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      <title>LGI Maths (WB 20.5.24) by </title>
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      <description>L.O: To explore the properties of circles</description>
      <language>en-us</language>
      <pubDate>2024-05-21 14:15:48 UTC</pubDate>
      <lastBuildDate>2025-04-24 07:27:54 UTC</lastBuildDate>
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         <title>Lesson Slides</title>
         <author>kayleighf</author>
         <link>https://padlet.com/Year623_24/kzlkaz6w4ivxsmj4/wish/3001886910</link>
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         <pubDate>2024-05-21 14:21:51 UTC</pubDate>
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      <item>
         <title>Questions</title>
         <author>kayleighf</author>
         <link>https://padlet.com/Year623_24/kzlkaz6w4ivxsmj4/wish/3001887138</link>
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         <pubDate>2024-05-21 14:22:01 UTC</pubDate>
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      <item>
         <title>Six Circles</title>
         <author>kayleighf</author>
         <link>https://padlet.com/Year623_24/kzlkaz6w4ivxsmj4/wish/3001889622</link>
         <description><![CDATA[<p>In the diagram, six circles of equal size touch adjacent circles and the sides of the large rectangle.<br><br>Each of the corners of the small rectangle is the centre of one of the large circles.<br><br>The perimeter of the small rectangle is 60cm.<br><br><strong>What is the perimeter of the large rectangle?</strong></p>]]></description>
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         <pubDate>2024-05-21 14:23:49 UTC</pubDate>
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         <title>Parts of a Circle</title>
         <author>kayleighf</author>
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         <pubDate>2024-05-21 15:50:54 UTC</pubDate>
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         <title></title>
         <author>kayleighf</author>
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         <pubDate>2024-05-21 15:51:27 UTC</pubDate>
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         <title>Lesson Slides</title>
         <author>kayleighf</author>
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         <pubDate>2024-05-21 16:06:23 UTC</pubDate>
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         <title>Circumference</title>
         <author>kayleighf</author>
         <link>https://padlet.com/Year623_24/kzlkaz6w4ivxsmj4/wish/3002052984</link>
         <description><![CDATA[<p>Circumference is the name given to the distance around the boundary of a circle (very similar to perimeter).</p><p><br></p><p>It can be calculated in two ways:</p><p><br></p><ul><li><p><strong>C = π (3.14) x D</strong></p></li><li><p><strong>C = 2 x π x R</strong></p></li></ul><p><br></p><p>Use this understanding to calculate the circumference of the given circles.</p><p><br></p><p> </p>]]></description>
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         <pubDate>2024-05-21 16:40:06 UTC</pubDate>
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      <item>
         <title>Fluency Focus</title>
         <author>kayleighf</author>
         <link>https://padlet.com/Year623_24/kzlkaz6w4ivxsmj4/wish/3002104303</link>
         <description><![CDATA[]]></description>
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         <pubDate>2024-05-21 17:29:55 UTC</pubDate>
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         <title>Diagnostic Questions</title>
         <author>kayleighf</author>
         <link>https://padlet.com/Year623_24/kzlkaz6w4ivxsmj4/wish/3002104622</link>
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         <pubDate>2024-05-21 17:30:14 UTC</pubDate>
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         <title>Purposeful Practice</title>
         <author>kayleighf</author>
         <link>https://padlet.com/Year623_24/kzlkaz6w4ivxsmj4/wish/3002104933</link>
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         <pubDate>2024-05-21 17:30:31 UTC</pubDate>
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      <item>
         <title>PQ Answers</title>
         <author>kayleighf</author>
         <link>https://padlet.com/Year623_24/kzlkaz6w4ivxsmj4/wish/3002105790</link>
         <description><![CDATA[<p>32mm</p><p><br/></p><p>40mm</p>]]></description>
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         <pubDate>2024-05-21 17:31:24 UTC</pubDate>
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         <title>FF Answers</title>
         <author>kayleighf</author>
         <link>https://padlet.com/Year623_24/kzlkaz6w4ivxsmj4/wish/3002107271</link>
         <description><![CDATA[]]></description>
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         <pubDate>2024-05-21 17:32:56 UTC</pubDate>
         <guid>https://padlet.com/Year623_24/kzlkaz6w4ivxsmj4/wish/3002107271</guid>
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      <item>
         <title>DQ Answers</title>
         <author>kayleighf</author>
         <link>https://padlet.com/Year623_24/kzlkaz6w4ivxsmj4/wish/3002109660</link>
         <description><![CDATA[<p>1) D because it is the only line that does not join the circumference to the <strong>centre</strong> of the circle. </p><p><br/></p><p>2) A (no explanation needed).</p><p><br/></p><p>3) A because the diameter of the red circle is half of 32cm (which is 6cm). The red circle's radius is then half of its diameter, giving us 8cm.</p>]]></description>
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         <pubDate>2024-05-21 17:35:34 UTC</pubDate>
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         <title>PP Answers</title>
         <author>kayleighf</author>
         <link>https://padlet.com/Year623_24/kzlkaz6w4ivxsmj4/wish/3002109971</link>
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         <pubDate>2024-05-21 17:35:53 UTC</pubDate>
         <guid>https://padlet.com/Year623_24/kzlkaz6w4ivxsmj4/wish/3002109971</guid>
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      <item>
         <title>Faded Practice</title>
         <author>kayleighf</author>
         <link>https://padlet.com/Year623_24/kzlkaz6w4ivxsmj4/wish/3002111204</link>
         <description><![CDATA[]]></description>
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         <pubDate>2024-05-21 17:37:11 UTC</pubDate>
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