https://padlet.com/jks339/imh1w7x0yjat4ja5 en-us 2021-02-19 15:00:33 UTC 2023-02-16 19:06:18 UTC hello@padlet.com https://padlet.net/icons/png/1f973.png jks339 https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219090607 Please post a brief written explanation to explain to your classmates your approach to solving this problem!]]> 2021-02-19 15:02:03 UTC https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219090607 https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219611066 complete the square (bottom can't be factored) then sub in for arctangent]]> 2021-02-19 17:10:01 UTC https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219611066 https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219673876 First you can long divide since the degree is higher on the top then you can separate the terms and integrate seperately.]]> 2021-02-19 17:24:46 UTC https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219673876 https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219676215 Pull the 4 out of the integration. Complete the square on the denominator.  Change the term 16(x-(3/4))^2 into (4x-3)^2. Use (4x-3) for usub and integrate the function as arcsin. Multiply the original 4 by the 4 from the usub to get the solution.]]> 2021-02-19 17:25:19 UTC https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219676215 gracekohler6 https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219699638 Because the degree of the numerator was bigger, I used long division and then took the antiderivative of each of the individual terms I got from dividing. ]]> 2021-02-19 17:31:05 UTC https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219699638 https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219699932 Note that it is nearly in the form of the derivative of arctan, but the x is in the numerator. By doing u-sub it corrects this issue by making the x apart of du.]]> 2021-02-19 17:31:10 UTC https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219699932 https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219700365 The first step is to use long division since the degree in the numerator is bigger than the denominator. Then, you are able to integrate normally. ]]> 2021-02-19 17:31:17 UTC https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219700365 https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219701170 2021-02-19 17:31:29 UTC https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219701170 https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219711928 since i could not factor the denominator I completed the square. After I used u substitution, integrated, and then plugged x back in for u to get my solution. ]]> 2021-02-19 17:33:49 UTC https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219711928 https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219728343 complete square inside sqrt and then put it back in and then solve it as sin-1]]> 2021-02-19 17:37:42 UTC https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1219728343 https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1220143729 The denominator can be factored down as it is a perfect square. You can then do u-sub on the denominator and solve through integrating. ]]> 2021-02-19 19:27:15 UTC https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1220143729 zhschult https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1227532556 U-sub with x^3 -2 as U

]]> 2021-02-22 17:01:22 UTC https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1227532556 zhschult https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1227597612 Bit messy but yeah. First you start with a polynomial division, labeled 1, then you write it all out. you then have to use a U-sub for the last term, labeled 2. Finally, you integrate the entire thing and there's your answer.]]> 2021-02-22 17:12:52 UTC https://padlet.com/jks339/imh1w7x0yjat4ja5/wish/1227597612