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      <title>Cálculo do Trabalho resultante ou total by Heidy Monteiro</title>
      <link>https://padlet.com/heidymonteiro20/ii7vcsacmr5zbdti</link>
      <description>Exercício modelo de como calcular o trabalho resultante</description>
      <language>en-us</language>
      <pubDate>2020-06-25 16:40:59 UTC</pubDate>
      <lastBuildDate>2025-04-10 13:47:31 UTC</lastBuildDate>
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      <item>
         <title>1-EXERCÍCIO DE EXEMPLO</title>
         <author>heidymonteiro20</author>
         <link>https://padlet.com/heidymonteiro20/ii7vcsacmr5zbdti/wish/640205880</link>
         <description><![CDATA[<div>Um bloco desliza em um plano inclinado de 37° com a horizontal sob a ação de três forças, conforme mostra a figura </div>]]></description>
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         <pubDate>2020-06-25 16:48:25 UTC</pubDate>
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         <title>2-Dados:</title>
         <author>heidymonteiro20</author>
         <link>https://padlet.com/heidymonteiro20/ii7vcsacmr5zbdti/wish/640211014</link>
         <description><![CDATA[<div>sen 37° = cos 53° = 0,60 e cos 37° = = sen 53° = 0,80, AB=10m;<br>T = F · d · cos θ </div>]]></description>
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         <pubDate>2020-06-25 16:54:09 UTC</pubDate>
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         <title>4-Resolução:Força de 100 N</title>
         <author>heidymonteiro20</author>
         <link>https://padlet.com/heidymonteiro20/ii7vcsacmr5zbdti/wish/640213985</link>
         <description><![CDATA[<div>  o ângulo θ entre a força e o deslocamento AB é de 53° (90° – 37°):<br> T<sub>100</sub> = F · d<sub>AB</sub> · cos 53°<br> T<sub>100</sub> = 100 · 10 · 0,60<br> T<sub>100</sub> = 600 J (motor)<br><br></div>]]></description>
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         <pubDate>2020-06-25 16:57:42 UTC</pubDate>
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         <title>3-Força de 80N</title>
         <author>heidymonteiro20</author>
         <link>https://padlet.com/heidymonteiro20/ii7vcsacmr5zbdti/wish/640217123</link>
         <description><![CDATA[<div>O ângulo θ entre a força e o deslocamento AB é de 90°:<br> T<sub>80</sub> = F · d<sub>AB</sub> · cos 90°<br> T<sub>80</sub> = 80 · 10 · 0<br> T<sub>80</sub> = 0 J (nulo)<br><br></div>]]></description>
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         <pubDate>2020-06-25 17:01:14 UTC</pubDate>
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         <title>5-Força de 20N</title>
         <author>heidymonteiro20</author>
         <link>https://padlet.com/heidymonteiro20/ii7vcsacmr5zbdti/wish/640220558</link>
         <description><![CDATA[<div>O ângulo θ entre a força e o deslocamento AB é 180°:<br> T<sub>20</sub> = F · d<sub>AB</sub> · cos 180°<br> T<sub>20</sub> = 20 · 10 · (–1)<br> T<sub>20</sub> = –200 J (resistente)<br><br></div>]]></description>
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         <pubDate>2020-06-25 17:05:09 UTC</pubDate>
         <guid>https://padlet.com/heidymonteiro20/ii7vcsacmr5zbdti/wish/640220558</guid>
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         <title>6-Por último:T</title>
         <author>heidymonteiro20</author>
         <link>https://padlet.com/heidymonteiro20/ii7vcsacmr5zbdti/wish/640222631</link>
         <description><![CDATA[<div> O trabalho resultante será a soma algébrica de todos os trabalhos:<br> T<sub>R</sub> = T<sub>100</sub> + T<sub>80</sub> + T<sub>20</sub><br> T<sub>R</sub> = 600 + 0 – 200<br> T<sub>R</sub> = 400 J<br><br></div>]]></description>
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         <pubDate>2020-06-25 17:07:31 UTC</pubDate>
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