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      <title>AFL  7th October 2020 - 11G1 Math. by Lakshmi Sathyanarayanan</title>
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      <description>Find the value of &#39;n&#39; if (n + 1)! = 12 x (n - 1)! (Where &#39;n&#39; is a natural number)</description>
      <language>en-us</language>
      <pubDate>2020-10-06 13:40:05 UTC</pubDate>
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         <title>Soha 11g1</title>
         <author></author>
         <link>https://padlet.com/boomasathyanarayanan/i7tees4t66jumvnd/wish/809635900</link>
         <description><![CDATA[<div> (n + 1)! = 12 x (n - 1)!<br>(n+1)n! = 12 x  n!/n (since (n-1)! = n!/n)<br>divide by n!<br>(n+1) (n) = 12<br>n^2 + n - 12 = 0<br>(n+4) (n-3) = 0<br>therefore <mark>n = 3 </mark></div>]]></description>
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         <pubDate>2020-10-07 08:59:36 UTC</pubDate>
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         <title>Nameera</title>
         <author></author>
         <link>https://padlet.com/boomasathyanarayanan/i7tees4t66jumvnd/wish/809636057</link>
         <description><![CDATA[<div>(n+1)! = 12(n-1)!<br>(n+1)(n!)= 12(n!)/n<br>n<sup>2</sup>+n-12=0<br>Therefore, <strong>n=3</strong><br><br></div>]]></description>
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         <pubDate>2020-10-07 08:59:41 UTC</pubDate>
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         <title>Naillya-11G1</title>
         <author>gvnaillya5</author>
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         <pubDate>2020-10-07 09:00:49 UTC</pubDate>
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         <title></title>
         <author></author>
         <link>https://padlet.com/boomasathyanarayanan/i7tees4t66jumvnd/wish/809638318</link>
         <description><![CDATA[<div>Abhipsa</div>]]></description>
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         <pubDate>2020-10-07 09:01:05 UTC</pubDate>
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         <title>Ann</title>
         <author></author>
         <link>https://padlet.com/boomasathyanarayanan/i7tees4t66jumvnd/wish/809646372</link>
         <description><![CDATA[<div>n=3 <br>n cannot be equal to -4 </div>]]></description>
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         <pubDate>2020-10-07 09:05:53 UTC</pubDate>
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      <item>
         <title>Levita</title>
         <author></author>
         <link>https://padlet.com/boomasathyanarayanan/i7tees4t66jumvnd/wish/809647335</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-10-07 09:06:29 UTC</pubDate>
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      <item>
         <title>Hanna 11G1</title>
         <author></author>
         <link>https://padlet.com/boomasathyanarayanan/i7tees4t66jumvnd/wish/809654803</link>
         <description><![CDATA[<div>(n+1)(n)(n-1!)=12x(n-1)!<br>n^2+n=12<br>n=3</div>]]></description>
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         <pubDate>2020-10-07 09:10:59 UTC</pubDate>
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         <title>Ria</title>
         <author></author>
         <link>https://padlet.com/boomasathyanarayanan/i7tees4t66jumvnd/wish/809655541</link>
         <description><![CDATA[<div>(n+1)(n)(n-1)! = 12 x (n-1)!<br>(n+1)(n) = 12<br>n<sup>2</sup> + n - 12 = 0<br>n + 4n - 3n -12 = 0<br>n = 3<br>n = -4 (not possible)<br><br>Therefore,<strong> n = 3</strong></div>]]></description>
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         <pubDate>2020-10-07 09:11:23 UTC</pubDate>
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         <title>Ginan</title>
         <author></author>
         <link>https://padlet.com/boomasathyanarayanan/i7tees4t66jumvnd/wish/809657694</link>
         <description><![CDATA[<div>(n+1)! = 12 (n-1)!<br>(n+1) (n) (n-1) ! = 12 (n-1) !<br>n^2+n-12=0<br>n^2+4n-3n-12 = 0<br>n(n+4) -3 (n+4)  = 0<br>(n+4) (n-3) = 0<br>n = -4, 3<br><mark>Final answer:<br>n = 3.</mark></div>]]></description>
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         <pubDate>2020-10-07 09:12:42 UTC</pubDate>
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