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      <title>week 11 Day 4 Maths Assessment for learning by Nagalakshmi Gajendra</title>
      <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78</link>
      <description>Ensure you write your name and level of the question.</description>
      <language>en-us</language>
      <pubDate>2020-06-03 08:06:25 UTC</pubDate>
      <lastBuildDate>2025-11-28 16:43:25 UTC</lastBuildDate>
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      <item>
         <title>Dhrivika - Level 1 </title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608413223</link>
         <description><![CDATA[<div> <mark>The mean of A is = 6   </mark>                 The mean of B is = 6 <br><mark>Method</mark> : My method was to add all the cubes in A or B and then divide it by the number of towers </div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:28:48 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608413223</guid>
      </item>
      <item>
         <title>Ankrithi</title>
         <author>ankrithik_gfs</author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608413436</link>
         <description><![CDATA[<div>Level 1<br>Mean of a:6<br>Solution:5+4+5+6+10=30<br>No.of towers=5<br>30/5=6<br><br>Mean of b:6<br>Solution:5+6+5+6+8=30<br>No. of towers=5<br>30/5=6</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:28:56 UTC</pubDate>
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      </item>
      <item>
         <title>Hamdan</title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608413471</link>
         <description><![CDATA[<div>lvl 1 <br>a is 30÷5= 6<br>b is 30÷5= 6 <br><br>5+5+4+6+10= 30 then we divide by how many groups there is to the number in this case, we have 5 groups ( aka columns)  so then , 5÷30 is 6 <br><br><br>5+6+5+6+8= 30 then we divide the groups which is 5 so, 30÷5= 6<br><br>formula: count the total amount then count how many rows of numbers there is and divide your number by the rows of number you have    <br>   </div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:28:57 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608413471</guid>
      </item>
      <item>
         <title>Marten </title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608413602</link>
         <description><![CDATA[<div>level 2 <br>I agree with  miss Lakshmi because for example  if the are 3 children have an age of 1 child= 7<br>2 child = 3 years and the third children would be 5 so they all add up to  15 so then I have to divide 15 by the number of child’s which would be 5.in this question we can’t use miss Jessica’s method because I can’t half the kids age<br>That’s why I agree with miss L</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:29:02 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608413602</guid>
      </item>
      <item>
         <title>Rameen</title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608414232</link>
         <description><![CDATA[<div>Level 1: for a it would be 6 because you need to add all of the blocks together and then divide it by how much towers there are which is 5 and the blocks of numbers are 30 so you need to divide 30 by 5 which would give you 6 and it’s the same for question B</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:29:27 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608414232</guid>
      </item>
      <item>
         <title>jena </title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608414267</link>
         <description><![CDATA[<div>Level 1                                                  you just add all of the cubes than divide it by 3 and it will give you the mean<br>so a)5+4+5+6+10=30\ 3 =10<br>b) 5+6+5+6+8=30\3=10</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:29:28 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608414267</guid>
      </item>
      <item>
         <title>Aya</title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608415080</link>
         <description><![CDATA[<div>level 1:how did I find 6for A I found it cause if you count the cubes which gave me 30 then  the tower which gave me 5 you divide it which will give me 6<br>For B it was 6 because if you count the cubes which gave me 30 then you divide it by the tower which is 8 the  it gave me the answer 6<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:30:00 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608415080</guid>
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      <item>
         <title>Christos  6G</title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608415677</link>
         <description><![CDATA[<div><br>Level:2<br>I agree with miss Lakshmi <br>if we were using the weight of a gold bar to find the mean of the weight, miss L method wouldn’t be useful because we can’t just change the weight to calculate the mean.for eg : there are 3 gold bars , the first gold bar weighs 300kg , the second gold bar weighs 200kg and the last one weighs 500kg which adds up to 1000 kg and divided by 3 bars which would give us the weight of 333.333kg...<br>Which ,miss l method won’t be useful for us because we can’t change the weight of something.thats why miss l method won’t be useful for us .</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:30:22 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608415677</guid>
      </item>
      <item>
         <title>Rahaf</title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608416132</link>
         <description><![CDATA[<div>I agree with miss L, because if you just move the cubes that’s not effective, think about a person’s <strong>age </strong>or <strong>height</strong>. You can’t just change/move someone’s age or physically change their height. But If you divide by the sum total it is more effective. For example: you have 7+3+5 which equals 15 and your adding 3 numbers. So 15 divided by 3 which equals 5 meaning 5 is the mean.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:30:34 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608416132</guid>
      </item>
      <item>
         <title>Lara </title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608417404</link>
         <description><![CDATA[<div>level 1 <br>For A it would be 6 because  5+5=10+10=20+6=26+4=30<br>So 30 divided by 5 because there are 5 numbers so you add the numbers get the total and divide the total by the amount of numbers you have so there you get the answer and you get the mean 👍🏻1b<br>It’s the exact same thing like before just different number but it still adds up to 30 and All the numbers are 5 so 30 divided by 5 is 6 ..</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:31:23 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608417404</guid>
      </item>
      <item>
         <title>Level2</title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608417960</link>
         <description><![CDATA[<div>Yousef<br>I agree with mrs L because if ur going to calculate the mean of the average for 3 people’s height can’t use mrs Jessica’s method</div>]]></description>
         <pubDate>2020-06-03 08:31:44 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608417960</guid>
      </item>
      <item>
         <title>Sidhant </title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608419092</link>
