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      <title>Chapter 11: Empirical Formulas and Percent Composition by Michael McCuen</title>
      <link>https://padlet.com/mmccue6926/jp2vofpzgxej</link>
      <description>Overview of chapter 11</description>
      <language>en-us</language>
      <pubDate>2017-11-27 15:07:44 UTC</pubDate>
      <lastBuildDate>2025-10-23 14:47:36 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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         <title>Empirical Formulas </title>
         <author>mmccue6926</author>
         <link>https://padlet.com/mmccue6926/jp2vofpzgxej/wish/210444817</link>
         <description><![CDATA[<div>Empirical Formulas show the smallest whole number ratio of the atoms in the compound.</div>]]></description>
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         <pubDate>2017-11-27 15:13:26 UTC</pubDate>
         <guid>https://padlet.com/mmccue6926/jp2vofpzgxej/wish/210444817</guid>
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      <item>
         <title>Empirical Formula</title>
         <author>mmccue6926</author>
         <link>https://padlet.com/mmccue6926/jp2vofpzgxej/wish/210445379</link>
         <description><![CDATA[<div>Empirical Formula: Percentage/ Molar Mass of Compound</div>]]></description>
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         <pubDate>2017-11-27 15:14:10 UTC</pubDate>
         <guid>https://padlet.com/mmccue6926/jp2vofpzgxej/wish/210445379</guid>
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         <title>Steps</title>
         <author>kfuent7970</author>
         <link>https://padlet.com/mmccue6926/jp2vofpzgxej/wish/210445385</link>
         <description><![CDATA[<div>1. % composition (if = 100%) converts to mass.</div><div>2. Convert from mass to moles</div><div>3. Calculate simplest ratio.</div><div>(divide all # mol by the smallest # moles)</div><div>3 ½. If not all whole numbers, multiply all by a whole # to create whole #’s.</div><div>4. Use simplest ratio as subscripts.</div>]]></description>
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         <pubDate>2017-11-27 15:14:10 UTC</pubDate>
         <guid>https://padlet.com/mmccue6926/jp2vofpzgxej/wish/210445385</guid>
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         <title>Example: Molecular Formula</title>
         <author>mmccue6926</author>
         <link>https://padlet.com/mmccue6926/jp2vofpzgxej/wish/210449028</link>
         <description><![CDATA[<div>Calculate the molecular formula of a compound whose molar mass is 60 g/mol and Empirical Formula is CH4N.<br>1. Percent composition is 60<br>2. Molar Mass of CH4N = 30.04 grams<br>3. 60/30.04 =  2<br>4. CH4N x 2<br>5.Molecular Formula = C2H8N2<br><br></div>]]></description>
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         <pubDate>2017-11-27 15:19:39 UTC</pubDate>
         <guid>https://padlet.com/mmccue6926/jp2vofpzgxej/wish/210449028</guid>
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      <item>
         <title>Example: Empirical Formula</title>
         <author>mmccue6926</author>
         <link>https://padlet.com/mmccue6926/jp2vofpzgxej/wish/210925212</link>
         <description><![CDATA[<div>A compound is found to contain 50.05 % sulfur and 49.95 % oxygen by weight. What is the empirical formula for this compound?<br>1. Change the percents to grams:<br>S -&gt; 50.05 g <br>O -&gt; 49.95 g</div><div>2. Convert the masses to moles:<br>S -&gt; 50.05 g / 32.066 g/mol = 1.5608 mol <br>O -&gt; 49.95 g / 16.00 g/mol = 3.1212 mol</div><div>3. Divide by the lowest, looking for the smallest whole-number:<br>S -&gt; 1.5608 / 1.5608 = 1 <br>O -&gt; 3.1212 / 1.5608 = 2</div><div>4. Write the empirical formula:<br>SO<sub>2</sub></div>]]></description>
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         <pubDate>2017-11-28 14:50:24 UTC</pubDate>
         <guid>https://padlet.com/mmccue6926/jp2vofpzgxej/wish/210925212</guid>
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         <title>Percent Composition</title>
         <author>mmccue6926</author>
         <link>https://padlet.com/mmccue6926/jp2vofpzgxej/wish/211873915</link>
         <description><![CDATA[<ol><li>Write the formula.</li><li>Use the formula to determine molar mass.</li><li>Use the molar mass to determine the mass percentage of each element.</li></ol><div>If you have a compound that has the formula C2H5OH, first determine the mass of each element.<br><br></div><ul><li>mass of C = (2 moles C / 1) * (12 g C / 1 mole) = 24 g C</li><li>mass of H = (6 moles H / 1) * (1 g H / 1 mole) = 6 g H</li></ul><div>When you are counting the number of hydrogens, don't forget to count the one at the end of the formula!<br><br></div><ul><li>mass of O = (1 mole O / 1) * (16 g O / 1 mole) = 16 g O<ul><li>Total mass = 24 g + 6 g + 16 g = 46 g</li></ul></li></ul><div>Next, determine the percent of each element in the total compound.<br><br></div><ul><li>C = (24 / 46) * 100% = 52%</li><li>H = (6 / 46) * 100% = 13%</li><li>O = (16 / 46) * 100% = 35%</li></ul><div><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2017-11-30 14:51:02 UTC</pubDate>
         <guid>https://padlet.com/mmccue6926/jp2vofpzgxej/wish/211873915</guid>
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