<?xml version="1.0"?>
<rss version="2.0">
   <channel>
      <title>Solve 365 + 438. Explain when you needed to group ones or tens together to make a new group.  by Michele Lempa</title>
      <link>https://padlet.com/michele_lempa/jghohyg45842</link>
      <description>Unit 4 Lesson 9. RAP your answer. (X)</description>
      <language>en-us</language>
      <pubDate>2018-02-24 15:40:38 UTC</pubDate>
      <lastBuildDate>2026-01-04 10:39:23 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
      <image>
         <url></url>
      </image>
      <item>
         <title>faaiq</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235351990</link>
         <description><![CDATA[<div>how you can solve 365+438 in ones or tens you  first  you can tell how  you are going to make a new group and than</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:10:39 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235351990</guid>
      </item>
      <item>
         <title>sincere</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235352173</link>
         <description><![CDATA[<div>the ansr to 365+438= 803&nbsp; i no this becuse now groups above .and&nbsp; i can explain how you no when to&nbsp;group your ones or tins because when you get to 9 you got to stop ther because if you go pase you will get 0 .</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:10:59 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235352173</guid>
      </item>
      <item>
         <title>avon</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235352196</link>
         <description><![CDATA[<div>i can explain 365+438 so i start &nbsp; from my ones the i do 8+then.</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:11:02 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235352196</guid>
      </item>
      <item>
         <title>harry hale</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235352233</link>
         <description><![CDATA[<div>i can explain 365+438 so i start from my ones the i do 8+5 then i carry my one over top of the six then i will add 6+3+1 it equal 10 but i'm gonna put zero now im going to do my hundred place&nbsp;the i carry my one over the 3 then i add 3 1 and 4 that equals 8 and my answer will be 803 and that's how i got my answer.</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:11:06 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235352233</guid>
      </item>
      <item>
         <title>Donyhla</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235352245</link>
         <description><![CDATA[<div>I can solve 365+438= by counting the 1's place first and grouping it together</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:11:08 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235352245</guid>
      </item>
      <item>
         <title>christian</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235352349</link>
         <description><![CDATA[<div>365+438=791</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:11:18 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235352349</guid>
      </item>
      <item>
         <title>Amyiah Judge </title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235352363</link>
         <description><![CDATA[<div>365+438=803 when I needed to regroup was&nbsp; when I had 10 ones then there were 3 ones left so I put 3 in the ones then the tens there are ten 10's so I add one more hundred and the answer is 803.&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:11:19 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235352363</guid>
      </item>
      <item>
         <title>Carmela Martin</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235352379</link>
         <description><![CDATA[<div>I needed to group ones or tens together to make a new group.</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:11:21 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235352379</guid>
      </item>
      <item>
         <title>jihad turner </title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235352469</link>
         <description><![CDATA[<div>The way I would solve this is I know how to make a new group and ones or tens is because 365+438=803.I know when to make new groups is </div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:11:31 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235352469</guid>
      </item>
      <item>
         <title>GeoVanie</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235352596</link>
         <description><![CDATA[<div>To solve 365+438 I help you solve frist you look at the 1's&nbsp; 8+5=13 so the 3 is 4 or the 6 is 7. 7+3 or 6+4=10 so in the 10's it 0 and in the 1's it's 3 now the hundreds the 0 is 10 so the 1 in 10 is now in the hundred place so it 400+400=800 so it is 803.</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:11:45 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235352596</guid>
      </item>
      <item>
         <title>Malik</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235352644</link>
         <description><![CDATA[<div>The way i&nbsp; would&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:11:52 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235352644</guid>
      </item>
      <item>
         <title>Juan</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235352711</link>
         <description><![CDATA[<div>I can solve 365+438 because 5+8=13 then 6+3=9 add 1 it eqwul 10 and 4+3=7 add one it 8. I add all the numbers up then i get 803 that the number i got.</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:11:59 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235352711</guid>
      </item>
      <item>
         <title>Jayden Armor</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235352738</link>
         <description><![CDATA[<div>I can explain 365+438 you will put a 1 up top the 6 and add 1+6+3 </div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:12:02 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235352738</guid>
      </item>
      <item>
         <title>Jalicia Acevedo </title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235352818</link>
         <description><![CDATA[<div>365+438=803 i know that because  new groups above  methed</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:12:10 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235352818</guid>
      </item>
      <item>
         <title>Mariaje</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235352858</link>
         <description><![CDATA[<div>When I need new groups to solve 365+438 first I need to figure out what method I will use then write that method using my equation then add them up so if ones or tens or hundreds number is ten or above then I know I got a new ones, tens or new hundred so then I know I carry my one to the section and keep adding and that is how u do it</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:12:13 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235352858</guid>
      </item>
      <item>
         <title>lamanni</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235355506</link>
         <description><![CDATA[<div>i no how to do it it hapins win you swish the number  you tern the 3 to the 5 an you let number rest antern it to a 0</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 14:16:40 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235355506</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/235431279</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2018-02-26 15:57:36 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/235431279</guid>
      </item>
      <item>
         <title>jihad</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/240838129</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2018-03-12 13:18:20 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/240838129</guid>
      </item>
      <item>
         <title>turner</title>
         <author></author>
         <link>https://padlet.com/michele_lempa/jghohyg45842/wish/240838180</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2018-03-12 13:18:24 UTC</pubDate>
         <guid>https://padlet.com/michele_lempa/jghohyg45842/wish/240838180</guid>
      </item>
   </channel>
</rss>
