For #2-( 0.150M)x(3.80mL)=(xM2)(10.0mL) M2= 0.057M

For #3-(0.150M)x(2.40mL)=(xM2)( 10.0mL) M2=0.036M

2. M1xM2= M2xV2

For #4-( 0.150M)(xmL)= (0.075M)(10.0mL) V2= 5.00mL

for#5- (0.150M)(xmL)= (0.023M)(10.0mL) V2=1.53mL

3.The relationship between the concentration of a solution and it's

color intensity that the lightest shade of blue has a weaker concentration

because it's more diluted. So the darkest shade of blue will have a greater

concentration.

4. The relationship between concentration and absorbance is if the

concentration increases then so must the absorbency.

5. Graph

6. Yes it makes sense to have (0,0) as a point because if there is no concentration

then there will be no absorbency.

7. Graph

8. The concentration of this unknown solution is about 0.250 M.

absorbance = 1.022(conc.)

0.088 = 1.022(conc.)

0.088/1.022 ≈ 0.086 M

conc. ≈ 0.086 M

2. % error = |experimental value - theoretical value| x 100

theoretical value

% error = |0.086 M - 0.0341 M| x 100

0.0341 M

% error = |0.0519 M| x 100

0.0341 M

% error ≈ 1.52 M x 100

% error ≈ 152%