https://padlet.com/dlavig9669/izzanbqfpchb en-us 2018-05-15 21:28:31 UTC 2018-05-28 16:28:15 UTC hello@padlet.com dlavig9669 https://padlet.com/dlavig9669/izzanbqfpchb/wish/261024763 Sine= Opposite/ Hypotenuse
Cosine= Adjacent/ Hypotenuse
Tangent= Opposite/ Adjacent]]> 2018-05-15 21:33:11 UTC https://padlet.com/dlavig9669/izzanbqfpchb/wish/261024763 dlavig9669 https://padlet.com/dlavig9669/izzanbqfpchb/wish/261025029 To solve a right triangle you will need to use the information you are given to find the rest of the triangle. If you are solving for an angle use SOHCATOA. If you are solving for a side use Pythagorean's theorem.]]> 2018-05-15 21:34:36 UTC https://padlet.com/dlavig9669/izzanbqfpchb/wish/261025029 dlavig9669 https://padlet.com/dlavig9669/izzanbqfpchb/wish/261025215 In this problem you are given the angle and side for a. Since you know 2 of the 3 angles, you can add your given angles and subtract from 180. This gives you angle B which is 73 degrees. Knowing one side means we will have to use SOHCAHTOA and Pythagorean's theorem. We will use SOCAHTOA first to solve for side b. We will use tangent. tan= opp./ adj. So tan17= 135/b. Plug that into the calculator and you get b to equal  441.6. Using Pythagorean's theorem we can solve for c, the last side. We do 135^2 + 441.6^2 = c^2. Once you do the math this comes out to be c=461.7.]]> 2018-05-15 21:35:53 UTC https://padlet.com/dlavig9669/izzanbqfpchb/wish/261025215 dlavig9669 https://padlet.com/dlavig9669/izzanbqfpchb/wish/262399967 a^2 + b^2 = c^2]]> 2018-05-21 15:26:06 UTC https://padlet.com/dlavig9669/izzanbqfpchb/wish/262399967 dlavig9669 https://padlet.com/dlavig9669/izzanbqfpchb/wish/262786954 A triangle with an angle of 90 degrees.]]> 2018-05-22 17:42:44 UTC https://padlet.com/dlavig9669/izzanbqfpchb/wish/262786954 dlavig9669 https://padlet.com/dlavig9669/izzanbqfpchb/wish/262787166 In this problem you are given the angle for h and two other sides. We will solve for x first. Since we have the adjacent side and the opposite side for x we will use tangent to solve. tanX=6/8. To do this we will use tangent inverse. We get the angle to be 37 degrees. If we add this to 90 and subtract from 180 we get the third angle to be 53 degrees. Now we can use Pythagorean's theorem to solve for h, the last side. h is the hypotenuse. 6^2 + 8^2= c^2. The last side is 10.]]> 2018-05-22 17:43:20 UTC https://padlet.com/dlavig9669/izzanbqfpchb/wish/262787166 dlavig9669 https://padlet.com/dlavig9669/izzanbqfpchb/wish/262790269 Use sine when solving for a side:
sin90= x/5
5sin90=x

Use sine inverse when solving for an angle:
sinx=5/8
sin^-1(5/8)=x]]> 2018-05-22 17:50:55 UTC https://padlet.com/dlavig9669/izzanbqfpchb/wish/262790269 dlavig9669 https://padlet.com/dlavig9669/izzanbqfpchb/wish/262790587 2018-05-22 17:51:47 UTC https://padlet.com/dlavig9669/izzanbqfpchb/wish/262790587