         <description><![CDATA[<div>level 2 <br>i agree with Miss L because if you add all the number of cubes and then divide it you will get the mean<br> if you get 4 cubes in one tower and 5 cubes in an another tower and 6 cubes in the last tower. if you add it up you get 15 and then divide it up by 3 you get 5.  <br><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:32:30 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608419092</guid>
      </item>
      <item>
         <title>Roy</title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608419577</link>
         <description><![CDATA[<div>Level 1<br>Answer for a is 6. This is because the mean of the cubes are 5, meanwhile the total number of cubes are 30. 30 divided by 5 is 6.<br>Answer for b is 6.<br><br>Level 3<br>It says the mean of 3 teams score is 2. This means that some numbers were added before they were divided by the mean of the numbers, which means it could be any number.<br><br>X+C+E = Z / A = 2<br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:32:45 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608419577</guid>
      </item>
      <item>
         <title>Naomi </title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608419638</link>
         <description><![CDATA[<div>level 2<br>I agree with miss L because in some cases you could be finding  the mean of a persons age. Miss Jessica’s method wouldn’t be useful here.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:32:47 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608419638</guid>
      </item>
      <item>
         <title>lilian</title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608421109</link>
         <description><![CDATA[<div>Level 2: I agree with miss L because if you add all the cubes together and divide it. It will be more effective than moving the cubes . In some cases you can find the mean of a persons age.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:33:40 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608421109</guid>
      </item>
      <item>
         <title>Farida </title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608425215</link>
         <description><![CDATA[<div>Level 2 I agree with miss L because she used the correct way and it is a quick and easy way and miss Jessicas’s method is also correct but it is not an accurate way or getting the mean.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:36:10 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608425215</guid>
      </item>
      <item>
         <title>Michelle </title>
         <author>maymishu2008</author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608427642</link>
         <description><![CDATA[<div>Level 2:-<br>Yes I do agree with with Ms.L because if there are three kids and kid a is 100 cm, kid 2 is 120 cm and kid 2  is 125 I can’t change there height by cutting them and giving it to an another kid so Ms.Jesica’s method won’t works.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:37:35 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608427642</guid>
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      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608427832</link>
         <description><![CDATA[<div>Joseph level 1<br>A)there are 30 cubes in total and there are 5 towers .we should do 30÷5=6<br>B)there are 30 cubes but in a different shape and there are still 5 towers . We should do 30÷5=6 and a and b have the same answers.</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:37:42 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608427832</guid>
      </item>
      <item>
         <title>Naya </title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608428245</link>
         <description><![CDATA[<div>Both are right but level two is more effective bcoz she use mathematical method which will be more accurate as we need to calculate the total number of cubes and divide it by 5 which is better than doing them physically <br>30/5 =6 <br><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:37:57 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608428245</guid>
      </item>
      <item>
         <title>Omar </title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608431735</link>
         <description><![CDATA[<div>level 1    the mean of a is 6                               the mean of b is also 6                                because if you try to split the biggest tower of cubes into the small one they will all be 6 same thing with tower b</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:39:53 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608431735</guid>
      </item>
      <item>
         <title>Rameen </title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608453441</link>
         <description><![CDATA[<div>level 2 <br>I would agree with miss Lakshmi because I feel like in some scenarios her method would be more effective e.g  who got the highest test score you can’t move it around because it’s not an object therefore I feel like miss L. has the most effective method. </div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:51:58 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608453441</guid>
      </item>
      <item>
         <title>Aarnav</title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608456833</link>
         <description><![CDATA[<div>Lvl 2<br>You cannot use blocks for...water density / Millie liters or liters.                                                                                               B b</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:54:03 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608456833</guid>
      </item>
      <item>
         <title>Michelle </title>
         <author>maymishu2008</author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608464378</link>
         <description><![CDATA[<div>Level 3:-<br>Possibility 1: 2,2,2.<br>Possibility 2: 3,1,2.<br>Possibility 3: 1,2,3.<br>Possibility 4: 3,2,1.<br>Possibility 5: 1,3,2.<br>Possibility 6: 2,3,1.<br>Possibility 7: 2,1,3.<br>Possibility 8: 0,1,2.<br>Possibility 9: 3,2,0.<br>Possibility 10: 1,0,3.<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 08:58:37 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608464378</guid>
      </item>
      <item>
         <title>Omar level 3 </title>
         <author></author>
         <link>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608469117</link>
         <description><![CDATA[<div>there is 3 teams and the  mean of goals is 2 so every team 1 could score 3 goals while team 2 could score 1 goal while team 3 can score 2 goals <br> solution number 2 : 2,2,2                             solution 3 : 2,1,3                                         solution 4 :   1,3,2                       solution 5 : 2,31                                          solution 6: 1,0,3                                solution 7 : 0,1,2                                solution   8 :  3,2,0                       solution 9 : 3,1,2                 solution 10 :  1,2,3                         <br>                  </div>]]></description>
         <enclosure url="" />
         <pubDate>2020-06-03 09:01:40 UTC</pubDate>
         <guid>https://padlet.com/nagalakshmigajendra/h3qrzgvbfkvpuj78/wish/608469117</guid>
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