2(l + b) h
Area of four walls = 250h m2
Cost of painting per m2 area = Rs 10
Cost of painting 250h m2 area = Rs (250h × 10)
= Rs 2500h
However, it is given that the cost of painting the walls is Rs 15000
15000 = 2500h
1500/2500
150/250
h=6

]]> 2020-06-03 09:48:22 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608549435 Group 3 (Mithun Vinod) https://padlet.com/lathajoy68/l137uopswr40/wish/608550155 Perimeter of rectangle =2(l+b)
2(l+b)=250
L+b=125
LSA of cuboid =2h(125)=250h
Cost =15000/10
Cost =1500
250h=1500
H=1500/250
H= 6 cm 

Therefore the height of the hall is 6 cm 


]]> 2020-06-03 09:48:48 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608550155 250h time 10 = total cost of painting which is 15000 therefore 2500h=15000therefore height is 15000divided by 25 =6 https://padlet.com/lathajoy68/l137uopswr40/wish/608551078 2020-06-03 09:49:24 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608551078 Jagannath group 1 https://padlet.com/lathajoy68/l137uopswr40/wish/608551360 LSA cube= 4 x 10 2                                        .    =4 x 100    . =400cm 2 .         ]]> 2020-06-03 09:49:34 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608551360 Noel Thomas Daniel (9-M) Area of four walls = 2lh + 2bh = 2(l + b) hPerimeter of the floor of hall = 2(l + b)Perimeter of the floor of hall = 250 mTherefore, 2(l + b) = 250 mPutting this value in the formula of Area of four walls we get,Area of four walls = 2(l + b) hArea of four walls = 250h m2Cost of painting per m2 area = Rs 10Cost of painting 250h m2 area = Rs (250h × 10)= Rs 2500hHowever, it is given that the cost of painting the walls is Rs 1500015000 = 2500h1500/2500150/ https://padlet.com/lathajoy68/l137uopswr40/wish/608551449 2020-06-03 09:49:37 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608551449 REHAN ROY https://padlet.com/lathajoy68/l137uopswr40/wish/608551469 (group 1)
L.S.A
CUBE= 4 (a)
          = 4 (10)^2
          = 4(100)
          = 400 cm 

CUBOID= 2(l+b)h
              = 2(12+10)8
              = 44×8
              = 352 cm

Therefore cube has a larger lateral surface of 400cm]]> 2020-06-03 09:49:38 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608551469 lathajoy68 https://padlet.com/lathajoy68/l137uopswr40/wish/608551679 Time up boys]]> 2020-06-03 09:49:45 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608551679 Group 1 ShazalShakir https://padlet.com/lathajoy68/l137uopswr40/wish/608554764 Shazal Shakir 

The question asks us to compare the LSA's of both cube and the cuboid. 

LSA of cube = 4a^2
                       = 4 x 10^2
                       = 4 x 100
                       = 400cm^2

LSA of cuboid = 2 x (l+b) x h
                          = 2 x (5+4) x 3 
                          = 2 x 9 x 3
                          = 18 x 3
                          = 54cm^2

Therefore we can conclude that the cubical box has a larger LSA by 500-54
     = 446cm^2

]]> 2020-06-03 09:51:26 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608554764 GROUP 1 done by Shazin Sherif https://padlet.com/lathajoy68/l137uopswr40/wish/608558940 Lateral surface area = 4(a)
                                     =4(10)^2
                                      =4 x (100)
                                      =400]]> 2020-06-03 09:53:50 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608558940 Athul Bijukumar athulbijukumar https://padlet.com/lathajoy68/l137uopswr40/wish/608562659 Group 3

Perimeter = 2(l + b)=250m
Rate = 10 rupees per m^2
Cost = 15000 rupees

LSA of a cuboid = 2(l + b)h
                              = 250h

Cost of painting 4 walls = 250h x 10 rupees = 2500h
=15000 rupees

Therefore, h = 15000/2500
= 6m]]> 2020-06-03 09:56:07 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/608562659 AFEEF ABID/GRADE 9/GROUP 2 l=5m https://padlet.com/lathajoy68/l137uopswr40/wish/610235225 B=4m
H=3m
Rate of whitewashing =AED 7.5 per m2
LSA+AREA OF CEILING 
={2*(l+b)h}+{l*b}
=74m2
Cost=AED 7.5*74
=555 AED]]> 2020-06-04 05:24:10 UTC https://padlet.com/lathajoy68/l137uopswr40/wish/610235225